Quiz: Experimental Physics Lab-I

Similar documents
DCDM BUSINESS SCHOOL NUMERICAL METHODS (COS 233-8) Solutions to Assignment 3. x f(x)

Chapter Newton-Raphson Method of Solving a Nonlinear Equation

Physics 121 Sample Common Exam 2 Rev2 NOTE: ANSWERS ARE ON PAGE 7. Instructions:

4. Eccentric axial loading, cross-section core

7.2 Volume. A cross section is the shape we get when cutting straight through an object.

UNIVERSITY OF IOANNINA DEPARTMENT OF ECONOMICS. M.Sc. in Economics MICROECONOMIC THEORY I. Problem Set II

6 Roots of Equations: Open Methods

Applied Statistics Qualifier Examination

Principle Component Analysis

ragsdale (zdr82) HW6 ditmire (58335) 1 the direction of the current in the figure. Using the lower circuit in the figure, we get

Effects of polarization on the reflected wave

Chapter Newton-Raphson Method of Solving a Nonlinear Equation

v v at 1 2 d vit at v v 2a d

Fall 2012 Analysis of Experimental Measurements B. Eisenstein/rev. S. Errede. with respect to λ. 1. χ λ χ λ ( ) λ, and thus:

Rank One Update And the Google Matrix by Al Bernstein Signal Science, LLC

INTRODUCTION TO COMPLEX NUMBERS

CISE 301: Numerical Methods Lecture 5, Topic 4 Least Squares, Curve Fitting

Department of Mechanical Engineering, University of Bath. Mathematics ME Problem sheet 11 Least Squares Fitting of data

ESCI 342 Atmospheric Dynamics I Lesson 1 Vectors and Vector Calculus

Lesson 2. Thermomechanical Measurements for Energy Systems (MENR) Measurements for Mechanical Systems and Production (MMER)

The Schur-Cohn Algorithm

Mathematics Extension 1

Lecture 4: Piecewise Cubic Interpolation

Haddow s Experiment:

a < a+ x < a+2 x < < a+n x = b, n A i n f(x i ) x. i=1 i=1

20 MATHEMATICS POLYNOMIALS

Jens Siebel (University of Applied Sciences Kaiserslautern) An Interactive Introduction to Complex Numbers

Torsion, Thermal Effects and Indeterminacy

Week3, Chapter 4. Position and Displacement. Motion in Two Dimensions. Instantaneous Velocity. Average Velocity

Chemical Reaction Engineering

We partition C into n small arcs by forming a partition of [a, b] by picking s i as follows: a = s 0 < s 1 < < s n = b.

Definition of Tracking

Review of linear algebra. Nuno Vasconcelos UCSD

Abhilasha Classes Class- XII Date: SOLUTION (Chap - 9,10,12) MM 50 Mob no

COMPLEX NUMBER & QUADRATIC EQUATION

Dennis Bricker, 2001 Dept of Industrial Engineering The University of Iowa. MDP: Taxi page 1

Problem Set 9. Figure 1: Diagram. This picture is a rough sketch of the 4 parabolas that give us the area that we need to find. The equations are:

Math1110 (Spring 2009) Prelim 3 - Solutions

Solution of Tutorial 5 Drive dynamics & control

Section 4.8. D v(t j 1 ) t. (4.8.1) j=1

Lecture 7 Circuits Ch. 27

6.6 The Marquardt Algorithm

Chemical Reaction Engineering

Lecture 3 Gaussian Probability Distribution

Ph2b Quiz - 1. Instructions

Least squares. Václav Hlaváč. Czech Technical University in Prague

Introduction to Numerical Integration Part II

Electrochemical Thermodynamics. Interfaces and Energy Conversion

? plate in A G in

In Calculus I you learned an approximation method using a Riemann sum. Recall that the Riemann sum is

Chapter 6 Notes, Larson/Hostetler 3e

SVMs for regression Non-parametric/instance based classification method

Statistics 423 Midterm Examination Winter 2009

Read section 3.3, 3.4 Announcements:

1 Probability Density Functions

CENTROID (AĞIRLIK MERKEZİ )

ARITHMETIC OPERATIONS. The real numbers have the following properties: a b c ab ac

Chapter 6 Continuous Random Variables and Distributions

Trigonometry. Trigonometry. Solutions. Curriculum Ready ACMMG: 223, 224, 245.

