Chapter 1 Graph of Functions

Similar documents
Math RE - Calculus I Functions Page 1 of 10. Topics of Functions used in Calculus

Systems of Linear Equations: Solving by Graphing

UNCORRECTED. To recognise the rules of a number of common algebraic relations: y = x 1 y 2 = x

Review of Essential Skills and Knowledge

PRINCIPLES OF MATHEMATICS 11 Chapter 2 Quadratic Functions Lesson 1 Graphs of Quadratic Functions (2.1) where a, b, and c are constants and a 0

4 The Cartesian Coordinate System- Pictures of Equations

STUDY KNOWHOW PROGRAM STUDY AND LEARNING CENTRE. Functions & Graphs

ZETA MATHS. Higher Mathematics Revision Checklist

2.1 The Rectangular Coordinate System

Quadratic Functions Objective: To be able to graph a quadratic function and identify the vertex and the roots.

Unit 3 Notes Mathematical Methods

KEY IDEAS. Chapter 1 Function Transformations. 1.1 Horizontal and Vertical Translations Pre-Calculus 12 Student Workbook MHR 1

CHAPTER 1 Functions and Their Graphs

LESSON #28 - POWER FUNCTIONS COMMON CORE ALGEBRA II

c) domain {x R, x 3}, range {y R}

Math 121. Practice Questions Chapters 2 and 3 Fall Find the other endpoint of the line segment that has the given endpoint and midpoint.

Unit 10 - Graphing Quadratic Functions

The letter m is used to denote the slope and we say that m = rise run = change in y change in x = 5 7. change in y change in x = 4 6 =

CHAPTER P Preparation for Calculus

Math 123 Summary of Important Algebra & Trigonometry Concepts Chapter 1 & Appendix D, Stewart, Calculus Early Transcendentals

Writing Quadratic Functions in Standard Form

Lesson 9.1 Using the Distance Formula

Linear Equation Theory - 2

= x. Algebra II Notes Quadratic Functions Unit Graphing Quadratic Functions. Math Background

Chapter 2 Analysis of Graphs of Functions

What Did You Learn? Key Terms. Key Concepts. 158 Chapter 1 Functions and Their Graphs

y = f(x + 4) a) Example: A repeating X by using two linear equations y = ±x. b) Example: y = f(x - 3). The translation is

3 Polynomial and Rational Functions

CHAPTER P Preparation for Calculus

Diagnostic Tests. (c) (sa sb )(sa sb ) Diagnostic Test: Algebra

MAT 1275: Introduction to Mathematical Analysis. Graphs and Simplest Equations for Basic Trigonometric Functions. y=sin( x) Function

14.1 Systems of Linear Equations in Two Variables

c) Words: The cost of a taxicab is $2.00 for the first 1/4 of a mile and $1.00 for each additional 1/8 of a mile.

6.4 graphs OF logarithmic FUnCTIOnS

Glossary. Also available at BigIdeasMath.com: multi-language glossary vocabulary flash cards

DIAGNOSTIC TESTS. (c) (sa sb )(sa sb )

Mt. Douglas Secondary

Answers for the problems can be found at the end of this packet starting on Page 12.

Unit 12 Study Notes 1 Systems of Equations

QUADRATIC FUNCTION REVIEW

ANALYTICAL GEOMETRY Revision of Grade 10 Analytical Geometry

PRACTICE FINAL EXAM. 3. Solve: 3x 8 < 7. Write your answer using interval notation. Graph your solution on the number line.

MATH 115: Final Exam Review. Can you find the distance between two points and the midpoint of a line segment? (1.1)

Math 115: Review for Chapter 2

CHAPTER 3 Graphs and Functions

SUMMARY OF FUNCTION TRANSFORMATIONS

Vocabulary. Term Page Definition Clarifying Example degree of a monomial. degree of a polynomial. end behavior. leading coefficient.

SAMPLE. A Gallery of Graphs. To recognise the rules of a number of common algebraic relationships: y = x 1,

Path of the Horse s Jump y 3. transformation of the graph of the parent quadratic function, y 5 x 2.

7-1. Basic Trigonometric Identities

C H A P T E R 3 Polynomial Functions

Coordinate geometry. + bx + c. Vertical asymptote. Sketch graphs of hyperbolas (including asymptotic behaviour) from the general

A function from a set D to a set R is a rule that assigns a unique element in R to each element in D.

