Mathematics Preliminary Course FINAL EXAMINATION Friday, September 6. General Instructions

Similar documents
Preliminary Mathematics

Mathematics DAPTO HIGH SCHOOL HSC Preliminary Course FINAL EXAMINATION. General Instructions

Mathematics. Knox Grammar School 2012 Year 11 Yearly Examination. Student Number. Teacher s Name. General Instructions.

Mathematics 2013 YEAR 11 YEARLY EXAMINATIONS BAULKHAM HILLS HIGH SCHOOL

Year 12 into 13 Maths Bridging Tasks

TRIAL HIGHER SCHOOL CERTIFICATE EXAMINATION Three Hours (plus five minutes reading time) Total marks - 100

Maths A Level Summer Assignment & Transition Work

Mathematics. SCEGGS Darlinghurst. Centre Number. Student Number. Preliminary Course Semester 2 Examination

Preliminary Mathematics

IYGB. Special Paper U. Time: 3 hours 30 minutes. Created by T. Madas. Created by T. Madas

(b) g(x) = 4 + 6(x 3) (x 3) 2 (= x x 2 ) M1A1 Note: Accept any alternative form that is correct. Award M1A0 for a substitution of (x + 3).

Ohio s State Tests ITEM RELEASE SPRING 2017 INTEGRATED MATHEMATICS II

Time: 3 Hrs. M.M. 90

NATIONAL QUALIFICATIONS

( ) Trigonometric identities and equations, Mixed exercise 10

Edexcel GCSE Mathematics (Linear) A* Paper (not for the faint hearted) Higher Tier

AQA Level 2 Certificate in Further Mathematics. Worksheets - Teacher Booklet

Mathematics. Caringbah High School. Trial HSC Examination. Total Marks 100. General Instructions

Class-IX CBSE Latest Pattern Sample Paper {Mathematics}

SOLUTIONS SECTION A [1] = 27(27 15)(27 25)(27 14) = 27(12)(2)(13) = cm. = s(s a)(s b)(s c)

Part (1) Second : Trigonometry. Tan

2017 HSC Mathematics Marking Guidelines

Chapter 8B - Trigonometric Functions (the first part)

Markscheme May 2016 Mathematical studies Standard level Paper 2

G r a d e 1 1 P r e - C a l c u l u s M a t h e m a t i c s ( 3 0 S ) Final Practice Exam Answer Key

MATHEMATICS (Extension 1)

MANLY SELECTIVE CAMPUS

Further Mathematics Summer work booklet

REQUIRED MATHEMATICAL SKILLS FOR ENTERING CADETS

MATHEMATICS EXTENSION 2

G r a d e 1 1 P r e - C a l c u l u s M a t h e m a t i c s ( 3 0 S ) Final Practice Exam

CBSE QUESTION PAPER CLASS-X MATHS

1. The positive zero of y = x 2 + 2x 3/5 is, to the nearest tenth, equal to

Pearson Edexcel Level 3 Advanced Subsidiary GCE in Mathematics (8MA0) Pearson Edexcel Level 3 Advanced GCE in Mathematics (9MA0)

Public Assessment of the HKDSE Mathematics Examination

MIND ACTION SERIES. MATHEMATICS PRACTISE EXAMINATION (Original Paper set up by Mark Phillips) GRADE 12 PAPER 2 OCTOBER 2016 TIME: 3 HOURS MARKS: 150

0809ge. Geometry Regents Exam Based on the diagram below, which statement is true?

Teddington School Sixth Form

Markscheme May 2016 Mathematical studies Standard level Paper 1

Total marks 70. Section I. 10 marks. Section II. 60 marks

2016 Notes from the Marking Centre - Mathematics

JUST IN TIME MATERIAL GRADE 11 KZN DEPARTMENT OF EDUCATION CURRICULUM GRADES DIRECTORATE TERM

The Bridge to A level. Diagnosis Worked Solutions

Math Section 4.3 Unit Circle Trigonometry

Core A-level mathematics reproduced from the QCA s Subject criteria for Mathematics document

