UNIT-1 SOLID STATE. Ans. Gallium (Ga) is a silvery white metal, liquid at room temp. It expands by 3.1% on solidifica-tion.

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UNIT-1 SOLID STATE 1 MARK QUESTIONS Q. 1. Name a liquefied metal which expands on solidification. Ans. Gallium (Ga) is a silvery white metal, liquid at room temp. It expands by 3.1% on solidifica-tion. Q. 2. How many number of molecules per unit cell which crystallizes in the form of end face centred (monoclinic) lattice with a molecule at each lattice. Ans. 2. Q. 3. What is the coordination number of carbon, in diamond? Ans. 4 and its unit cell has 8 atoms. [The space lattice of diamond is FCC] Q. 4. Name the solid which has weakest intermolecular force? Ans. Ice Q. 5. Arrange the following types of interactions in correct order of their increasing strength : Covalent, hydrogen bonding, Vander Waals, dipole dipole Ans. Vander Waals < dipole dipole < hydrogen bonding < covalent. Q. 6. Give reason for the appearance of colour in alkali metal halides. Ans. Due to F-centres. Q. 7. Which type of defect occur in Ag Br? 1

Ans. Schottky defect and Frekel defect. Q. 8. Give one example of doping which produces p-type of semi-conductors. Ans. Ge doped with Al. Q. 9. Out of (a) Graphite and Carborundum which one is harder? Ans. Carborundum. Q. 10. How can a material be made amorphous? Ans. By melting the material and by cooling it rapidly. 2 MARKS QUESTIONS Q. 1. Give Reason : The energy required to vaporize one mol of copper is smaller than that of energy required to vaporize 1 mol of diamond. Ans. Copper is a metallic solid having metallic bonds while diamond is a covalent solid having covalent bonds. Metallic bonds are weaker than covalent bonds and thus less amount of energy is required to break metallic bonds than covalent bonds. Q. 2. The unit cube length for LiCl (NaCl) is 5.14 A. Assuming anion-anion contact. Calculate the ionic radius for Chloride ion. Ans. Interionic distance of LiCl = 5.14 / 2 = 2.57 A AC = 2 2 AB BC 2

= = 3.63 2 2 2.57 2.57 therefore, radius of Cl = ½ 3.63 = 1.81 A Q. 3. Give reasons : (a) Diamond and rhombic Sulphur are covalent solids, but the latter has lower melting points. Ans. (a) Among NaCl and CsCl, CsCl is quite stable. Due to weak Vander Waal s Force in Sulphur molecule. CsCl coordination number is 8. It is surrounded by 8 anion tightly. Q. 4. How many unit cells are present in a cube shaped ideal crystal of NaCl of mass 1 gm? Ans. Mass of 1 unit cell = volume density = a³ d = 3 a M Z Na 0 3 58.5 4 = 23 6.023 10 No. of unit cells in 1 gm = 1/M = 6.023 10 23 / 58.5 4 = 2.57 10 21 Q. 5. In the mineral spinal; having the formula MgAl 2 O 4. The oxide ions are arranged in CCP, Mg 2+ ions occupy the tetrahedral voids. While Al 3+ ions occupy the octahedral voids. (i) What percentage of tetrahedral voids is occupied by Mg 2+ ions? 3

(ii) What percentage of octahedral voids is occupied by Al 3+ ions? Ans. According to the formula, MgAl 2 O 4. If there are 4 oxide ions, there will be 1 Mg 2+ ions and 2 Al 3+. But if the 4 O 2 ions are ccp in arrangement, there will be 4 octahedral and 8 tetrahedral voids. (i) Percentage of tetrahedral voids occupied by Mg 2+ = (1 / 8) 100 = 12.5% (ii) Percentage of octahedral voids occupied by Al 3+ = (2 / 4) 100 = 50% Q. 6. Give reasons : (a) Window glass of old building look milky. b) Window glass of old building is thick at bottom. (c) Ans. (a) (c) CaCl 2 will introduce Schottky defect if added to AgCl crystal. Due to annealing over a number of years glass acquires some crystalline character. Glass is not a true solid. But a super-cooled liquid of high viscosity. It has the property to flow. 2 Ag + will be replaced by 1 Ca 2+ ions to maintain electrical neutrality. Thus a hole is created and lattice site for every Ca 2+ ion introduced. Q. 7. Analysis shows that nickel oxide has the formula NiO.98 O 1.00. What fractions of nickel exist as Ni 2+ and Ni 3+ ions? Ans. NiO.98 O 1.00 Let Ni 2+ be x and Ni 3+ be 0.98 x Total charge on compd. is equal to zero. [2 (Ni 2+ ) + 3 (Ni 3+ ) 2 (O 2 )] = 0 4

2 x + 3 (0.98 x) 2 = 0 x = 0.94 Therefore Ni 2+ % = 0.94 0.98 Ni 3+ = 4% 100 = 96% Q. 8. What type of defect can arise when a solid is heated? Which physical property is affected by this and in what way? Ans. When a solid is heated vacancy defect arises. This is because on heating some atoms or ions leacve the lattice site completely some lattice sites are vacant. As a result of this defect the density of the substance decreases, because some atoms leave the structure completely. Q. 9. (a) What happens when a Ferromagnetic or Ferrimagnetic solid is heated? Ans. (a) The ions of MgO and NaF all have the same number of electrons and intermolecular distance are about the same (235 & 215 pm). Why are the melting points are so different (2642 C & 992 C? It changes into paramagnetic at hight temperature due to randomization of spins. The ions in MgO carry two unit charges. In NaCl only one unit charge. Hence electrostatic forces of attraction in MgO are stronger. Q. 10. (a) If the radius of the Br ion is 0.182 nm, how large a cation can fit in each of the tetrahedral hole. AgI crystallizes in a cubic closed packed ZnS structure. What fraction of tetrahedral site is occupied by Ag ion? (c) At what temp. range, most of the metals becomes super conductors? Ans. (a) For a tetrahedron the limiting ratio is 0.225 0.414 For largest cation highest value 0.414 would be considered. 5

r + / r = 0.414 r + = 0.414 0.182 = 0.075 nm. In FCC there are 8 tetrahedral voids. Out of this ½ is occupied by Ag cation. (c) 2 k 5 k. 6