Q1. A string of length L is fixed at both ends. Which one of the following is NOT a possible wavelength for standing waves on this string?

Similar documents
Q1. A) 48 m/s B) 17 m/s C) 22 m/s D) 66 m/s E) 53 m/s. Ans: = 84.0 Q2.

Q1. In figure 1, Q = 60 µc, q = 20 µc, a = 3.0 m, and b = 4.0 m. Calculate the total electric force on q due to the other 2 charges.

Phys102 Final-061 Zero Version Coordinator: Nasser Wednesday, January 24, 2007 Page: 1

Phys101 Final Code: 1 Term: 132 Wednesday, May 21, 2014 Page: 1

4) What is the magnitude of the net electric field at the center of the square?

Phys102 Second Major-102 Zero Version Coordinator: Al-Shukri Thursday, May 05, 2011 Page: 1

GAUSS' LAW E. A. surface

Information for Physics 1201 Midterm I Wednesday, February 20

A) 0.77 N B) 0.24 N C) 0.63 N D) 0.31 N E) 0.86 N. v = ω k = 80 = 32 m/s. Ans: (32) 2 = 0.77 N

Phy 213: General Physics III 6/14/2007 Chapter 28 Worksheet 1

Physics 102. Second Midterm Examination. Summer Term ( ) (Fundamental constants) (Coulomb constant)

Three charges, all with a charge of 10 C are situated as shown (each grid line is separated by 1 meter).

= m. Suppose the speed of a wave on a string is given by v = Κ τμ

Phys102 First Major-122 Zero Version Coordinator: Sunaidi Wednesday, March 06, 2013 Page: 1

Phys101 First Major-131 Zero Version Coordinator: Dr. A. A. Naqvi Wednesday, September 25, 2013 Page: 1

Figure 1 A) 2.3 V B) +2.3 V C) +3.6 V D) 1.1 V E) +1.1 V Q2. The current in the 12- Ω resistor shown in the circuit of Figure 2 is:

Honors Physics Final Review Summary

Chapter 2 GAUSS LAW Recommended Problems:

Plan o o. I(t) Divide problem into sub-problems Modify schematic and coordinate system (if needed) Write general equations

Chapter 19. Electric Potential Energy and the Electric Potential

37 Maxwell s Equations

Potential and Capacitance

Chapter 30. Inductance

Solution to HW14 Fall-2002

TOPPER SAMPLE PAPER 2 Class XII- Physics

CHAPTER 6 WORK AND ENERGY

Phys101 Second Major-061 Zero Version Coordinator: AbdelMonem Saturday, December 09, 2006 Page: 1

Q x = cos 1 30 = 53.1 South

Chapter 6. Dielectrics and Capacitance

Edexcel GCSE Physics

ENGI 4430 Parametric Vector Functions Page 2-01

Phys102 Final-163 Zero Version Coordinator: Saleem Rao Tuesday, August 22, 2017 Page: 1. = m/s

Electric Current and Resistance

Name Student ID. A student uses a voltmeter to measure the electric potential difference across the three boxes.

Physics 212. Lecture 12. Today's Concept: Magnetic Force on moving charges. Physics 212 Lecture 12, Slide 1

Chapter VII Electrodynamics

Chapter 3. AC Machinery Fundamentals. Copyright The McGraw-Hill Companies, Inc. Permission required for reproduction or display.

CHAPTER 8b Static Equilibrium Units

PHY 2054C Review guide Fall 2018 Chapter 17 Wave optics

AQA GCSE Physics. Topic 7: Magnetism and Electromagnetism. Notes. (Content in bold is for Higher Tier only)

Chapter 32. Maxwell s Equations and Electromagnetic Waves

Phys102 Final-132 Zero Version Coordinator: A.A.Naqvi Wednesday, May 21, 2014 Page: 1

Finding the Earth s magnetic field

Q1. A wave travelling along a string is described by

CBSE Board Class XII Physics Set 1 Board Paper 2008 (Solution)

CLASS XI SET A PHYSICS

20 Faraday s Law and Maxwell s Extension to Ampere s Law

W V. (d) W. (3) Which one is used to determine the internal resistance of a cell

14. Which shows the direction of the centripetal force acting on a mass spun in a vertical circle?

STUDENT NAME: STUDENT id #: WORK ONLY 5 QUESTIONS

PHYS College Physics II Final Examination Review

Lab 11 LRC Circuits, Damped Forced Harmonic Motion

ELECTROSTATIC FIELDS IN MATERIAL MEDIA

14. Which shows the direction of the centripetal force acting on a mass spun in a vertical circle?

Chapter 9 Vector Differential Calculus, Grad, Div, Curl

Synchronous Motor V-Curves

A) 4 B) 3 C) 2 D) 5 E) 6

Kinetics of Particles. Chapter 3

Q1. Ans: (1.725) =5.0 = Q2.

