CHEMISTRY Chains and Rings. OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced Subsidiary GCE

Similar documents
Tuesday 2 June 2015 Afternoon

FOR EXAMINER S USE You may use the Data Sheet for Chemistry. You are advised to show all the steps in any calculations.

Wednesday 16 January 2013 Morning

CHEMISTRY 2812/01 Chains and Rings

CHEMISTRY 2811/01 Foundation Chemistry

2815/01 CHEMISTRY. Trends and Patterns. OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced GCE

F322: Chains, Energy and Resources Halogenoalkanes

This document consists of 12 printed pages and a Data Sheet for Chemistry.

CHEMISTRY 2815/06. Transition Elements. OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced GCE

UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS General Certificate of Education Advanced Subsidiary Level and Advanced Level

CHEMISTRY 2813/01. How Far, How Fast? OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced Subsidiary GCE

CHEMISTRY 2815/01. Trends and Patterns. OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced GCE

CHEMISTRY 2815/06 Transition Elements

THIS IS A NEW SPECIFICATION

CHEMISTRY Foundation Chemistry. OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced Subsidiary GCE

Cambridge International Examinations Cambridge International Advanced Subsidiary and Advanced Level

THIS IS A NEW SPECIFICATION

Concepts for Advanced Mathematics (C2) WEDNESDAY 9 JANUARY 2008

UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS General Certificate of Education Advanced Subsidiary Level and Advanced Level

Wednesday 16 January 2013 Morning

THIS IS A NEW SPECIFICATION

Cambridge International Examinations Cambridge International Advanced Subsidiary and Advanced Level

Tuesday 4 June 2013 Afternoon

Friday 10 June 2016 Afternoon

CHEMISTRY 2815/01 Trends and Patterns

surname number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F322 CHEMISTRY A Chains, Energy and Resources

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F322 CHEMISTRY A. Chains, Energy and Resources

OCR{i CHEMISTRY 1O JUNE 2OO4. Chains and Rings

SPECIMEN. Candidate Number

Morning. This document consists of 8 printed pages and a Data Sheet for Chemistry.

Wednesday 19 June 2013 Morning


Cherry Hill Tuition A Level Chemistry OCR (A) Paper 11

CHEMISTRY Chains and Rings. OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced Subsidiary GCE

Cambridge International Examinations Cambridge International Advanced Subsidiary and Advanced Level

CHEMISTRY 2816/01. Unifying Concepts. OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced GCE. 1 hour 15 minutes


Cambridge International Examinations Cambridge International Advanced Subsidiary and Advanced Level

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F332/TEST CHEMISTRY B (SALTERS) Chemistry of Natural Resources

Cherry Hill Tuition A Level Chemistry OCR (A) Paper 9 THIS IS A NEW SPECIFICATION

Cambridge International Examinations Cambridge International Advanced Subsidiary and Advanced Level

UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS General Certifi cate of Education Advanced Subsidiary Level and Advanced Level

CHEMISTRY (SALTERS) Chemistry of Materials. OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced GCE

THIS IS A NEW SPECIFICATION

October/November hour 15 minutes. Candidates answer on the Question Paper. Additional Materials: Data Booklet READ THESE INSTRUCTIONS FIRST

surname number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F322 CHEMISTRY A Chains, Energy and Resources

CHEMISTRY (SALTERS) 2850

4. A sample of 0.200g of an organic compound was subjected to combustion analysis and

Tuesday 4 June 2013 Afternoon

THIS IS A NEW SPECIFICATION

CHEMISTRY Chains, Rings and Spectroscopy. OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced GCE. 1 hour 30 minutes

Morning Time: 1 hour 15 minutes

CHEMISTRY 2814/01 Chains, Rings and Spectroscopy

Cambridge International Examinations Cambridge International Advanced Subsidiary and Advanced Level

This document consists of 11 printed pages, 1 blank page and a Data Sheet for Chemistry.

Thursday 19 January 2012 Afternoon

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED GCE F324 CHEMISTRY A. Rings, Polymers and Analysis

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED GCE F324 CHEMISTRY A. Rings, Polymers and Analysis

CHEMISTRY. Chains, Rings and Spectroscopy. OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced GCE. 1 hour 30 minutes

A mass spectrometer can be used to distinguish between samples of butane and propanal. The table shows some precise relative atomic mass values.

Monday 14 January 2013 Afternoon

surname number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED GCE F324 CHEMISTRY A Rings, Polymers and Analysis

F324. CHEMISTRY A Rings, Polymers and Analysis ADVANCED GCE. Friday 24 June 2011 Morning PMT. Duration: 1 hour

Practical Examination 2 (Part B Practical Test)

Wednesday 23 May 2012 Afternoon

Candidate number. Centre number

F322: Chains, Energy and Resources Basic Concepts

All items required by teachers and candidates for this task are included in this pack.

