N1.1 Homework Answers

Similar documents
3 a b c km m m 8 a 3.4 m b 2.4 m

Evans, Lipson, Wallace, Greenwood

On each of them are the numbers +6, 5, +4, 3, +2, 1. The two dice are rolled. The score is obtained by adding the numbers on the upper faces.

ANSWERS. mathematical. StUDieS StaNDaRD LeVeL. Peter Blythe Jim Fensom Jane Forrest Paula Waldman de Tokman

Numerical methods, Mixed exercise 10

Solutions to Homework 5

MSLC Math 151 WI09 Exam 2 Review Solutions

MA1506 Tutorial 2 Solutions. Question 1. (1a) 1 ) y x. e x. 1 exp (in general, Integrating factor is. ye dx. So ) (1b) e e. e c.

Additional Math (4047) Paper 2 (100 marks) y x. 2 d. d d

Step 1: Units. Step 2: Start Ups. Step 3: Review Tests. Important: turn to page 21 while you are reading this.

Logarithms. Secondary Mathematics 3 Page 164 Jordan School District

Examples and applications on SSSP and MST

Case Study Vancomycin Answers Provided by Jeffrey Stark, Graduate Student

Decimals DECIMALS.

1997 AP Calculus AB: Section I, Part A

y cos x = cos xdx = sin x + c y = tan x + c sec x But, y = 1 when x = 0 giving c = 1. y = tan x + sec x (A1) (C4) OR y cos x = sin x + 1 [8]

# 1 ' 10 ' 100. Decimal point = 4 hundred. = 6 tens (or sixty) = 5 ones (or five) = 2 tenths. = 7 hundredths.

Trigonometry. Contents. Syllabus subject matter

as a derivative. 7. [3.3] On Earth, you can easily shoot a paper clip straight up into the air with a rubber band. In t sec

Section 6.1. Question: 2. Let H be a subgroup of a group G. Then H operates on G by left multiplication. Describe the orbits for this operation.

CS553 Lecture Register Allocation I 3

Multiple Short Term Infusion Homework # 5 PHA 5127

PHA 5127 Answers Homework 2 Fall 2001

Alpha and beta decay equation practice

CSE 373: AVL trees. Warmup: Warmup. Interlude: Exploring the balance invariant. AVL Trees: Invariants. AVL tree invariants review

MEMORIAL UNIVERSITY OF NEWFOUNDLAND

Where k is either given or determined from the data and c is an arbitrary constant.

SAMPLE. Answers. 1ax < 1 b x > 13 c x 3 d x 12 e x 6 f x > 3 g x > 2. h x 8 i x a x < 2

Problem 22: Journey to the Center of the Earth

Steinberg s Conjecture is false

Math 34A. Final Review

Higher order derivatives

Binomials and Pascal s Triangle

Gradebook & Midterm & Office Hours

Ch. 24 Molecular Reaction Dynamics 1. Collision Theory

5. B To determine all the holes and asymptotes of the equation: y = bdc dced f gbd

Module graph.py. 1 Introduction. 2 Graph basics. 3 Module graph.py. 3.1 Objects. CS 231 Naomi Nishimura

EEO 401 Digital Signal Processing Prof. Mark Fowler

Mathematics 1110H Calculus I: Limits, derivatives, and Integrals Trent University, Summer 2018 Solutions to the Actual Final Examination

Unit 4 Answers. Exercise 4.1. KS3 Maths Progress Delta 1. 1 a 4 b 3 c 7 d 8. 2 a. b 1 3. c 3 8. d a. b 5 6 > 3 4. c 1 3 < 3 7.

S i m p l i f y i n g A l g e b r a SIMPLIFYING ALGEBRA.

Davisson Germer experiment

1 1 1 p q p q. 2ln x x. in simplest form. in simplest form in terms of x and h.

