Formulae and Summary

Similar documents
Chapter 1. Functions 1.3. Trigonometric Functions

Core A-level mathematics reproduced from the QCA s Subject criteria for Mathematics document

REQUIRED MATHEMATICAL SKILLS FOR ENTERING CADETS

Learning Objectives These show clearly the purpose and extent of coverage for each topic.

You should be comfortable with everything below (and if you aren t you d better brush up).

Candidates are expected to have available a calculator. Only division by (x + a) or (x a) will be required.

CALCULUS ASSESSMENT REVIEW

Contact hour per week: 04 Contact hour per Semester: 64 ALGEBRA 1 DETERMINANTS 2 2 MATRICES 4 3 BINOMIAL THEOREM 3 4 LOGARITHMS 2 5 VECTOR ALGEBRA 6

Higher Mathematics Course Notes

STATE COUNCIL OF EDUCATIONAL RESEARCH AND TRAINING TNCF DRAFT SYLLABUS.

ADDITIONAL MATHEMATICS

The American School of Marrakesh. AP Calculus AB Summer Preparation Packet

Sec 4 Maths. SET A PAPER 2 Question

Grade 11 or 12 Pre-Calculus

Formulas to remember

Core Mathematics C1 (AS) Unit C1

MATHEMATICS. IMPORTANT FORMULAE AND CONCEPTS for. Summative Assessment -II. Revision CLASS X Prepared by

Core 3 (A2) Practice Examination Questions

Algebra 2 Khan Academy Video Correlations By SpringBoard Activity

Algebra 2 Khan Academy Video Correlations By SpringBoard Activity

Table of Contents. Module 1

Unit 6 Trigonometric Identities Prove trigonometric identities Solve trigonometric equations

Calculus: Early Transcendental Functions Lecture Notes for Calculus 101. Feras Awad Mahmoud

FIRST SEMESTER DIPLOMA EXAMINATION IN ENGINEERING/ TECHNOLIGY- OCTOBER, TECHNICAL MATHEMATICS- I (Common Except DCP and CABM)

PART ONE: Solve algebraically and check. Be sure to show all work.

ADDITIONAL MATHEMATICS

MATHEMATICS LEARNING AREA. Methods Units 1 and 2 Course Outline. Week Content Sadler Reference Trigonometry

Core Mathematics 3 Trigonometry

Outline schemes of work A-level Mathematics 6360

Trigonometry Trigonometry comes from the Greek word meaning measurement of triangles Angles are typically labeled with Greek letters

Maths Higher Prelim Content

Chapter P: Preliminaries

[STRAIGHT OBJECTIVE TYPE] log 4 2 x 4 log. x x log 2 x 1

For a semi-circle with radius r, its circumfrence is πr, so the radian measure of a semi-circle (a straight line) is

AS PURE MATHS REVISION NOTES

Pre-Calculus Chapter 0. Solving Equations and Inequalities 0.1 Solving Equations with Absolute Value 0.2 Solving Quadratic Equations

WORKBOOK. MATH 30. PRE-CALCULUS MATHEMATICS.

[STRAIGHT OBJECTIVE TYPE] Q.4 The expression cot 9 + cot 27 + cot 63 + cot 81 is equal to (A) 16 (B) 64 (C) 80 (D) none of these

College Algebra with Trigonometry

DEPARTMENT OF MATHEMATICS

Mathematics syllabus for Grade 11 and 12 For Bilingual Schools in the Sultanate of Oman

Chapter P: Preliminaries

Math Review for AP Calculus

(D) (A) Q.3 To which of the following circles, the line y x + 3 = 0 is normal at the point ? 2 (A) 2

ADDITIONAL MATHEMATICS

0 Review of Basic Concepts

PU I Year Trigonometry

Lone Star College-CyFair Formula Sheet

Part r A A A 1 Mark Part r B B B 2 Marks Mark P t ar t t C C 5 Mar M ks Part r E 4 Marks Mark Tot To a t l

weebly.com/ Core Mathematics 3 Trigonometry

CO-ORDINATE GEOMETRY

Precalculus Review. Functions to KNOW! 1. Polynomial Functions. Types: General form Generic Graph and unique properties. Constants. Linear.