Pure Mathematics Year 1 (AS) Unit Test 1: Algebra and Functions

St. Anne s Diocesan College. Form 6 Core Mathematics: Paper II September Time: 3 hours Marks: 150

Review exercise 2. 1 The equation of the line is: = 5 a The gradient of l1 is 3. y y x x. So the gradient of l2 is. The equation of line l2 is: y =

Correct substitution. cos = (A1) For substituting correctly sin 55.8 A1

Mathematics Trigonometry: Unit Circle

MATHEMATICS 2017 HSC Course Assessment Task 4 (Trial Examination) Thursday, 3 August 2017

Special Mathematics Notes

Math 5 Trigonometry Final Exam Spring 2009

Practice Assessment Task SET 3

PROVINCIAL EXAMINATION MINISTRY OF EDUCATION MATHEMATICS 12 GENERAL INSTRUCTIONS

0606 ADDITIONAL MATHEMATICS

8. Quadrilaterals. If AC = 21 cm, BC = 29 cm and AB = 30 cm, find the perimeter of the quadrilateral ARPQ.

Summer Review for Students Entering AP Calculus AB

Since 1 revolution = 1 = = Since 1 revolution = 1 = =

b = 2, c = 3, we get x = 0.3 for the positive root. Ans. (D) x 2-2x - 8 < 0, or (x - 4)(x + 2) < 0, Therefore -2 < x < 4 Ans. (C)

Solutions to RSPL/1. Mathematics 10

CAMI Education linked to CAPS: Mathematics

Class X Mathematics Sample Question Paper Time allowed: 3 Hours Max. Marks: 80. Section-A

IB Math SL 1: Trig Practice Problems: MarkScheme Circular Functions and Trig - Practice Problems (to 07) MarkScheme

Q Scheme Marks AOs. Attempt to multiply out the denominator (for example, 3 terms correct but must be rational or 64 3 seen or implied).

Section I 10 marks (pages 2 5) Attempt Questions 1 10 Allow about 15 minutes for this section

MATHEMATICS. NORTH SYDNEY BOYS HIGH SCHOOL 2008 Trial HSC Examination STUDENT NUMBER:... QUESTION Total %

MATH II CCR MATH STANDARDS

AS and A-level Mathematics Teaching Guidance

Specialist Mathematics 2019 v1.2

Use this space for computations. 1 In trapezoid RSTV below with bases RS and VT, diagonals RT and SV intersect at Q.

1) SSS 2) SAS 3) ASA 4) AAS Never: SSA and AAA Triangles with no right angles.

Paper2Practice [303 marks]

CLASS IX : CHAPTER - 1 NUMBER SYSTEM

Functions and their Graphs

PURE MATHEMATICS AM 27

I pledge that I have neither given nor received help with this assessment.

Rearrange m ore complicated formulae where the subject may appear twice or as a power (A*) Rearrange a formula where the subject appears twice (A)

2012 HSC Notes from the Marking Centre Mathematics Extension 2

St. Anne s Diocesan College. Grade 12 Core Mathematics: Paper II September Time: 3 hours Marks: 150

ALGEBRA 2/TRIGONOMETRY


Trig Practice 08 and Specimen Papers

Integers, Fractions, Decimals and Percentages. Equations and Inequations

Milford Public Schools Curriculum. Department: Mathematics Course Name: Precalculus Level 1

1 / 23

Mathematics Extension 2

Mathematics 4306/2H (Specification A)

the coordinates of C (3) Find the size of the angle ACB. Give your answer in degrees to 2 decimal places. (4)

M15/5/MATME/SP2/ENG/TZ2/XX/M MARKSCHEME. May 2015 MATHEMATICS. Standard level. Paper pages

0114ge. Geometry Regents Exam 0114

NORTH SYDNEY BOYS. Mathematics. I Student Name: HIGH SCHOOL. Extension 1. o MrWeiss Year 11 Task 2

DEPARTMENT OF MATHEMATICS

Answers for NSSH exam paper 2 type of questions, based on the syllabus part 2 (includes 16)