AP Chemistry Multiple Choice Questions - Chapter a. Updated July 3, 2015 Boyceville High School, Mr. Hamm Page 1 of 7

On the irreducibility of some polynomials in two variables

PHYS ,Fall 05, Term Exam #1, Oct., 12, 2005

1973 AP Calculus AB: Section I

Chapter 1. Analysis of a M/G/1/K Queue without Vacations

CS 6353 Compiler Construction, Homework #1. 1. Write regular expressions for the following informally described languages:

MATHEMATICS PAPER IIB COORDINATE GEOMETRY AND CALCULUS. Note: This question paper consists of three sections A, B and C.

UNCORRECTED SAMPLE PAGES 4-1. Naming fractions KEY IDEAS. 1 Each shape represents ONE whole. a i ii. b i ii

4. (5a + b) 7 & x 1 = (3x 1)log 10 4 = log (M1) [4] d = 3 [4] T 2 = 5 + = 16 or or 16.

4 x 4, and. where x is Town Square

Thomas Whitham Sixth Form

1997 AP Calculus AB: Section I, Part A

(HELD ON 21st MAY SUNDAY 2017) MATHEMATICS CODE - 1 [PAPER-1]

Edge-Triggered D Flip-flop. Formal Analysis. Fundamental-Mode Sequential Circuits. D latch: How do flip-flops work?

AP Calculus BC Problem Drill 16: Indeterminate Forms, L Hopital s Rule, & Improper Intergals

Chapter 8: Electron Configurations and Periodicity

Weighted graphs -- reminder. Data Structures LECTURE 15. Shortest paths algorithms. Example: weighted graph. Two basic properties of shortest paths

DUET WITH DIAMONDS COLOR SHIFTING BRACELET By Leslie Rogalski

Edexcel GCSE Maths Foundation Skills Book Ratio, proportion and rates of change 1

Minimum Spanning Trees

Graph Isomorphism. Graphs - II. Cayley s Formula. Planar Graphs. Outline. Is K 5 planar? The number of labeled trees on n nodes is n n-2

Outline. Computer Science 331. Computation of Min-Cost Spanning Trees. Costs of Spanning Trees in Weighted Graphs

Chapter 6: Polarization and Crystal Optics

Exam 2 Thursday (7:30-9pm) It will cover material through HW 7, but no material that was on the 1 st exam.

SAFE HANDS & IIT-ian's PACE EDT-15 (JEE) SOLUTIONS

Unit 6: Solving Exponential Equations and More

Solutions for HW11. Exercise 34. (a) Use the recurrence relation t(g) = t(g e) + t(g/e) to count the number of spanning trees of v 1

Final Exam Solutions

Solution of Assignment #2

Thomas Whitham Sixth Form

b. How many ternary words of length 23 with eight 0 s, nine 1 s and six 2 s?

Paths. Connectivity. Euler and Hamilton Paths. Planar graphs.

Assignment 4 Biophys 4322/5322

General Notes About 2007 AP Physics Scoring Guidelines

Page 1. Question 19.1b Electric Charge II Question 19.2a Conductors I. ConcepTest Clicker Questions Chapter 19. Physics, 4 th Edition James S.

Y 0. Standing Wave Interference between the incident & reflected waves Standing wave. A string with one end fixed on a wall

Lecture 1: Numerical Integration The Trapezoidal and Simpson s Rule

A Propagating Wave Packet Group Velocity Dispersion

Davisson Germer experiment Announcements:

1 a 4 b 14 c 6 d 18. e 11 f 19 g 29 h a = 5 2 = 3 b 3 7 = = 4. c 0 9 = = 9 d = = 17

ECE602 Exam 1 April 5, You must show ALL of your work for full credit.

Lecture 6.4: Galois groups

Cycles and Simple Cycles. Paths and Simple Paths. Trees. Problem: There is No Completely Standard Terminology!

Probability and Stochastic Processes: A Friendly Introduction for Electrical and Computer Engineers Roy D. Yates and David J.

Computing and Communications -- Network Coding

Lecture 16: Bipolar Junction Transistors. Large Signal Models.

y = 2xe x + x 2 e x at (0, 3). solution: Since y is implicitly related to x we have to use implicit differentiation: 3 6y = 0 y = 1 2 x ln(b) ln(b)

Math 61 : Discrete Structures Final Exam Instructor: Ciprian Manolescu. You have 180 minutes.