YEAR 12 - Mathematics Pure (C1) Term 1 plan

West Windsor-Plainsboro Regional School District Algebra and Trigonometry Grades 11-12

Chapter 2: Differentiation

1.3 Basic Trigonometric Functions

Copyright 2018 UC Regents and ALEKS Corporation. ALEKS is a registered trademark of ALEKS Corporation. 2/10

2 2xdx. Craigmount High School Mathematics Department

Precalculus Summer Assignment 2015

0615a2. Algebra 2/Trigonometry Regents Exam x 2 y? 4 x. y 2. x 3 y

Pure Core 2. Revision Notes

Lesson-3 TRIGONOMETRIC RATIOS AND IDENTITIES

ACCESS TO SCIENCE, ENGINEERING AND AGRICULTURE: MATHEMATICS 1 MATH00030 SEMESTER / Trigonometry

SUBJECT: ADDITIONAL MATHEMATICS CURRICULUM OUTLINE LEVEL: 3 TOPIC OBJECTIVES ASSIGNMENTS / ASSESSMENT WEB-BASED RESOURCES. Online worksheet.

Review of Topics in Algebra and Pre-Calculus I. Introduction to Functions function Characteristics of a function from set A to set B

Chapter 2: Differentiation

CURRICULUM GUIDE. Honors Algebra II / Trigonometry

( and 1 degree (1 ) , there are. radians in a full circle. As the circumference of a circle is. radians. Therefore, 1 radian.

CLASS X FORMULAE MATHS

Problems (F/M): Part 2 - Solutions (16 pages; 29/4/17)

Math Prep for Statics

DuVal High School Summer Review Packet AP Calculus

Mathematics, Algebra, and Geometry

Mathematics 1 Lecture Notes Chapter 1 Algebra Review

Curriculum Map for Mathematics HL (DP1)

Summer Work Packet for MPH Math Classes

2. Find the midpoint of the segment that joins the points (5, 1) and (3, 5). 6. Find an equation of the line with slope 7 that passes through (4, 1).

Test Codes : MIA (Objective Type) and MIB (Short Answer Type) 2007

Pre-Calculus MATH 119 Fall Section 1.1. Section objectives. Section 1.3. Section objectives. Section A.10. Section objectives

1d C4 Integration cot4x 1 4 1e C4 Integration trig reverse chain 1

AS and A-level Mathematics Teaching Guidance

Solving equations UNCORRECTED PAGE PROOFS

!"#$%&'(#)%"*#%*+"),-$.)#/*01#2-31#)(.*4%5)(*6).#* * *9)"&*#2-*5$%5%.-&*#%5)(*8).#*9%$*1*'"),-$.)#/*31#2-31#)(.*5$-51$1#)%"*(%'$.

A-Level Mathematics TRIGONOMETRY. G. David Boswell - R2S Explore 2019

Π xdx cos 2 x

Welcome to AP Calculus!!!

Course outline Mathematics: Methods ATAR Year 11

C3 Revision Questions. (using questions from January 2006, January 2007, January 2008 and January 2009)

Coach Stones Expanded Standard Pre-Calculus Algorithm Packet Page 1 Section: P.1 Algebraic Expressions, Mathematical Models and Real Numbers

Pearson Edexcel Level 3 Advanced Subsidiary GCE in Mathematics (8MA0) Pearson Edexcel Level 3 Advanced GCE in Mathematics (9MA0)

MODULE 1: FOUNDATIONS OF MATHEMATICS

Using this definition, it is possible to define an angle of any (positive or negative) measurement by recognizing how its terminal side is obtained.

TRIGONOMETRY OUTCOMES

MATHEMATICS. Higher 2 (Syllabus 9740)

The matrix: "Is an organization of some elements written in rows


Free download from not for resale. Apps 1.1 : Applying algebraic skills to rectilinear shapes.

