Solutions with relevant marking scheme to Board Question papers available in downloadable PDF format at

15 Model Question Papers 12 Board Question Papers Salient Features Comprises a total of 27 Test Papers: (15 Model Question Papers + 12 Board Question Papers) Provides Model Question Papers with solutions and 2 Additional Practice Question Papers without solutions for each subject for better preparation. Consists Board Question Papers of 2015 and 2016. Solutions with relevant marking scheme to Board Question papers available in downloadable PDF format at www.targetpublications.org/tp10186 Printed at: India Printing Works, Mumbai Target Publications Pvt. Ltd. No part of this book may be reproduced or transmitted in any form or by any means, C.D. ROM/Audio Video Cassettes or electronic, mechanical including photocopying; recording or by any information storage and retrieval system without permission in writing from the Publisher. P.O. No. 594 10186_11090_JUP

Preface SSC Question Paper Set is a penultimate weapon, designed to facilitate thorough preparation for the students appearing for the SSC Board Examination. The book includes 15 Model Questions Papers across three subjects Solved Question Papers and 2 Practice Question Papers for each subject. These Question Papers are in tune with the changed syllabus and are prepared based on the latest paper pattern. Additionally, 12 Board Question Papers (2015 and 2016) have been included to gear up the students for the Examination. The Model Answer Papers offer complete answers for every question with the relevant marking scheme to make sure the students encounter no scope for error. Solutions to Board Question Papers of 2015 and 2016 examinations are available in downloadable PDF format at our website www.targetpublications.org. The purpose behind this is to make students familiar with the current question paper pattern and marking schemes. It also gives them a holistic understanding of the exact nature of the board question papers. As the old adage goes, Practice makes a man Perfect, students will find here, a goldmine of Question Papers to practice, before they are up for their final battle. We are sure these Question Papers will prove to be extremely instrumental in achieving monumental scores in the Board Examinations. The journey to create a complete book is strewn with triumphs, failures and near misses. If you think we ve nearly missed something or want to applaud us for our triumphs, we d love to hear from you. A book affects eternity; one can never tell where its influence stops. We wish the students all the best for their examinations. Yours faithfully, Publisher.

Index Subject Page No. Marking Scheme No. Subject Test 1. Algebra 2. Geometry. No. Science & Technology Board Question Paper 1. March 2015 2. July 2015. March 2016 4. July 2016 Algebra/Geometry 1 Science Question Papers Page No. Model Answers 1 5 78 2 7 86 9 9 4 11 For Additional Practice 5 1 1 15 101 2 17 110 20 119 4 22 For Additional Practice 5 24 1 (Section A) 26 129 1 (Section B) 28 1 2 (Section A) 0 17 2 (Section B) 2 141 (Section A) 4 144 (Section B) 6 148 4 (Section A) 8 For Additional Practice 5 (Section B) 44 4 (Section B) 40 5 (Section A) 42 Subject Question Papers Algebra 46 Geometry 48 Science & Technology 50 Algebra 5 Geometry 55 Science & Technology 57 Algebra 61 Geometry 6 Science & Technology 65 Algebra 69 Geometry 71 Science & Technology 7 Page No. Model Answers Solutions in downloadable PDF format available at www.targetpublications.org

Algebra/Geometry ALGEBRA / GEOMETRY : MARKING SCHEME Marking Scheme (for March 2014 exam and onwards) Written Exam Algebra 40 Marks Time: 2 hrs. Geometry 40 Marks Time: 2 hrs. * Internal Assessment 20 Marks Total 100 Marks * Internal Assessment Home Assignment: 10 Marks 5-5 Home assignment for Algebra and Geometry of 10 marks each would be given. Marks obtained out of 100 would be converted to marks out of 10. Test of multiple choice question: 10 Marks Depending upon the entire syllabus, internal test for Algebra and Geometry with 20 marks each would be taken at the end of second semester. Marks obtained out of 40 would be converted to marks out of 10. Total 20 marks ALGEBRA AND GEOMETRY Mark Wise Distribution of Questions Marks Marks with Option 6 sub questions of 1 mark each: Attempt any 5 05 06 6 sub questions of 2 marks each: Attempt any 4 08 12 5 sub questions of marks each: Attempt any 09 15 sub questions of 4 marks each: Attempt any 2 08 12 sub questions of 5 marks each: Attempt any 2 10 15 Total: 40 60 Weightage to Types of Questions Sr. No. Type of Questions Marks Percentage of Marks 1. Very short answer 06 10 2. Short answer 27 45. Long answer 27 45 Total: 60 100 1

