REVIEW FOR CHAPTER 1

Similar documents
Math 155 (Lecture 3)

Math 475, Problem Set #12: Answers

Lecture Overview. 2 Permutations and Combinations. n(n 1) (n (k 1)) = n(n 1) (n k + 1) =

Name of the Student:

Books Recommended for Further Reading

Lecture Notes for CS 313H, Fall 2011

Lecture 10: Mathematical Preliminaries

Chapter 6. Advanced Counting Techniques

Homework 3. = k 1. Let S be a set of n elements, and let a, b, c be distinct elements of S. The number of k-subsets of S is

Enumerative & Asymptotic Combinatorics

Tutorial F n F n 1

CALCULATION OF FIBONACCI VECTORS

Introduction To Discrete Mathematics

Week 5-6: The Binomial Coefficients

Discrete mathematics , Fall Instructor: prof. János Pach. 1 Counting problems and the inclusion-exclusion principle

Name of the Student:

CSE 1400 Applied Discrete Mathematics Number Theory and Proofs

Exercises 1 Sets and functions

1 Counting and Stirling Numbers

If a subset E of R contains no open interval, is it of zero measure? For instance, is the set of irrationals in [0, 1] is of measure zero?

Generating Functions. 1 Operations on generating functions

Math 172 Spring 2010 Haiman Notes on ordinary generating functions

1 Summary: Binary and Logic

SOLVED EXAMPLES

Math F215: Induction April 7, 2013

It is always the case that unions, intersections, complements, and set differences are preserved by the inverse image of a function.

Section 5.1 The Basics of Counting

4 The Sperner property.

Infinite Sequences and Series

Number of Spanning Trees of Circulant Graphs C 6n and their Applications

Combinatorics II. Combinatorics. Product Rule. Sum Rule II. Theorem (Product Rule) Theorem (Sum Rule)

Course : Algebraic Combinatorics

In number theory we will generally be working with integers, though occasionally fractions and irrationals will come into play.

1. By using truth tables prove that, for all statements P and Q, the statement

Chapter 0. Review of set theory. 0.1 Sets

2.4 - Sequences and Series

Putnam Training Exercise Counting, Probability, Pigeonhole Principle (Answers)

MT5821 Advanced Combinatorics

Mathematical Induction

CSE 191, Class Note 05: Counting Methods Computer Sci & Eng Dept SUNY Buffalo

As stated by Laplace, Probability is common sense reduced to calculation.

Sequences, Sums, and Products

Homework 9. (n + 1)! = 1 1

MATH 324 Summer 2006 Elementary Number Theory Solutions to Assignment 2 Due: Thursday July 27, 2006

PROBLEMS ON ABSTRACT ALGEBRA

GENERALIZATIONS OF ZECKENDORFS THEOREM. TilVIOTHY J. KELLER Student, Harvey Mudd College, Claremont, California

Injections, Surjections, and the Pigeonhole Principle

Sequences, Mathematical Induction, and Recursion. CSE 2353 Discrete Computational Structures Spring 2018

Chapter 1 : Combinatorial Analysis

Commutativity in Permutation Groups

A Combinatoric Proof and Generalization of Ferguson s Formula for k-generalized Fibonacci Numbers

Measure and Measurable Functions

An Introduction to Randomized Algorithms

Lecture notes for Enumerative Combinatorics

distinct distinct n k n k n! n n k k n 1 if k n, identical identical p j (k) p 0 if k > n n (k)

A COUNTABLE SPACE WITH AN UNCOUNTABLE FUNDAMENTAL GROUP

Combinatorics. Stephan Wagner

MT5821 Advanced Combinatorics

We will conclude the chapter with the study a few methods and techniques which are useful

Basic Counting. Periklis A. Papakonstantinou. York University

arxiv: v1 [math.co] 23 Mar 2016

LECTURE 11: POSTNIKOV AND WHITEHEAD TOWERS

Recurrence Relations

The r-generalized Fibonacci Numbers and Polynomial Coefficients

Combinatorially Thinking

Disjoint Systems. Abstract

Counting Well-Formed Parenthesizations Easily

Infinite Series and Improper Integrals

(k) x n. n! tk = x a. (i) x p p! ti ) ( q 0. i 0. k A (i) n p

Model Theory 2016, Exercises, Second batch, covering Weeks 5-7, with Solutions

Lecture 2. The Lovász Local Lemma

STAT Homework 1 - Solutions

Topic 5: Basics of Probability

, then cv V. Differential Equations Elements of Lineaer Algebra Name: Consider the differential equation. and y2 cos( kx)

CHAPTER I: Vector Spaces

1 Introduction. 1.1 Notation and Terminology

Axioms of Measure Theory

Let us consider the following problem to warm up towards a more general statement.

