Name (please print) π cos(θ) + sin(θ)dθ

Similar documents
Name (please print) π cos(θ) + sin(θ)dθ

Calculus III. Math 233 Spring Final exam May 3rd. Suggested solutions

MATH 2400 Final Exam Review Solutions

Name: Date: 12/06/2018. M20550 Calculus III Tutorial Worksheet 11

Math 3435 Homework Set 11 Solutions 10 Points. x= 1,, is in the disk of radius 1 centered at origin

In general, the formula is S f ds = D f(φ(u, v)) Φ u Φ v da. To compute surface area, we choose f = 1. We compute

Math 263 Final. (b) The cross product is. i j k c. =< c 1, 1, 1 >

Math 233. Practice Problems Chapter 15. i j k

The Divergence Theorem

MATHS 267 Answers to Stokes Practice Dr. Jones

Ma 1c Practical - Solutions to Homework Set 7

MATHEMATICS 200 April 2010 Final Exam Solutions

7a3 2. (c) πa 3 (d) πa 3 (e) πa3

Sections minutes. 5 to 10 problems, similar to homework problems. No calculators, no notes, no books, no phones. No green book needed.

MATHEMATICS 317 April 2017 Final Exam Solutions

MATH 52 FINAL EXAM DECEMBER 7, 2009

MATH 52 FINAL EXAM SOLUTIONS

Solutions to Math 41 Final Exam December 9, 2013

Review problems for the final exam Calculus III Fall 2003

Assignment 11 Solutions

MATHEMATICS 200 December 2013 Final Exam Solutions

Problem Set 5 Math 213, Fall 2016

MAT 211 Final Exam. Spring Jennings. Show your work!

( ) ( ) ( ) ( ) Calculus III - Problem Drill 24: Stokes and Divergence Theorem

MAC2313 Final A. (5 pts) 1. How many of the following are necessarily true? i. The vector field F = 2x + 3y, 3x 5y is conservative.

Solutions to Sample Questions for Final Exam

xy 2 e 2z dx dy dz = 8 3 (1 e 4 ) = 2.62 mc. 12 x2 y 3 e 2z 2 m 2 m 2 m Figure P4.1: Cube of Problem 4.1.

MATHEMATICS 317 December 2010 Final Exam Solutions

1969 AP Calculus BC: Section I

MATH 52 MIDTERM 1. April 23, 2004

Math 11 Fall 2016 Final Practice Problem Solutions

Math. 151, WebCalc Sections December Final Examination Solutions

Multiple Choice. Compute the Jacobian, (u, v), of the coordinate transformation x = u2 v 4, y = uv. (a) 2u 2 + 4v 4 (b) xu yv (c) 3u 2 + 7v 6

2. Below are four algebraic vector fields and four sketches of vector fields. Match them.

Jim Lambers MAT 280 Summer Semester Practice Final Exam Solution. dy + xz dz = x(t)y(t) dt. t 3 (4t 3 ) + e t2 (2t) + t 7 (3t 2 ) dt

Name: Instructor: Lecture time: TA: Section time:

1985 AP Calculus AB: Section I

Summer Review Packet AP Calculus

LINE INTEGRALS AND SURFACE INTEGRALS TEST 5 HOMEWORK PACKET A. Vector Fields and Line Integrals 1. Match the vector field with its plot.

Mathematics (Course B) Lent Term 2005 Examples Sheet 2

F ds, where F and S are as given.

Math 20C Homework 2 Partial Solutions

Calculus 152 Take Home Test 2 (50 points)

Note: Each problem is worth 14 points except numbers 5 and 6 which are 15 points. = 3 2

MULTIVARIABLE INTEGRATION

MATH 162. FINAL EXAM ANSWERS December 17, 2006

Review Sheet for the Final

Power Series. x n. Using the ratio test. n n + 1. x n+1 n 3. = lim x. lim n + 1. = 1 < x < 1. Then r = 1 and I = ( 1, 1) ( 1) n 1 x n.

1. If the line l has symmetric equations. = y 3 = z+2 find a vector equation for the line l that contains the point (2, 1, 3) and is parallel to l.