4 7x =250; 5 3x =500; Read section 3.3, 3.4 Announcements: Bell Ringer: Use your calculator to solve

Section 5.1 #7, 10, 16, 21, 25; Section 5.2 #8, 9, 15, 20, 27, 30; Section 5.3 #4, 6, 9, 13, 16, 28, 31; Section 5.4 #7, 18, 21, 23, 25, 29, 40

GAUSS ELIMINATION. Consider the following system of algebraic linear equations

SUMMER KNOWHOW STUDY AND LEARNING CENTRE

l 2 p2 n 4n 2, the total surface area of the

Many-Body Calculations of the Isotope Shift

SAINT IGNATIUS COLLEGE

MATH 253 WORKSHEET 24 MORE INTEGRATION IN POLAR COORDINATES. r dr = = 4 = Here we used: (1) The half-angle formula cos 2 θ = 1 2

Multiple view geometry

The Wave Equation I. MA 436 Kurt Bryan

Higher Checklist (Unit 3) Higher Checklist (Unit 3) Vectors

Chapter 1: Fundamentals

Name: SID: Discussion Session:

CS434a/541a: Pattern Recognition Prof. Olga Veksler. Lecture 9

Operations with Polynomials

Model Fitting and Robust Regression Methods

ψ ij has the eigenvalue

For all questions, answer choice E) NOTA" means none of the above answers is correct.

A B= ( ) because from A to B is 3 right, 2 down.

Goals: Determine how to calculate the area described by a function. Define the definite integral. Explore the relationship between the definite

Symmetries and Conservation Laws in Classical Mechanics

Math Calculus with Analytic Geometry II

First Semester Review Calculus BC

St John s College. UPPER V Mathematics: Paper 1 Learning Outcome 1 and 2. Examiner: GE Marks: 150 Moderator: BT / SLS INSTRUCTIONS AND INFORMATION

Practice Final. Name: Problem 1. Show all of your work, label your answers clearly, and do not use a calculator.

Math 426: Probability Final Exam Practice

Properties of Integrals, Indefinite Integrals. Goals: Definition of the Definite Integral Integral Calculations using Antiderivatives

CAAM 453 NUMERICAL ANALYSIS I Examination There are four questions, plus a bonus. Do not look at them until you begin the exam.

( ) ( )()4 x 10-6 C) ( ) = 3.6 N ( ) = "0.9 N. ( )ˆ i ' ( ) 2 ( ) 2. q 1 = 4 µc q 2 = -4 µc q 3 = 4 µc. q 1 q 2 q 3

Partial Derivatives. Limits. For a single variable function f (x), the limit lim

Math 8 Winter 2015 Applications of Integration

Proof that if Voting is Perfect in One Dimension, then the First. Eigenvector Extracted from the Double-Centered Transformed

Lecture 36. Finite Element Methods

APPENDIX 2 FITTING A STRAIGHT LINE TO OBSERVATIONS

Variable time amplitude amplification and quantum algorithms for linear algebra. Andris Ambainis University of Latvia

Investigation phase in case of Bragg coupling

Physics 4B. A positive value is obtained, so the current is counterclockwise around the circuit.

4.4 Areas, Integrals and Antiderivatives

Please initial the statement below to show that you have read it

MATHEMATICAL MODEL AND STATISTICAL ANALYSIS OF THE TENSILE STRENGTH (Rm) OF THE STEEL QUALITY J55 API 5CT BEFORE AND AFTER THE FORMING OF THE PIPES

Remember: Project Proposals are due April 11.

Transcription:

Mxmum Mrks: 18 Totl tme llowed: 35 mn Quz: Expermentl Physcs Lb-I Nme: Roll no: Attempt ll questons. 1. In n experment, bll of mss 100 g s dropped from heght of 65 cm nto the snd contner, the mpct s clled crter. Fve students mesured the dmeter of the crter from the sme heght. The dt for ech student s shown n Fgure (1), whch student mde the most precse mesurement? [3] No. of trls No. of trls 15 10 5 15 10 5 3.7 4.7 5.7 6.7 Crter dmeter (cm) () 3.7 4.7 5.7 6.7 Crter dmeter (cm) (c) No. of trls No. of trls 15 10 5 15 10 5 3.7 4.7 5.7 6.7 Crter dmeter (cm) (b) 3.7 4.7 5.7 6.7 Crter dmeter (cm) (d) No. of trls 15 10 5 3.7 4.7 5.7 6.7 Crter dmeter (cm) (e) FIG. 1: Expermentl dt for crter formton. Soluton: The correct nswer s (). Snce type-a uncertnty s evluted sttstclly nd cn be mnmzed by repetng the experment mny tmes, therefore the spred of the Gussn dstrbuton ssocted wth type-a uncertntes should be s thn s possble. Thus, the wdth of the crter dmeter vs number of trls grph must hve lest spred. The only choce tht shows ths chrcterstc s choce (). Dte: Tuesdy, December 2, 2014. 1

Mxmum Mrks: 18 Totl tme llowed: 35 mn 2. The fgure bove represents log-log (to the bse 10) plot of vrble y versus vrble x. The orgn represents the pont x 1 nd y 1. Whch of the followng gves the pproxmte functonl reltonshp between y nd x? [3] FIG. 2: Log-log plot of vrble y versus vrble x. () y c x. (b) y 1x + c. 2 (c) y 6x + c. (d) y cx 2. (e) log y c + 5 log x. Soluton: The correct nswer s (). A functon of the form y cx m wll pper s strght lne on log-log plot. Here m s the slope of the lne nd c s the y vlue correspondng to x 1. Therefore, log 10 (y) log 10 (cx m ), log 10 (c) + m log 10 x. Dte: Tuesdy, December 2, 2014. 2

Mxmum Mrks: 18 Totl tme llowed: 35 mn The vlue of the slope cn be found out, m log 10(100) log 10 (10) log 10 (300) log 10 (3), 2 1 2.477 0.477 1 2. The reltonshp between y nd x wll tke the form, log 10 (y) log 10 (c) + 1 2 log 10 T, or y c x 1/2. 3. The volume V of rectngulr block s determned by mesurng the length l x, l y nd l z of ts sdes. From the sctter of the mesurements stndrd uncertnty of 0.01% s ssgned to ech dmenson. Wht s the frctonl uncertnty n V, f, (1) The sctter s due to uncertntes n settng nd redng the mesurng nstrument. (2) If t s due to temperture fluctutons? [3] () 0.2% nd 0.3% respectvely. (b) 0.02% nd 5% respectvely. (c) 0.02% nd 0.03% respectvely. (d) 0.03% nd 0.02% respectvely. (e) None of the bove Soluton: The correct nswer s (c). (1) The stndrd uncertnty n ech dmenson s 0.01%. The volume of rectngulr block s, V l x l y l z. The uncertnty ffects the three sdes ndependently. Hence, the stndrd uncertnty n V cn be clculted through the Tylor seres pproxmton, ( V ) 2 ( ) 2 ( ) 2 V V V l x + l y + l z, l x l y l z (ly l z l x ) 2 + ( lx l z l y ) 2 + ( lx l y l z ) 2. Dte: Tuesdy, December 2, 2014. 3

Mxmum Mrks: 18 Totl tme llowed: 35 mn Dvdng both sdes of the bove expresson by V yelds, V V ( ) 2 ( ) 2 ( ) 2 ly l z lx l z lx l y l x + l y + l z, l x l y l z l x l y l z l x l y l z ( lx ) 2 ( ) 2 ( ) 2 ly lz + +, l x l y l z (0.01) 2 + (0.01) 2 + (0.01) 2 0.017%, 0.02%. (2) For temperture vrtons, ll sdes re ffected eqully. Therefore, one cn use the formul for volume wth equl lengths, V l 3, nd the uncertnty n V s, V ( V ) 2 l l 3l 2 l. Dvdng by V on both sdes gves, V V 3l2 l l 3 3 0.03%. ( l l ), 3 0.01%, Ths result shows tht the overll uncertnty cn ncrese, f uncertntes re not ndependent nor rndom. 4. Fgure (3A) shows the poston x(t) versus tme plot for n elevtor cb tht s ntlly sttonry, then moves upwrd (whch we tke to be the postve drecton of x), nd then stops. Choose the best opton for the velocty v(t) nd ccelerton (t) shown n Fgure (3B). [3] Soluton: The correct nswer s (d). The slope (v dx/dt) of x(t) s zero n the ntervls from to b nd t pont d, ths mens tht the cb s sttonry. Durng the ntervl bc, the slope s constnt Dte: Tuesdy, December 2, 2014. 4

