Spring 2018 Exam 2 MARK BOX HAND IN PART NAME: PIN: INSTRUCTIONS

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Spring 208 Exam 2 problem MARK BOX points HAND IN PART 0 0 4 2-5 56=4x4 6 0 7 0 NAME: PIN: % 00 INSTRUCTIONS This exam comes in two parts () HAND IN PART Hand in only this part (2) STATEMENT OF MULTIPLE CHOICE PROBLEMS Do not hand in this part You can take this part home to learn from and to check your answers once the solutions are posted On Problem 0, fill in the blanks As you know, if you do not make at least half of the points on Problem 0, then your score for the entire exam will be whatever you made on Problem 0 The mark box above indicates the problems along with their points Check that your copy of the exam has all of the problems Upon request, you will be given as much (blank) scratch paper as you need During the exam, the use of unauthorized materials is prohibited Unauthorized materials include: books, personal notes, electronic devices, and any device with which you can connect to the internet Unauthorized materials (including cell phones, as well as your watch) must be in a secured (eg zipped up, snapped closed) bag placed completely under your desk or, if you did not bring such a bag, give it to Prof Girardi to hold for you during the exam (and it will be returned when you leave the exam) This means no electronic devices (such as cell phones) allowed in your pockets At a student s request, I will project my watch upon the projector screen Cheating is grounds for a F in the course During this exam, do not leave your seat unless you have permission If you have a question, raise your hand When you finish: turn your exam over, put your pencil down and raise your hand This exam covers (from Calculus by Thomas, 3 th ed, ET): 0 06 Honor Code Statement I understand that it is the responsibility of every member of the Carolina community to uphold and maintain the University of South Carolina s Honor Code As a Carolinian, I certify that I have neither given nor received unauthorized aid on this exam I understand that if it is determined that I used any unauthorized assistance or otherwise violated the University s Honor Code then I will receive a failing grade for this course and be referred to the academic Dean and the Office of Academic Integrity for additional disciplinary actions Furthermore, I have not only read but will also follow the instructions on the exam Signature : Prof Girardi Page of Math 42

Spring 208 Exam 2 0 Fill-in the boxes All series are understood to be, unless otherwise indicated 0 For a formal series a n, where each a n R, consider the corresponding sequence {s n } of partial sums, so s n = n k= a k By definition, the formal series a n converges if and only if 02 p-series Fill in the boxes with the proper range of p R The series n p converges if and only if 03 Geometric Series Fill in the boxes with the proper range of r R The series r n converges if and only if r satisfies 04 State the Direct Comparison Test for a positive-termed series a n If when n 7 and c n converges, then a n converges If when n 7 and d n diverges, then a n diverges Hint: sing the song to yourself 05 State the Limit Comparison Test for a positive-termed series a n Let b n > 0 and L = lim n a n bn If, then [ b n converges a n converges ] If L = 0, then If L =, then Goal: cleverly pick positive b n s so that you know what b n does (converges or diverges) and the sequence { an bn }n converges 06 State the Ratio and Root Tests for arbitrary-termed series a n with < a n < Let ρ = lim a n+ n a n or ρ = lim a n n n If ρ >, then a n If ρ <, then a n Prof Girardi Page 2 of Math 42

Spring 208 Exam 2 Circle T if the statement is TRUE Circle F if the statement if FALSE To be more specific: circle T if the statement is always true and circle F if the statement is NOT always true The symbol is understood to mean Scoring this problem: A problem with precisely one answer marked and the answer is correct, point All other cases, 0 points T F If a n converges, then lim n a n = 0 2 T F If lim n a n 0, then a n diverges 3 T F If lim n a n = 0, then a n converges 4 T F A series a n is precisely one of the following: absolutely convergent, conditionally convergent, divergent 5 T F If a n 0 for all n N, then a n is either absolutely convergent or divergent 6 T F If a n converges, then a n converges 7 T F If a n diverges, then a n diverges 8 T F If a n diverges, then a n diverges 9 T F If a function f : [0, ) R satisfies that lim x f(x) = L and {a n } is a sequence satisfying that f(n) = a n for each natural number n, then lim n a n = L 0 T F If a sequence {a n } satisfies that lim n a n = L and f : [0, ) R is a function satisfying that f(n) = a n for each natural number n, then lim x f(x) = L T F The a n converges if and only if a n converges 7 2 T F If a n converges, then (a n + 00) converges 3 T F If 4 T F If p n diverges, then (p + 00) n diverges, for a fixed real number p n p converges, then n p+00 converges, for a fixed real number p Prof Girardi Page 3 of Math 42

Spring 208 Exam 2 MULTIPLE CHOICE PROBLEMS Indicate (by circling) directly in the table below your solution to the multiple choice problems You may choice up to 2 answers for each multiple choice problem The scoring is as follows For a problem with precisely one answer marked and the answer is correct, 4 points For a problem with precisely two answers marked, one of which is correct, points All other cases, 0 points Fill in the number of solutions circled column Table for Your Muliple Choice Solutions Do Not Write Below problem 2 2a 2b 2c 2d 2e 3 3a 3b 3c 3d 3e 4 4a 4b 4c 4d 4e 5 5a 5b 5c 5d 5e 6 6a 6b 6c 6d 6e 7 7a 7b 7c 7d 7e 8 8a 8b 8c 8d 8e 9 9a 9b 9c 9d 9e 0 0a 0b 0c 0d 0e a b c d e 2 2a 2b 2c 2d 2e 3 3a 3b 3c 3d 3e 4 4a 4b 4c 4d 4e 5 5a 5b 5c 5d 5e number of solutions circled 2 B x 4 0 0 Total: Prof Girardi Page 4 of Math 42