Solutions to O Level Add Math paper

1. Peter cuts a square out of a rectangular piece of metal. accurately drawn. x + 2. x + 4. x + 2

Calculus first semester exam information and practice problems

CAMI Education linked to CAPS: Mathematics

MA40S Pre-calculus UNIT C Trigonometric Identities CLASS NOTES Analyze Trigonometric Identities Graphically and Verify them Algebraically

2001 Solutions Euclid Contest (Grade 12)

Transcription:

03 Preliminary Course FINAL EXAMINATION Friday, September 6 Mathematics General Instructions o Reading Time 5 minutes. o Working Time 3 hours. o Write using a black pen. o Approved calculators may be used. o All necessary working should be shown for every question. Outcomes to be Assessed: A student: Total marks (00) Section I 0 marks o Attempt Questions 0 o Answer on the multiple choice answer sheet provided o Allow approximately 5 minutes for this section Section II 90 marks o Attempt Questions 6 o Answer in the booklets provided o Begin each question in a new booklet o Allow approximately hours 45 minutes for this section Name: Student Number: Teacher:

P P3 P4 P5 provides reasoning to support conclusions which are appropriate to the context. performs routine arithmetic and algebraic manipulation involving surds, simple rational expressions and trigonometric identities. chooses and applies appropriate arithmetic, algebraic, graphical, trigonometric and geometric techniques. understands the concept of a function and the relationship between a function and its graph.

Section I 0 marks Attempt Questions -0 Allow about 5 minutes for this section Use the multiple choice answer sheet for your responses to Questions 0. What is the value of (A).4 (B).45 (C).46 (D).5 8.8 3.47.79 + 7.75 correct to two significant figures? Which of the following equations has solutions x= and x= 3? (A) (B) (C) (D) x x x x 5x 6= 0 + 5x 6= 0 x 6= 0 + x 6= 0 3 Which statement is incorrect? (A) The diagonals of a rhombus bisect each other (B) The diagonals of a rhombus are equal (C) The diagonals of a rhombus are perpendicular to each other (D) The diagonals of a rhombus bisect the vertex angles 4 x The function f( x) = is: x (A) an even function (B) an odd function (C) neither an even nor odd function (D) a zero function

5 Which graph does not represent a function? (A) (B) (C) (D)

6 Which of the following is a correct expression involving θ in triangle ABC? (A) (B) (C) (D) 5 = 6 + 0 + 6 0 cosθ 6 + 0 5 cosθ = 0 5 5 6 sin sin 5 3' θ = sinθ sin 5 3' = 6 5 7 What is the gradient of the line perpendicular to the line x+ y+ 3= 0? (A) (B) (C) (D) 8 The solution to t (A) 0< t < (B) t < 0 or t > (C) t > > t is: (D) t < or t > 0

9 What is the exact value of cos 40? (A) (B) (C) 3 (D) 3 0 Simplify cos(90 θ ) sin(90 θ) (A) (B) cotθ (C) (D) tanθ tanθ End of Section I

Section II 90 marks Attempt Questions -6 Allow about hours 45 minutes for this section Begin each question in a new booklet All necessary working should be shown All questions are of equal value Question (5 marks). Use a SEPARATE writing booklet. Marks (a) Solve 5x = x+ 0 (b) Factorise: (i) (ii) x 7x 4 + ( x ) 6 (c) The line 6x ky = passes through the point (3, ). Find the value of k. (d) Solve the following pair of simultaneous equations: 3 x+ y = 5x 4y = 4 (e) Find the value of x if 75 + 7 = x 3 Question continues on the next page

Question (continued) Marks (f) ABCD is a parallelogram. CB is produced to E so that CB = BE. 3 Prove AFD EFB

Question (5 marks). Use a SEPARATE writing booklet. Marks (a) Solve 3 5 = x 3 (b) Solve + 3x= x+ 3 (c) What are the values of a and b if 5 = a+ b? + 3 (d) Prove + sinθ tanθ + secθ = cosθ (e) BF is parallel to CG, BC = EC and ABE =. (i) Show that BEC = 68. (ii) Hence, or otherwise, show that CG bisects DCE.