Created by T. Madas SURFACE INTEGRALS. Created by T. Madas

APPM 1360 Final Exam Spring 2016

MATH 280 Multivariate Calculus Fall Integration over a curve

Math Calculus II Homework # Due Date Solutions

MATH 223 FINAL EXAM STUDY GUIDE ( )

SOLUTIONS TO THE FINAL EXAM. December 14, 2010, 9:00am-12:00 (3 hours)

Mat 267 Engineering Calculus III Updated on 9/19/2010

x + ye z2 + ze y2, y + xe z2 + ze x2, z and where T is the

Math Review for Exam 3

MATH 332: Vector Analysis Summer 2005 Homework

HOMEWORK 8 SOLUTIONS

One side of each sheet is blank and may be used as scratch paper.

S12.1 SOLUTIONS TO PROBLEMS 12 (ODD NUMBERS)

SOME PROBLEMS YOU SHOULD BE ABLE TO DO

Sept , 17, 23, 29, 37, 41, 45, 47, , 5, 13, 17, 19, 29, 33. Exam Sept 26. Covers Sept 30-Oct 4.

M151B Practice Problems for Exam 1

3, 1, 3 3, 1, 1 3, 1, 1. x(t) = t cos(πt) y(t) = t sin(πt), z(t) = t 2 t 0

I) Simplifying fractions: x x. 1) 1 1 y x. 1 1 x 1. 4 x. 13x. x y xy. x 2. Factoring: 10) 13) 12) III) Solving: x 9 Prime (using only) 11)

CALCULUS AB/BC SUMMER REVIEW PACKET (Answers)

Amherst College, DEPARTMENT OF MATHEMATICS Math 11, Final Examination, May 14, Answer Key. x 1 x 1 = 8. x 7 = lim. 5(x + 4) x x(x + 4) = lim

MA 351 Fall 2008 Exam #3 Review Solutions 1. (2) = λ = x 2y OR x = y = 0. = y = x 2y (2x + 2) = 2x2 + 2x 2y = 2y 2 = 2x 2 + 2x = y 2 = x 2 + x

53. Flux Integrals. Here, R is the region over which the double integral is evaluated.

MATH 228: Calculus III (FALL 2016) Sample Problems for FINAL EXAM SOLUTIONS

APJ ABDUL KALAM TECHNOLOGICAL UNIVERSITY FIRST SEMESTER B.TECH DEGREE EXAMINATION, FEBRUARY 2017 MA101: CALCULUS PART A

MLC Practice Final Exam

Integral Theorems. September 14, We begin by recalling the Fundamental Theorem of Calculus, that the integral is the inverse of the derivative,

and ( x, y) in a domain D R a unique real number denoted x y and b) = x y = {(, ) + 36} that is all points inside and on

MATH 263 ASSIGNMENT 9 SOLUTIONS. F dv =

University of Alberta. Math 214 Sample Exam Math 214 Solutions

1. Evaluate the integrals. a. (9 pts) x e x/2 dx. Solution: Using integration by parts, let u = x du = dx and dv = e x/2 dx v = 2e x/2.

z k sin(φ)(x ı + y j + z k)da = R 1 3 cos3 (φ) π 2π dθ = div(z k)dv = E curl(e x ı + e x j + e z k) d S = S

Integrals in cylindrical, spherical coordinates (Sect. 15.7)

Math 221 Examination 2 Several Variable Calculus

Green s, Divergence, Stokes: Statements and First Applications

16.5 Surface Integrals of Vector Fields

Page Points Score Total: 210. No more than 200 points may be earned on the exam.

McGill University April 16, Advanced Calculus for Engineers

1 + f 2 x + f 2 y dy dx, where f(x, y) = 2 + 3x + 4y, is

ES.182A Topic 44 Notes Jeremy Orloff

Problem Set 6 Math 213, Fall 2016

G G. G. x = u cos v, y = f(u), z = u sin v. H. x = u + v, y = v, z = u v. 1 + g 2 x + g 2 y du dv

Answer sheet: Final exam for Math 2339, Dec 10, 2010

Limits. Final Exam Study Guide. Calculus I. 1. Basic Limits I: Evaluate each limit exactly. (a) lim. (c) lim. 2t 15 3 (g) lim. (e) lim. (f) lim.

