Math Review Packet. for Pre-Algebra to Algebra 1

Similar documents
Summer Packet Geometry PAP

Algebra Concepts Equation Solving Flow Chart Page 1 of 6. How Do I Solve This Equation?

Indicate the answer choice that best completes the statement or answers the question.

Geometry A & Geometry B & Honors Geometry Summer Packet

Algebra I Part B. Help Pages & Who Knows

Basic ALGEBRA 2 SUMMER PACKET

PAP Geometry Summer Assignment 2017

MA 22000, Lesson 2 Functions & Addition/Subtraction Polynomials Algebra section of text: Sections 3.5 and 5.2, Calculus section of text: Section R.

Algebra 1 Skills Needed for Success in Math

Summer Packet Pre-AP Algebra

( ) ( 4) ( ) ( ) Final Exam: Lessons 1 11 Final Exam solutions ( )

RAMAPO&INDIAN*HILLS*SCHOOL*DISTRICT*

Algebra Final Exam Review Packet

A Quick Algebra Review

Eby, MATH 0310 Spring 2017 Page 53. Parentheses are IMPORTANT!! Exponents only change what they! So if a is not inside parentheses, then it

My Math Plan Assessment #1 Study Guide

Note-Taking Guides. How to use these documents for success

New Rochelle High School Geometry Summer Assignment

Algebra Review C H A P T E R. To solve an algebraic equation with one variable, find the value of the unknown variable.

ACCUPLACER MATH 0310

OBJECTIVES UNIT 1. Lesson 1.0

Algebra 1 FINAL EXAM REVIEW Spring Semester Material (by chapter)

Bishop Kelley High School Summer Math Program Course: Algebra 2 A

Example: x 10-2 = ( since 10 2 = 100 and [ 10 2 ] -1 = 1 which 100 means divided by 100)

One of your primary goals in mathematics should be to become a good problem solver. It helps to approach a problem with a plan.

Intermediate Algebra 100A Final Exam Review Fall 2007

Rising 7th Grade Math. Pre-Algebra Summer Review Packet

Math 75 Mini-Mod Due Dates Spring 2016

STA Summer Review for Students Entering Algebra 3

Solving Equations. Solving Equations - decimal coefficients and constants. 2) Solve for x: 3(3x 6) = 3(x -2) 1) Solve for x: 5 x 2 28 x

Precalculus Summer Assignment 2015

Summer Work for students entering PreCalculus

Name: Geometry & Intermediate Algebra Summer Assignment

Visit us at: for a wealth of information about college mathematics placement testing!

Answer the following questions using a fraction and a percent (round to the nearest tenth of a percent).

SUMMER REVIEW PACKET. Name:

Summer Work for students entering PreCalculus

Bishop Kelley High School Summer Math Program Course: Algebra 2 A

Equations and Inequalities. College Algebra

Geometry 263 Prerequisites

6. The braking distance (in feet) for a car traveling 50 miles per hour on a wet uphill road is given by

Elementary Algebra Study Guide Some Basic Facts This section will cover the following topics

Introductory Algebra Chapter 9 Review

Classwork #40: Final Review: Solving Equations, Word Problems, Linear Equations, Systems of Linear Equations

Regina Summer Math Review. For students who will be taking. Algebra 2. Completed review packet due the first day of classes

Algebra 1 S1 Lesson Summaries. Lesson Goal: Mastery 70% or higher

A. Simplifying Polynomial Expressions

Which Mathematics Course Should You Take? August 22, 2018 Which mathematics course you should take depends on your current mathematics skill level

( )( ) Algebra I / Technical Algebra. (This can be read: given n elements, choose r, 5! 5 4 3! ! ( 5 3 )! 3!(2) 2

Day 3: Section P-6 Rational Expressions; Section P-7 Equations. Rational Expressions

Algebra One Dictionary

Math 0210 Common Final Review Questions (2 5 i)(2 5 i )

ALGEBRA 2 Summer Review Assignments Graphing

Section 1.1 Real Numbers and Number Operations

Math Analysis/Honors Math Analysis Summer Assignment

2.3.2 Evaluate Variable Expressions Involving Multiplication of Rational Numbers

Summer Solutions Common Core Mathematics 8. Common Core. Mathematics. Help Pages

Summer Work Packet for MPH Math Classes

Fundamentals of Algebra, Geometry, and Trigonometry. (Self-Study Course)

MATH 110: FINAL EXAM REVIEW

Level 1: Simplifying (Reducing) Radicals: 1 1 = 1 = 2 2 = 4 = 3 3 = 9 = 4 4 = 16 = 5 5 = 25 = 6 6 = 36 = 7 7 = 49 =

