Equilibrium of Stress

Similar documents
Surface and Contact Stress

Chapter 3 Kinematics in Two Dimensions; Vectors

f = µ mg = kg 9.8m/s = 15.7N. Since this is more than the applied

Example 1. A robot has a mass of 60 kg. How much does that robot weigh sitting on the earth at sea level? Given: m. Find: Relationships: W

ENGI 4430 Parametric Vector Functions Page 2-01

Chapter 2 GAUSS LAW Recommended Problems:

PHYS 219 Spring semester Lecture 02: Coulomb s Law how point charges interact. Ron Reifenberger Birck Nanotechnology Center Purdue University

Chapter 5: Force and Motion I-a

Figure 1a. A planar mechanism.

CHAPTER 8b Static Equilibrium Units

Lecture 5: Equilibrium and Oscillations

Kinematic transformation of mechanical behavior Neville Hogan

Lecture 7 Further Development of Theory and Applications

Chapter 9 Vector Differential Calculus, Grad, Div, Curl

Physics 212. Lecture 12. Today's Concept: Magnetic Force on moving charges. Physics 212 Lecture 12, Slide 1

3 Stress internal forces stress stress components Stress analysis stress transformation equations principal stresses stress invariants

Phys101 Final Code: 1 Term: 132 Wednesday, May 21, 2014 Page: 1

Fundamental Concepts in Structural Plasticity

Kinetics of Particles. Chapter 3

Building to Transformations on Coordinate Axis Grade 5: Geometry Graph points on the coordinate plane to solve real-world and mathematical problems.

UNIT 1 COPLANAR AND NON-COPLANAR FORCES

Sections 15.1 to 15.12, 16.1 and 16.2 of the textbook (Robbins-Miller) cover the materials required for this topic.

Study Guide Physics Pre-Comp 2013

MODULE 1. e x + c. [You can t separate a demominator, but you can divide a single denominator into each numerator term] a + b a(a + b)+1 = a + b

AP Physics Kinematic Wrap Up

LHS Mathematics Department Honors Pre-Calculus Final Exam 2002 Answers

. (7.1.1) This centripetal acceleration is provided by centripetal force. It is directed towards the center of the circle and has a magnitude

Part a: Writing the nodal equations and solving for v o gives the magnitude and phase response: tan ( 0.25 )

PHYS 314 HOMEWORK #3

14. Which shows the direction of the centripetal force acting on a mass spun in a vertical circle?

37 Maxwell s Equations

Plan o o. I(t) Divide problem into sub-problems Modify schematic and coordinate system (if needed) Write general equations

14. Which shows the direction of the centripetal force acting on a mass spun in a vertical circle?

SPH3U1 Lesson 06 Kinematics

Here is instructions on how to use the simulation program.(the first simulation is used in question 5)

Thermodynamics and Equilibrium

Phy 213: General Physics III 6/14/2007 Chapter 28 Worksheet 1

MATHEMATICS Higher Grade - Paper I

Lim f (x) e. Find the largest possible domain and its discontinuity points. Why is it discontinuous at those points (if any)?

39th International Physics Olympiad - Hanoi - Vietnam Theoretical Problem No. 1 /Solution. Solution

Aircraft Performance - Drag

Course Stabilty of Structures

Rigid Body Dynamics (continued)

, which yields. where z1. and z2

Chapter Summary. Mathematical Induction Strong Induction Recursive Definitions Structural Induction Recursive Algorithms

Higher. Specimen NAB Assessment

Pre-Calculus Individual Test 2017 February Regional

205MPa and a modulus of elasticity E 207 GPa. The critical load 75kN. Gravity is vertically downward and the weight of link 3 is W3

Phys102 Second Major-102 Zero Version Coordinator: Al-Shukri Thursday, May 05, 2011 Page: 1

Yeu-Sheng Paul Shiue, Ph.D 薛宇盛 Professor and Chair Mechanical Engineering Department Christian Brothers University 650 East Parkway South Memphis, TN

Flipping Physics Lecture Notes: Simple Harmonic Motion Introduction via a Horizontal Mass-Spring System

INTRODUCTION. F v. v v v v. M α M=

Q1. In figure 1, Q = 60 µc, q = 20 µc, a = 3.0 m, and b = 4.0 m. Calculate the total electric force on q due to the other 2 charges.

