Magnetically Coupled Coil

Similar documents
8 THREE PHASE A.C. CIRCUITS

Electronic Circuits I Revision after midterm

POLYPHASE CIRCUITS. Introduction:

ELE B7 Power System Engineering. Unbalanced Fault Analysis

Polyphase Systems. Objectives 23.1 INTRODUCTION

ELE B7 Power Systems Engineering. Power System Components Modeling

I1 = I2 I1 = I2 + I3 I1 + I2 = I3 + I4 I 3

Power System Representation and Equations. A one-line diagram of a simple power system

Polyphase Systems 22.1 INTRODUCTION

332:221 Principles of Electrical Engineering I Fall Hourly Exam 2 November 6, 2006

I 3 2 = I I 4 = 2A

Exam 2 Solutions ECE 221 Electric Circuits

Lecture 7 notes Nodal Analysis

EE 330/330L Energy Systems (Spring 2012) Laboratory 1 Three-Phase Loads

a) Read over steps (1)- (4) below and sketch the path of the cycle on a P V plot on the graph below. Label all appropriate points.

Dorf, R.C., Wan, Z. T- Equivalent Networks The Electrical Engineering Handbook Ed. Richard C. Dorf Boca Raton: CRC Press LLC, 2000

#6A&B Magnetic Field Mapping

DIRECT CURRENT CIRCUITS

Math 32B Discussion Session Week 8 Notes February 28 and March 2, f(b) f(a) = f (t)dt (1)

196 Circuit Analysis with PSpice: A Simplified Approach

4. UNBALANCED 3 FAULTS

Lec 3: Power System Components

IEEE PES Boston Chapter. Protection Engineering Course Series. Instructor: Dean V. Sorensen (National Grid)

Tutorial Worksheet. 1. Find all solutions to the linear system by following the given steps. x + 2y + 3z = 2 2x + 3y + z = 4.

Chapter 4: Techniques of Circuit Analysis. Chapter 4: Techniques of Circuit Analysis

Review of Calculus, cont d

Symmetrical Components 1

T b a(f) [f ] +. P b a(f) = Conclude that if f is in AC then it is the difference of two monotone absolutely continuous functions.

Fundamentals of Electrical Circuits - Chapter 3

Overview. Before beginning this module, you should be able to: After completing this module, you should be able to:

Appendix C Partial discharges. 1. Relationship Between Measured and Actual Discharge Quantities

Chapter 8 Three-Phase Power System and Three-Phase Transformers

Physics 202, Lecture 10. Basic Circuit Components

Green s Theorem. (2x e y ) da. (2x e y ) dx dy. x 2 xe y. (1 e y ) dy. y=1. = y e y. y=0. = 2 e

18.06 Problem Set 4 Due Wednesday, Oct. 11, 2006 at 4:00 p.m. in 2-106

NEW CIRCUITS OF HIGH-VOLTAGE PULSE GENERATORS WITH INDUCTIVE-CAPACITIVE ENERGY STORAGE

Scientific notation is a way of expressing really big numbers or really small numbers.

CE 160 Lab 2 Notes: Shear and Moment Diagrams for Beams

Designing Information Devices and Systems I Spring 2018 Homework 7

Designing Information Devices and Systems I Fall 2016 Babak Ayazifar, Vladimir Stojanovic Homework 6. This homework is due October 11, 2016, at Noon.

y z A left-handed system can be rotated to look like the following. z

1/16/2013. Overview. 05-Three Phase Analysis Text: Three Phase. Three-Phase Voltages. Benefits of Three-Phase Systems.

Designing Information Devices and Systems I Discussion 8B

16z z q. q( B) Max{2 z z z z B} r z r z r z r z B. John Riley 19 October Econ 401A: Microeconomic Theory. Homework 2 Answers

Summary of equations chapters 7. To make current flow you have to push on the charges. For most materials:

In the diagram below, the rotation continues until N-S alignment, resulting in lock-up that is, if nothing is done to prevent it.