MATH 0960 ELEMENTARY ALGEBRA FOR COLLEGE STUDENTS (8 TH EDITION) BY ANGEL & RUNDE Course Outline

Algebra/Trigonometry Review Notes

Course 15 Numbers and Their Properties


Equations and Inequalities

LESSON 9.1 ROOTS AND RADICALS

MATH SKILL HANDBOOK. a (b ) II. Measurements and Significant Figures. 0 mm

5. Find the slope intercept equation of the line parallel to y = 3x + 1 through the point (4, 5).

AP CALCULUS SUMMER REVIEW WORK

Level Unit Chapter Lesson ChapterTitle LessonTitle Introduction Introduction How to take the placement tests How to take the

Algebra II Notes Polynomial Functions Unit Introduction to Polynomials. Math Background

ACCUPLACER MATH 0311 OR MATH 0120

Summer Assignment for students ENTERING: Algebra 2 Trigonometry Honors

5.5 Special Rights. A Solidify Understanding Task

FOR ALL STUDENTS TAKING ALGEBRA I SUMMER REVIEW PACKET

Chapter 7: Exponents

MA094 Part 2 - Beginning Algebra Summary

Remember, you may not use a calculator when you take the assessment test.

Pre-Algebra Curriculum Map Unit 1: The Number System M08.A-N Essential Questions Standards Content Skills Vocabulary

Part 2 - Beginning Algebra Summary

Accessible Topic - Topics accessible to visually impaired students using a screen reader.

The letter m is used to denote the slope and we say that m = rise run = change in y change in x = 5 7. change in y change in x = 4 6 =

Algebra 1. Math Review Packet. Equations, Inequalities, Linear Functions, Linear Systems, Exponents, Polynomials, Factoring, Quadratics, Radicals

For problems 1 4, evaluate each expression, if possible. Write answers as integers or simplified fractions

PreCalculus. American Heritage Upper School Summer Math Packet

Algebra Review. 1. Evaluate the expression when a = -3 and b = A) 17 B) 1 C) Simplify: A) 17 B) 29 C) 16 D)

Algebra I Unit Report Summary

1 a) Remember, the negative in the front and the negative in the exponent have nothing to do w/ 1 each other. Answer: 3/ 2 3/ 4. 8x y.

A. Incorrect. Solve for a variable on the bottom by first moving it to the top. D. Incorrect. This answer has too many significant figures.

ALGEBRA SUMMER MATH PACKET

Rising 8th Grade Math. Algebra 1 Summer Review Packet

The slope, m, compares the change in y-values to the change in x-values. Use the points (2, 4) and (6, 6) to determine the slope.

Appendix A. Common Mathematical Operations in Chemistry

Mathematics GRADE 8 Teacher Packet

Radicals: To simplify means that 1) no radicand has a perfect square factor and 2) there is no radical in the denominator (rationalize).

Algebra 1 Skills Needed to be Successful in Algebra 2

Name Class Date. You can use the properties of equality to solve equations. Subtraction is the inverse of addition.

Math 8 Curriculum Map and I Can Statements Diane Hamilton

Transcription:

Math Review Packet for Pre-Algebra to Algebra 1 Epressions, Equations, Eponents, Scientific Notation, Linear Functions, Proportions, Pythagorean Theorem 2016 Math in the Middle

Evaluating Algebraic Epressions 1. Substitute the given values for the variables in the epression 2. Evaluate the epression using the order of operations Parentheses/Brackets (inside to outside) Eponents Multiplication/Division (left to right) Addition/Subtraction (left to right) e: 9 2 4(y + z) for = -, y = 2, z = 5 9(-) 2 4(2 + 5) 9(-) 2 4(2 + 15) 9(-) 2 4 17 9 9 4 17 81 4 17 81 68 = 1 The Distributive Property 1. Multiply the number outside the parentheses by each term in the parentheses. 2. Keep the addition/subtraction sign between each term. e: 5(8 ) 5(8 ) 5(8) 5() 40 15 Simplifying Algebraic Epressions 1. Clear any parentheses using the Distributive Property 2. Add or subtract like terms (use the sign in front of each term to determine whether to add or subtract) e: 2( 4) 12 + 9 2( 4) 12 + 9 6 8 12 + 9-6 + 1