Question 3 (5 marks). Use a SEPARATE writing booklet. Marks (a) In the diagram below the points A, B and C have coordinates (, ), ( 4, 3) and (, 3) respectively. (i) Calculate the exact length of interval BC (ii) Find the gradient of BC (iii) Hence, show that the equation of BC is y = x+ 5 (iv) Find, to the nearest degree, the acute angle between the x-axis and the line BC (v) Find the perpendicular distance between A and the line BC (vi) Find the coordinates of D, in the first quadrant, so that ABCD is a parallelogram (vii) Find the exact area of the parallelogram ABCD (b) The lengths of the sides of triangle ABC are a = 5. cm, b = 7.3 cm and c = 6.7 cm. (i) Explain why BAC is the smallest angle in the triangle. (ii) Calculate the size of the smallest angle in ABC. Give the answer correct to the nearest minute. (iii) Hence find the area of the triangle. Give the answer correct to the nearest square centimetre.

Question 4 (5 marks). Use a SEPARATE writing booklet. Marks (a) In the diagram, AOB and COD are straight lines. AC AB and AB BD. (i) Prove ACO BDO (ii) If CD is 35 cm, find the length of OD (b) A ship leaves port P and travels on a bearing of 04 a distance of 300 km to point Q. It then turns and travels on a bearing of 39 for 00 km to point R. (i) Show that PQR = 45. (ii) What is the distance from R to P? Answer correct to the nearest kilometre. (iii) Find the bearing of R from P? 3 Answer correct to the nearest degree. (c) (i) Show that cos x + 3sin x= sin x (ii) Hence, or otherwise, solve cos x 3sin x for 0 x 360 + =

Question 5 (5 marks). Use a SEPARATE writing booklet. Marks (a) The function y = f( x) is defined as follows: x for x f( x) = for < x< x + for x (i) Evaluate f( ) + f() (ii) Write an expression for f( a + ) (b) Make neat sketches of the following graphs on separate number planes. Mark clearly the essential features of each graph. (i) (ii) ( x 3) ( y 4) 5 y + + = = 4 x (iii) xy = (iv) y = x (c) Solve 7 3x < 3 and graph your solution on a number line. 3 (d) If 4 tanθ = and cosθ > 0, is the value of sinθ positive or negative? 5

Question 6 (5 marks). Use a SEPARATE writing booklet. Marks (a) In the diagram below AO BP CQ. Find the value of x (b) Graph the region represented by the inequalities: x y x + > 5 and 0 (c) Simplify 3 x x x x x x 4 5 4 + 4 + 4 3 (d) Find the domain of y =. 5 x (e) Find the equation of the line through the point of intersection of the lines 3 6x 5y = 3and 4x+ y = and also through the point (, ) (f) If the points ( a, 3), ( a, a ) and ( a 3, a+ ) are collinear, find the 3 value of a. End of Examination Paper

Section I Answer Sheet Student Number: 0 marks Attempt Questions -0 Allow about 5 minutes for this section Use this multiple choice answer sheet for questions 0. Select the alternative A, B, C or D that best answers the question. Fill in the response oval completely. Sample + 4 =? (A) (B) 6 (C) 8 (D) 9 A B C D If you think you have made a mistake, put a cross through the incorrect answer and fill in the new answer. A B C D If you change your mind and have crossed out what you consider to be the correct answer, then indicate this by writing the word correct and drawing an arrow as follows: correct A B C D Completely fill the response oval representing the most correct answer. A B C D A B C D 3 A B C D 4 A B C D 5 A B C D 6 A B C D 7 A B C D 8 A B C D 9 A B C D 0 A B C D

Solutions to Year Mathematics Preliminary Examination 03 Section I Multiple Choice Solutions 8.8 3.47.79 7.75.455....5 (sf) (D) 3 The diagonals of a rhombus are equal (B) ( x )( x3) 0 x x60 (D) x 4 f( x) x x f( x) ( x) ( ) x x f( x) (B) 5 For some x values there are two matching y values 6 5 6 sin sin 53 (C) (C) 7 x y 30 y x3 m m (C) 8 t t t t 0 tt ( ) 0 t 0ort (B) 9 cos 40 cos(8060 ) cos 60 (B) 0 cos(90 ) sin(90 ) sin cos tan (C)