Designing Information Devices and Systems I Anant Sahai, Ali Niknejad. This homework is due October 19, 2015, at Noon.

CHM Physical Chemistry I Chapter 1 - Supplementary Material

MATH34032: Green s Functions, Integral Equations and the Calculus of Variations 1. 1 [(y ) 2 + yy + y 2 ] dx,

INTEGRATION. 1 Integrals of Complex Valued functions of a REAL variable

QUADRATIC EQUATION. Contents

April 8, 2017 Math 9. Geometry. Solving vector problems. Problem. Prove that if vectors and satisfy, then.

Chapter E - Problems

EMF Notes 9; Electromagnetic Induction ELECTROMAGNETIC INDUCTION

AP CALCULUS Test #6: Unit #6 Basic Integration and Applications

Project 6: Minigoals Towards Simplifying and Rewriting Expressions

Potential Changes Around a Circuit. You must be able to calculate potential changes around a closed loop.

Part 4. Integration (with Proofs)

Lecture Summaries for Multivariable Integral Calculus M52B

Can one hear the shape of a drum?

1.3 SCALARS AND VECTORS

Introduction to Olympiad Inequalities

(a) A partition P of [a, b] is a finite subset of [a, b] containing a and b. If Q is another partition and P Q, then Q is a refinement of P.

Thermodynamics. Question 1. Question 2. Question 3 3/10/2010. Practice Questions PV TR PV T R

Duality # Second iteration for HW problem. Recall our LP example problem we have been working on, in equality form, is given below.

Journal of Chemical and Pharmaceutical Research, 2013, 5(12): Research Article

SECTION A STUDENT MATERIAL. Part 1. What and Why.?

Polynomials. Polynomials. Curriculum Ready ACMNA:

10/25/2005 Section 5_2 Conductors empty.doc 1/ Conductors. We have been studying the electrostatics of freespace (i.e., a vacuum).

Solutions to Assignment 1

Core 2 Logarithms and exponentials. Section 1: Introduction to logarithms

Electromagnetism Notes, NYU Spring 2018

SECOND HARMONIC GENERATION OF Bi 4 Ti 3 O 12 FILMS

MA10207B: ANALYSIS SECOND SEMESTER OUTLINE NOTES

Module B3 3.1 Sinusoidal steady-state analysis (single-phase), a review 3.2 Three-phase analysis. Kirtley

Educational Modeling for Fault Analysis of Power Systems with STATCOM Controllers using Simulink

1 PYTHAGORAS THEOREM 1. Given a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Intermediate Math Circles Wednesday 17 October 2012 Geometry II: Side Lengths

Tests for the Ratio of Two Poisson Rates

Lecture 1 - Introduction and Basic Facts about PDEs

Electrical Circuits II (ECE233b)

How do we solve these things, especially when they get complicated? How do we know when a system has a solution, and when is it unique?

New Expansion and Infinite Series

Applications of Bernoulli s theorem. Lecture - 7

Comparing the Pre-image and Image of a Dilation

I do slope intercept form With my shades on Martin-Gay, Developmental Mathematics

LESSON 11: TRANSFORMER NAME PLATE DATA AND CONNECTIONS

4 7x =250; 5 3x =500; Read section 3.3, 3.4 Announcements: Bell Ringer: Use your calculator to solve

Electromagnetic-Power-based Modal Classification, Modal Expansion, and Modal Decomposition for Perfect Electric Conductors

(h+ ) = 0, (3.1) s = s 0, (3.2)

ECE Microwave Engineering. Fall Prof. David R. Jackson Dept. of ECE. Notes 7. Waveguides Part 4: Rectangular and Circular Waveguide

Jackson 2.26 Homework Problem Solution Dr. Christopher S. Baird University of Massachusetts Lowell

f (x)dx = f(b) f(a). a b f (x)dx is the limit of sums

Formula for Trapezoid estimate using Left and Right estimates: Trap( n) If the graph of f is decreasing on [a, b], then f ( x ) dx