Evaluate each epression for a = 9, b = -, c = -2, d = 7. Show your work. 1. a - cd 2. 2b + c 2. a + d c b 4. (a b) 2 + d(a + c) 5. 4c (b a) 6. a b - 5a 7. 2bc + d(12 5) 8. b + 0.5[8 (2c + a)] Simplify each epression using the Distributive Property. 9. 5(2g 8) 10. 7(y + ) 11. -(4w ) 12. (6r + )2 Simplify each epression, showing all work. 1. 8( + 1) 12 14. 6w 7 + 12w z 15. 9n 8 + (2n 11) 16. (7 + 4y) 2(2 + y) 17. (15 + 8d)(-5) 24d + d 18. 9(b 1) c + b + c 19. 20f 4(5f + 4) + 16 20. 8(h 4) h (h + 7)

Solving One-Step Equations 1. Cancel out the number on the same side of the equal sign as the variable using inverse operations (addition/subtraction; multiplication/division) 2. Be sure to do the same thing to both sides of the equation! e: -18 = 6j -18 = 6j 6 6 - = j j = - Solving Two-Step Equations 1. Undo operations one at a time with inverse operations, using the order of operations in reverse (i.e. undo addition/subtraction before multiplication/division) 2. Be sure to always do the same thing to both sides of the equation! e: a 7 12 = 9 a 7 7 X 12 = 9 + 12 + 12 a 7 = X 7 a = 21 Solving Multi-Step Equations 1. Clear any parentheses using the Distributive Property 2. Combine like terms on each side of the equal sign. Get the variable terms on the same side of the equation by adding/subtracting a variable term to/from both sides of the equation to cancel it out on one side 4. The equation is now a two-step equation, so finish solving it as described above e: 5(2 1) = + 4-1 10-5 = + 4-1 10-5 = 7-1 - 7-7 - 5 = - 1 + 5 + 5 = 4 = 4

Solve each equation, showing all work. 21. f 64 = -2 22. -7 = 2d b 12 = 6 24. 1 = m + 21 2. 25. 5 = -28 w + 8 = -9-8 + h 4 = 1 28. 22 = 6y + 7 26. 27. 29. 8 4 = + 1 0. -2(5d 8) = 20 1. 7r + 21 = 49r 2. -9g = -(g + 2). 5( 2) = 5(4 + 1) 4. d 4 + d = 8d (-12) 5. f 6 = -2f + (f 2) 6. -2(y 1) = 4y (y + 2)

Scientific Notation Standard Form to Scientific Notation: move the decimal after the first non-zero digit and eliminate any trailing zeros. Multiply by 10 to the power equal to the number of places you moved the decimal point. If the original number was greater than 1, the eponent is positive. If the number was less than 1, the eponent is negative. Scientific Notation to Standard Form: move the decimal point the number of places indicated by the eponent. If the eponent is positive, move the decimal right. If negative, move left. e: 0.0000571 0.0000571 Original number < 1, so negative eponent = 5.71 10-5 e:.5 10 Positive eponent, so move decimal right.500 =,500 Negative Eponents & Simplifying Monomials Zero Eponent: power equals 1 Any number raised to the zero Negative Eponent: Move the base to the opposite side of the fraction line and make the eponent positive Monomial Monomial: Multiply the coefficients and add the eponents of like bases Monomial Monomial: Divide the coefficients and subtract the eponents of like bases Power of a Monomial: Raise each base (including the coefficient) to that power. If a base already has an eponent, multiply the two eponents Power of a Quotient: Raise each base (including the coefficient) to that power. If a base already has an eponent, multiply the two eponents e: y 0 = 1 e: -4 = 1 4 e: (4 )(2 5 ) = 8 8 e: a a 6 = a 5 = 1 a 5 e: (-2fg 5 ) = -8f g 15 e: 5d c 2 = 25d6 c 2

Convert each number to Scientific Notation. 7. 67,000,000,000 8. 0.000921 9. 0.00000000004 40.,201,000,000,000,000 Convert each number to Standard Form. 41. 5.92 10-5 42. 1.1 10 7 4. 6.7 10-8 44..27 10 2 Simplify each epression. Write your answers using only positive eponents. 45. w -9 46. m 5 47. f5 f 48. m 2 h 2 g 49. (a 5 ) 2 50. 1 b 51. z 0 52. 4r 6 r 2r 2 5. 9p 2 q 54. 8d 2cd 2 55. (g 4 h) 2 (2g h -1 ) 2 56. (6a) 0 57. (-n 2 k 4 ) 2 58. w 5 2 59. y w 2 y 4 6 10 7 2 10 60. (1.5 10-6 ) (4 10 9 )