Question (a) 5x x0 4x x 3 Marking Criteria Correct answer (b) (i) x 7x4 (x)( x4) Correct answer (b) (ii) x ( ) 6 ( x4)( x4) ( x)( x6) Correct solution Attempt at difference of two squares Correct expansion x 4x (c) Sub. (3, ) into 6xky : 6(3) k() k 6 k 8 Correct solution Correct substitution of (3, ) Correct answer without justification (d) x y...() 5x4y 4...() () 5 : 5x5y 5...(3) (3) () : 9y 9 y In () : x x 3 Correct solution Correct elimination/substitution method with only one correct value for either x or y Correct attempt at either elimination or substitution method e) 75 7 5 33 3 8 3 643 9 x 9 3 Correct solution x = 9 Substantially correct solution Correct attempt at simplifying the surds

Question (continued) (f) Marking Criteria 3 Correct solution AD BC (equal opposite sides in parallelogram ABCD) CB BE (given) AD EB (both equal BC) AFD BFE (equal vertically opposite angles) DAF EBF (equal alternate angles, AD EC) AFD EFB (SAA) Communication: d) clear setting out and labelling of equations mark f) articulate reasoning, clear argument mark Two correct statements, Correct proof but not fully One correct statement, Correct proof without any justification

Question (a) 3 5 x 3 7 x 7x 46 7x 0 0 x 7 (b) 3x x 3x x or 3xx x 4x3 3 x x 4 Solutions are valid if: 3x 0 i.e. x 3 x is only valid solution Check solutions by substitution into equation (c) 5 55 4 9 7 97 a9andb7 (d) sin tan sec cos LHS tan sec sin cos cos sin cos RHS starting from RHS show it equals LHS Marking Criteria 3 Correct solution Substantially correct solution Correct attempt at solution 3 Correct solution One mistake in the solution Correct attempt at solution 3 Correct solution One mistake in working towards the answer Correctly attempting to rationalise the denominator Correct solution with correct setting out Correct attempt at proof by rewriting expression in terms of sin and/or cos equivalent

Question (continued) (e) (i) Marking Criteria Correct proof CBE 68 (supplement of ABE) CBE BEC 68 (angles opposite equal sides in isosceles CBE) One correct statement, Correct proof, not fully (ii) CBE DCG 68 (equal corresponding angles, BF CG) BEC ECG 68 (equal alternate angles, BF CG) CG bisects DCE ( ECG GCD) Communication: (e) clear, concise and correct setting out of proofs 4 marks Correct proof One correct statement, Correct proof, not fully

Question 3 (a) (i) Marking Criteria Correct answer BC 3 6 45 3 5 units Correct length as an unsimplified surd (ii) 6 m 3 (iii) y3( x) y3x y x5 Correct answer Correct solution (iv) tan tan () 63.434... 63 (nearest deg) Correct solution Correct statement tan (v) axbyc d a b () ( ) 5 9 units 5 Correct solution Correct substitution into correct formula (vi) B A: Right 5, up C D : Right 5, up ( CD BA, CD BA) Correct answer D ( 5,3) (4, 4) One correct coordinate

Question 3 (continued) (vii) A bh 9 3 5 5 7 units Marking Criteria Correct answer (b) (i) BAC is opposite the shortest side Correct reason (ii) 7.3 6.7 5. cos BAC 7.36.7 0.775... BAC cos (0.775...) 43035.9 43 (nearest min) (iii) A bcsin A 7.3 6.7sin 43 0 35 6.785... 7 cm (nearest cm ) Correct solution rounded correctly Correct substitution into cosine rule Substantially correct solution Correct solution A 7.3 6.7sin 43 ' 6.787... 7 cm (nearest cm ) Communication: a) v) showing substitution mark vi) explaining how coordinates are found mark b) ii) showing unrounded answer in degrees/minutes/seconds before rounding mark

