CHEMISTRY OF THE HUMAN BODY

Similar documents
CHEMISTRY OF THE HUMAN BODY

Problem Set 1

Full file at Chapter 2 Water: The Solvent for Biochemical Reactions

1) Which of the following represents the breaking of a noncovalent interaction? Topic: The Nature of Noncovalent Interactions

Chapter 2 Water: The Solvent for Biochemical Reactions

LS1a Midterm Exam 1 Review Session Problems

Water, water everywhere,; not a drop to drink. Consumption resulting from how environment inhabited Deforestation disrupts water cycle

BIOC 460 General Chemistry Review: Chemical Equilibrium, Ionization of H 2 O, ph, pk a

Biochemistry I Fall 2013 Exam 1 Dr. Stone 100 points Name Ka for acetic acid = 1.74 x 10-5

Sample Questions for the Chemistry of Life Topic Test

Acid-Base Balance. Lecture # 5 Second class/ 2015

Volume NaOH Delivered (ml)

1. What is an ångstrom unit, and why is it used to describe molecular structures?

Individual Exam. Individual. (Sample Questions) WUCT Team ID:

Water: The Solvent for Biochemical Reactions

LS1a Midterm Exam 1 Review Session Problems

BIOMEDICAL SCIENCE MIN WAN

Prof. Jason D. Kahn Your Signature: Exams written in pencil or erasable ink will not be re-graded under any circumstances.

LS1a Fall 2014 Problem Set #2 Due Monday 10/6 at 6 pm in the drop boxes on the Science Center 2 nd Floor

Lec.1 Chemistry Of Water

2. WATER : THE SOLVENT FOR BIOCHEMICAL REACTIONS

Chemistry 222. Start mol End mol

Prof. Jason Kahn Your Signature: Exams written in pencil or erasable ink will not be re-graded under any circumstances.

Sample Question Solutions for the Chemistry of Life Topic Test

16 years ago TODAY (9/11) at 8:46, the first tower was hit at 9:03, the second tower was hit. Lecture 2 (9/11/17)

Page 1 of Please choose the letter a as your answer for this question.

Extension 17: Haemoglobin, the transport of oxygen in the blood and ph buffers in the blood

Chapter 8 Lecture Notes: Acids, Bases, and ph

Affinity labels for studying enzyme active sites. Irreversible Enzyme Inhibition. Inhibition of serine protease with DFP

-log [H+][OH-] = - log [1 x ] Left hand side ( log H + ) + ( log OH - ) = ph + poh Right hand side = ( log 1) + ( log ) = 14 ph + poh = 14

Now, the excess strong base will react: HA + OH - A - + H 2 O Start mol End mol

Practice Midterm Exam 200 points total 75 minutes Multiple Choice (3 pts each 30 pts total) Mark your answers in the space to the left:

Individual Exam. Individual. (Sample Questions) WUCT Team ID:

Water, ph and pka. Lecture 2: Margaret A. Daugherty. Fall Water: What makes it so good for life? Solvent properties.

Chem 204. Mid-Term Exam I. July 21, There are 3 sections to this exam: Answer ALL questions

General Phenomena: Law of mass action, dissociation of water, ph, buffers

Biochemistry 3100 Sample Problems Binding proteins, Kinetics & Catalysis

Part I. Multiple choice. Circle the correct answer for each problem. 3 points each

S H/T 0 ph = log([h + ]) E = mc 2 S = klnw G = H T S ph = pk a + log([a ]/[HA]) K a = [H + ][A ]/[HA] G = RTlnK eq e iπ + 1 = 0

12U Biochemistry Unit Test

Kinetics & Equilibrium

Chapter 1 1) Biological Molecules a) Only a small subset of the known elements are found in living systems i) Most abundant- C, N, O, and H ii) Less

2: CHEMICAL COMPOSITION OF THE BODY

Ionization of acids and bases

Chapter 10: Hemoglobin

R = J/mole K = cal/mole K = N A k B K a K b = K w

Part I. Multiple choice. Circle the correct answer for each problem. 3 points each

Model Worksheet Teacher Key

Multiple choice: 10 questions, worth 2 points each. Circle all of the correct answers. Some questions many have more than one correct answer.

Water. Water participates in H-bonding with biomolecules.

Chemistry 100 Final Exam April 21, 2012

Chapter 8 Educational Goals

CHAPTER 29 HW: AMINO ACIDS + PROTEINS

I. Acids & Bases. A. General ideas:

Chemical and Physical Properties of Organic Molecules

4) Chapter 1 includes heredity (i.e. DNA and genes) as well as evolution. Discuss the connection between heredity and evolution?