Large holes in quasi-random graphs

FLOOR AND ROOF FUNCTION ANALOGS OF THE BELL NUMBERS. H. W. Gould Department of Mathematics, West Virginia University, Morgantown, WV 26506, USA

Lecture Notes for Analysis Class

+ au n+1 + bu n = 0.)

EDGE AND SECANT IDEALS OF SHARED-VERTEX GRAPHS

A sequence of numbers is a function whose domain is the positive integers. We can see that the sequence

Linear chord diagrams with long chords

Math 220A Fall 2007 Homework #2. Will Garner A

Sequences A sequence of numbers is a function whose domain is the positive integers. We can see that the sequence

Combinatorics I Introduction. Combinatorics. Combinatorics I Motivating Example. Combinations. Product Rule. Permutations. Theorem (Product Rule)

Recursive Algorithms. Recurrences. Recursive Algorithms Analysis

CSI 2101 Discrete Structures Winter Homework Assignment #4 (100 points, weight 5%) Due: Thursday, April 5, at 1:00pm (in lecture)

On the Linear Complexity of Feedback Registers

CIS Spring 2018 (instructor Val Tannen)

The Borel hierarchy classifies subsets of the reals by their topological complexity. Another approach is to classify them by size.

Sets. Sets. Operations on Sets Laws of Algebra of Sets Cardinal Number of a Finite and Infinite Set. Representation of Sets Power Set Venn Diagram

PAPER : IIT-JAM 2010

and each factor on the right is clearly greater than 1. which is a contradiction, so n must be prime.

Machine Learning Theory Tübingen University, WS 2016/2017 Lecture 11

Absolutely Harmonious Labeling of Graphs

ANOTHER GENERALIZED FIBONACCI SEQUENCE 1. INTRODUCTION

SOME TRIBONACCI IDENTITIES

Transcription:

REVIEW FOR CHAPTER 1 A short summary: I this chapter you helped develop some basic coutig priciples. I particular, the uses of ordered pairs (The Product Priciple), fuctios, ad set partitios (The Sum Priciple) were developed ad used, ad the sigi cat role of fuctios i coutig was itroduced. terms: fuctio; oe-to-oe fuctio; oto fuctio; bijectio; disjoit sets; partitio of a set. Basic Coutig Priciples: The Product Priciple If a ite set S is partitioed ito m blocks of the same size, the S has size m. The Sum Priciple For ay partitio of a ite set S, the size of S is the sum of the sizes of the blocks of the partitio. The Bijectio Priciple Two sets have the same size if ad oly if there is a bijectio betwee them. The Pigeohole Priciple If a set with more tha elemets is partitioed ito blocks, the at least oe block has more tha oe elemet. 1. Ay set with elemets has 2 subsets.

REVIEW FOR CHAPTER 2 A short summary: I this chapter, you reviewed the Priciple of Mathematical Iductio i the cotext of uderstadig the uderlyig iductive processes. At rst we used the so-called simple priciple, but this was superseded by the strog priciple which is just as easy to use ad is ofte more coveiet to apply. Oe of the importat uses of mathematical iductio i coutig problems is that it allows use to prove the Geeral Product Priciple. Sice the Product Priciple from Chapter 1 is a special case of the geeral priciple, the term Product Priciple will be reserved for this more geeral oe. terms: iductive process; rst-order recurrece; permutatio; k-permutatio. Basic Priciples: The Priciple of Mathematical Iductio To prove a sequece of statemets idexed by itegers k b it is su ciet to 1. State the sequece of statemets to be proved; 2. (Base Step) Prove the statemet is true for k = b; 3. (Iductive Step) Prove that (for ay N b) the truth of the statemets for k = b, k = b + 1,..., k = N implies the statemet with k = N + 1 is true; 4. (Iductive Coclusio) Coclude by the Priciple of Mathematical Iductio that every statemet i the sequece is true. The Product Priciple Suppose you make a sequece of m choices, where the rst choice ca be made i k 1 ways, ad for each way of makig the rst i 1 choices, the i-th choice ca be made i k i ways, the the total umber of di eret ways to make this sequece of m choices is k 1 k 2 k. 1. The umber of bijectios o [] is!. (Such bijectios are also called permutatios of the set []:) 2. The umber of fuctios from [m] to [] is m. 3. The umber of k-elemet permutatios of [] is ( 1) ( k +1), which ca be deoted as k :