Physics 2B Chapter 23 Notes - Faraday s Law & Inductors Spring 2018

Surface and Contact Stress

Work, Energy, and Power

clicker 1/25/2011 All C s are 8.00 nf. The battery is 12 V. What is the equivalent capacitance? summary o

Time varying fields and Maxwell's equations Chapter 9

PHYSICS Unit 3 Trial Examination

Figure 1a. A planar mechanism.

1 Course Notes in Introductory Physics Jeffrey Seguritan

Matter & Interactions Chapter 17 Solutions

Flipping Physics Lecture Notes: Simple Harmonic Motion Introduction via a Horizontal Mass-Spring System

Module 4: General Formulation of Electric Circuit Theory

Study Guide Physics Pre-Comp 2013

Schedule. Time Varying electromagnetic fields (1 Week) 6.1 Overview 6.2 Faraday s law (6.2.1 only) 6.3 Maxwell s equations

ENGINEERING COUNCIL CERTIFICATE LEVEL THERMODYNAMIC, FLUID AND PROCESS ENGINEERING C106 TUTORIAL 5 THE VISCOUS NATURE OF FLUIDS

Chapter 16. Capacitance. Capacitance, cont. Parallel-Plate Capacitor, Example 1/20/2011. Electric Energy and Capacitance

Q1. In a stretched string the frequency of the wave DOES NOT depends on:

Faculty of Engineering and Department of Physics Engineering Physics 131 Midterm Examination February 27, 2006; 7:00 pm 8:30 pm

A) 100 K B) 150 K C) 200 K D) 250 K E) 350 K

SAFE HANDS & IIT-ian's PACE EDT-04 (JEE) Solutions

Physics 102. Final Examination. Spring Semester ( ) P M. Fundamental constants. n = 10P

f n+2 f n = 2 = = 40 H z

Louisiana State University Physics 2102, Exam 3 April 2nd, 2009.

Flipping Physics Lecture Notes: Simple Harmonic Motion Introduction via a Horizontal Mass-Spring System

Short notes for Heat transfer

Applying Kirchoff s law on the primary circuit. V = - e1 V+ e1 = 0 V.D. e.m.f. From the secondary circuit e2 = v2. K e. Equivalent circuit :

AP Physics Kinematic Wrap Up

Thermodynamics and Equilibrium

PHYS General Physics for Engineering II FIRST MIDTERM

MODULE 1. e x + c. [You can t separate a demominator, but you can divide a single denominator into each numerator term] a + b a(a + b)+1 = a + b

Equilibrium of Stress

Yeu-Sheng Paul Shiue, Ph.D 薛宇盛 Professor and Chair Mechanical Engineering Department Christian Brothers University 650 East Parkway South Memphis, TN

Solutions to PHY2049 Exam 2 (Nov. 3, 2017)

Exam 2, Phy 2049, Spring Solutions:

Hooke s Law (Springs) DAVISSON. F A Deformed. F S is the spring force, in newtons (N) k is the spring constant, in N/m

Exam 2 Solutions. ε 3. ε 1. Problem 1

Chapter 2 SOUND WAVES

Electric_Field_core_P1

Chapter 8. The Steady Magnetic Field 8.1 Biot-Savart Law

Louisiana State University Physics 2102, Exam 2, March 5th, 2009.

f = µ mg = kg 9.8m/s = 15.7N. Since this is more than the applied

CHAPTER 6 -- ENERGY. Approach #2: Using the component of mg along the line of d:

Transcription:

Term: 111 Thursday, January 05, 2012 Page: 1 Q1. A string f length L is fixed at bth ends. Which ne f the fllwing is NOT a pssible wavelength fr standing waves n this string? Q2. λ n = 2L n = A) 4L B) L C) 2L D) L/2 E) 2L/3 2L L 2L/3 L/2... A pint surce emits 30.0 W f sund istrpically. A detectr has an area f 0.800 cm 2, and is at a distance f 20.0 m frm the surce. Calculate the pwer intercepted by the detectr. A) 4.77 10-7 W -4 B) 5.97 10 W -7 C) 7.46 10 W -4 D) 9.60 10 W -4 E) 3.95 10 W d detectr, s surce I d = P s 4πr 2 P d = I d. A d = P s. A d 30 8 10 5 = = 4.77 10 7 W 4πr2 4π 400

Term: 111 Thursday, January 05, 2012 Page: 2 Q3. Tw blcks, A and B, have identical masses, but are made f different substances. The specific heats f the blcks are c A = 440 J/(kg K) and c B = 160 J/(kg K). The blcks are initially at 21.0 C; and the same quantity f heat is added t each blck. If the final temperature f blck A is 72.0 C, what is the final temperature f blck B? A) 161 C B) 72.0 C C) 198 C D) 21.0 C E) 119 C Q A = Q B m A c A. T A = m B c B. T B T B = c A. T c A = 440 (72 21) = 140 C B 160 T Bf = 140 + 21 = 161 C Q4. Gas within a chamber passes thrugh the cycle shwn in Figure 1. The heat added during prcess AB (Q AB ) is 20 J, and n heat is transferred during prcess BC. The net wrk dne during the cycle is 15 J. Determine the heat transferred during prcess CA (Q CA ). A) -5.0 J B) -35 J C) +35 J D) +5.0 J E) -20 J Q AB = +20 J Q BC = 0 W net = 15 J Cyclic prcess: E int = 0 W net = Q net 15 = 20 + 0 + Q CA Q CA = 5.0 J

Term: 111 Thursday, January 05, 2012 Page: 3 Q5. One mle f a mnatmic ideal gas at 400.0 K is taken t half f its riginal vlume by an isbaric prcess. Hw much wrk is dne in the prcess? A) 1662 J n the gas B) 3324 J n the gas C) 8300 J n the gas D) 1662 J by the gas E) 3324 J by the gas p f v f = nrt f p i v i = nrt i T f = v f = 1 T i v i 2 T f = T i 2 W = p V = nr T = nr T i 2 T i = nr T i 2 1 8.31 400 = = 1662 J 2 Q6. A Carnt heat engine perates between tw reservirs at temperatures f 300 K and 500 K. The wrk dne in ne cycle is 1200 J. What is the change in the entrpy f the ht reservir? A) 6.0 J/K B) +6.0 J/K C) 10 J/K D) +10 J/K E) 0.96 J/K ε = 1 T L T H = 1 300 500 = 0.4 ε = W Q H Q H = W ε = 1200 0.4 = 3000 J s H = Q H T H = 3000 500 = 6.0 J K

Term: 111 Thursday, January 05, 2012 Page: 4 Q7. An electrn traveling hrizntally enters a regin where a unifrm electric field is directed upward, as shwn in Figure 2. What is the directin f the electric frce exerted n the electrn nce it has entered the field? A) dwnward B) upward C) t the left D) t the right E) ut f the page F = qe = ( e)e = ee F is ppsite t E Q8. A slid nn-cnducting sphere f radius R carries a unifrm charge density. At a radial distance r 1 = R/4, the electric field has a magnitude f E. What is the magnitude f the electric field at a radial distance r 2 = 2R? Radial distances are measured frm the center f the sphere. A) E B) E /2 C) E /4 D) zer E) 2E E 0 = kq R 3. R 4 = kq 4R 2 4R2 = kq E 0 1 4R 2 = E 0 kq E = kq 4R 2 = kq. E 0 kq = E 0