Secondary School Certificate Examination Syllabus MATHEMATICS. Class X examination in 2011 and onwards. SSC Part-II (Class X)

Topic Outline for Algebra 2 & and Trigonometry One Year Program

PreCalculus. Curriculum (637 topics additional topics)

Transcription:

Appendix A Formulae and Summary Note to student: It is not useful to memorise all the formulae, partly because many of the complicated formulae may be obtained from the simpler ones. Rather, you should familiarise yourself with the simpler formulae by solving a number of practice questions which use those. Consult your school to check which formulae you are expected to know by heart for examinations, and which others will be provided to you in a help sheet. Exponents and Logarithms For a,b > 0, a 1 = 1 a. a 0 = 1. a xy = (a x ) y. a x a y = a x+y. (ab) x = a x b x. ab = a b. (A.1) (A.) (A.3) (A.4) (A.5) (A.6) For a > 1, y = a x is positive and an increasing function of x along the real line; for 0 < a < 1, a x is a decreasing function of x.

160 Appendix A. Formulae and Summary The basic relation between exponents and logarithms is y = b x x = log b y. (A.7) For a,b > 0, a 1, b 1 and P,Q > 0, log b 1 = 0. log b PQ = log b P +log b Q. P log b Q = log bp log b Q. log b P c = clog b P. log b P = log ap log a b. log b a = 1 log a b. (A.8) (A.9) (A.10) (A.11) (A.1) (A.13) For a > 1 and x > 0, y = log a x is an increasing function of x; it is positive for x > 1, negative for x < 1 and vanishes at x = 1. The graph of y = log a x may be obtained by reflecting the exponential curve y = a x about the line y = x. Binomial Expansions For a positive integer n, the Binomial Theorem states ( ) ( ) ( ) n n n (a+b) n = a n + a n 1 b+ a n b + a n 3 b 3 +... 1 3 ( ) ( ) n n + a n r b r +...+ ab n 1 +b n (A.14) r n 1 where the binomial coefficient is defined by ( ) n n n! C r = r r!(n r)! (A.15) and n! n (n 1) (n )... 1 with 0! 1. ( ) Note that the (r + 1)-th term in the above expansion is given by n r a n r b r.

161 Polynomials Remainder Theorem: If the polynomial P(x) is divided by (x α), the remainder is P(α). In other words, P(x) (x α)q(x)+r with P(α) = R. Factorisation Theorem: P(α) = 0 if and only if P(x) (x α)q(x). For the quadratic equation ax +bx+c = 0, where x = b±. (A.16) a b 4ac (A.17) is called the discriminant. The two roots are real if and only if 0; the case = 0 corresponds to a repeated root. Denoting the two roots of a quadratic equation by α and β, then α+β = b a. αβ = c a. (A.18) Other common relations are α β = ± (α β) = ± (α+β) 4αβ. and α +β = (α+β) αβ. (A.19) (A.0) The shape of the curve y = ax + bx + c is determined by the sign of a: When a > 0, the curve has a minimum point while for a < 0 it has amaximum. For a cubiccurve y = ax 3 +bx +cx+d, the sign of the leading coefficient again determines its the main shape. If a > 0, the curve rises upwards for large positive x and decreases for large negative x. In between, it will either have a local minimum and a local maximum or gently undulate.

16 Appendix A. Formulae and Summary Partial Fractions Given a rational function P(x)/Q(x), its decomposition into partial fractions is as follows: First use long division to reduce the degree of the numerator to below that of the denominator. Next, each factor of (x a) in Q(x) would require a partial fraction A/(x a). If the factor is repeated in Q, for example (x a), then one uses two partial fractions A 1 /(x a) and A /(x a) for that factor. If Q contains a term that cannot be factorised (using real numbers), for example x +x+1, then the partial fraction for that term is of the form (Ax+B)/(x +x+1), that is, the numerator is one degree lower than the denominator. Simultaneous Equations A m n matrix A multiplying from the left a n p matrix B yields a m p matrix C; that is C = AB. The c ij element of C is obtained by multiplying the i-th row of A to the j-th column of B term by term and adding the pieces. The pair of simultaneous equations in the variables (x, y): ax+by = e cx+dy = f, (A.1) (A.) may be written as the matrix equation MX = R with ( ) a b M =, (A.3) c d and X = R = ( x y ( e f ) ) (A.4). (A.5)