CHAPTER 1 Functions, Graphs, and Limits

Solutions to the Math 1051 Sample Final Exam (from Spring 2003) Page 1

MA123, Chapter 1: Equations, functions and graphs (pp. 1-15)

MA123, Chapter 1: Equations, functions, and graphs (pp. 1-15, Gootman)

UNCORRECTED SAMPLE PAGES. 3Quadratics. Chapter 3. Objectives

10.5. Polar Coordinates. 714 Chapter 10: Conic Sections and Polar Coordinates. Definition of Polar Coordinates

Chapter 5: Quadratic Equations and Functions 5.1 Modeling Data With Quadratic Functions Quadratic Functions and Their Graphs

4 Linear Functions 45

Glossary. Also available at BigIdeasMath.com: multi-language glossary vocabulary flash cards. An equation that contains an absolute value expression

Chapter 4 Analytic Trigonometry

LESSON #24 - POWER FUNCTIONS COMMON CORE ALGEBRA II

Ready To Go On? Skills Intervention 5-1 Using Transformations to Graph Quadratic Functions

Sample Questions to the Final Exam in Math 1111 Chapter 2 Section 2.1: Basics of Functions and Their Graphs

EOC Review. Algebra I

Module 3, Section 4 Analytic Geometry II

National 5 Learning Checklist - Relationships

8.7 Systems of Non-Linear Equations and Inequalities

Performing well in calculus is impossible without a solid algebra foundation. Many calculus

Name Period Date. Practice FINAL EXAM Intro to Calculus (50 points) Show all work on separate sheet of paper for full credit!

1.2 Functions and Their Properties PreCalculus

Diagnostic Tests Study Guide

1. Solutions to Systems of Linear Equations. Determine whether the ordered pairs are solutions to the system. x y 6. 3x y 2

MHF4U1 ASSIGNMENT CHAPTER 1

1.5. Analyzing Graphs of Functions. The Graph of a Function. What you should learn. Why you should learn it. 54 Chapter 1 Functions and Their Graphs

Chapter 18 Quadratic Function 2

APPENDIXES. B Coordinate Geometry and Lines C. D Trigonometry E F. G The Logarithm Defined as an Integral H Complex Numbers I

FINAL EXAM REVIEW ITEMS Math 0312: Intermediate Algebra Name

Differentiation and applications

4Cubic. polynomials UNCORRECTED PAGE PROOFS

1.1 Laws of exponents Conversion between exponents and logarithms Logarithm laws Exponential and logarithmic equations 10

MATH 60 Review Problems for Final Exam

Graphing Review Part 1: Circles, Ellipses and Lines

10.2 INTRODUCTION TO CONICS: PARABOLAS

Formulas and Concepts Study Guide MAT 101: College Algebra

12.1 Systems of Linear equations: Substitution and Elimination

McKinney High School AP Calculus Summer Packet

Mathematics 10 Page 1 of 7 The Quadratic Function (Vertex Form): Translations. and axis of symmetry is at x a.

8.4. If we let x denote the number of gallons pumped, then the price y in dollars can $ $1.70 $ $1.70 $ $1.70 $ $1.

Quadratics in Vertex Form Unit 1

LESSON #42 - INVERSES OF FUNCTIONS AND FUNCTION NOTATION PART 2 COMMON CORE ALGEBRA II

Trigonometric Functions

Equations for Some Hyperbolas

Chapter 8 Notes SN AA U2C8

Number Plane Graphs and Coordinate Geometry

Ready To Go On? Skills Intervention 6-1 Polynomials

a. plotting points in Cartesian coordinates (Grade 9 and 10), b. using a graphing calculator such as the TI-83 Graphing Calculator,

Ch 5 Alg 2 L2 Note Sheet Key Do Activity 1 on your Ch 5 Activity Sheet.

