Practice Paper Set 2 MAXIMUM MARK 100 FINAL. GCSE (9-1) MATHEMATICS J560/06 Paper 6 (Higher Tier) PRACTICE PAPER (SET 2) MARK SCHEME

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H Practice Paper Set GCSE (9-) MATHEMATICS J560/06 Paper 6 (Higher Tier) PRACTICE PAPER (SET ) MARK SCHEME Duration: hour 0 minutes MAXIMUM MARK 00 FINAL This document consists of pages

J560/06 Mark Scheme Practice Paper (Set ) Subject-Specific Marking Instructions. M marks are for using a correct method and are not lost for purely numerical errors. A marks are for an accurate answer and depend on preceding M (method) marks. Therefore M0 A cannot be awarded. B marks are independent of M (method) marks and are for a correct final answer, a partially correct answer, or a correct intermediate stage. SC marks are for special cases that are worthy of some credit.. Unless the answer and marks columns of the mark scheme specify M and A marks etc, or the mark scheme is banded, then if the correct answer is clearly given and is not from wrong working full marks should be awarded. Do not award the marks if the answer was obtained from an incorrect method, i.e. incorrect working is seen and the correct answer clearly follows from it.. Where follow through (FT) is indicated in the mark scheme, marks can be awarded where the candidate s work follows correctly from a previous answer whether or not it was correct. Figures or expressions that are being followed through are sometimes encompassed by single quotation marks after the word their for clarity, e.g. FT 80 (their 7 + 6), or FT 00 (their 5 + 7 ). Answers to part questions which are being followed through are indicated by e.g. FT their (a). For questions with FT available you must ensure that you refer back to the relevant previous answer. You may find it easier to mark these questions candidate by candidate rather than question by question. 4. Where dependent (dep) marks are indicated in the mark scheme, you must check that the candidate has met all the criteria specified for the mark to be awarded. 5. The following abbreviations are commonly found in GCSE Mathematics mark schemes. - figs 7, for example, means any answer with only these digits. You should ignore leading or trailing zeros and any decimal point e.g. 7000,.7,.70, 0.007 would be acceptable but 070 or 74 would not. - isw means ignore subsequent working after correct answer obtained and applies as a default. - nfww means not from wrong working. - oe means or equivalent. - rot means rounded or truncated. - seen means that you should award the mark if that number/expression is seen anywhere in the answer space, including the answer line, even if it is not in the method leading to the final answer. - soi means seen or implied.

J560/06 Mark Scheme Practice Paper (Set ) 6. In questions with no final answer line, make no deductions for wrong work after an acceptable answer (i.e. isw) unless the mark scheme says otherwise, indicated by the instruction mark final answer. 7. In questions with a final answer line following working space, (i) if the correct answer is seen in the body of working and the answer given on the answer line is a clear transcription error allow full marks unless the mark scheme says mark final answer. Place the annotation next to the correct answer. (ii) if the correct answer is seen in the body of working but the answer line is blank, allow full marks. Place the annotation next to the correct answer. (iii) if the correct answer is seen in the body of working but a completely different answer is seen on the answer line, then accuracy marks for the answer are lost. Method marks could still be awarded. Use the M0, M, M annotations as appropriate and place the annotation next to the wrong answer. 8. In questions with a final answer line: (i) If one answer is provided on the answer line, mark the method that leads to that answer. (ii) If more than one answer is provided on the answer line and there is a single method provided, award method marks only. (iii) If more than one answer is provided on the answer line and there is more than one method provided, award zero marks for the question unless the candidate has clearly indicated which method is to be marked. 9. In questions with no final answer line: (i) If a single response is provided, mark as usual. (ii) If more than one response is provided, award zero marks for the question unless the candidate has clearly indicated which response is to be marked. 0. When the data of a question is consistently misread in such a way as not to alter the nature or difficulty of the question, please follow the candidate s work and allow follow through for A and B marks. Deduct mark from any A or B marks earned and record this by using the MR annotation. M marks are not deducted for misreads.