163 The determinant of the matrix M is defined by det(m)= ad bc. If det(m) 0 then one may define an inverse matrix M 1 = ( 1 d b det(m) c a ) (A.6) and the solution to the problem is X = M 1 R = 1 det(m) ( de bf ce+af ). (A.7) If det(m)= 0 the matrix is termed singular and there is no inverse matrix. The inverse matrix satisfies ( ) MM 1 = M 1 1 0 M =, (A.8) 0 1 the last matrix being the identity matrix, usually denoted by the letter I. Trigonometry For angle measurements in radian, θ s/r where s is the arc length of circle subtended by that angle. Therefore π radians equals 360. For a right-angled triangle ABC, with C = 90, sina = a/c, cosa = b/c and tana = sina/cosa = a/b, where the small case letters denote lengths opposite the corresponding angles. The sin and cos functions range over the interval [ 1,1] while the tan functions ranges over the real line. Periodicity: sin(θ + 360 ) = sin(θ), cos(θ + 360 ) = cos(θ) and tan(θ +180 ) = tan(θ). The principal values for the inverse functions sin 1 and tan 1 are those that lie in the range π/ y π/ while for the cos 1 function has the range 0 y π.

164 Appendix A. Formulae and Summary The functions csc, sec and cot are reciprocals of the sin, cos and tan functions (cscx is also written as cosec x). Phenomena that are described by an equation of the form y(x) = A+Bsin(kx+C) are called sinusoidal. Some identities: sin A+cos A = 1. 1+tan A = sec A. sin( A) = sina. cos( A) = cosa. tan( A) = tana. (A.9) (A.30) (A.31) (A.3) (A.33) Addition Formulae: sin(a±b) = sina cosb ±cosa sinb. (A.34) cos(c ±D) = cosc cosd sinc sind. (A.35) tan(a±b) = tana±tanb 1 tana tanb. (A.36) Special Cases of addition formulae: sin(90 ±A) = cosa. sin(180 ±A) = sina. cos(90 ±A) = sina. cos(180 ±A) = cosa. tan(90 ±A) = cota. (A.37) (A.38) (A.39) (A.40) (A.41) Double Angle Formulae: sina = sinacosa. (A.4) cosa = cos A 1 = 1 sin A = cos A sin A. tana = tana 1 tan A. (A.43) (A.44)

165 Factor Formulae: R-Formulae: sina+sinb = sin A+B sina sinb = cos A+B cosa+cosb = cos A+B cosa cosb = sin A+B cos A B sin A B cos A B sin A B. (A.45). (A.46). (A.47). (A.48) acosθ±bsinθ = Rcos(θ α). asinθ±bcosθ = Rsin(θ±α). (A.49) (A.50) with R = a +b, tanα = b/a. Properties of Triangles For a right-angled triangle, a mnemonic is soh-cah-toa, which summarises sin = Oppositeside/Hypotenuse, cos = Adjacentside/Hypotenuse and tan = Opposite/Adjacent. Area of a triangle: A = 1 ab sinc. (A.51) The sine rule: c sinc = b sinb = a sina. (A.5) Each ratio in the formula equals the diameter of a circle which circumscribes the triangle (the centre of the circle being at the intersection of the perpendicular bisectors of the three sides). The cosine rule: c = a +b ab cosc. (A.53)

166 Appendix A. Formulae and Summary Elevation, Depression and Bearing If a point P is above the horizontal through the observation point O, thentheanglethatop makes withthehorizontal istheangle of elevation of P. Similarly if P were below the horizontal then the corresponding angle would be termed angle of depression. A bearing denotes a direction relative to North. It is usually expressed by a clockwise angle measured in degrees. For example, 065 would refer to the direction 65 clockwise from North. Such bearings are called absolute bearings. It is also convenient to use relative bearings, which define an angle relative to a chosen axis, for example the axis along which an aircraft is pointing. Coordinate Geometry If (x,y) and (x 1,y 1 ) are two points on the line, y y 1 x x 1 = m = tanα, (A.54) where 0 α < π is the angle the line makes with the positive x-axis. The equation for a straight line may be written in the form y = mx+c (A.55) where m is the slope and c the intercept on the y-axis. If another line is perpendicular to (A.55), its slope must be 1/m. The mid-point ( of a line joining two points (x 1,y 1 ) and (x,y ) is x1 +x given by, y ) 1 +y. The equation for a circle is (x x 0 ) +(y y 0 ) = r, (A.56)