Transcription:

Graph of Functions Chapter Graph of Functions. Rectangular Coordinate Sstem and Plotting points The Coordinate Plane Quadrant II Quadrant I (0,0) Quadrant III Quadrant IV Figure. The aes divide the plane into four regions, called quadrants; those are numbered as in Figure.. The point (, ) lies on quadrant I, the point (-4, -) lies on quadrant III and so on. Eamples. Plot the points (3, ), (-, -), (0, -3), (, 0), (-5, 0) and (0, ) (0,) (3,) (-5,0) (,0) (-,-) (0, -3) Figure.. Distance and Midpoint Formulas The Distance formula: Consider two points P(a, b) and Q(c, d). Then we have the following measures RUN = PR c a, and RISE = RQ d b. Using Pthagorean 0

Graph of Functions theorem we have the distance between P and Q is PR ( c a) ( d b ) Q P R Figure.3 The distance formula between two points A(, ) and B(, ) is given b AB ( ) ( ) RUN RISE. Find the distance between the points (5, 7) and (-3, 8) The distance d (5 3) (7 8) 65 The Midpoint Formula: The midpoint of the line segment from A(, ) and B(, ) is given b, 3. Find the midpoint of the line segment from (5, 4) to (3, 6) Solution: The midpoint is (4, 5).3 Straight Lines and Slopes The well-known general form of a straight line is a b c 0 and the standard form of a straight line is m b, also known as slope-intercept form. In the second form m is called the slope of the line. Remember that if a straight line passes through A(, ) and B(, ) the slope is RISE m RUN 4. Find the slope of the straight line which passes through the points (7, 4) and (, 3) RISE 4 3 Solution: The slope is m RUN 7 5

Graph of Functions 5. Find the slope of the straight line whose equation is given b 6 0 0 5 Solution: we write the given equation 6 0 0 as. 3 3 The slope is m. 3 Properties of slopes The slope of non-vertical lines is a number m that measures how steep are the lines. The following cases ma arise: When m 0, the straight line is horizontal When m, the straight line makes 45 degree angle with the ais in the positive direction Larger the absolute value of the slope steeper the straight lines For a vertical line the slope is undefined The straight lines with positive slope are increasing and make acute angles with ais in the positive direction The straight lines with negative slopes are decreasing and make obtuse angles with ais in the positive direction If m and m are the slopes of two given straight lines then the following cases ma arise When m m, the straight lines are parallel When m m, the straight lines are perpendicular 6. Plot the following straight lines and observe the slopes a) b) c).5 d) e) f).5 Solution: e) b) d) a) f) c) Figure.4 7. Show that the straight lines 0 3 and 0 5 0 are perpendicular to each other. Solution: Observe that for 0 3 the slope is m 0 and on the other hand the slope of 0 5 0 is m. We have m m 0 and the straight lines are perpendicular.

Graph of Functions 8. Show that the straight lines 0 3 and 5 50 5 0 are parallel to each other. Solution: The straight line 0 3 has slope m 0 and the straight line 5 50 5 0 has also the same slope m 0. The straight lines are parallel..4 Basics of Functions In everda life we encounter situations in which one item is associated with another. For instance, the growth of a plant ma depend on amount of fertilizer or the understanding of a problem ma associate with hours of stud. Relation and Function: A relation is a set of ordered pairs. A function is a relation in which no two ordered pairs have the same first coordinate. In the ordered pairs the set of all first coordinates constitutes the domain and the set of all second coordinates is the range of the relation. Formal definition of function A function is a rule that provides for ever single value of a corresponding unique value of. The domain of the function is the set of all permissible values of ; on the other hand the range of the function is the set of all possible values of. Vertical line test to determine a function A graph defines a function if an vertical line intersects the graph at no more than one point. a) Following are the graphs of functions Fig.5 Fig.6 Fig.7 b) Following are not the graphs of functions Fig.8 Fig.9 Fig.0.5 Graph of Functions 9. Plot the function f () 3

Graph of Functions Solution: This function is called an identit function. For ever single value of we have a unique value of equals. Thus following are the points on the graph of the function. - - 0 f () - - 0 Table. 0. Plot the function Fig. Solution: It is a vertical straight-line at units to the right from the origin. You tr to make a plot.. Plot the function 3 5 Solution: Let us consider the following points - - 0 f () - 5 8 Table. Fig.. Plot the quadratic function 4

Graph of Functions -3 - - 0 3 f () 8 3 0-0 3 8 Table.3.6 Transformation of Functions Fig.3 In this section ou will observe when the rule of a function is algebraicall changed in certain was to get a new function, then the graph of the new function can be obtained from the graph of the original function b simple geometric transformations. Below we discuss horizontal and vertical shifting. Vertical shift Consider the original function f ( ) and its graph then compare with two other functions g( ) f ( ) and h( ) f ( ). Look at the graphs below. And notice that the graph of g() is found from the graph of f () b shifting it verticall unit downward. On the other hand the graph of h( ) f ( ) is found from the graph of f () b shifting it verticall unit upward. h( ) 6 5 f () 4 3 g( ) -4-3 - - 4 - Fig.4 5