Tuesday 19 June 2012 Afternoon

Advanced Subsidiary Unit 1: The Core Principles of Chemistry

Friday 26 May 2017 Morning

CHEMISTRY. How Far, How Fast? THURSDAY 11 JANUARY 2007 ADVANCED SUBSIDIARY GCE 2813/01. Morning. Time: 45 minutes

THIS IS A NEW SPECIFICATION MODIFIED LANGUAGE

UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS General Certifi cate of Education Advanced Subsidiary Level and Advanced Level

Surname. Number OXFORD CAMBRIDGE AND RSA EXAMINATIONS ADVANCED SUBSIDIARY GCE F332/TEST CHEMISTRY B (SALTERS) Chemistry of Natural Resources

Wednesday 16 January 2013 Morning

Morning. This document consists of 14 printed pages, 2 blank pages and a Data Sheet for Chemistry (Salters).

H 22. (a) Give the general formula of alkanes. (1) (b) Carbon monoxide, CO, is formed during the incomplete combustion of decane.

UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS General Certificate of Education Advanced Subsidiary Level and Advanced Level

llll l] l ilil lllll lllll ' ' ililr iliil ililr ililt ilfl ilil lilil llill llll lill L- This question paper consists of 12 printed pages.

UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS General Certificate of Education Advanced Subsidiary Level and Advanced Level

UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS General Certifi cate of Education Advanced Subsidiary Level and Advanced Level

Friday 27 May 2016 Morning

THIS IS A NEW SPECIFICATION

Candidate number. Centre number

Cambridge International Examinations Cambridge International Advanced Subsidiary and Advanced Level

Thursday 10 January 2013 Morning

Chemistry 2.5 AS WORKBOOK. Working to Excellence Working to Excellence

Friday 10 June 2016 Afternoon Time allowed: 1 hour 30 minutes

Cherry Hill Tuition A Level Chemistry OCR (A) Paper 12

* * MATHEMATICS (MEI) 4761 Mechanics 1 ADVANCED SUBSIDIARY GCE. Wednesday 21 January 2009 Afternoon. Duration: 1 hour 30 minutes.

Thursday 26 January 2012 Afternoon

Cambridge International Examinations Cambridge International Advanced Subsidiary and Advanced Level

physicsandmathstutor.com

UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS General Certificate of Education Advanced Subsidiary Level and Advanced Level

Afternoon Time: 1 hour 30 minutes

Afternoon. This document consists of 14 printed pages and 2 blank pages.

SPECIMEN. All items required by teachers and candidates for this task are included in this pack.

CHEMISTRY 2814/01 Chains, Rings and Spectroscopy

Use your knowledge of organic reaction mechanisms to complete the mechanism for this step by drawing two curly arrows on the following equation.

Transcription:

OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced Subsidiary GCE CHEMISTRY 2812 Chains and Rings Wednesday 8 JUNE 2005 Morning 1 hour Candidates answer on the question paper. Additional materials: Data Sheet for Chemistry Scientific calculator Candidate Name Centre Number Candidate Number TIME 1 hour INSTRUCTIONS TO CANDIDATES Write your name in the space above. Write your Centre number and Candidate number in the boxes above. Answer all the questions. Write your answers in the spaces provided on the question paper. Read each question carefully and make sure you know what you have to do before starting your answer. INFORMATION FOR CANDIDATES The number of marks is given in brackets [ ] at the end of each question or part question. You will be awarded marks for the quality of written communication where this is indicated in the question. You may use a scientific calculator. You may use the Data Sheet for Chemistry. You are advised to show all the steps in any calculations. FOR EXAMINER S USE Question Number 1 2 Max. 13 15 Mark 3 4 5 TOTAL 13 8 11 60 This question paper consists of 11 printed pages and 1 blank page. SP (SLM/KS) S73711/5 OCR 2005 [T/100/3424] Registered Charity Number: 1066969 [Turn over

2 Answer all the questions. 1 The table below lists the boiling points of some alkanes. alkane number of molecular boiling point / C carbon atoms formula butane 4 C 4 H 10 0 pentane 5 C 5 H 12 36 hexane 6 69 heptane 7 C 7 H 16 99 octane 8 C 8 H 18 nonane 9 C 9 H 20 152 decane 10 C 10 H 22 175 (a) What is the molecular formula of hexane?...[1] (b) (i) State the trend in the boiling points of the alkanes.... Explain the trend in the boiling points of the alkanes.... (iii) Predict the boiling point of octane.... C [1] (c) Long chain alkanes, such as nonane, can be cracked into shorter chain alkanes and alkenes. (i) Write a balanced equation for the cracking of nonane into heptane and ethene. Much of the ethene is then converted into ethanol. Write a balanced equation for the conversion of ethene into ethanol. State the essential conditions. equation...[1] conditions......[2]

(d) 3 Heptane can be isomerised to produce branched chain alkanes such as 2-methylhexane or 2,3-dimethylpentane. The equation below shows the isomerisation of heptane into 2-methylhexane. (i) Using skeletal formulae, complete the balanced equation for the isomerisation of heptane into 2,3-dimethylpentane. [1] The boiling point of 2,3-dimethylpentane is 84 C. Predict the boiling point of 2-methylhexane.... C [1] (e) Heptane can be reformed to produce methylcyclohexane which is a cycloalkane. Write a balanced equation to show the reforming of heptane to obtain methylcyclohexane. [2] (f) State why branched chain alkanes and cycloalkanes are more useful than straight chain alkanes.... [Total: 13] [Turn over