Spring 208 Exam 2 6 Below the choice-boxes (AC/CC/Divg), carefully justify the behavior of the series Be sure to clearly explain your logic and specify which test(s) you are using Then check the correct choice-box absolutely convergent n=2 ( ) n ln n n conditionally convergent divergent Prof Girardi Page 5 of Math 42

Spring 208 Exam 2 7 Below the choice-boxes (AC/CC/Divg), carefully justify the behavior of the series Be sure to clearly explain your logic and specify which test(s) you are using Then check the correct choice-box You may use Part 7 in Part 72 7 ( ) n (3n 2) n absolutely convergent conditionally convergent divergent absolutely convergent 72 ( ) n (3n 2) n+ 2 conditionally convergent divergent To clarify, the quantity (3n 2) in the denominator is raised to the power (n + 2 ) Prof Girardi Page 6 of Math 42

Spring 208 Exam 2 STATEMENT OF MULTIPLE CHOICE PROBLEMS These sheets of paper are not collected Abbreviations used: DCT is Direct Comparison Test LCT is Limit Comparison Test AST is Alternating Series Test 2 Limit of a sequence Evaluate 2n lim n n + a 0 b 2 c 2 d 3 Limit of a sequence Evaluate sin n lim n n a 0 b c d diverges but not to ± 4 Consider the formal series n + 3 n a This series diverges since n + 3 n = n + 3 n and n diverges b This series diverges by the DCT, using for comparison n c This series diverges by the DCT, using for comparison 3 n d This series converges by the DCT, using for comparison 3 n Prof Girardi Page 7 of Math 42

Spring 208 Exam 2 5 Consider the formal series ( ) n (n + 2)(n + 7) a This series is absolutely convergent by the LCT, using for comparison n 2 b This series is conditionally convergent, as can be shown by using only the AST and no other tests c This series is conditionally convergent by LCT (using for comparison ) as well as AST n d This series diverges 6 Consider the formal series k 2 e k k= a This series converges because the limit used in the Ratio Test is e b This series diverges because the limit used in the Ratio Test is e c This series converges because the limit used in the Ratio Test is e d This series diverges because the limit used in the Ratio Test is e 7 Consider the formal series n! e n2 (Remember your Algebra Priorities: e n2 = e (n2 ) ) a This series converges because the limit used in the Ratio Test is 0 b This series converges because the limit used in the Ratio Test is e c This series converges because the limit used in the Ratio Test is e 2 d This series diverges because the limit used in the Ratio Test is Prof Girardi Page 8 of Math 42

Spring 208 Exam 2 8 Consider the formal series ( ) tan n a This series converges because the limit used in the Root Test is b This series converges because the limit used in the Root Test is 0 c This series converges by the Integral Test d This series diverges by the n th term test e This series diverges by the LCT, using for comparison n f None of the others 9 What is the smallest integer N such that the Alternating Series Estimate/Remainder Theorem guarentees that ( ) n N ( ) n 005? n 2 n 2 Note that 005 = 005 0000 = 5 00 = 20 a 3 b 4 c 5 d 6 0 Find the vaule for b for which e b + e 2b + e 3b + e 4b + = 9 a ln 8 9 b 8 9 c ln 9 0 d 9 0 Prof Girardi Page 9 of Math 42

Spring 208 Exam 2 Determine the behavior of the series 2 n n! n! (2n)! a The series converges because the limit used in the Ratio Test is 0 b The series converges because the limit used in the Ratio Test is 2 c The series diverges because the limit used in the Ratio Test is 2 d The series diverges because the limit used in the Ratio Test is 2 The series n n 2 +, by the Direct Comparison Test, a diverges, using for comparison the p-series b converges, using for comparison the p-series c diverges, using for comparison the p-series d converges, using for comparison the p-series 3 The series + ln n, by the Limit Comparison Test, n 05 n 05 n 5 n 5 a diverges, using for comparison the p-series, since lim n n b diverges, using for comparison the p-series, since lim n n ( +ln n) ( n) ( +ln n) ( n) = 0 = c converges, using for comparison the p-series d converges, using for comparison the p-series ( +ln, since lim n) n 2 n ( ) n 2 ( +ln, since lim n) n 2 n ( ) n 2 = 0 = Prof Girardi Page 0 of Math 42

Spring 208 Exam 2 4 The series ( ) n+ n ln n, is n=2 a absolutely convergent, as shown by the Direct Comparison Test, using for comparison the series n 2 b conditionally convergent, as shown by using only the Alternating Series Test (and no other tests) c conditionally convergent, as shown by using both the Alternating Series Test and the Integral Test d divergent, as shown by the Direct Comparison Test, using for comparison the series n 5 Consider the formal series n (2n + )n ( ) n 2n a This series diverges by the n th -term test b This series diverges because the limit used in the Root Test is c This series diverges because the limit used in the Root Test is 2 d This series is absolutely convergent because the limit used in the Root Test is 0 Prof Girardi Page of Math 42