Marking Scheme Weightage to Objectives Sr. Algebra Geometry Objectives No Percentage marks Percentage marks 1. Knowledge 15 15 2. Understanding 15 15. Application 60 50 4. Skill 10 20 Total: 100 100 Unit wise Distribution: Algebra Sr. No. Unit Marks with option 1. Arithmetic Progression 12 2. Quadratic equations 12. Linear equation in two variables 12 4. Probability 10 5. Statistics I 06 6. Statistics II 08 Total: 60 Unit wise Distribution: Geometry Sr. No. Unit Marks with option 1. Similarity 12 2. Circle 10. Geometric Constructions 10 4. Trigonometry 10 5. Co-ordinate Geometry 08 6. Mensuration 10 Total: 60 2

Science and Technology SCIENCE & TECHNOLOGY : MARKING SCHEME Marking Scheme (for March 2014 exam and onwards) Total Marks: 100 Written examination: 80 Marks Two separate question paper has to be solved on separate answer sheets. Paper I: 40 Marks: 2 hours Paper II: 40 Marks: 2 hours Practical examination: 20 Marks: 1 hour 0 minutes Question Paper pattern: Paper - I (Section A) Questions Marks Marks with option Q. 1 A. Answer 5 questions. (1 mark question) 5 5 Q. 1 B. Answer 5 MCQs. (1 mark question) 5 5 Q. 2. Answer any 5 out of 6. (2 marks question) 10 12 Q.. Answer any 5 out of 6. ( marks question) 15 18 Q. 4. Answer any 1 out of 2. (5 marks question) 5 10 Paper - II (Section B) Q. 1 A. Answer 5 questions. (1 mark question) 5 5 Q. 1 B. Answer 5 MCQs. (1 mark question) 5 5 Q. 2. Answer any 5 out of 6. (2 marks question) 10 12 Q.. Answer any 5 out of 6. ( marks question) 15 18 Q. 4. Answer any 1 out of 2. (5 marks question) 5 10 Total 80 100

Marking Scheme Types of Questions for Paper I and Paper II Q. 1 A Fill in the blanks, Find odd man out, Find co-relation, Match the pairs, State true or false, Name, Write unit or molecular formula Q. 1 B Multiple choice questions based on practicals. Q. 2 Give reasons, Draw / correct diagrams, Write note, Write balanced chemical equation, Laws, Definitions, Solve examples, Distinguish, Complete the table, Write characteristics, Write uses. Q. Give two examples and explain any one, Write law / definition and explain with example, Write merits-demerits, Explain. Q. 4 Prove, Explain working with appropriate diagram, Long question, Explain with given points principle, diagram, construction, working, use, Questions based on given paragraph About HOTS questions HOTS questions means Higher Order Thinking Skill questions. Approx. 20% questions are HOTS questions and are based on the syllabus. HOTS questions can be of 1 mark to 5 marks. In depth study of textbook helps in answering HOTS questions. Chapter wise weightage: No. Chapter Name Marks Marks with option 1 School of elements 4 5 2 The magic of chemical reactions 4 6 The acid base chemistry 4 5 4 The electric spark 5 7 5 All about electromagnetism 6 7 6 Wonders of light (Part I) 7 8 7 Wonders of light (Part II) 6 7 8 Understanding metals and non-metals 7 9 9 Amazing world of carbon compounds 5 7 10 Life s internal secrets 6 7 11 The regulators of life 6 7 12 The life cycle 6 7 1 Mapping our genes 6 8 14 Striving for better environment (Part I) 4 5 15 Striving for better environment (Part II) 4 5 4