2 Propane, C 3 H 8, is used in the reaction sequence shown below. 4 A B reaction 1 reaction 2 C CH 2 C C CH 2 CH 2 Cl C CH 2 CH 2 OH Cl 2 /uv light aqueous OH / heat reaction 3 ethanolic OH / heat E polymerisation C CH CH 2 reaction 4 C OH CH C C D (a) The reaction sequence shows several important reaction mechanisms. Select from reactions 1 to 4, the reaction that shows (i) free radical substitution, reaction... [1] electrophilic addition, reaction... [1] (iii) elimination. reaction... [1] (b) In reaction 2, the aqueous OH acts as a nucleophile. (i) State what is meant by the term nucleophile. Complete, with the aid of curly arrows, the mechanism involved in reaction 2. Show any relevant dipoles. C CH 2 CH 2 Cl C CH 2 CH 2 OH +... OH [4]

(c) Compounds B and D are structural isomers of each other. 5 (i) State what is meant by the term structural isomers.......[2] Draw the skeletal formulae of compounds B and D. Compound B Compound D [2] (d) Compound C can be polymerised to form compound E. (i) State the type of polymerisation....[1] Name compound E....[1] (iii) Draw a section of compound E. Show two repeat units. [1] [Total: 15] [Turn over

3 Acrolein, CH 2 ==CHCHO, and acrylic acid, CH 2 ==CHCOOH, are both used in industry for the manufacture of plastic resins and polymers. Both acrolein and acrylic acid can be made from prop-2-en-1-ol, CH 2 ==CHCH 2 OH. 6 (a) (i) Draw the structures of prop-2-en-1-ol and acrolein. Clearly display the functional groups in each compound. prop-2-en-1-ol acrolein [2] Name the functional group common to both prop-2-en-1-ol and acrolein. (b) Prop-2-en-1-ol can be oxidised to form either acrolein or acrylic acid. (i) Identify a suitable oxidising mixture....[2] Write a balanced equation for the oxidation of prop-2-en-1-ol into acrolein. [O] to represent the oxidising agent. (c) A sample of prop-2-en-1-ol was oxidised and an infra-red spectrum of the organic product was obtained. 100 transmittance / % 50 0 4000 3000 2000 1500 1000 500 wavenumber / cm 1

7 By referring to your Data Sheet, decide whether acrolein, CH 2 ==CHCHO, or acrylic acid, CH 2 ==CHCOOH, was formed. The infra-red spectrum above is of... because......[3] (d) Acrylic acid reacts with prop-2-en-1-ol to produce an ester. (i) Complete the balanced equation for this reaction. CH 2 ==CHCOOH + CH 2 ==CHCH 2 OH... +... [2] Draw the structure of the ester. Clearly display all of the functional groups. [2] [Total: 13] [Turn over

8 4 Propene, C CH CH 2, is an alkene and undergoes an addition reaction with bromine. (a) (i) State what you would see when propene reacts with bromine. Complete, with the aid of curly arrows, the mechanism involved in the reaction between propene and bromine. Show any relevant dipoles and charges. C CH CH 2 Br Br [4] (b) Propene, C CH CH 2, also reacts with HBr to produce two bromoalkanes that are structural isomers. C CHBrC C CH CH 2 + HBr C CH 2 CH 2 Br Propyne, C C CH, reacts like propene. It reacts with HBr to give three isomers with molecular formula C 3 H 6 Br 2. Draw the three isomers with molecular formula C 3 H 6 Br 2. [3] [Total: 8]

9 BLANK PAGE QUESTION 5 IS ON PAGES 10 AND 11 [Turn over

5 In this question, one mark is available for the quality of spelling, punctuation and grammar. 10 (a) The rates of hydrolysis of chloroethane, bromoethane and iodoethane are different. Describe how you would monitor the reaction rates. Explain why chloroethane, bromoethane and iodoethane react at different rates. suitable equations in your answer....[6]

(b) 11 In 1930, an American engineer, Thomas Midgley, demonstrated a new refrigerant. As part of his demonstration, he inhaled a lung full of dichlorodifluoromethane, CCl 2 F 2, and used it to blow out a candle. Midgley s demonstration to suggest two properties of CCl 2 F 2. Explain, with a reason, two other uses of chemicals such as CCl 2 F 2, other than as a refrigerant....[4] END OF QUESTION PAPER Quality of Written Communication [1] [Total: 11]

12 Permission to reproduce items where third-party owned material protected by copyright is included has been sought and cleared where possible. Every reasonable effort has been made by the publisher (OCR) to trace copyright holders, but if any items requiring clearance have unwittingly been included, the publisher will be pleased to make amends at the earliest possible opportunity. OCR is part of the Cambridge Assessment Group. Cambridge Assessment is the brand name of University of Cambridge Local Examinations Syndicate (UCLES), which is itself a department of the University of Cambridge.