The Riemann-Stieltjes Integral

SINUSOIDAL STEADY-STATE ANALYSIS

Generalization of 2-Corner Frequency Source Models Used in SMSIM

Resistive Network Analysis

State space systems analysis (continued) Stability. A. Definitions A system is said to be Asymptotically Stable (AS) when it satisfies

Industrial Electrical Engineering and Automation

Transcription:

Mgnetilly Coupled Ciruits Overview Mutul Indutne Energy in Coupled Coils Liner Trnsformers Idel Trnsformers Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 Mgnetilly Coupled Coil i v L φ Frdy s Lw: where v = N dφ φ = NPi v = N d(npi) = N 2 P di = L di v = voltge in volts (V) N = number of turns φ = mgneti flux in webers (Wb) t = time in seonds (s) P = permene of the flux spe i = urrent in mperes (A) L = indutne in henrys (H) Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 3 Introdution to Mgnetilly Coupled Ciruits φ2 φ2 v φ φ22 Mgnetilly oupled oils re oneptully similr to two indutors tht hve shred (oupled) mgneti field Not ll of the mgneti field is shred Mgneti oupling is widely used in power systems Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 2 Mgnetilly Coupled Coil i v L φ v = N dφ =(N 2 P) di = L di The flux (& urrent) hve to hnge to indue voltge The reltionship between the flux nd the urrent is onstnt Consistent with wht we lredy know bout indutors L is proportionl to N 2 Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 4

Mutul Indutne φ2 φ φ = φ φ2 We n deompose the mgneti flux indued in one oil into two omponents φ is the totl flux produed in oil φ is the portion of this flux tht links only oil φ2 links both oil nd oil 2 The oils re not onneted eletrilly Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 5 Mutul Indutne Continued 2 φ2 φ v =L v2 = ± M2 M2 =N2NP2 M2: the mutul indutne of oil 2 with respet to oil Note tht v2 is the open iruit voltge Wht if urrent ws pplied to oil 2 s well? Superposition pplies Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 7 Mutul Indutne Continued φ2 φ dφ v =N dφ2 v2 = ± N2 = ± M2 d(npi) =N d(np2i) = ± N2 =L = ± (N2NP2) d Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 6 Mutul Indutne: Two Soures M v v = L ± M di2 2 v2 = ±M2 We will ssume M2 = M2 = M If ssumption holds, the oils re lled liner trnsformer M is lled the mutul indutne di2 Like indutors, is mesured in units of henrys (H) Polrity of oupling term depends on how the oils re wound Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 8

Liner Trnsformer: The Dot Convention φ2 φ2 v φ φ22 The dot onvention determines the polrity of the oupling Dot Convention: If urrent enters dotted terminl, it indues positive voltge t the dotted terminl of the seond oil If urrent leves dotted terminl, it indues negtive voltge t the dotted terminl of the seond oil Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 9 Exmple 2: The Dot Convention M M M M Write the defining equtions for eh of the iruits shown bove. Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 Exmple : The Dot Convention M M M M Write the defining equtions for eh of the iruits shown bove. Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 0 Mutul Indutne & Self Indutne L = N 2 P P = P P2 L2 = N 2 2 P2 P2 = P22 P2 LL2 = N 2 N 2 2 PP2 LL2 = N 2 N 2 2 (P P2)(P22 P2) Sine M2 = M2 forlinersystem,p2 = P2 nd ( LL2 = N 2 N 2 2 P 2 2 P )( P ) 22 P2 P2 = M 2 k 2 M = k LL2 Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 2