Term: 111 Thursday, January 05, 2012 Page: 5 Q9. Tw pint charges are fixed alng the x axis as fllws: q 1 = +2.0µC at x 1 =0, and q 2 = -5.0 µc at x 2 = 1.0 m. At which f the fllwing values f x is the electric ptential equal t zer? Take the electric ptential t be zer at infinity. A) +0.29 m B) +0.05 m C) +0.54 m D) +0.45 m E) +0.71 m All the given answers are (+). The pint must be between the charges. Let it be a distance x frm the rigin. V = k 2 x 5 1 x 10 6 = 0 2 x = 5 1 x 2 2x = 5x 7x = 2 x = 2 7 = 0.29 m Q10. A 10-µF capacitr is charged s that the ptential difference between its plates is 10 V. A 5.0-µF capacitr is charged s that the ptential difference between its plates is 5.0 V. The tw charged capacitrs are then cnnected as shwn in Figure 3. What is the final charge n the 10-µF capacitr? A) 83 µc B) 67 µc C) 33 µc D) zer E) 17 µc q 1i = 10 10 = 100µc q 2i = 5 5 = 25µc Q i = q 1i + q 2i = 125 µc q 1f = c 1 v q 2f = c 2 v Q f = (C 1 + C 2 )V Q i = (C 1 + C 2 )V Charge Cnservatin Q i V = = 125 C 1 + C 2 15 = 8.3 V q 1f = 10 8.3 = 83 µc

Term: 111 Thursday, January 05, 2012 Page: 6 Q11. Figure 5 shws fur situatins in which psitive and negative charges mve hrizntally, and gives the rate at which each charge mves. Rank the situatins accrding t the net current thrugh the regins, greatest first. Fig # 5 a = 7A A) a and b and c tie, then d B) a, then d, then c, then b C) a, then d, then b, then c D) a, then c, then d, then b E) a, then c, then b, then d b = 3 + 4 = 7A c = 2 + 5 = 7A d = 6 1 = 5A Q12. A flashlight bulb, made f a thin tungsten wire, is rated at 0.300 A / 3.00 V (the values f the current and vltage under perating cnditins). If the resistance f the wire at rm temperature (20.0 C) is 1.00 Ω, what is its temperature when the bulb is turned ON? The temperature cefficient f resistivity f tungsten is 0.00450 C -1. Assume the dimensins f the wire d nt change. A) 2020 C B) 1980 C C) 2000 C D) 1080 C E) 1820 C R f = V i = 3 0.3 = 10Ω R = R f R i = 10 1 = 9 Ω R = αr i T T = R αr i = T f = T i + T = 2020 C 9 4.5 10 3 = 2000 C 1

Term: 111 Thursday, January 05, 2012 Page: 7 Q13. A heating element is perated by maintaining a vltage f 110 V acrss the length f a wire whse crss sectinal area is 8.0 10-7 m 2. The resistivity f the wire s material is 5.0 10-7 Ω m. If the element dissipates 5.0 kw, what is its length? P = V2 R A) 3.9 m B) 2.0 m C) 1.2 m D) 5.8 m E) 4.1 m R = V2 P = (110)2 5000 = 2.42 Ω R = ρl A L = RA ρ = 2.42 8 10 7 5 10 7 = 3.9 m Q14. In the circuit shwn in Figure 4, E 1 = 6.0 V, E 2 = 12 V, R 1 = 200 Ω, and R 2 = 100 Ω. Determine the current passing thrugh R 2. i 1 i 2 A) 180 ma t the left B) 180 ma t the right C) 120 ma t the left D) 120 ma t the right E) 60 ma t the right i x ε 2 = i x R 1 i x = ε 2 R 1 = 12 200 = 0.06 A ε 1 + i x R 1 i 1 R 2 = 0 i 1 = ε 1 + i x R 1 = 6 + 12 = 180 ma R 2 100

Term: 111 Thursday, January 05, 2012 Page: 8 Q15. A 1.0 µf capacitr with an initial stred energy f 0.50 J is discharged thrugh a 1.0 M Ω resistr. Find the current thrugh the resistr when the discharge starts. U 0 2 = q 0 2 A) 1.0 ma τ B) 2.5 ma C) 3.2 ma D) 0.50 ma E) 0 ma 2C q 0 = 2cU 0 = 2 10 6 0.5 = 10 3 C i = (q 0 ) 1 RC e τ/rc i 0 = q 0 = q 0 τ RC i 0 = 10 3 = 1.0 ma 1.0 Q16. Cnsider the five resistrs cnnected as shwn in Figure 6. Find the equivalent resistance between the pints A and B. 6 R A) 3R/2 B) 3R C) 15R D) 6R E) 36R/5 1 = 1 R P 6R + 1 6R + 1 3R = 4 6R R P = 6R 4 = 3R 2