S.S.C. Preliminary Examination 1 ALGEBRA Algebra Time: 2 Hours Total Marks: 40 Note: i. All questions are compulsory. ii. Use of calculator is not allowed. Q.1. Attempt any five of the following sub-questions: [5] i. If 12x + 1y = 29 and 1x + 12y = 21, then find x y. ii. Write D y for the following simultaneous equation: 5x 2y = 10 ; x y = 11 iii. Determine whether the given value of x is a root of given quadratic equation: 4x 2 9 = 0, x = 2 iv. From the total expenditure, expenditure on education is 20%. Write the measure of the central angle to show in pie diagram. v. Two coins are tossed. Write the sample space for the given experiment. vi. Write the following quadratic equation in standard form: x 6 x = 5 Q.2. Attempt any four of the following sub-questions: [8] i. Find the value of the following determinant: 6 4 2 5 2 ii. Write the first four terms of the A. P. where a = 10, d =. iii. Class Frequency 5 15 7 15 25 10 25 5 20 5 45 1 Find the mean of given data by Direct Method. iv. Find S 10, if a = 6 and d =. v. Form a quadratic equation whose roots are and 5 2. vi. A card is drawn from a pack of well shuffled 52 playing cards. Find the probability that the card drawn is a face card. Q.. Attempt any three of the following sub-questions: [9] i. Two digit numbers are formed from the digits 2,, 5, 7, 9 without repetition. Find the probability of getting a. odd number b. two digit number so formed is multiple of 7 ii. Solve the following quadratic equation by formula method: 5m 2 2m = 2. iii. An obtuse angle of a rhombus is greater than twice the acute angle by 60. Find the measure of each angle. iv. Find the three consecutive terms of an A.P. whose sum is and the product of their cubes is 512. 5

S.S.C. Question Paper v. The following table gives information about the monetary investment by some residents in a city. Mode of Investment Percentage of residents Shares 10 Mutual funds 20 Real Estate 5 Gold 0 Govt. Bonds 5 Draw a pie diagram to represent the data. Q.4. Attempt any two of the following sub-questions: [8] i. If you spin the spinner, find the probability that it will point at 8 a. odd number. 1 7 2 b. multiples of. 6 c. an even numbered white sector. 5 4 d. number less than 4. ii. The following table gives the result of certain examination for 180 students. a. Find value of x. b. Draw histogram iii. Marks 0 10 10 20 20 0 0 40 40 50 50 60 No. of students 10 x 25 2x 55 0 Below is the given frequency distribution of Daily wages (in `) of 10 workers. Daily wages (in `) 80 84 85 89 90 94 95 99 100 104 105 109 No. of workers 10 20 25 40 0 5 Find the median daily wages of workers. Q.5. Attempt any two of the following sub-questions: [10] i. A publisher printed a certain number of copies of a book. If he had printed 2000 copies more, each copy would have cost ` 5 less. If he had printed 1600 copies less, each copy would have cost him ` 10 more. Find the number of copies printed and the cost of each book. ii. If one root of the quadratic equation ax 2 + bx + c = 0 is the square of the other, show that b + a 2 c + ac 2 = abc. iii. A farmer borrows ` 1000 and agrees to repay with a total interest of ` 140 in 12 instalments, each instalment being less than the preceding instalment by ` 10. What should be his first and last instalment? 6

S.S.C. Model Answer Paper S.S.C. Preliminary Examination 1 ALGEBRA Model Answer Paper Q. 1. Attempt any five of the following sub-questions: i. Substituting equation 1 st from equation 2 nd, 1x + 12y = 21 12x + 1y = 29 () () () x y = 8 x y = 8 ii. D y = 5 10 11 iii. By putting x = 2 in L.H.S., we get L.H.S. = 4x 2 9 2 = 4 2 9 = 4 9 4 9 L.H.S. = 0 L.H.S. = R.H.S. x = 2 is the root of the given quadratic equation. iv. Central angle for expenditure on education = 20 60 100 = 72 v. When two coins are tossed, S = {HH, HT, TH, TT} vi. x 6 x = 5 Multiplying both sides by x, we get x 2 6 = 5x x 2 5x 6 = 0 Q. 2. Attempt any four of the following sub-questions: i. 6 4 2 5 2 = ( 6 2) (4 2 5 ) = 6 6 + 20 2 = 6 6 +20 6 = 6 (6 + 20) = 26 6 6 4 2 5 2 = 26 6 78