Pipe flow friction, small vs. big pipes

4.4 Design of Sections for Flexure (Part III)

Answers & Solutions. for MHT CET-2018 Paper-I (Mathematics) Instruction for Candidates

22/ Breakdown of the Born-Oppenheimer approximation. Selection rules for rotational-vibrational transitions. P, R branches.

Problem Set 6 Solutions

TEMASEK JUNIOR COLLEGE, SINGAPORE. JC 2 Preliminary Examination 2017

Kernels. ffl A kernel K is a function of two objects, for example, two sentence/tree pairs (x1; y1) and (x2; y2)

2008 AP Calculus BC Multiple Choice Exam

CSC Design and Analysis of Algorithms. Example: Change-Making Problem

Transcription:

Camrig Essntials Mathmatis Cor 8 N. Homwork Answrs N. Homwork Answrs a i 6 ii i 0 ii 3 2 Any pairs of numrs whih satisfy th alulation. For xampl a 4 = 3 3 6 3 = 3 4 6 2 2 8 2 3 3 2 8 5 5 20 30 4 a 5 a 8 an +3 0 an 2 6 a 2 + = 5 3 8 = 5 8 2 = 6 20 4 = 5 Original matrial Camrig Univrsity Prss 2009

Camrig Essntials Mathmatis Cor 8 N.2 Homwork Answrs N.2 Homwork Answrs a 49 52 96 256 2 a 8 3 26 54 3 a 96 = 4 49 = 2 = 4 484 = 4 2 = 2 = 22 800 = 8 00 = 9 0 = 90 4 a 9 m 8 m 2 5 a 3 u quals 2 8 is th u of 2 is th u root of 64 is th u of 4 Th u root of 25 is 5 f 000 is th u of 0 6 64 a 99 85 8 8 a 5 3 6 9 36 = 6 an 49 = 42 lis twn 36 an 49 so 42 must li twn 6 an. 0 a 36 024.29 33 9.5 f 3.6 g 9.22 h 2.3 i 3.6 Original matrial Camrig Univrsity Prss 2009

Camrig Essntials Mathmatis Cor 8 N.3 Homwork Answrs N.3 Homwork Answrs a 3, 6, 9, 2, 5, 8, 2, 24, 2, 30 4, 8, 2, 6, 20, 24, 28, 32, 36, 40 2, 24 2 2 a 28 36 60 3 a 2 All multipls of 6 ar vn numrs an numrs ning in 5 ar o. 4 a, 2, 3, 4, 6, 8, 2, 24, 2, 4, 5, 8, 0, 20, 40, 2, 4, 8 8 5 a 6 42 2 6 a is a prim numr. Numr Numr Fators of fators 2, 2 2 3, 3 2 4, 2, 4 3 5, 5 2 6, 2, 3, 6 4, 2 8, 2, 4, 8 4 9, 3, 9 3 0, 2, 5, 0 4 is th only numr with just on fator. Numr Fators Numr of fators, 2 2, 2, 3, 4, 6, 2 6 3, 3 2 4, 2,, 4 4 5, 3, 5, 5 4 6, 2, 4, 8, 6 5, 2 8, 2, 3, 6, 9, 8 6 9, 9 2 20, 2, 4, 5, 0, 20 6 Numrs with just two fators ar prim numrs. Squar numrs hav an o numrs of fators. Original matrial Camrig Univrsity Prss 2009

Camrig Essntials Mathmatis Cor 8 N.3 Homwork Answrs a 9, 2 3, 6 9, 25 8, 25 3, 43 8 a 90 = 2 3 3 5 = 2 3 2 5 9 26 = 2 3 3 = 2 3 2 0 a 264 = 2 2 2 3 = 2 3 3 008 = 2 2 2 2 3 3 = 2 4 3 2 Original matrial Camrig Univrsity Prss 2009 2