Graph of Functions Rule on vertical shift: The graph of g( ) f ( ) k is found b shifting the graph of f () verticall b k units. If k is positive then the shift is upward and if it is negative the shift is downward. Horizontal shift Consider the original function f ( ) and its graph then compare with two other functions g( ) ( ) f ( ) and h( ) ( ) f ( ). Look at the graphs below. And notice that the graph of g() is found from the graph of f () b shifting it horizontall unit to the right. On the other hand the graph of h() is found from the graph of f () b shifting it horizontall unit to the left. 6 h( ) ( ) 5 4 3 g( ) ( ) -4-3 - - 3 4 Fig.5 Rule on horizontal shift: The graph of g( ) f ( h ) is found b shifting the graph of f () horizontall b h units. If h is positive then the shift is to the left and if it is negative the shift is on right. Reflection The graph of g( ) f ( ) is found b reflecting the graph of f () along -ais. = f() = - f() Fig.6 6

Graph of Functions Stretch (Elongate or epand) and Shrink (Compress or contract) The following diagram is useful to remember the stretch and shrink of a graph b a known factor c, with the following values. We consider the cases f ( c ) for horizontal stretch ( H ST ) or horizontal shrink ( H SH ) and cf () for vertical stretch ( V ST ) or vertical shrink ( V SH ).. c c H ST H SH V SH V ST Rule on vertical stretch and shrink: The graph of g( ) cf ( ) is found b Shrinking verticall the graph of f () b a factor of c when c Stretching verticall the graph of f () b a factor of c when c Note: Remember that for g( ) cf ( ), when c is negative we have horizontal reflection or reflection along -ais. Rule on horizontal stretch and shrink: The graph of g( ) f ( c ) is found b Stretching horizontall the graph of f () b a factor of / c when c Shrinking horizontall the graph of f () b a factor of / c when c Note: Remember that for some cases of g( ) f ( c ), when c is negative we have vertical reflection or reflection along -ais. a) Compare the graphs of f ( ), g( ) (0.5 ) f (0.5 ). Observe that the graph of g( ) ( ) f ( ) and f ( ) is horizontall shrunk b a factor of c = / for the coordinates (divide coordinates b or multipl b /) to get the graph of g( ) ( ) f ( ), while the graph of f ( ) is horizontall stretched b a factor of c = 0.5 for the coordinates (divide coordinates b 0.5 or multipl b /0.5 = ) to get the graph of g( ) (0.5 ) f (0.5 ). g( ) (0.5 ) f ( ) g( ) ( ) Fig.7 7

Graph of Functions b) Compare the graphs of f ( ), h( ) 0.5 0.5 f ( ). Observe that the graph of g( ) f ( ) and f ( ) is verticall stretched b a factor of c = for the coordinates (multipl coordinate b ) to get the graph of g( ) ( ) f ( ). On the other hand the graph of f ( ) is verticall shrunk b a factor of c = 0.5 for the coordinates (multipl coordinate b 0.5) to get the graph of g( ) (0.5 ) f (0.5 ). g( ) ( ) f ( ) g( ) (0.5 ) Fig.8 Determining a function obtained from a series of transformations 4 3. Discuss the transformation of g ( ) compared to f( ) 4 Solution: We follow the following steps: Step. Get 4 f ( ), c 4, the graph is verticall stretched b a factor of 4 (multipl coordinate b 4) 4 Step. Get 4 f( ), from step, the graph moves unit horizontall to the right 4 Step 3. Get 4 f( ), from Step, the graph moves units upward. (,4) (,4) (, 5) f( ) (,) (-, -) (0, -4) F (-, -4) F F3 F4 Fig.9 We get second graph (F) multipling coordinate b 4, then move the graph horizontall b positive unit to get third graph (F3) and finall unit upward to get the fourth graph (F4), which is the final position. (0, -3) 8