Chapter 2. Coulomb s Law and Electric Field Intensity

i-clicker i-clicker Newton s Laws of Motion First Exam Coming Up! Components of Equation of Motion

1 The limitations of Hartree Fock approximation

NUMBERS, MATHEMATICS AND EQUATIONS

Information for Physics 1201 Midterm I Wednesday, February 20

An Introduction to Complex Numbers - A Complex Solution to a Simple Problem ( If i didn t exist, it would be necessary invent me.

CMSC 425: Lecture 9 Basics of Skeletal Animation and Kinematics

SAFE HANDS & IIT-ian's PACE EDT-04 (JEE) Solutions

CHAPTER 6 WORK AND ENERGY

Introduction: A Generalized approach for computing the trajectories associated with the Newtonian N Body Problem

= m. Suppose the speed of a wave on a string is given by v = Κ τμ

Q1. A string of length L is fixed at both ends. Which one of the following is NOT a possible wavelength for standing waves on this string?

Higher Mathematics Booklet CONTENTS

Physics 101 Math Review. Solutions

Homology groups of disks with holes

Finding the Earth s magnetic field

Conceptual Dynamics SDC. An Interactive Text and Workbook. Kirstie Plantenberg Richard Hill. Better Textbooks. Lower Prices.

CHAPTER 6 -- ENERGY. Approach #2: Using the component of mg along the line of d:

GAUSS' LAW E. A. surface

Flipping Physics Lecture Notes: Simple Harmonic Motion Introduction via a Horizontal Mass-Spring System

ENGI 1313 Mechanics I

0606 ADDITIONAL MATHEMATICS

Solution to HW14 Fall-2002

Work, Energy, and Power

MATHEMATICS Higher Grade - Paper I

(1.1) V which contains charges. If a charge density ρ, is defined as the limit of the ratio of the charge contained. 0, and if a force density f

Differentiation Applications 1: Related Rates

Physics 2B Chapter 23 Notes - Faraday s Law & Inductors Spring 2018

Subject: KINEMATICS OF MACHINES Topic: VELOCITY AND ACCELERATION Session I

EXAM #1 PHYSICAL SCIENCE 103 FALLF, 2017

Introduction to Spacetime Geometry

NWACC Dept of Mathematics Dept Final Exam Review for Trig - Part 3 Trigonometry, 9th Edition; Lial, Hornsby, Schneider Fall 2008

( ) ( ) Pre-Calculus Team Florida Regional Competition March Pre-Calculus Team Florida Regional Competition March α = for 0 < α <, and

Computational modeling techniques

Faculty of Engineering and Department of Physics Engineering Physics 131 Midterm Examination February 27, 2006; 7:00 pm 8:30 pm

Math 105: Review for Exam I - Solutions

Precalculus A. Semester Exam Review

Trigonometry, 8th ed; Lial, Hornsby, Schneider

Trigonometric Ratios Unit 5 Tentative TEST date

Chapter 2. Kinematics in One Dimension. Kinematics deals with the concepts that are needed to describe motion.

Chapter 8. The Steady Magnetic Field 8.1 Biot-Savart Law

Electric Current and Resistance

Q1. A) 48 m/s B) 17 m/s C) 22 m/s D) 66 m/s E) 53 m/s. Ans: = 84.0 Q2.

CHAPTER 4 Dynamics: Newton s Laws of Motion /newtlaws/newtltoc.html

Chapter 32. Maxwell s Equations and Electromagnetic Waves

Module M3: Relative Motion

Transcription:

Equilibrium f Stress Cnsider tw perpendicular planes passing thrugh a pint p. The stress cmpnents acting n these planes are as shwn in ig. 3.4.1a. These stresses are usuall shwn tgether acting n a small material element f finite size, ig. 3.4.1b. It has been seen that the stress ma var frm pint t pint in a material but, if the element is ver small, the stresses n ne side can be taken t be (mre r less) equal t the stresses acting n the ther side. B cnventin, in analses f the tpe which will fllw, all stress cmpnents shwn are psitive. p ( a) igure 3.4.1: stress cmpnents acting n tw perpendicular planes thrugh a pint; (a) tw perpendicular surfaces at a pint, small material element at the pint The fur stresses can cnvenientl be written in the matri frm: ij (3.4.1) It will be shwn belw that the stress cmpnents acting n an ther plane thrugh p can be evaluated frm a knwledge f nl these stress cmpnents. 3.4.1 Smmetr f the Shear Stress Cnsider the material element shwn in ig. 3.4.1b, reprduced in ig. 3.4.a belw. The element has dimensins is and is subjected t unifrm stresses ver its sides. The resultant frces f the stresses acting n each side f the element act thrugh the sidecentres, and are shwn in ig. 3.4.b. The stresses shwn are psitive, but nte hw 5 Kell

psitive stresses can lead t negative frces, depending n the definitin f the aes used. The resultant frce n the cmplete element is seen t be zer. ( a) igure 3.4.: stress cmpnents acting n a material element; (a) stresses, resultant frces n each side B taking mments abut an pint in the blck, ne finds that { Prblem 1} (3.4.) Thus the shear stresses acting n the element are all equal, and fr this reasn the stresses are usuall labelled, ig. 3.4.3a, r simpl labelled, ig. 3.4.3b. ( a) igure 3.4.3: shear stress acting n a material element 3.4. Three Dimensinal Stress The three-dimensinal cunterpart t the tw-dimensinal element f ig. 3.4. is shwn in ig. 3.4.4. Again, all stresses shwn are psitive. 53 Kell

z z z z z zz igure 3.4.4: a three dimensinal material element Mment equilibrium in this case requires that,, (3.4.3) z z z z The nine stress cmpnents, si f which are independent, can nw be written in the matri frm z ij z (3.4.4) z z zz A vectr has ne directin assciated with it and is characterised b three cmpnents (,, z ). The stress is a quantit which has tw directins assciated with it (the directin f a frce and the nrmal t the plane n which the frce acts) and is characterised b the nine cmpnents f Eqn. 3.4.4. Such a mathematical bject is called a tensr. Just as the three cmpnents f a vectr change with a change f crdinate aes (fr eample, as in ig...1), s the nine cmpnents f the stress tensr change with a change f aes. This is discussed in the net sectin fr the tw-dimensinal case. (The cncept f a tensr will be eamined mre clsel in Bks II and especiall IV.) 3.4.3 Stress Transfrmatin Equatins Cnsider the case where the nine stress cmpnents acting n three perpendicular planes thrugh a material particle are knwn. These cmpnents are,, etc. when using, z, aes, and can be represented b the cube shwn in ig. 3.4.5a. Rtate nw the planes abut the three aes these new planes can be represented b the rtated cube shwn in ig. 3.4.5b; the aes nrmal t the planes are nw labelled,, z and the crrespnding stress cmpnents with respect t these new aes are,, etc. 54 Kell

zz z z z z z z z zz z z z (a) igure 3.4.5: a three dimensinal material element; (a) riginal element, rtated element There is a relatinship between the stress cmpnents,, etc. and the stress cmpnents,, etc. The relatinship can be derived using Newtn s Laws. The equatins describing the relatinship in the full three-dimensinal case are ver length the will be discussed in Bks II and IV. Here, the relatinship fr the twdimensinal case will be derived this D relatinship will prve ver useful in analsing man practical situatins. Tw-dimensinal Stress Transfrmatin Equatins Assume that the stress cmpnents f ig. 3.4.6a are knwn. It is required t find the stresses arising n ther planes thrugh p. Cnsider the perpendicular planes shwn in ig. 3.4.65b, btained b rtating the riginal element thrugh a psitive (cunterclckwise) angle. The new surfaces are defined b the aes. 55 Kell

( a) igure 3.4.6: stress cmpnents acting n tw different sets f perpendicular surfaces, i.e. in tw different crdinate sstems; (a) riginal sstem, rtated sstem T evaluate these new stress cmpnents, cnsider a triangular element f material at the pint, ig. 3.4.7. Carring ut frce equilibrium in the directin, ne has (with unit depth int the page) : AB OB cs OAsin OB sin OAcs 0 (3.4.5) Since OB AB cs, OA AB sin, and dividing thrugh b AB, cs sin sin (3.4.6) B O A igure 3.4.7: a free bd diagram f a triangular element f material 56 Kell