Camrig Essntials Mathmatis Cor 8 N2. Homwork Answrs N2. Homwork Answrs a 3 5 4 20 6 25 23 25 f 3 8 g 43 200 h 58 25 2 a 4 5 9 9 20 3 4 53 99 500 63 9 25 3 a 0.8 0.25 0. 0.35.25 f 2.2 g 4.5 h 2.5 i 5.8 j 5.35 4 a 0.0325 0.685 2.4 4.45 2.85 5 a 60 oys 4 0.25 6 0.66666 6 a i 0.4285 ii 0.2854 iii 0.4285 Rurring imals Th rurring imals ontain th sam rpating squn of six igits, ut start at iffrnt points in th squn. 8 =.4285 9 =.2854 0 =.4285 a i 0.25 ii 0.555555 iii 0.8542 iv 0.666666 v 0.5 vi 0.222 4 an 9 2 ar trminating imals. 5 9, 6, 0 5 an 8 ar rurring imals. Original matrial Camrig Univrsity Prss 2009

Camrig Essntials Mathmatis Cor 8 N2. Homwork Answrs 8 a i 8 = 45 360 9 = 40 360 0 = 36 360 ii 8 = 8 4 9 = 8 8 3 = 6 8 iii 4 288 280 35 = = = 5 360 9 360 8 360 i 8, 9, 0 ii 4,, 9 8 3 iii 4,, 8 5 9 i 8 = 0.25 9 = 0. 0 = 0. 4 ii = 0.388888 = 0.444444 = 0.333333 8 9 3 iii 4 5 = 0.8 9 = 0. 8 = 0.85 9 a 5 8 5 6 is gratr than 0.6. is gratr than 0.3. 0.59 is gratr than 5 9. 0 a i 3 5 an 6 6 ii 5 6 an 4 5 iii 2 8 an 2 9 i 4 6 = 2 3 ii 0 5 = 2 3 iii 24 Original matrial Camrig Univrsity Prss 2009 2

Camrig Essntials Mathmatis Cor 8 N2.2 Homwork Answrs N2.2 Homwork Answrs a 9 8 2 = 4 = 2 3 6 8 5 = f 25 5 4 2 = g 2 3 2 2 = h 0 = 2 30 5 5 3 i 0 = j 20 2 24 4 = k 30 5 8 3 = l 24 4 3 = 5 5 2 3 5 4 5 + 4 9 + = + = = 4 5 20 20 20 20 3 a 3 4 0 2 9 20 5 6 f 9 g 5 6 h 5 8 i 3 4 4 a 5 2 24 9 22 29 35 f 6 90 g 33 50 h 53 5 5 a 2 0 3 6 9 22 3 0 f 3 24 g 9 h 3 20 6 a 0 9 40 36 20 29 42 f 60 g 6 33 h 2 35 a 6 9 40 30 36 5 2 f 2 3 g 40 5 4 h 28 5 30 8 a 8 2 40 20 8 5 5 6 f 40 g 3 20 h 3 36 Original matrial Camrig Univrsity Prss 2009

Camrig Essntials Mathmatis Cor 8 N2.2 Homwork 2 Answrs N2.2 Homwork 2 Answrs a 5 8 20 g 40 m 2 mils f 20 g 2 h 3 g i 2 2 a 9 whit hoolats 5 plain hoolats 2 milk hoolats; 2 = 36 3 6 4 = 36 9 28 m 2 3 a 2 35 35 4 6 5 9 3 f 6 4 g 2 8 5 h 26 4 a 5 g 2 m 28 mm 56 25 kg f 38 m 5 a 5 fifths; 5 = 5 6 sixths; 6 = 6 24 sixths; 4 6 = 24 6 Diviing y 8 is th sam as multiplying y 8. a 45 48 2 64 50 f 20 8 a 40 8 = 5 thrfor 5 8 = 40 0 3 5 = 6 thrfor 6 3 5 = 0 2 3 4 = 9 thrfor 9 3 4 = 2 2 5 = 5 thrfor 5 5 = 2 Original matrial Camrig Univrsity Prss 2009