Question 4 (a) (i) Marking Criteria Correct solution AB 90 (given) AOC BOD (equal vertically opposite angles) ACO BDO (equiangular) One correct statement, Correct proof, not fully (ii) AC CO BD DO 5 (corresponding sides in similar triangles are in same ratio) 5 OD 35 7 5 cm Correct solution, Correct solution, not fully Correct first statement with reason (b) (i) Correct proof PQT 76 (supplementary cointerior angles on parallel lines) TQR (angles at point add to 360 ) PQR 45 ( TQR PQT ) (ii) RP 300 00 300 00 cos 45 4547.8... RP 4547.8....47... km (nearest km) Correctly finding PQT or TQR, Correct proof, not fully Correct solution Correct substitution in cosine rule

Question 4 (continued) (iii) sin QPR sin 45 00 RP 00sin 45 sin QPR RP 0.665... QPR 4.76... Bearing of Rfrom P 044 47 Marking Criteria 3 Correct solution Correct value of QPR Correct substitution into sine rule (c) (i) cos x 3sin xsin x LHS cos x 3sin ( sin x) 3sin sin x 3sin sin x RHS x x x Correct proof Correct attempt at proof (ii) cos x 3sin x sin x sin x x 90, 70 Correct solution One correct value for x Communication: (a)(i) mark for copying diagram mark for stating vertices in corresponding order mark for sufficient proof i.e. equiangular when two pairs of corresponding angles are equal (ii) mark for correct reason why corresponding pairs of sides are in same ratio mark for correct units for OD (b)(i) marks for each of correct geometric reasons to show angle PQR = 45 o (ii) mark for correct rounding (iii) mark for correct rounding

Question 5 (a) f( ) f() (i) ( ) () Marking Criteria Correct solution Correct attempt at solution (ii) f( a ) a a Correct answer (b) (i) Correct graph showing all essential features Correct graph without all essential features shown (ii) Correct graph showing all essential features Correct graph without all essential features shown

Question 5 (continued) (iii) Marking Criteria Correct graph showing all essential features, including asymptotes Correct graph without all essential features shown (iv) Correct graph showing all essential features, including asymptotes Correct graph without all essential features shown (c) 73x 3 73x3or73x3 3x4 3x0 4 0 x x 3 3 4 0 x 3 3 3 Correct solution and number line graph Correct solution Correct attempt at solution and correct number line graphfrom their working (d) tan is negative in nd and 4th quadrants cos is positive in st and 4th quadrants lies in 4th quadrant where sin is negative Correct attempt at solution Correct number line graph from incorrect solution Correct answer Communication: (a) Showing clear and correct substitution for (i) and (ii) 3 marks (d) Clear setting out of reason for sin being negative mark

Question 6 (a) Marking Criteria Correct proof with full and correct reason x 3 (intercepts on transversals are cut 3 4 in same ratio by a family of parallel lines) 9 x cm 4 Correct first statement, Correct proof, not fully (b) Correct region One correct region (c) 3 x x 4x5 x 4x 4x4 ( x)( x x) ( x5)( x) ( x)( x) 4( x x) x 5 4 3 Correct solution Substantially correct solution Correct attempt at factorisation

Question 6 (continued) (d) y, x5 5 x Domain: 5x 0 x 5 (e) 6x5y3 k(4x y) 0 Sub. (,) : 5 3 k(8 ) 0 40k 0 4 k 0 k 5 6x5y3 (4x y) 0 5 30x5y5 4x y 0 6x6y6 0 x y0 Marking Guidelines Correct answer Correct attempt at finding domain by stating x 5 or x 5 3 Correct solution Correct value of k Correct point of intersection and attempt to find equation of required line Correct form of equation shown by first line and attempt to substitute (, ) Correct attempt to solve equations simultaneously (f) ( a) 3 ( a) 3 ( a) a ( a3) a a5 a 3a 3a3 (3a3)( a5) (3a)( a) 3a 8a53a 7a a 3 3 a 3 Correct solution Substantially correct solution Correct attempt at solution shown by first line of working Communication: Question 6 (4 marks) (b) The graph is drawn neatly with template. Intercepts shown and graph labelled. Mark (d) Clear setting out. For example stating limitations such as x 5. Mark (e) Clear and logical setting out of solution (example: mention of substitution). Mark (f) Clear explanation that equal gradients will prove the points are collinear. Mark