Coeffiient of Coupling (k) k 2 = M = k LL2 ( P )( P ) 22 P2 P2 k is lled the oeffiient of oupling Sine k, k 2 k is nonnegtive sine P > 0 If two oils hve no ommon flux, k =0 If both oils shre ll flux, k = It is physilly impossible for k =, but some mgneti ores hve k very lose to Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 3 Liner Trnsformers: Energy Continued The energy stored in the oils during the seond period is given by w2 = = t2 t t2 t = ±MI p2 dτ ( ±M di ) 2 dτ I di2 L2i2 dτ dτ I2 0 di2 L2 = ±MII2 2 I 2 2 I2 0 i2 di2 Then the totl energy stored in mgnetilly oupled oils fter the urrents hve been pplied is given by w = w w2 = 2 I 2 2 I 2 2 ± MII2 Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 5 Liner Trnsformers: Energy Suppose no energy is stored in the oils t t =0nd over some period of time t the urrent in oil inreses from 0 to I while the urrent in oil 2 is zero, i2 =0. The energy stored in the oils over this period is given by w = t 0 vi dτ = t 0 ( L di ) I i dτ = L i = dτ 2 I 2 0 Now suppose the urrent in oil is held onstnt, i = I, while the urrent in oil 2 inreses from 0 to I2. v = L ± M d v2 = ±M d L di2 2 = ±M d di2 = L2 p2 = vi v2i2 = ±M d I L2 di2 Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 4 Liner Trnsformers: Energy Comments M v w = 2 2 2 ± Mii2 The polrity of the shred term depends on how the oils re wound Cn the energy stored ever be negtive? Rell tht M = k LL2 This limits the expression bove to nonnegtive vlues only Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 6

TimeDomin Anlysis M Time Domin v = L ± M d v2 = ±M d L di2 2 Wht is v if i = A os(ωt) nd i2 =0? Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 7 Sinusoidl StedyStte Anlysis Continued I jωm I 2 V jωl jωl2 V 2 Frequeny Domin (Phsors) V = jωli jωmi2 V2 = jωmi jωl2i2 The dot onvention still pplies (not shown) Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 9 Sinusoidl StedyStte Anlysis Wht is v if i = A os(ωt) nd i2 =0? v =L ± M d v =L v2 = ± M d L di2 2 v2 = ± M d v =ωla ( sin(ωt)) v2 = ± ωma ( sin(ωt)) v =ωla os(ωt 90 ) v2 = ± ωma os(ωt 90 ) Wht is the reltionship in the phsor domin? V =jωli V2 = ± jωmi Superposition pplies so if i2 = A2 os(ωt), Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 8 Exmple 3: Liner Trnsformers & Phsor Anlysis 0 Ω 4 mh i s i L v s 2 mh 8 mh 30 Ω Find the stedystte expressions for the urrents is nd il when vs = 70 os(5000t) V. Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 20

Exmple 3: Workspe Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 2 Liner Trnsformer Anlysis: Typil Configurtion Z s R R 2 jωm I I 2 V s jωl jωl2 b Liner Trnsformer d Trnsformers re typilly used in only few types of iruits The most ommon onfigurtion onnets soure to lod Useful to derese (or inrese) the voltge ross the lod Why not just use voltge divider? Should know how to nlyze this type of iruit thoroughly Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 23 Phsor Anlysis: TEquivlent I jωm I 2 I I 2 jω(lm) jω(l2m) V V 2 jωl jωl2 jωm V V 2 Frequeny Domin (Phsors) V = jωli jωmi2 V2 = jωmi2 jωl2i2 The Tequivlent is only vlid if bottom terminls re onneted There is lso equivlent (see text) Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 22 Liner Trnsformer: Soure Lod Anlysis Z s R R 2 jωm I I 2 V s jωl jωl2 b Liner Trnsformer d R = Resistne of primry winding R2 = Resistne of seondry winding L = Selfindutne of primry L2 = Selfindutne of seondry M = Mutul indutne Zs = Soure impedne ZL = Lod impedne Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 24