Camrig Essntials Mathmatis Cor 8 N2.3 Homwork Answrs N2.3 Homwork Answrs a 20 = 00 5 32 8 = 00 25 55 = 00 20 84 2 = 00 25 00 f 2.5 5 = = 00 200 40 2 a 5% 3% 4% 23.5%.8% f 246% 3 Appl Par Strawrry Mlon Banana 2 0 5 6 a 3 3 0 40 4 8 20 30%.5% 25% 2.5% 5% 4 Dan shoul work out 2 00% = 28.5 %, so 2 = 29% to narst prnt. 5 a 9 9 4.3 8.4 32 f 5.04 6 a 28.50 6.3 m 6.5 km 2. kg 9.5 g f 5.46 m g 390.50 h 33 mm Ys, sh is orrt. 40% of 60 = 0.4 60 = 24 60% of 40 = 0.6 40 = 24 8 a 600 m 2 90 m 2 9 a 48% 20% 3.5% 0 a 3 50 26% a 5% 4.8%.5% 8% 32.5% Original matrial Camrig Univrsity Prss 2009

Camrig Essntials Mathmatis Cor 8 N2.3 Homwork 2 Answrs N2.3 Homwork 2 Answrs a 54 62.2 6.28 5 8.2 f 53.09 2 028.3 = 6.64 3 a Th numr of arrls of oil prou aily in 2008 will 05% of th numr prou in 2000. As a fration, this prntag is quivalnt to 00 20 9602250 arrls 4 a 300.0 = 33 300 0.29 = 899 5 a 38 440 58 46 Option B is hapr y 02. 6 Original valu = 20 000 Aftr an inras of 5%, th valu is.05 20 000 = 220 500. Aftr a furthr ras of 5%, th valu is 0.95 220 500 = 209 45. Th hous is worth lss than whn h ought it, not th sam. Original matrial Camrig Univrsity Prss 2009

Camrig Essntials Mathmatis Cor 8 N2.4 Homwork Answrs N2.4 Homwork Answrs a 0.6 0.25 0. 0.625 0.36 f 0.65 2 a 60% 25% 0% 62.5% 36% f 65% 3 a 0.23 0.6 0.35 0.48 0.05 4 a 23 00 6 4 = 00 25 35 = 00 20 48 2 = 00 25.5 5 3 = = 00 200 40 5 a 5.6.2 2.8 9.6.8 f 3.9 g 9.5 h 50. 6 a 6.60.48 kg 0.6 litrs 23.4 hours = 23 hours 24 minuts 5.95 m f 48.50 a Fin 0%. Thn halv it to fin 5%. Thn halv it it again to fin A all thr numrs togthr to fin 2 %. Or multiply y thn ivi y 4 thn ivi y 0 (or quivalnt). 3.50 493.50 8 Th trainrs ost 59.50 in th sal, so Charli os hav nough mony. 9 a 4.8 48 0.48 4800 4.8 f 0.48 g 0.48 h 4.8 0 a 0.5 0.05 0.005 2 2 %. Original matrial Camrig Univrsity Prss 2009

Camrig Essntials Mathmatis Cor 8 N3. Homwork Answrs N3. Homwork Answrs a 300 000 8000 36 000 2 950 000 2 a 4 0 3 9 0 2 5 0 6 0 4 3 a.4 0.03.2 0.049 4 a 40 500 00 3000 5 a 0.8 0.004 0.3 60 2 f 40 6 a 0.0 0.2 = 0.002 0.2 0.0 = 20 a 0. 0.2 = 0.02 0 0.5 = 20 or 2 0. = 20 Original matrial Camrig Univrsity Prss 2009

Camrig Essntials Mathmatis Cor 8 N3. Homwork 2 Answrs N3. Homwork 2 Answrs a 80 460 300 820 2 a 400 500 300 4600 3 a 000 2000 23 000 3 000 4 hunr pouns 5 a 35 608 36 000 6 250 km lngth < 255 km. Any lngth in this rang is orrt. a 4.8 6.4.5 8. 8 a.68 9.06 3.8 4.0 9 a.4.43.64 0 a 3.5 m 2 24.3 m 2 25.8 m 2 Original matrial Camrig Univrsity Prss 2009