Mxmum Mrks: 18 Totl tme llowed: 35 mn x(t) c d b 0 (A) t b c b c Ι d t 0 ΙΙ t d b c d b c d 0 ΙΙΙ 0 ΙV (B) FIG. 3: (A) Poston versus tme grph, (B) grphs for velocty nd ccelerton. v(t) vs t (t) vs t () II IV (b) I II (c) I IV (d) II III (e) I III nd nonzero nd the cb moves wth constnt velocty ndcted by bc n subfgure (II). Snce the cb ntlly begns to move nd then lter slows to stop, v vres s ndcted by the slopes of b 0 nd c 0 n the subfgure (II). Thus, subfgure (II) s the requred plot. The ccelerton of prtcle t ny nstnt s the rte t whch ts velocty s chngng t tht nstnt. Grphclly, the ccelerton t ny pont s the slope of the curve of Dte: Tuesdy, December 2, 2014. 5

Mxmum Mrks: 18 Totl tme llowed: 35 mn v(t) t tht pont, therefore, dv dt d ( ) dx d2 x dt dt dt. 2 Comprng subfgure (III) wth subfgure (II), ech pont on subfgure (III) shows the dervtve (slope) of the v(t) curve t the correspondng tme. When v s constnt, the dervtve s zero nd so lso s the ccelerton. When the cb frst begns to move, the v(t) curve hs postve dervtve (the slope s postve), whch mens tht (t) s postve. When the cb slows to stop, the dervtve nd slope of the v(t) curve s negtve, hence (t) s negtve. 5. The perod of osclltons T of body constrned to rotte bout horzontl xs for smll mpltudes s gven by the expresson, ( ) 1/2 I T 2π, (1) mgd where m s mss of the body, d s the dstnce between center of mss (CM) nd the xs of rotton nd I s the moment of nert (MI) bout the xs of rotton gven by (from prllel xs theorem: I I o + md 2 ). Here I o s the moment of nert bout prllel xs through center of mss. If k s the rdus of gyrton tht depends on geometry.e., k l2 + b 2 12, then I 0 mk 2. Now Equton (1) cn be wrtten s, k T 2π 2 + d 2. (2) gd How would you fnd the vlue of g by plottng? [3] () T versus d. (b) T 2 d versus d 2. (c) T 2 versus d. (d) T versus log(d). (e) All of the bove. Soluton: The correct nswer s (b). Dte: Tuesdy, December 2, 2014. 6

Mxmum Mrks: 18 Totl tme llowed: 35 mn By lookng t Equton (2), one cn tell tht f we plot T versus d tht wll follow prbol trend. The best wy s to lnerze the gven functon whch s n mportnt technque from dt nlyss perspectve. Rerrngng Equton (2) yelds, ( 4π T 2 2 d )d 2 + 4π2 k 2. g g Ths s strght lne functon wth T 2 d s the dependent vrble, d 2 s the ndependent vrble, (4π 2 /g) s the slope whle (4π 2 k 2 /g) s the ntercept. The g vlue cn be computed through the resultnt outcome of slope (4π 2 /g). 6. Lssjous fgures re used for the mesurement of phse nd produced when one sgnl s connected to the vertcl trce of the osclloscope nd the other to the horzontl trce. If the two sgnls hve the sme frequency, then the lssjous fgure wll ssume the shpe of n ellpse. The ellpse s shpe vres ccordng the phse dfference between two sgnls nd ccordng to the rto of mpltudes of the two sgnls. The phse dfference cn be clculted through the followng expresson, Y H x 0.2V (b) () 2ms FIG. 4: () The output sgnl of n osclloscope, nd (b) n ellpse. sn(ϕ) ± Y H, (3) where H s hlf the mxmum heght nd Y s the ntercept on the y xs s shown n Fgure (4b). Dte: Tuesdy, December 2, 2014. 7