The frces can als be reslved in the directin and ne btains the relatin ( )sin cs cs (3.4.7) inall, cnsideratin f the element in ig. 3.4.8 ields tw further relatins, ne f which is the same as Eqn. 3.4.6. igure 3.4.8: a free bd diagram f a triangular element f material In summar, ne btains the stress transfrmatin equatins: cs sin sin cs sin cs ( sin sin ) cs D Stress Transfrmatin Equatins (3.4.8) These equatins have man uses, as will be seen in the net sectin. In matri frm, cs sin sin cs cs sin sin cs (3.4.9) Bd rce, Acceleratin and Nn-Unifrm Stress Here, it will be shwn that the Stress Transfrmatin Equatins are valid als when (i) there are bd frces, (ii) the bd is accelerating and (iii) the stress and ther quantities are nt unifrm. 57 Kell

Suppse that a bd frce i j acts n the material and that the material b b b is accelerating with an acceleratin a ai aj. The cmpnents f bd frce and acceleratin are shwn in ig. 3.4.9 (a reprductin f ig. 3.4.7). The bd frce will var depending n the size f the material under cnsideratin, e.g. the frce f gravit b mg will be larger fr larger materials; therefre cnsider a quantit which is independent f the amunt f material: the bd frce per unit mass, b / m. Then, Eqn 3.4.5 nw reads : AB OB cs OAsin OB sin OAcs / m m cs / m msin ma cs ma sin 0 b b (3.4.10) where m is the mass f the triangular prtin f material. The vlume f the triangle is AB /sin s that, this time, when 3.4.10 is divided thrugh b AB, ne has cs sin sin AB / m / sin / m / cs a / sin a / cs b b (3.4.11) where is the densit. Nw, as the element is shrunk in size dwn t the verte O, AB 0, and Eqn. 3.4.6 is recvered. Thus the Stress Transfrmatin Equatins are valid prvided the material under cnsideratin is ver small; in the limit, the are valid at the pint O. B a a b b O A igure 3.4.9: a free bd diagram f a triangular element f material, including a bd frce and acceleratin inall, cnsider the case where the stress is nt unifrm ver the faces f the triangular prtin f material. Intuitivel, it can be seen that, if ne again shrinks the prtin f material dwn in size t the verte O, the Stress Transfrmatin Equatins will again be 58 Kell

valid, with the quantities,, etc. being the values at the verte. T be mre precise, cnsider the stress acting ver the face OB in ig. 3.4.10. N matter hw the stress varies in the material, if the distance OB is small, the stress can be apprimated b a linear stress distributin, ig. 3.4.10b. This linear distributin can itself be decmpsed int tw cmpnents, a unifrm stress f magnitude (the value f at the verte) and a triangular distributin with maimum value. The resultant frce n the face is then OB /. This time, as the element is shrunk in size, 0 and Eqn. 3.4.6 is again recvered. The same argument can be used t shw that the Stress Transfrmatin Equatins are valid fr an varing stress, bd frce r acceleratin. B B O O igure 3.4.10: stress varing ver a face; (a) stress is linear ver OB if OB is small, linear distributin f stress as a unifrm stress and a triangular stress Three Dimensins Re-visited As the planes were rtated in the tw-dimensinal analsis, n cnsideratin was given t the stresses acting in the third dimensin. Cnsidering again a three dimensinal blck, ig. 3.4.11, there is nl ne tractin vectr acting n the plane at the material particle, t. This tractin vectr can be described in terms f the, z, aes as t i j k, ig 3.4.11a. Alternativel, it can be described in terms f the z z zz,, z aes as t zi zj zzk, ig 3.4.11b. 59 Kell

z z z t z t z z zz zz (a) igure 3.4.11: a three dimensinal material element; (a) riginal element, rtated element (rtatin abut the z ais) With the rtatin nl happening in the plane, abut the z ais, ne has, zz zz k k. One can thus eamine the tw dimensinal plane shwn in ig. 3.4.1, with i j i j. (3.4.1) z z z z Using sme trignmetr, ne can see that z z cs z sin. (3.4.13) sin cs z z z z t z z j i z igure 3.4.1: the tractin vectr represented using tw different crdinate sstems 60 Kell