Algebra ii. Given, a = 10, d = t 1 = a = 10 t 2 = t 1 + d = 10 = 7 t = t 2 + d = 7 = 4 t 4 = t + d = 4 = 1 First four terms of A.P. are 10, 7, 4, 1. iii. Class Class mark (x i ) Frequency (f i ) f i x i 5 15 10 7 70 15 25 20 10 200 25 5 0 20 600 5 45 40 1 520 Total: f i = 50 f i x i = 190 Mean = x fx i i = f i 190 50 = 27.8 Mean = 27.8 iv. Given, a = 6,d = S n = n [2a + (n 1)d] 2 S 10 = 10 2 [2 6 + (10 1)] = 5 (12 + 27) = 5 (9) S 10 = 195 v. Let, = and = 5 2 then, + = + 5 2 = 1 2 and = 5 2 = 15 2 i.e., the required quadratic equation is x 2 ( + ) x + = 0 x 2 1 2 x + 15 2 = 0 i.e., 2x 2 + x 15 = 0.[Multiplying both sides by 2] vi. From a pack of 52 cards, a card is drawn n(s) = 52 Let A be the event that the card drawn is a face card. n(a) = 12 P(A) = P(A) n(a) 12 n(s) 52 1 = 1 79

S.S.C. Model Answer Paper Q.. Attempt any three of the following sub-questions: i. S = {2, 25, 27, 29, 2, 5, 7, 9, 52, 5, 57, 59, 72, 7, 75, 79, 92, 9, 95, 97} n(s) = 20 a. Let A be the event of getting odd number A = {2, 25, 27, 29, 5, 7, 9, 5, 57, 59, 7, 75, 79, 9, 95, 97} n(a) = 16 n(a) 16 P(A) = n(s) 20 P(A) = 4 5 b. Let B be the event that two digit number is a multiple of 7. B = {5} n(b) = 1 P(B) = n(b) 1 n(s) 20 P(B) = 1 20 80 ii. The given equation is 5m 2 2m = 2 i.e., 5m 2 2m 2 = 0 Comparing it with am 2 + bm + c = 0, we get a = 5, b = 2, c = 2 2 b b 4ac m = 2a 2 ( 2) ( 2) 45 ( 2) = 25 = 2 44 10 = 2 2 11 10 = m = 21 11 10 1± 11 5 iii. Let ABCD be a rhombus. Let m A = x and mb = y According to the given condition, y = 2x + 60 2x y = 60.(i) In rhombus, adjacent angles are supplementary x + y = 180.(ii) Adding equation (i) and (ii), 2x y = 60 x + y = 180 D C x = 120 x = 40 x y Substituting x = 40 in equation (ii), we get 40 + y = 180 A B y = 140 The measures of angle A, B, C and D are 40, 140, 40 and 140 respectively.

iv. Let the three consecutive terms of A.P. be a d, a, a + d According to the first condition, a d + a + a + d = Algebra a = 1.(i) According to the second condition, (a d) (a) (a + d) = 512 (a d) (a) (a + d) = 8. [Taking cube root on both sides] a (a 2 d 2 ) = 8 1 [(1) 2 d 2 ] = 8.[From (i)] 1 (1 d 2 ) = 8 1 + d 2 = 8 d 2 = 9 d = When d = and a = 1, the required terms are 4, 1, 2 When d = and a = 1, the required terms are 2, 1, 4 v. Mode of Investment Percentage of residents Measure of Central angle () Shares 10 Mutual funds 20 Real Estate 5 Gold 0 Govt. Bonds 5 10 60 = 6 100 20 60 = 72 100 5 60 = 126 100 0 60 = 108 100 5 60 = 18 100 Total: 100 60 [1½] The pie diagram representation is as follows: Mutual Funds 72 [1½] Real Estate 126 6 Shares 108 18 Govt. Bonds Gold 81