Term: 111 Thursday, January 05, 2012 Page: 9 Q17. In the circuit shwn in Figure 7, R 1 = 100 Ω, R 2 = 50 Ω, and the ideal batteries have emfs E 1 = 6.0 V, E 2 = 5.0 V, and E 3 = 4.0 V. Find the ptential difference V B V A. A) +1.0 V B) 1.0 V C) +9.0 V D) 9.0 V E) +15 V V B = ϵ 3 ϵ 2 = V A V B V A = ϵ 2 ϵ 3 = 5 4 = +1.0 V Q18. In the circuit shwn in Figure 8, an ideal battery is cnnected t tw resistrs (R 1 > R 2 ). The sectin lying alng an x axis is divided int five segments f equal length. Rank the segments accrding t the magnitude f the electric field in them, greatest first. A) b, then d, then a and c and e tie B) d, then b, then a and c and e tie C) a and c and e tie, then b, then d D) a and c and e tie, then d, then b E) The electric field is the same in all segments. V R = ir E = V R L = ir L E R {i, L same}

Term: 111 Thursday, January 05, 2012 Page: 10 Q19. At ne instant, a charged particle is mving with velcity v = 2.0ˆi + 3.0ˆj (m/s) in a unifrm external magnetic field B = 3.0ˆj (T). At that instant, the magnetic field 3 prduces a frce F = 5.8 10 kˆ (N) n the particle. What is the charge f the particle? A) 9.7 10-4 C -4 B) +9.7 10 C -4 C) 6.4 10 C -4 D) +6.4 10 C E) +3.2 10-4 C v B = (2ı + 3ȷ ) ( 3ȷ ) = 6 k F = q v B q = F v B = 5.8 10 3 k = 9.7 10 6k 4 C Q20. A 10 g wire f length L = 70 cm is suspended by a pair f flexible leads, as shwn Figure 9. The wire carries a current f 0.7 A that flws t the right. What is the minimum magnetic field needed t have zer tensin in the leads? A) 0.2 T, int the page B) 0.2 T, ut f the page C) 0.2 T, upward D) 0.2 T, dwnward E) N magnetic field can balance the wire Fr minimum: B L B must be int the page F B = F g ilb = mg B = mg il = 10 2 9.8 0.7 0.7 = 0.2 T check: L ı, B k L B = ı k = +ȷ

Term: 111 Thursday, January 05, 2012 Page: 11 Q21. A 26-turn rectangular cil f wire carrying a current f 0.25 A is placed in a unifrm magnetic field f magnitude 0.050 T. The cil is 2.5 cm lng and has width w. The trque acting n the cil is 2.3 10-4 N.m. If the angle between the magnetic field and the plane f the cil is 55, then the width w f the cil is: A) 4.9 cm B) 0.050 cm C) 1.3 cm D) 0.030 cm E) 3.5 cm τ = µbsinθ = NiABSinθ = NiLw sinθ w = = 4.9 cm τ NiLB sinθ = 2.3 10 4 26 0.25 0.025 0.05 sin35 Q22. An electrn is accelerated frm rest by a ptential difference f 350 V. It then enters a unifrm magnetic field f magnitude 2.00 mt with its velcity perpendicular t the magnetic field. The radius f the circular path f the electrn in the magnetic field is: A) 3.16 cm B) 2.58 cm C) 4.71 cm D) 6.37 cm E) 5.83 cm 1 2 mv2 = qv v = 2qV m qvb = mv2 R R = mv qb = m qb. 2qV m = 1 B. 2mV q R = 1 1 0.002 2 9.11 10 31 350 2 1.6 10 19 = 3.16 cm

Term: 111 Thursday, January 05, 2012 Page: 12 Q23. In Figure 10, a clsed lp carries current i = 0.20 A. The lp cnsists f tw straight wires and tw cncentric circular arcs f radii R 1 = 2.0 m and R 2 = 4.0 m. What is the magnetic field at the center P? A) 2.4 10-8 T int the page -8 B) 2.4 10 T ut f the page -8 C) 3.5 10 T int the page -8 D) 3.5 10 T ut f the page E) zer Net B is int the page B P = µ 0iϕ 4π 1 1 R 1 R 2 = 4π 10 7 0.2 3π 2 4π = 2.4 10 8 T 1 2 1 4 Q24. Tw infinitely lng wires carry currents in ppsite directins, as shwn in Figure 11. The current in each wire is 5.0 A, and the distance d = 1.0 m. What is the net magnetic field at pint P? 1 A) 0.50 µt, t the left B) 0.50 µt, t the right C) 1.5 µt, t the left D) 1.5 µt, t the right E) zer B 2 2 B 1 B 1 = µ 0i 4πd, B 2 = µ 0i 2πd T the right B net = µ 0i 2πd µ 0i 4πd = µ 0i 4πd T the Left = 4π 10 7 5 4π 1 = 5.0 10 7 T Since B 2 > B 1 B net is t the left