Topic 1: The Chemical Context of Life, Holtzclaw and Holtzclaw, 2014

Objective: Students will be able identify peptide bonds in proteins and describe the overall reaction between amino acids that create peptide bonds.

Important - Please read this before you turn the page.

Principles Of Acid-Base Balance

Unit 1: Chemistry of Life Guided Reading Questions (80 pts total)

Final Chem 4511/6501 Spring 2011 May 5, 2011 b Name

2014 AP Biology Summer Homework Assignment

AP Chemistry Chapter 14 Review Packet Multiple Choice Questions: 2. What is the equilibrium constant for the following reaction?

2: CHEMICAL COMPOSITION OF THE BODY

ph and buffers Dr. Mamoun Ahram Summer, 2018

Big Idea 6 Equilibrium

Placement Exam for Exemption from Chemistry 120 Fall 2006

From Amino Acids to Proteins - in 4 Easy Steps

[base] [acid] ph = pka + log

CHEM 109A Organic Chemistry

Chemistry 14C Spring 2018 Final Exam Part A Page 1

MODULE 2: BIOLOGICAL MOLECULES

Biology Midterm Review

When a person is stressed, their body will work in some way to alleviate the imposed stress.

+3 for pka = 14 pkb = 9.25 [+1 for the idea that pka and pkb are related.]

Chem 150, Spring Unit 4 - Acids & Bases. Introduction

BA, BSc, and MSc Degree Examinations

2. In regards to the fluid mosaic model, which of the following is TRUE?

Chemistry 25 (Spring term 2016) Final Examination for NON-SENIORS GOOD LUCK AND HAVE A GREAT SUMMER!!!

Aqueous Equilibria, Part 1 AP Chemistry Lecture Outline

Key Terms (1 point each). Fill in the blank with the proper term. Each term may be used only once.

EXAM 1 Fall 2009 BCHS3304, SECTION # 21734, GENERAL BIOCHEMISTRY I Dr. Glen B Legge

BI/CH421 Biochemistry I Exam 1 09/29/2014

A) at equilibrium B) endergonic C) endothermic D) exergonic E) exothermic.

What binds to Hb in addition to O 2?

Lecture Presentation. Chapter 16. Aqueous Ionic Equilibrium. Sherril Soman Grand Valley State University Pearson Education, Inc.

Basic Chemistry. Chemistry Review. Bio 250: Anatomy & Physiology

Denaturation and renaturation of proteins

Chemistry 105 ~ Skills Summary for Laboratory Final Exam

General Chemistry and Energetics Your Section #: Exam I (100 points total) October 6, 2010

Solubility Equilibria

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Figure 2.1

ACIDS AND BASES. Note: For most of the acid-base reactions, we will be using the Bronsted-Lowry definitions.

Chapter 1. Topic: Overview of basic principles

The following question(s) were incorrectly answered.

BCH 4053 Spring 2001 Chapter 2 Lecture Notes

Midterm Exam III. CHEM 181: Introduction to Chemical Principles November 25, 2014 Answer Key

ORGANIC - BROWN 8E CH AMINO ACIDS AND PROTEINS.

K w. Acids and bases 8/24/2009. Acids and Bases 9 / 03 / Ionization of water. Proton Jumping Large proton and hydroxide mobility

Transcription:

CHEMISTRY OF THE HUMAN BODY (Sample Questions) WUCT 2018 The three questions below are meant to give a sense of the kinds of questions that might be asked on the exam in April 2018. The actual exam is 60 minutes long, and it may differ in topic areas covered and difficulty. Necessary constants, equations, and conversions may be found on the last page of this document. Unless otherwise stated, explanations must be written in complete sentences, diagrams must be labeled, and units must be shown in calculations to receive full credit. Please answer the questions in the space provided. No work on the back of the sheets or attached sheets will be graded. The amount of points each question is worth will be indicated on the actual exam. Note that not all lone pairs are necessarily shown on every chemical structure. Team Members: 1. 2. High School: Page 1 of 9