Slope & Rate of Change Finding the Slope Given Two Points: Use the coordinates from the points in the slope formula: Slope (m) = y 2 y 1 2 1 Finding the Rate of Change From a Table: Determine the amount the dependent variable (y) is changing and the amount the independent variable () is changing. Rate of Change = change in y change in Finding the Slope From a Graph: Choose 2 points on the graph. Find the vertical change (rise) and horizontal change (run) between the 2 points and write it as a fraction rise run. (Up is positive, down is negative, right is positive, and left is negative). y e: (4, -2), (-, 8) m = 8 ( 2) 4 = 10 7 = 10 7 e: m 1 y 1 2 y 2 # months 5 7 9 Cost ($) 80 10 180 20 = 50 2 +2 +2 +2 +50 +50 +50 = 25 dollars/month rise = +1 run = -2 m = 1 2 = 1 2 Graphing Linear Equations Slope-Intercept Form: y = m + b e: y = 2-4 slope y-intercept y-intercept: -4 How To Graph: 1. Make a point on the y-ais at the y-intercept. 2. Use the slope to determine where to make the net point. The numerator tells you the rise (how far up/down) and the denominator tells you the run (how far right/left) to make the net point.. Repeat to make more points and then connect the points with a line. slope: 2 = 2 1 rise run

Find the slope of the line that passes through the points. Show your work. 61. (-5, ), (2, 1) 62. (8, 4), (11, 6) 6. (9, ), (9, -1) 64. (-4, -2), (-6, 4) Find the rate of change. Show your work. 65. 66. Number of Hours 6 9 12 Distance (in miles) 15 270 405 540 Number of Weeks 1 5 7 Pounds 17 169 165 161 Find the slope of the line. 67. 68. 69. Graph the line. 70. y = - 71. y = 1 + 2 72. y = - 1 7. y = - 2 2 74. y = 2 + 1 75. y = 1 4

Solving Proportions 1. Set the two cross-products equal to each other 2. Solve the equation for the variable e: m 4 = 5 5m = 12 5 5 m = 2.4 Similar Figures 1. To find a missing side length, set up a proportion, matching up corresponding sides. 2. Solve the proportion using the steps above. e: 9 mm 1.5 = 9 5.5 5.5 mm = 2.45 mm 1.5 mm The Pythagorean Theorem *** The Pythagorean Theorem applies to right triangles only ** The sides net to the right angle (a & b) are legs e: 12 cm The side across from the right angle (c) is the hypotenuse b = leg a = leg Pythagorean Theorem: a 2 + b 2 = c 2 To find the hypotenuse: add the squares of the legs and then find the square root of the sum To find a leg: subtract the square of the given leg from the square of the hypotenuse and then find the square root of the difference 15 cm is the hypotenuse 12 2 + 15 2 = 2 144 + 225 = 2 69 = 2 = 69 19.2 cm e: a =?, b =, c = 6 a is a leg a 2 + 2 = 6 2 a 2 + 9 = 6 a 2 = 6 9 = 27 a = 27 5.2

Solve each proportion, showing all work. 76. 6 7 = 4 77. 12 m 5 = k 78. h 7 = 8 79. 22 2 n = 9 80. 6 4 21 = c Assume each pair of figures is similar. Find the missing side length, showing all work. 81. 7 cm 82. 1.5 in 8. ft 2 cm 1 in n 14 cm 6 in 8 ft r 2 ft 84. 5 mm 85. 86. 20 mm y 18 in 12 in 9 mm 18 in j 2 mm 24 in f 10 cm 5 cm 8 cm Find the missing side length in each right triangle to the nearest tenth. Show your work! 87. a = 6, b = 8, c =? 88. a =?, b = 9 cm, c = 1 cm 89. a = 7, b =?, c = 14 90. a = 14 in, b = 14 in, c =? 91. 92. 9. 7 in 94. 5 10 mm 5 in 10 mm 20 18 95. 15 96. 104 in 97. 5 ft 98. 1 10 ft 52 in 20 cm 24 cm Determine whether or not you can form a right triangle from the given side lengths. Eplain. 99. 18, 22, 26 100. 5, 12, 1

Evaluate each epression for a = 9, b = -, c = -2, d = 7. Show your work. 1. a - cd 2. 2b + c 2. a + d c b 2-50 -6 19 4. (a b) 2 + d(a + c) 5. 4c (b a) 6. a b - 5a 7. 2bc + d(12 5) 8. b + 0.5[8 (2c + a)] 4-48 61-1.5 Simplify each epression using the Distributive Property. 9. 5(2g 8) 10. 7(y + ) 11. -(4w ) 12. (6r + )2 10g - 40 7y + 21-12w + 9 12r + 6 Simplify each epression, showing all work. 1. 8( + 1) 12 14. 6w 7 + 12w z 15. 9n 8 + (2n 11) 16. (7 + 4y) 2(2 + y) -4 + 8 18w - z - 7 15n - 41 17 + 10y 17. (15 + 8d)(-5) 24d + d 18. 9(b 1) c + b + c 19. 20f 4(5f + 4) + 16 20. 8(h 4) h (h + 7) -6d - 75 12b - 9 0 6h - 9