S.S.C. Model Answer Paper Q. 4. Attempt any two of the following sub-questions: i. Since, the pointer can point at any numbers from 1 to 8. n(s) = 8 a. Let A be the event that the spinner points at odd number. A = 1,, 5, 7 n(a) = 4 P(A) = n(a) n(s) = 4 1 8 2 P(A) = 1 2 b. Let B be the event that the spinner points at multiples of. B =, 6 n(b) = 2 P(B) = n(b) n(s) = 2 8 = 1 4 P(B) = 1 4 c. Let C be the event that the spinner points at even numbered white sector. C = n(c) = 0 P(C) = 0 d. Let D be the event that the spinner points at a number less than 4. D = 1, 2, n(d) = P(D) = n(d) n(s) = 8 P(D) = 8 ii. Total number of students = 180 10 + x + 25 + 2x + 55 + 0 = 180 x + 120 = 180 x = 60 x = 20 Marks No. of students 0 10 10 10 20 20 20 0 25 0 40 40 40 50 55 50 60 0 82

Algebra Y Scale: On X-axis: 1 cm = 10 marks On Y-axis: 1 cm = 5 students No. of students 60 55 50 45 40 5 0 25 20 15 10 5 X 0 Y 10 20 0 40 Marks 50 60 X [] iii. Original class Class boundaries Frequency Cum. frequency less than type 80 84 79.5 84.5 10 10 85 89 84.5 89.5 20 0 90 94 89.5 94.5 25 55 c.f. 95 99 L 94.5 99.5 40 f 95 100 104 99.5 104.5 0 125 105 109 104.5 109.5 5 10 Here, f i = N = 10 N 10 = 65 2 2 Cumulative frequency (less than type) which is just greater than (or equal) to 65 is 95. Median class is 94.5 99.5 8

S.S.C. Model Answer Paper Now, L = 94.5, c.f. = 55, h = 5, f = 40 N h Median = L + -c. f. 2 f 5 = 94.5 + 65 55 40 = 94.5 + 10 5 40 = 94.5 + 1.25 = 95.75 Median daily wages of workers is ` 95.75. Q. 5. Attempt any two of the following sub-questions: i. Let the publisher printed x copies and cost of each copy be ` y. amount invested by publisher = ` xy According to first condition, (x + 2000) (y 5) = xy xy 5x + 2000y 10000 = xy 5x + 2000y = 10000.(i) According to second condition, (x 1600) (y + 10) = xy xy + 10x 1600y 16000 = xy 10x 1600y = 16000.(ii) Multiplying equation (i) by 2 and then adding with equation (ii), we get 10x + 4000y = 20000 10x 1600y = 16000 2400y = 6000 y = 15 Substituting value of y in equation (ii), we get 10x 1600 15 = 16000 x = 4000 Number of copies printed are 4000 and cost of each book is ` 15. ii. Let and be the two roots of the quadratic equation ax 2 + bx + c = 0 According to the given conditon, = 2 Now, + = + 2 = b a Also, = c a b a. (i). 2 = c a = c a. (ii) Now, cubing equation (i), we get ( + 2 ) b = a () + ( 2 ) + ( 2 )( + 2 b ) = a.[(a + b) = a + b + ab(a + b)] 84

+ ( ) 2 + ( + 2 ) = b a Algebra 2 c a + c a + c b a a b a.[from (i) and (ii)] c a + 2 c bc b = 2 2 a a a Multiplying both sides by a,we get ca 2 + c 2 a bc(a) = b b + a 2 c + ac 2 = abc iii. The instalment are in A.P. Here, S 12 = 1000 + 140 = 1140 Also, n = 12, d = 10 Now, S n = n [2a + (n 1) d] 2 S 12 = 12 2 [2 a + (12 1) (10)] 1140 = 6 [2a 110] 190 = 2a 110 a = 150 First instalment is ` 150 Also, t n = a + (n 1) d t 12 = 150 + (12 1) ( 10) = 150 110 t 12 = 40 Last instalment is ` 40 85