Graph of Functions.7 Combination of Functions, Composite Functions Combinations of Functions In this section we will discuss about addition (sum), subtraction (difference), multiplication (product) and division (quotient) of functions. We also further discuss an important operation called composition of functions. Suppose f ( ), g( ) are two functions, then their sum is the function sa h () defined as h( ) f ( ) g( ) ( f g)( ) and the difference k( ) f ( ) g( ) ( f g)( ). In the same wa the other defined functions are m( ) f ( ) g( ) ( fg)( ) is a function from multiplication and n( ) f ( )/ g( ) ( f / g)( ), g( ) 0 is a function from division. The domain of all these combinations of functions is the common domain to both the functions. If D f is the domain of f( ), and D g is the domain of g ( ), then the common domain is Df D g. Note that for f ( )/ g( ), g( ) 0, the domain is Df D g when g ( ) 0. 4 4. For the functions f ( ) and g( ) functions and their domain determine the following a) f ( ) g( ) b) g( ) f ( ) c) g( ) f ( ) d) f( ), g ( ) 0 g ( ) Solution: a) 4 f ( ) g( ), the common domain is [0, ) b) 4 g( ) f ( ), the common domain is [0, ) c) 4 g( ) f ( ) ( ), the common domain is [0, ) d) f ( ) g ( ) 4, g ( ) 0, the common domain is (0, ) Composite function or composition of functions For two given functions f ( ), g( ), the compositions are defined as f ( ) g( ) f g f ( g( )) and g( ) f ( ) g f g( f ( )) The domain of f gis defined as i) is in g ( ) and ii) g ( ) is in f() 9

Graph of Functions 4 5. For the functions f ( ) and g( ) functions and their domain determine the following a) f ( ) g( ) b) g( ) f ( ) Solution: a) b) has domain all 0 f ( ) g( ) f ( g( )) f ( ) g( ) f ( ) g( f ( )) g( ) 4 4 has domain all such that 4 0which is true for all real values of. Thus the domain is the entire real line. 6. For the functions f( ) and g ( ) determine the following functions and their domain a) f ( ) g( ) b) g( ) f ( ) Solution: a) f ( ) g( ) f ( g( )) f The domain is which is domain for g ( ) and also for g ( ) should be defined on f() when g( ) 0. Thus the domain is all real values of, 0 b) g( ) f ( ) g( f ( )) g The domain is which is domain for f( ) and also for f() should be defined on g ( ) when f ( ) 0. Thus the domain is all real values of, 0.8 One-to-one and Inverse Functions One-to-one function If the inverse of an function is also a function then the function must be one-t0-one. For a one-to-one function f(), each in the domain has onl one image in the range. No in the range is the image of more than one in the domain. Thus if a function f() has an inverse it is one-to-one. And when the function f() is one-to-one then for an element and in the domain of f() with we will have f ( ) f ( ). A one-to-one function can be determined b horizontal line test. 30

Graph of Functions Horizontal line test If ever horizontal line intersects the graph of f () in at most one point, then the function is one-to-one. Fig.0 Fig. Fig. One-to-one function One-to-one function Not one-to-one 7. Graph the following functions and determine if it is a one-to-one function. 3 3 3 a) f ( ) 9 7 b) f ( ) 9 7 c) f ( ) 7 Solution: a) b) c) Fig.3 Fig.4 Fig.5 One-to-one function Not one-to-one one-to-one In Fig.5 the horizontal line 7 seems to have infinitel man values ver close to zero, still it considered to be one-to-one. Inverse Functions Two one-to-one functions f() and gare ( ) said to be inverses to each other if f ( ) g( ) g( ) f ( ) and we write f ( f ( )). If () range D. f ( ) g ( ). Note that f has domain D and range R then its inverse ghas ( ) domain R and If gis ( ) the inverse of f(), then the graph of gis ( ) the reflection of f() in the line, known as the line of smmetr. 8. We consider a one-to-one function f ( ) 3 and few points. Also suppose that gis ( ) the inverse of f(). We have following results 0 - f( ) f() 3 5 3 5 g ( ) 0 - Fig.6 g ( ) 3

Graph of Functions Determining the inverse of a one-to-one function f() Set f () Interchange the variables and so that the domain of inverse of f() is represented b numbers on the -ais. Solve for and replace b f ( ) 9. Find the inverse of f ( ) 3 f ( ) 3 Solution: f ( ) 3 3 3 3 3 f ( ) 3 0. Find the inverse of f( ) 3 Solution: We write, domain is all and range is all 3 Replace b and b to get Solve for : 3 3 ( ) 3 3 f ( ) has domain with all and range with all. 3 f ( ). Find the inverse of f ( ) Solution: We write, domain is all 0 and range is Replace b and b to get Solve for : f() f ( ) f ( ) 3