J560/06 Mark Scheme Practice Paper (Set ). Unless the question asks for an answer to a specific degree of accuracy, always mark at the greatest number of significant figures even if this is rounded or truncated on the answer line. For example, an answer in the mark scheme is 5.75, which is seen in the working. The candidate then rounds or truncates this to 5.8, 5 or 6 on the answer line. Allow full marks for the 5.75.. Ranges of answers given in the mark scheme are always inclusive.. For methods not provided for in the mark scheme give as far as possible equivalent marks for equivalent work. If in doubt, consult your Team Leader. 4. Anything in the mark scheme which is in square brackets [ ] is not required for the mark to be earned, but if present it must be correct. 4

J560/06 Mark Scheme Practice Paper (Set ) (a).58 final answer M for.57[7 ] seen AO. or their answer seen to more than dp Both rounded and unrounded value AO.a corrected to dp must be seen (b) (i) ( + n) = 7 = 79 AO. (ii) 8 AO.a (a) Any two from,,, 4, 6 AO.a (b) Any valid explanation AO.4a e.g. S is a factor (a) Insufficient trials AO.5a Any acceptable reason (b) 8 AO.b AO.b B for two correct or for one correct with total balls = 0 Or M for 66 47 0 or 0 0 0 7 or 0 0 4 (a) Final amount is less than initial investment AO.4b Or equivalent correct reason (b) Used an incorrect multiplier for the interest rate AO.4a Or equivalent correct reason 5

J560/06 Mark Scheme Practice Paper (Set ) (c) 6498.40 or 6498.9 M for 5800.0 5 AO.a Or M for 5800.0 n oe Where n, n 5 5 (a).6 or 5 8 oe AO.b M for (x 4) = x or 6x 8 = x MFT for 6x x = 8 Alternative method: x M for x = 4 x Or M for x 4 = 0 (b) [ ] x = ± y + AO.a M for y + = x MFT for y + = x 6 (a) 75 AO.a (b) 8 to with correct working 4 AO.d AO. AO. M for 0.7 their 75 oe and 0.85 their 75 oe Or M for 0.7 their 75 oe or 0.85 their 75 oe AND M for reading from graph using their cardio interval Implied by.5 or and 48.75 or 49 seen Using their max and min cardio rates (c) Heart rate out of zone for about 4 minutes AO.4a Or heart rate less than 87.5 during the 50 minutes 7 69 4 AO.b AO.d AO. M for n 6 + n + n = 09 oe MFT for 5n = 09 + 6 A for n = Allow equivalent part marks for use of different person as starting point Rearrangement of their equation to isolate n terms 6

J560/06 Mark Scheme Practice Paper (Set ) 8 604.8 kg 4 B for answer 0.08 [kg] AO. OR AO.b AO.d M for 400 400 8 soi Volume calculation using consistent AO. units M for their volume 000 soi Conversion of mm to m for all dimensions done at any stage M for 50 their volume [ 60] soi Calculation of mass of or 60 slabs 9 (a) 4 oe on first set of branches 0 5 4, 9 9, 6, on second set of 9 9 branches AO.b B for two or more correct probabilities (b) 8 5 AO.b AO.a M for 6 4 + 4 6 oe 0 9 0 9 Or M for 6 4 oe or 4 6 oe 0 9 0 9 FT probabilities from their tree diagram for method marks 0 (a).0 0 6 4.04 0 5 AO. AO.b (b).54 0 7 AO.a (c) 5.7[0] 0 5 AO.b AO.a B for one correct or for.95[] 0 6 and 4.04 0 5 or for.0 0 m and 4.04 0 n B for.455 0 6 or.885 0 6 seen M for their (.455.885) 0 6 Where m and n are integers Using values in ranges.445 n.455 and.885 n.895 (a) E F B B AO.a 7