Camrig Essntials Mathmatis Cor 8 N3.2 Homwork Answrs N3.2 Homwork Answrs a 293 26 383 94 2.25 3 a 5.2 25.2 6.5 33 4 34.65 5 5.6 6 a 2 22.4 35 2.2 29.90 8 24.96 kg 9 a 308 893 62 644 0 44 a 23 68 89 4 2 3 3 a 5 600 600 000 4 25 Original matrial Camrig Univrsity Prss 2009

Camrig Essntials Mathmatis Cor 8 N3.2 Homwork 2 Answrs N3.2 Homwork 2 Answrs To fin 50% of a numr ivi th numr y 5 To fin 4 of a numr ivi th numr y 3 To fin 0.333 of a numr ivi th numr y 2 To fin 20% of a numr ivi th numr y 0 To fin 0. of a numr ivi th numr y 4 2 a 63 30 48 68 f 6.9 g 28 h 52 3 0.36 kg 4 2.55 lss 5 245 6 Sam laim 2.25, Kat laim.50 an Sharon laim.25. 26 m 8 a 2.8 4. 6.5 8.4 9 Answrs may vary hk pupil s rouning. a 200 8 0 25 24 f 8000 Original matrial Camrig Univrsity Prss 2009

Camrig Essntials Mathmatis Cor 8 N3.3 Homwork Answrs N3.3 Homwork Answrs a 26.08 283.6 23.02 34. 5.48 f 62.6 2 a 8.8 kg 23.48 kg Lss y.52 kg 3 a i 35 4 = 40 ii 5.2 i 50 5 = 50 ii 25.2 i 8 0. =.8 ii.424 4 US $ 553 5 3.98 6 20.6 a 4.2 6.4 2.8 Original matrial Camrig Univrsity Prss 2009

Camrig Essntials Mathmatis Cor 8 N3.4 Homwork Answrs N3.4 Homwork Answrs a 4 4 34 5 f 2.3 2 a 440 2.5 3 a Qustion 3 Qustion 2 4 a 0 500 ran i 28 ran ii 220 5 0 gallons 6 a 65.2 p 25.80 8 3 of 2.56 is 4. 8 2 % of 6.5 is 4.86 So 2% of 6.5 is gratr 9 a 6 hours 9 hours 36 minuts 39 sons.2 hours f 42 minuts 0 a 360º 25 5 or 360 2 4 minuts 0 sons Original matrial Camrig Univrsity Prss 2009

Camrig Essntials Mathmatis Cor 8 N4. Homwork Answrs N4. Homwork Answrs a 52 00 58 2 48 f 6 g 0 h 0 i 9 j 5 k 2.5 l 5.33 m n o 2 a 2 0 29 4 f 84 g 2 h 64 i 0 3 a (8 + 2) 4 + 2 = 8 + 2 4 + 2 = 3 (8 + 2) (4 + 2) = 3.33 8 + 2 (4 + 2) = 0 26 + 5 8 5 = 4 f (26 + 5) 8 5 = 323 g 26 + 5 (8 5) = h (26 + 5) (8 5) = 23 4 Sharmi work out 2 + 48 6 + 4 = 2 + 3 + 4 = 9 Sh shoul hav foun th answr to 2 + 48 first thn ivi y 6 + 4. Sh oul think of it as having rakts lik this (2 + 48). (6 + 4) 5 a P = 3 (4m + 2n) P = 8 m 6 a P = 4 m A = 2 m 2 ( + 3) m Ys aus th g lngths ar all qual. Q = 4 ( + 3) m f B = ( + 3) 2 m 2 g i W = 2 m 2 ii X = 3 m 2 iii Y = 3 m 2 iv Z = 9 m 2 v Ara = ( 2 + 3 + 3 + 9) m 2 = ( 2 + 6 + 9) m 2 h Primtr = 4 (5 + 3) = 32 m Ara = (5 + 3) 2 = 64 m 2 or 5 2 + 30 + 9 = 25 + 30 + 9 = 64 m 2 Original matrial Camrig Univrsity Prss 2009