Mxmum Mrks: 18 Totl tme llowed: 35 mn Clculte the phse dfference ϕ nd ts uncertnty (ssume ths s n nlog scle) bsed on the Lssjous pttern gven n Fgure (4). [3] d (Hnt: dx (sn 1 u) 1 du ). 1 u 2 dx Soluton: Snce ech block on the osclloscope screen s equvlent to 0.2 V, therefore by redng the scle, the vlues of the ellpse s prmeters becomes, Y 0.2 + 0.05 0.25 V, X 0.4 + 0.04 0.44 V. Substtutng these vlues n Equton (3) yelds, ( ) Y ϕ sn 1, H ( ) 0.25 sn 1 34.62, 0.44 35. Snce ths s n nlog scle, uncertntes ssocted wth Y nd H cn be found out s, The vlues of Y nd H cn be quoted s, u Y 6 0.04/2 6 0.008 V, u H 6 0.04/2 6 0.008 V. Y (0.250 ± 0.008) V, H (0.440 ± 0.008) V. Notce tht uncertnty hs only one sgnfcnt fgure nd the decml plces of both the orgnl quntty nd the uncertnty re t the sme poston. The uncertnty n the phse ϕ cn be clculted through the Tylor seres pproxmton, ϕ ( ) 2 ( ) 2 ϕ ϕ Y Y + H H. (4) Dte: Tuesdy, December 2, 2014. 8

Mxmum Mrks: 18 Totl tme llowed: 35 mn Dfferenttng equton (3) w.r.t Y gves, ( ) ϕ Y 1 d(y/h) 1 ( ), Y 2 dy H 2 ( ) 1 1 1 ( ), Y 2 H H 2 1 1 ( ) 0.25 2 0.44 2 2.76. Dfferenttng equton (3) w.r.t H yelds, ϕ H 1 1 ( ) Y 2 H 2 ( ) 1, 0.44 ( d(y/h) dh 1 1 ( ) ( YH ), Y 2 2 H 2 ( 1 0.25 1 ( ) 0.25 2 0.44 2 0.44 2 1.57. Substtutng n Equton (4) results n, ), ), ϕ (2.76 0.008) 2 + (1.57 0.008) 2, 0.025 0.02. The uncertnty vlue n degrees would be, ϕ 0.02 ( 180 3.14 ) 1.1. Hence, the fnl vlue of phse ϕ cn be quoted s, ϕ (35 ± 1). Dte: Tuesdy, December 2, 2014. 9

Mxmum Mrks: 18 Totl tme llowed: 35 mn Formul sheet: Tylor seres pproxmton: If quntty q q(x, y, z) s mesured usng some nput vrbles x, y nd z whch re mesured wth uncertntes x, y nd z, respectvely, then q cn lso be fnd out usng the Tylor seres pproxmton gven s, q ( ) 2 ( ) 2 ( ) 2 q q q x x + y y + z z. Stndrd devton: s d2 N. Stndrd uncertnty: σ N (s). N 1 Stndrd uncertnty n the men: σ m σ N. Weghted verge: x vg w x w Slope (m) nd ntercept (c) wth equl weghts: m y (x x) (x or m N x) 2 N x y x y x 2 ( x ) 2 (5) c ȳ m x or c Uncertnty n slope m nd ntercept c s gven s, where, u m u c N d 2 x 2 y x x y N x 2 ( x ) 2. (6) D(N 2), (7) ( )( 1 N ) N + x2 d 2, (8) D (N 2) d y mx c, N D (x x) 2. Slope m nd ntercept c wth unequl weghts Dte: Tuesdy, December 2, 2014. 10

Mxmum Mrks: 18 Totl tme llowed: 35 mn The weghts re recprocl squres of the totl uncertnty (u Totl ), w 1. (9) u 2 Totl The mthemtcl reltonshps for slope (m) nd ntercept (c) re, m Σ w Σ w (x y ) Σ (w x ) Σ (w y ) Σ w Σ (wx 2 ) (Σ w x ) 2, (10) c Σ (w x 2 ) Σ (w y ) Σ (w x ) Σ (w x y ) Σ w Σ (w x 2 ) (Σ w x ) 2, (11) where x s the ndependent vrble, y s the dependent vrble nd w s the weght. The expressons for the uncertntes n m nd c re, Σ w u m Σ w Σ (w x 2 ) (Σ w x ), (12) 2 u c Σ (w x 2 ) Σ w Σ (w x 2 ) (Σ w x ). (13) 2 Dte: Tuesdy, December 2, 2014. 11