HOMEWORK SOLUTIONS MATH 1910 Sections 8.2, 8.3, 8.5 Fall 2016

( ) 7 ( 5x 5 + 3) 9 b) y = x x

1 4 (1 cos(4θ))dθ = θ 4 sin(4θ)

MTH 234 Solutions to Exam 2 April 13, Multiple Choice. Circle the best answer. No work needed. No partial credit available.

Math 11 Fall 2007 Practice Problem Solutions

The region enclosed by the curve of f and the x-axis is rotated 360 about the x-axis. Find the volume of the solid formed.

Practice Problems for Exam 3 (Solutions) 1. Let F(x, y) = xyi+(y 3x)j, and let C be the curve r(t) = ti+(3t t 2 )j for 0 t 2. Compute F dr.

3. On the grid below, sketch and label graphs of the following functions: y = sin x, y = cos x, and y = sin(x π/2). π/2 π 3π/2 2π 5π/2

Transcription:

Mathematics 2443-3 Final Eamination Form B December 2, 27 Instructions: Give brief, clear answers. I. Evaluate by changing to polar coordinates: 2 + y 2 3 and above the -ais. + y d 23 3 )/3. π 3 Name please print) r cosθ) + r sinθ))r dr dθ + y d where is the region between 2 + y 2 and π cosθ) + sinθ)dθ 3 r 2 dr II. For the function f,y) ln 2 +y 2 ), find the maimum rate of change at the point 2,), and the direction in which it occurs. Find the directional derivative of f at 2,) in the direction toward 4,2). We have f,y) 2 ı + 2y j, so f2,) 4 2 +y 2 2 +y 2 ı + 2 j. The maimum rate of change at 2,) is f2,) 4 ı + 2 j 2, and it is in the direction of f2,). A vector in the direction from 2,) toward 4,2) is 2 ı + j, so a unit vector in that direction is u 2 ı + j. The rate of change in that direction is f2,) u 2. Alternatively, one can observe that the given direction is eactly the direction of f,2), so the rate of change in that direction, as already found, is f2,) 2.) III. Let be the portion of the sphere of radius a that lies in the first octant. Use the standard parameterization of to calculate y ı j + k ) d. If is the region θ π/2, φ π/2 in the θφ-plane, then y ı j + k) d y ı j + k) r φ r θ )d y ı j + k) a sinφ) ı + y j + z k)d asinφ)z d π/2 dθ π/2 asinφ)acosφ)dφ π/2)a 2 sin 2 φ)/2 π/2 πa 2 /4 IV. V. ) The radius of a right circular cone is increasing at a rate of 3 in/s while its height is decreasing at a rate of 6 in/s. At what rate is the volume V πr 2 h/3 changing when the radius is and the height is? Using the Chain ule, dv dt πr2 h/3) dr r dt + πr2 h/3) dr h dt 2πrh dr 3 dt + πr2 dh. Evaluating when 3 dt r and h, we find dv dt π 3 + π 6) π. It is decreasing at a rate of π 3 3 in 3 /s. Use the Divergence Theorem to calculate the surface integral 2 z 3 ı + 2yz 3 j + z 4 k ) d, where is the surface of the bo with 3, y 2, z. 2 z 3 ı + 2yz 3 j + z 4 k ) d 2z 3 + 2z 3 + 4z 3 dv 2 3 8z 3 ddy dz 3 2d 2 E dy 4z 3 dz 9 2 8.