167 where (x 0,y 0 ) is the centre and r the radius. Given the form x +y ax by +c = 0, (A.57) for some constants a,b,c, you can complete the squares to get (x a) +(y b) = a +b c; if c < a +b then (5.4) represents a circle with centre (a,b) and radius R = a +b c. A tangent to a circle at any point P is perpendicular to the line OP where O is the centre of the circle. Therefore the normal to the circle at P lies along OP. Given three points A(x 1,y 1 ), B(x,y ) and C(x 3,y 3 ), with their relative order being anti-clockwise, the area of the triangle ABC may be obtained from the formula A = 1 x 1 x x 3 x 1 y 1 y y 3 y 1 (A.58) where the terms are generated as follows. First, start at the left of the top row and multiply each term in the top row by a term one step to the right in the bottom row, adding the pieces: x 1 y +x y 3 +x 3 y 1. Then start at the right of the top row and multiply each term in the top row by a term one step to the left in the bottom row, addingthe pieces: x 1 y 3 +x 3 y +x y 1. Finally, subtract the two contributions and include the overall 1/ to get A = 1 (x 1y +x y 3 +x 3 y 1 x 1 y 3 x 3 y x y 1 ). (A.59) Theareaofapolygonmaybedeterminedbydividingthepolygon into triangles and using the above formula for each triangle. Plane Geometry A cyclic polygon is one whose vertices lie on the circumference of a circle. Every triangle is in fact cyclic.

168 Appendix A. Formulae and Summary Inscribed Angle Theorem Let A and B be two points on the circumference of a circle. The angle subtended by A and B at the centre of the circle is twice that subtended at a point C on the circumference. Tangent-Chord Theorem (Alternate Segment Theorem) LetthetriangleABC beinscribedinacircleandatangent drawn at point A. Let D be another point on the tangent line such that D and C are on opposite sides of the line AB. Then DAB = BCA. Intersecting Chords Theorem Let A,B,C, and D be points on the circumference of a circle and X the point of intersection of the lines AC and BD. Then the triangle ABX is similar to triangle DCX. Tangent-Secant Theorem Let A,B and C be points on the circumference of a circle and let the tangent at A meet the line CB produced at D. Then (DA) = DB DC. Differential Calculus Let f and g be functions of x, and A, B, n represent constants in the following. (A.63) d Axn = Anx n 1. (A.60) d ex = e x. (A.61) dlnx = 1 x. (A.6) d sinx = cosx. d cosx = sinx. d tanx = sec x. (A.65)

169 d df (f +g) = + dg. d(fg) d f g df(g(x)) (A.66) = f dg +gdf. Product Rule (A.67) = gf fg g df = 1/. Quotient Rule (A.68) = df dg dg. Chain Rule (A.69) ( ). (A.70) df The stationary points of y = f(x) are those for which df = 0. The stationary points are local minima, local maxima, or points of inflexion. If d f > (<) 0 at the stationary point, it is a local minimum (maximum). Stationary points with d f = 0 can be examined using the first derivative test. Local extrema need not be global extrema. If x is small but not strictly zero, we may form the approximation ( ) dy y x. (A.71) Integral Calculus Fundamental Theorem of Calculus: b f(x) = F(b) F(a), where F(x) is a function that satisfies a (A.7) Hence b a df(x) df(x) = f(x). (A.73) = F(b) F(a). (A.74)

170 Appendix A. Formulae and Summary Indefinite integrals: f(x) = F(x)+C, (A.75) where (A.73) still holds and C is a constant of integration which can be fixed once we have more information about the problem. In the formulae for indefinite integrals below, f and g are functions of x while a,b,n are constants; C is a constant of integration. (a+bx) n = (a+bx)n+1 +C, n 1.(A.76) b(n+1) 1 a+bx = 1 b ln(a+bx)+c. (A.77) sin(a+bx) = 1 b cos(a+bx)+c. (A.78) cos(a+bx) = 1 b sin(a+bx)+c. (A.79) e (a+bx) = 1 b e(a+bx) +C. (A.80) (f +g) = f + g. (A.81) The following identity holds: c a f(x) = b a c f(x)+ f(x). b (A.8) For calculating areas between the curve y = f(x) and the x-axis, note that if f(x) < 0 within a region x 1 x x, the integral in that region would give a negative value and the area is then the negative of the integral. One may also evaluate the area between a curve and the y-axis. In this case the integral would be y y 1 x dy.