Liner Trnsformer: Soure Lod Anlysis Continued Z s R R 2 jωm I I 2 V s jωl jωl2 b Liner Trnsformer d Vs = (Zs R jωl)i jωmi2 0 = jωmi (R2 jωl2 ZL)I2 Z Zs R jωl R2 jωl2 ZL Vs = ZI jωmi2 0 = jωmi I2 Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 25 Liner Trnsformer: Soure Lod Internl Impedne Z s R R 2 jωm I I 2 V s jωl jωl2 b Liner Trnsformer d Zi V s I = Z ω 2 M 2 = Z ω2 M 2 Zb = Zi Zs = R jωl ω2 M 2 Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 27 Liner Trnsformer: Soure Lod Anlysis Continued 2 Vs = ZI jωmi2 0 = jωmi I2 I2 = jωm I (Z ω2 M 2 ) Vs = I = I Z ω 2 M 2 V s I2 = jωm Z ω 2 M V 2 s Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 26 Liner Trnsformer: Soure Lod Refleted Impedne Z s R R 2 jωm I I 2 V s jωl jωl2 b Liner Trnsformer d Zb = R jωl ω2 M 2 ZR = Zb (R jωl) = ω2 M 2 = ω2 M 2 2 Z 22 Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 28

Exmple 4: Liner Trnsformers 500 Ω 200 Ω 00 Ω j200 Ω 800 Ω I I 2 300 0 V j3600 Ω j600 Ω j2500 Ω b d Find the following:. Selfimpedne of primry & seondry iruits 2. Impedne refleted into the primry winding 3. Impedne seen looking into the primry terminls of the trnsformer 4. Thévenin equivlent with respet to the terminls,d Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 29 Exmple 5: Liner Trnsformers 8 Ω j56 Ω 20 Ω j50 Ω 3 Ω I I 2 760 0 V j40 Ω j00 Ω (rms) b d Find the following:. Thévenin equivlent with respet to the terminls,d 2. If ZL is set equl to Z eq, whtisi? 3. Wht is I2? Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 3 Exmple 4: Workspe Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 30 Exmple 5: Workspe () Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 32

Exmple 5: Workspe (2) Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 33 Idel Trnsformer Anlysis N:N2 dφ v = N v2 = N2 dφ v2 v = N 2 = n N p = p2 vi = v2i2 i i2 = = n v Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 35 Introdution to Idel Trnsformers N:N2 Idel/Liner trnsformers re similr to idel/rel models of opertionl mplifiers Both idel models mke ssumptions tht simplify nlysis Idel pproximtion: ll of the flux links both oils Idel Assumptions Lrge retne: L,L2,M Perfet oupling: k Primry nd seondry re lossless: R = R2 =0 Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 34 Idel Trnsformers: Comments N:N2 v2 v = N 2 = n N i2 i = N = N2 n Defining equtions for idel trnsformers do not inlude time The phsor domin equtions re identil to the time domin The idel trnsformer nnot store energy Note diretion of seondry urrent Sometimes only the turns rtio is given: N2/N = n Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 36

Idel Trnsformers: The Dot Convention N:N2 The dot onvention determines the polrity of the defining equtions Dot Convention: If v nd v2 re both positive or both negtive t the dotted terminls, use n. Otherwise, use n. If i nd i2 both enter or both leve the dotted terminls, use n. Otherwise, use n. Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 37 Exmple 7: The Dot Convention for Idel Trnsformers :n :n :n :n Write the defining equtions for eh of the iruits shown bove. Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 39 Exmple 6: The Dot Convention for Idel Trnsformers :n :n :n :n Write the defining equtions for eh of the iruits shown bove. Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 38 Idel Trnsformer: Refleted Impedne Z s I I 2 :n V s V V 2 b d ZR = V I = V 2 n I2n = V 2 I2 n 2 = n 2 Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 40

Exmple 8: Idel Trnsformers 0.25 Ω 5 mh 237.5 mω 0: v g 25 µh If vg = 2500 os(400t) V, find i, v, i2, ndv2. Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 4 Exmple 9: Idel Trnsformers 25 Ω 20 Ω 60 Ω :4 250 0 mv j50 Ω C (rms) Find the vlue of C tht mximizes the power bsorbed by the 60 Ω resistor. Wht is the verge power delivered for this vlue of C? Reple the resistor with vrible resistor nd find the vlue tht mximizes the power delivered? Wht is the mximum verge power tht n be delivered? Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 43 Exmple 8: Workspe Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 42 Exmple 9: Workspe () Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 44

Exmple 9: Workspe (2) Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 45