Page 2 VI. VII.. 2. Let be the upper half of the sphere of radius 2, that is, the points,y,z) with 2 + y 2 + z 2 4 and z, and suppose that is oriented with the upward normal. Use tokes Theorem to evaluate curl 2 e yz ı + y 2 e z j + z 2 e y k) d. The boundary of is the circle C of radius 2 in the y-plane, with the positive orientation. By tokes Theorem, curl 2 e yz ı + y 2 e z j + z 2 e y k) d 2 e yz ı + y 2 e z j + z 2 e y k) d r. On C C, z, so this line integral is C 2 ı + y 2 j) d r. Using Green s Theorem, 2 ı + y 2 j) d r C y 2 2 dd. y D Let be the upper half of the sphere of radius, that is, the points,y,z) with 2 + y 2 + z 2 and z. Using the geometric interpretation of the surface integral of a vector field as the flu that is, not by calculation using a parameterization or a formula from the formulas list), eplain each of the following equalities: j d Consider the flow of unit speed in the j direction. j d is the net flow per unit time) across. ince this flow is horizontal, the amount that flows into the hemisphere on the left side eactly equals the amount that flows out of it on the right, so the net flow is. k d π Consider the flow of unit speed in the k direction. k d 2π is the net flow per unit time across. ince the flow is directly upward, the amount that flows across is the same as the amount that flows across the the unit disk in the y-plane. The amount of vertical flow per unit time is just the area of this disk, which is π. VIII. Verify that the function u sin at) + ln + at) is a solution to the wave equation u tt a 2 u. sin at) + ln + at)) tt acos at) + a ) + at a 2 t a2 sin at) + at) 2 and sin at) + ln + at)) cos at) + ) + at sin at) + at) 2, so a 2 u a 2 ) sin at) + at) 2 a 2 a 2 sin at) + at) 2 u tt.

Page 3 Name please print) IX. ) Let be the portion of the cylinder 2 + z 2 4 that lies between the vertical planes y and y 2. The surface is parameterized by 2cosθ), y h, z 2sinθ) for θ 2π and h 2 2cosθ).. Calculate r θ, r h, r h r θ, and r h r θ. r θ 2sinθ) ı + 2cosθ) k and r h j. ı j k r h r θ 2cosθ) ı + 2sinθ) k, so r h r θ 4cos 2 θ) + 4sin 2 θ) 2. 2 sinθ) 2 cosθ) 2. Calculate d. d r h r θ d 2d, where is the region θ 2π and h 2 cosθ) in the parameter domain. o we have 2 2cosθ) d cosθ)2d 2cosθ)dhdθ 2cosθ)2 2cosθ))dθ 3. Calculate k d. k d 2 cosθ) 4cosθ) 2 + cos2θ))dθ 4π + 4π. k r h r θ )d 2sinθ)cosθ)dhdθ k 2cosθ) ı + 2sinθ) k)d 2sinθ)cosθ)2 cosθ))dθ 4sinθ)cosθ) 2sinθ)cos 2 θ)dθ 2sin 2 θ) 2cos 3 θ)/3 2sinθ)cosθ)d 2π. X. The curl of the vector field y ı z j + k is ı j k. Let be the triangle which is the part of the plane 2 + y + z 2 that lies in the first octant. Give the upward normal, and give its boundary C the corresponding positive orientation. Use tokes Theorem to evaluate the line integral y ı z j+ k) d r. C Hint: the surface integral on is easy to calculate if one uses the definition G d G n d.) A normal vector to is 2 ı+ j+ k. This is upward, since the k-component is positive, and 2 ı+ j+ k 6, so a unit upward normal is n / 6)2 ı + j + k). Using tokes Theorem, we have y ı + z j + k) d r curly ı + z j + k) d ı j k) nd C ı j k) / 6)2 ı + j + k))d / 6)2 )d.

Page 4 XI. On two different coordinate systems, graph the following vector fields:. F,y) ı + y j 2. F,y) y 2 + y 2 ı + 2 + y 2 j XII. 3) XIII. ) A function of the variables, 2, and 3 is given implicitly by + 2 + 3. Use implicit differentiation to find 3. Applying, we have 3 2 3 3 2, so 2 3 3 2. Use the Divergence Theorem to show that if E is a solid with boundary the surface, then 3 ı + y 3 j + z 3 k) d always equals the volume of E. 3 ı + y 3 j + z 3 k) d E 3 + 3 + 3 dv dv vole). E

Page Name please print) XIV. ketch the region and change the order of integration for e e f,y)dy d. e ye lny) e lny) f,y)ddy. XV. In an y-coordinate system, sketch the gradient of the function whose graph is shown to the right. z y y