J560/06 Mark Scheme Practice Paper (Set ) (b) Clear intention AO.b (a) 4 48 7 AO.b (b) AO.b BFT for at least 5 points plotted correctly If 0 scored, SC for translation of correct curve (c) States correct with comparison showing approximately 8 employees over 55 and one quarter of 80 = 0 AO.b AO.5a FT reading from their cumulative frequency curve at 55 B for one quarter of employees = 0 or for approximately 8 employees over 55 FT their curve AM = MD given BMA = CMD vertically opposite BAM = CDM alternate angles Triangles AMB, DMC congruent, ASA M M M A 4 AO.4b After M0, B for two pairs of equal angles and one pair of equal sides with insufficient or no reasons Or B for two pairs of equal angles identified Accept any correct proof 8

J560/06 Mark Scheme Practice Paper (Set ) 4 (a) x -, x 4 M for (x 4)(x + ) AO.b A for solutions - and 4 seen (b) - 4 AO.a AO.b M for y = x + 4 drawn M for x + y = 5 drawn MFT for correct region/points identified on graph 5 (a) 6 x y AO.a M for x y or x y 6 6 x y (b) (i) x y AO.a (ii) x + 4x ( x )( x + ) x(x + 4) or x + x 6 or x(x + 4) ( x )( x + ) AO.b M for numerator 4x(x + ) x(x ) oe M for denominator (x )(x + ) oe 6 (a).44 AO.a (b) 56.5 AO.a AO.a AO. M for 9 4 = y 0 oe Or M for 9 4 k or y = soi x M for.565 or 0.8 soi Or M for 0.8 soi Alternative method: M for calculation of values of y for their x and their 0.8x M for calculation of percentage increase in y values 9

J560/06 Mark Scheme Practice Paper (Set ) 7 (a) Gradient AB = 4 M Calculation of gradient of AB = 7 Gradient BC = 4 = 0 7 M Calculation of gradient of BC Product of gradients = = A Perpendicular because product of gradients is - B AO.4b AO.b (b) 8.06[ ] or 65 4 AO.b AO.a AO. 8 (a) hours minutes 6 AO.b AO.d AO. AO. B for identifying AC as hypotenuse M for (0 ) + ( ) Or M for attempt to use Pythagoras M for [AC ] =.8 + 6..8 6. cos 95 Or M for attempt to use cosine rule AND A for [AC =] 7.0 M for (.8 + 6. + their 7.0) 5 Or M for attempt at their distance 5 (b) Any sensible assumption about distance, speed or time e.g. he walks in a straight line e.g. he doesn t have a rest Any sensible explanation AO.5 9 (a) 4a b AO.b AO.b B for AD = a or BC = b soi Allow OD = 4a e.g. underestimate so time would be longer or OC = b for B 0

J560/06 Mark Scheme Practice Paper (Set ) (b) AD = CE = a M M for AD = a or CE = a AC = DE = b a M M for AC = b a or DE = b a Opposite sides equal and parallel hence ACED is a parallelogram A AO.4a AO.b AO.

J560/06 Practice Paper (Set ) Assessment Objectives (AO) Grid Question AO AO AO Total (a) 0 0 (b)(i) 0 0 (b)(ii) 0 0 (a) 0 0 (b) 0 0 (a) 0 0 (b) 0 4(a) 0 0 4(b) 0 0 4(c) 0 0 5(a) 0 0 5(b) 0 0 6(a) 0 0 6(b) 0 0 4 4 6(c) 0 0 7 0 4 8 0 4 9(a) 0 0 9(b) 0 0(a) 0 0(b) 0 0 0(c) 0 (a) 0 0 (b) 0 0 (a) 0 0 (b) 0 0 (c) 0 0 0 4 0 4 4(a) 0 0 4(b) 0 4 5(a) 0 0 5(b)(i) 0 0 5(b)(ii) 0 0 6(a) 0 0 6(b) 0 7(a) 0 4 7(b) 0 4 8(a) 0 4 6 8(b) 0 0 9(a) 0 9(b) 0 4 5 Totals 40 0 0 00