REVIEW FOR CHAPTER 3 A short summary: I this chapter you leared how the partitio iduced by a equivalece relatio ca be used i coutig problems. I order to use this techique, you eeded practice i idetifyig the uderlyig equivalece relatio. By the ed of the chapter you had proved the formula for calculatig the umber of k-subsets of [], which is also kow as the biomial coe ciet k, ad the formula for coutig multisets. terms: re exive relatio; symmetric relatio; trasitive relatio; equivalece relatio; equivalece class; biomial coe ciet; ordered-fuctios; multisets. Basic Priciples: Equivalece classes Whe R is a equivalece relatio o the set S, its set of equivalece classes forms a partitio of S. 1. For ay k; 0 with k, the umber of k-elemet subsets of [] is! = k k! ( k)! : 2. For ay k; 0, there are (k + 1) k ordered-fuctios from [k] to []. 3. For ay k; 0, there are +k 1 k ways to choose a k-elemet multiset from []:

REVIEW FOR CHAPTER 4 A short summary: I this chapter you were itroduced to the fudametals of graph theory. Trees are amog the most useful types of graphs, ad miimal spaig trees i coected weighted graphs are used i may applicatios. The Bijectio Priciple ad the Priciple of Mathematical Iductio were crucial i the veri catio of importat properties of graphs. terms: graph; degree of a vertex; coected graph; cycle; tree; spaig tree; weighted edge; miimal spaig tree; Prüfer code. Basic algorithm: Dijkstra s Algorithm 1. The sum of the degrees of the vertices i a graph equals twice the umber of edges. 2. Ay tree with vertices has 1 edges. 3. The umber of labelled trees o vertices is 2 :

REVIEW FOR CHAPTER 5 A short summary: Picture eumerators were used to solve coutig problems related to multisets ad to motivate geeratig fuctios, which are formal power series whose coe ciets record the elemets of a sequece of umbers. Formal power series ca be used to solve a variety of coutig problems ad to obtai a explicit formula for certai recurreces, ad you saw a example of this techique whe you foud Biet s Formula. I order to work with geeratig fuctios you must uderstad the algebra of formula power series. terms: geeratig polyomial; geeratig fuctio. Basic Priciples: Additio of Formal Power Series! 0 1 a i x i + @ b j x j A = j=0 (a k + b k )x k : k=0 Multiplicatio of Formal Power Series! 0 1 a i x i @ b j x j A = j=0 k=0! kx a i b k i x k : Product Priciple of Picture Eumerators See Problem 204. Product Priciple for Geeratig Fuctios See page 82. 1. (1 x) = + i 1 x i : i 2. Biet s Formula: If F is the -th Fiboacci umber the F = p 1 1 + p! +1 5 1 1 p5 5 2 2 p! +1 5 :

REVIEW FOR CHAPTER 6 A short summary: I this chapter you reviewed the termiology of sets i order to write ad uderstad the Priciple of Iclusio ad Exclusio. You used this priciple to determie the umber of deragemets ad the umber of oto fuctios. terms: set termiology (uio, itersectio, complemet); deragemet. Basic Priciples: The Priciple S of Iclusio ad Exclusio The umber of elemets i i=1 A i is [ A i = X \ ( 1) jsj 1 A i : i=1 S[] ; S6=; The umber of elemets i the complemet of S i=1 A i i a (uiversal) set A is [ X \ A i = jaj ( 1) jsj 1 A i : i=1 S[] ; S6=; i2s i2s 1. The umber of deragemets of [] is X s=0 ( 1) s! s! : 2. The umber of oto fuctios from [k] to [] is X ( 1) s ( s) k : s s=0

REVIEW FOR CHAPTER 7 k objects ad coditios recipiets ad mathematical model for distributio o how they are received Distict Idetical Distict k NOT DONE o coditios fuctios (set partitios ito parts) Distict k 1 if k ; 0 otherwise Each gets at most oe k-elemet permutatios P Distict s=0 ( 1)s s ( s) k NOT DONE Each gets at least oe oto fuctios (set partitios ito parts) Distict k! =! 1 if k = ; 0 otherwise Each gets exactly oe permutatios Distict, order matters (k + 1) k P i=1 L(k; i) ordered-fuctios broke permutatios ( parts) Distict, order matters (k) (k 1) k L(k; ) = k (k 1) k Each gets at least oe ordered-oto-fuctios broke permutatios ( parts) +k 1 Idetical k NOT DONE o coditios multisets (umber of partitios ito parts) Idetical Each gets at most oe k subsets 1 if k ; 0 otherwise k 1 1 Idetical NOT DONE Each gets at least oe compositios ( parts) (umber of partitios ito parts) Idetical 1 if k = ; 0 otherwise 1 if k = ; 0 otherwise Each gets exactly oe