Solve each equation, showing all work. 21. f 64 = -2 22. -7 = 2d 2. b 12 = 6 24. 1 = m + 21 f = 41 d = - 7 / 2 = -.5 b = 72 m = -8 25. 5 = -28 26. w + 8 = -9 27. -8 + h 4 = 1 28. 22 = 6y + 7 = -5 w = 19 h = 84 y = 5 / 2 = 2.5 29. 8 4 = + 1 0. -2(5d 8) = 20 1. 7r + 21 = 49r 2. -9g = -(g + 2) = 1 = - 2 / 5 = -0.4 r = 1 / 2 = 0.5 no solution. 5( 2) = 5(4 + 1) 4. d 4 + d = 8d (-12) 5. f 6 = -2f + (f 2) 6. -2(y 1) = 4y (y + 2) = - d = -4 all real numbers y = 4 / 5 = 0.8

Convert each number to Scientific Notation. 7. 67,000,000,000 8. 0.000921 9. 0.00000000004 40.,201,000,000,000,000 6.7 10 10 9.21 10-4 4 10-11.201 10 15 Convert each number to Standard Form. 41. 5.92 10-5 42. 1.1 10 7 4. 6.7 10-8 44..27 10 2 0.0000592 11,000,000 0.000000067 27 Simplify each epression. Write your answers using only positive eponents. 45. w -9 46. m 5 47. f5 f 48. m 2 1 w 9 m f 8 h 6 h 2 g g 49. (a 5 ) 2 50. 1 b 51. z 0 52. 4r 6 r 2r 2 a 10 b 1 24r 9 5. 9p 2 q q 54. 8d 2cd 2 p 2 4d 5 c 55. (g 4 h) 2 (2g h -1 ) 2 56. (6a) 0 4g 14 1 57. (-n 2 k 4 ) 2 58. w 5 2 y 59. w 2 y 4 9n 4 k 8 w 9 6 10 7 2 10 60. (1.5 10-6 ) (4 10 9 ) 9 y 9 10 4 6 10

Find the slope of the line that passes through the points. Show your work. 61. (-5, ), (2, 1) 62. (8, 4), (11, 6) 6. (9, ), (9, -1) 64. (-4, -2), (-6, 4) m = - 2 7 m = 2 m = undefined m = - Find the rate of change. Show your work. 65. 66. Number of Hours 6 9 12 Distance (in miles) 15 270 405 540 Number of Weeks 1 5 7 Pounds 17 169 165 161 45 miles per hour -2 pounds per week Find the slope of the line. 67. 68. 69. m = - m = 0 m = 2 Graph the line. 70. y = - 71. y = 1 + 2 72. y = - 1 7. y = - 2 2 74. y = 2 + 1 75. y = 1 4

Solve each proportion, showing all work. 76. 6 7 = 4 77. 12 m 5 = k 78. h 7 = 8 79. 22 2 n = 9 80. 6 4 21 = c m = 4.6 k = 7.2 h = 28 h = 88 h = 15.75 Assume each pair of figures is similar. Find the missing side length to the nearest tenth. 81. 7 cm 82. 1.5 in 8. ft 2 cm 1 in n 14 cm 6 in 8 ft = 4 cm = 4 in = 5. ft r 2 ft 84. 5 mm 85. 86. 20 mm y 10 cm 18 in 12 in 9 mm 18 in f j 2 mm 24 in j 18. mm y = 1.5 in f = 6.25 cm 5 cm 8 cm Find the missing side length in each right triangle to the nearest tenth. Show your work! 87. a = 6, b = 8, c =? 88. a =?, b = 9 cm, c = 1 cm 89. a = 7, b =?, c = 14 90. a = 14 in, b = 14 in, c =? c = 10 units a 9.4 cm b 12.1 units c 19.8 in 91. 92. 9. 7 in 94. 5 10 mm 5 in 10 mm 20 18 = 4 units 14.1 mm 8.6 in 8.7 units 95. 15 96. 104 in 97. 5 ft 98. 1 10 ft 52 in 19.8 units 116. in.5 ft 24 cm 20 cm 1. cm Determine whether or not you can form a right triangle from the given side lengths. Eplain. 99. 18, 22, 26 100. 5, 12, 1 No; 18 2 + 22 2 26 2 Yes; 5 2 + 12 2 = 1 2