1. This question concerns a tetrameric (consisting of four subunits) protein, hemoglobin (abbreviated as Hb), that binds O 2(g) a nd CO 2(g) in our body. Each subunit of the hemoglobin protein contains a single heme B group (shown below). We will examine various properties of gases, and of the hemoglobin protein itself. Note that there is a ferrous iron (Fe 2 + ) at the center of each of the heme B group. a. What is the oxidation state of free, molecular oxygen (not shown)? b. What is the ground-state electron configuration of Fe(II)? Noble gas abbreviations may not be used. Page 2 of 9

c. The equilibrium of dissociation with equilibrium constant K d of oxygenated Hb, Hb(O 2 ) 4(&'), is given by the following chemical equation: Hb O ( ) &' Hb &' + 4O (. Where the equilibrium constant K d is: K 0 = po ( ) [Hb] [Hb(O ( ) ) ] i. While exercising, oxygen is consumed via a process called aerobic respiration. Assuming that equilibrium is established, and that the person is at rest, explain how the equilibrium would shift after the person runs ten miles. ii. Carbon monoxide gas (CO (g) ) exposure can lead to CO poisoning in humans, which can result in hypoxia and/or death. Draw Lewis structures below for both CO (g) and O 2 (g). Circle the Lewis structure of the molecule that you predict to have a stronger affinity for the Fe 2+ of the heme B group shown on the first page. Page 3 of 9

iii. Given the following reactions and dissociation constants: Hb(CO) 4(&') Hb (&') + 4 CO (.) with K :'1 = 10 ;4.5 Hb(O 2 ) 4(&') Hb (&') + 4 O 2(.) with K :'2 = 10 ;2 Calculate the K eq. of the reaction: Hb(CO) 4(&') + 4O 2(.) Hb(O 2 ) 4(&') +4 CO (.) Page 4 of 9

2. Proteins serve many essential roles in the body including cell signaling, cell structure, and cellular transport. This question will explore some ways in which proteins interact with themselves and others in order to perform their respective functions. a. This question part will concern the intermolecular forces that are involved in some protein structures. One of the common structural aspect of proteins is the βsheet. Shown below are protein strand 1 and protein strand 2, which are part of a β- sheet. This diagram will be referenced parts i and ii of this question. i. Name the dominant intermolecular interaction that occurs between Strand 1 and Strand 2. ii. On the figure above, draw straight, dashed lines (- - - - -) between the pairs of atoms participating in each interaction you indicated in part i. Page 5 of 9

b. While most amino acids interact through intermolecular forces, cysteine (shown below) is unique in that is can form a covalent bond with another cysteine. This disulfide bond is essential in many protein structures. For the purposes of this question, consider the R group (circled below) of cysteine to be polar. i. Is the reaction below to form a disulfide bond a reduction or oxidation? Justify your reasoning. Page 6 of 9

c. Consider peptide strand N which is the normal structure of this protein, and strand M which is a mutant because the two outermost circled groups have been changed. The full structures are shown below. i. Strand N is typically found within the interior of the cellular membrane, in between the lipid bilayer, where there is no water. Why might it be more favorable for strand M to be in the aqueous environment of the cytoplasm? Complete answers will analyze the circled groups of each strand. Page 7 of 9

ii. Suppose strand M is able to flex and fold about its bonds. Propose a model for how this peptide might bond in order to minimize the hydrophilic interactions so that it is more favorable to remain in a hydrophobic environment. Models may be a diagram (not all atoms need to be included) or written description, and they should include relevant interactions and bonds. iii. Consider the orientations of the middle two circled groups, -CH(CH 3 ) 2. How will these two groups be oriented so that the bonding interaction in part 2cii (previous question part) will occur? Diagrams and/or written explanations may be used. Page 8 of 9

3. The body must be able to maintain a wide range of ph values in various areas of the body. For example, the ph of blood is 7.35, the ph of the stomach ranges from 1.5 to 3.5. a. Many body systems use buffer systems to maintain their optimal ph. Using the equation of a weak acid dissociation show below, derive the Henderson- Hasselbalch equation as it is shown below. Include all intermediate steps. HA H? + A ; ph = pk & + log [A; ] [HA] b. The Phosphate Buffer system plays an important role in buffering renal tubular fluid and other intracellular fluids to additions of strong acids and bases. At physiological ph, the predominant species of this system are H 2 PO 4 - and its conjugate base, HPO 4 2-. The other species of this polyprotic system, such as H 3 PO 4 and PO 4 3-, can be ignored. If a solution consists of 35.3 mm HPO 4 2- and 2.3mM H 2 PO 4 -, what is the ph? (Hint: The pka of H 2 PO 4 - is 7.21). END OF EXAM Page 9 of 9