Term: 111 Thursday, January 05, 2012 Page: 13 Q25. Figure 12 shws three lng parallel wires at the vertices f an equilateral triangle f side a = 10 cm, and carrying the same current I = 5.0 A. The currents in wires 1 and 2 are ut f the page, while in wire 3 the current is int the page. Calculate the net magnetic frce per unit length n wire 3 due t wires 1 and 2. A) +8.7 10-5 ĵ N/m B) 8.7 10-5 ĵ N/m C) +3.1 10-5 ĵ N/m D) 3.1 10-5 ĵ N/m E) +9.8 10-5 ĵ N/m θ θ θ F = 2. F i. sinθȷ F l = 2 µ 0i 2 sin 60 ȷ 2πa = 8π 10 7 25 sin 60 2π 0.1 ȷ = 8.7 10 5 ȷ N m Q26. A lng wire has a radius greater than 4.0 mm, and carries a current that is unifrmly distributed ver its crss sectin. The magnitude f the magnetic field due t this current is 0.28 mt at a pint 4.0 mm frm the axis f the wire, and 0.20 mt at a pint 10 mm frm the axis f the wire. What is the radius f the wire? A) 5.3 mm B) 6.0 mm C) 7.5 mm D) 8.0 mm E) 4.6 mm Since B r 1 = 4.0 mm, B 1 = 0.28 mt 2 < B 1 r 2 = 10 mm, B 2 = 0.20 mt r 1 is inside r 2 is utside B 1 = µ 02r 1 2πR 2 B 2 B 2 = µ = 0i B 1 2πr 2 R 2 r 1 r 2 R = r 1 r 2. B 2 B 1 = 5.3 mm

Term: 111 Thursday, January 05, 2012 Page: 14 Q27. Figure 13 shws a snapsht f the velcity vectrs f five electrns near a wire carrying current i. The five velcities have the same magnitude. Which electrn experiences the largest magnetic frce? A) 1 B) 2 C) 3 D) 4 E) 5 Q28. v 3 and v 4 are farther away frm the wire. v 2 and v 5 will nt experience a magnetic frce because they are parallel t B v 1 experiences the largest magnetic frce. Figure 14 shws fur wire lps, with edge lengths f either L r 2L. All fur wires mve tward a regin f unifrm magnetic field B (directed ut the page) at the same cnstant velcity. As they enter the magnetic field, in which lp(s) is the greatest induced emf? A) 1 and 2 B) 3 and 4 C) 3 nly D) 1 nly E) 2 nly ε ind = B. L. v ε ind Length (ϵ 1 = ε 2 ) > (ϵ 3 = ε4 4 )

Term: 111 Thursday, January 05, 2012 Page: 15 Q29. A square lp f wire is held in a unifrm 0.24 T magnetic field directed perpendicular t the plane f the lp. The length f each side f the lp is decreasing at a cnstant rate f 5.0 cm/s. What is the emf induced in the lp at the instant the length is 12 cm? ε = dφ B dt A) 2.9 mv B) 1.2 mv C) 3.5 mv D) 12 mv E) 5.0 mv = d dt (BA) = B da dt = B. d dt (x2 ) = 2Bx dx dt = (2)(0.24)(0.12)(0.05) = 2.9 mv Q30. A circular lp f wire f radius 14 cm is placed in the xy plane in a magnetic field that makes an angle f 30 with the nrmal t the plane f the lp, as shwn in Figure 15. The magnitude f this field increases at cnstant rate frm 30 mt t 60 mt in 15 ms. If the lp has a resistance f 5.0 Ω, what is the current induced in the lp, lking frm the tp? ϵ = d dϕ B dt A) 21 ma, clckwise B) 21 ma, cunter clckwise C) 10 ma, clckwise D) 10 ma, cunter clckwise E) 32 ma, clckwise = d dt i = ϵ R = A cs θ B R t i = π (0.14)2 cs 30 5.0 = 21 ma (BA cs θ) = A cs θ db dt 30 10 3 15 10 3 i