Camrig Essntials Mathmatis Cor 8 N4.2 Homwork Answrs N4.2 Homwork Answrs a 5 2 = 2 is inorrt. Multipliation must on for sutration so it is 0 =. (6 4) 2 8 2 = 68 is inorrt ivision must on for sutration so it is 44 4 = 40. 3 2.8 2 = 8 is inorrt 3 3 2 woul only 2 an it must lss than this. 2 4 3 = 8. is inorrt 4 3 2 = 4 9 whih is lss than 2. 2.5 So whn it is ivi y 2.5, th answr must lss than. 2 a 8 30 = 2340 80 30 = 2400 so 8 30 must a it smallr than 2400. 6.95 0.2 = 34.5 y 0.2 maks th answr iggr so it must iggr than 6.95. 48. = 380 48 = 48 so th answr must a it smallr than 48. 94 9 0.5 = 4.6 85 is aout 9. Multiplying y 0.5 is th sam as iviing y 2 so th answr must aout 4. 3 a x = 44 4 8 (i) x = 3 29 (iii) x = 20 5 + 6 (ii) 4 If you a th lngths togthr th total lngth ut is m whih an not orrt as thr was only 6 m of rion..9 + 2.4 +.4 +.3 =.0 5 Mo mans th most frquntly ourring valu. In this as it is 4. mo as it os not appar in th list of sho sizs. 4 2 is not a possil Original matrial Camrig Univrsity Prss 2009

Camrig Essntials Mathmatis Cor 8 N4.3 Homwork Answrs N4.3 Homwork Answrs a 8 20 = 2 5 6 2 = 2 5 5 = 3 2 a 8 : 2 = 2 : 3 6 : 6 = : 5 : 0 = : 2 3 a 0 36 = 5 8 8 36 = 2 0 : 26 = 5 : 3 8 : 8 = : 4 a 2 : : 3 : 4 3 : 5 5 : 3 f 2 : g 3 : 2 h 2 : i : 5 j 2 : k : 2 l 3 : 4 5 a x = 2 p = 6 n = 3 y = 8 q = 5 f g = 9, h = 8 Original matrial Camrig Univrsity Prss 2009

Camrig Essntials Mathmatis Cor 8 N4.3 Homwork 2 Answrs N4.3 Homwork 2 Answrs a 4 : 30 = 2 : 5 8 : 200 = : 25 0 : 000 = : 00 5 : 20 = : 8 300 : 2000 = 3 : 20 f 5 : 000 = : 200 g 25 : 600 = : 24 h 35 : 2000 = : 400 i 6 : 48 = : 8 2 a 9.6 m 5.25 m 3 a i 0 000 m ii 0 km 3.2 m 4 a Smallr part = 0 m, largr part = 50 m. Smallr part = 24 m, largr part = 36 m. Smallr part = 2 m, largr part = 48 m. Smallr part = 2 m, largr part = 33 m. Smallst part = 5 m, mil-siz part = 20 m, largst part = 25 m. 5 9 6 a i 800 ml ii litr 40 ml No it is not orrt, a ratio of : 4 mans thr ar 5 parts, so it is 5 not 4. a 6 : 0 = 8 : 5 2 : 5 = : 5 42 : 36 = : 6 No, it woul man thy wr th sam ag. Original matrial Camrig Univrsity Prss 2009

Camrig Essntials Mathmatis Cor 8 N4.4 Homwork Answrs N4.4 Homwork Answrs a Pouns ( ) 0 5 0 5 20 Yn ( ) 0 000 2000 3000 4000 2 a Tim (hours) 0 2.5 5.5 0 Distan (km) 0 25 2250 335 4500 Sp of aroplan is 450 km/hour 2800 km (s graph) Original matrial Camrig Univrsity Prss 2009

Camrig Essntials Mathmatis Cor 8 N4.4 Homwork Answrs 3 a : 5.5 :.25 : 0. : 0.45 : 0.8 4 a Th two varials ar irtly proportional aus it is a linar graph (it is a straight lin whih passs through th origin). (approximatly) 220 pouns 0 pouns 2.2 pouns : 2.2 f (approximatly) 54 pouns g 0.45 kg h : 0.45 i 2200 pouns Original matrial Camrig Univrsity Prss 2009 2