Traffic Flow Theory and Simulation

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Transcription:

Traffic Flow Theory and Simulation V.L. Knoop Lecture 2 Arrival patterns and cumulative curves

Arrival patterns From microscopic to macroscopic 24-3-2014 Delft University of Technology Challenge the future

Recap traffic flow variables Microscopic (vehicle-based) Space headway (s [m]) Time headway (h [s]) Speed (v [m/s]) s=h*v Macroscopic (flow-based) Density (k [veh/km]) Flow (q [veh/h]) Average speed (u [km/h]) q=k*u Lecture 2 Arrival patterns 3 32

Excercise a task for you! What is the average speed if you travel 10 km/h from home to university 20 km/h on the way back What is the average speed if you make a trip with speed v1 on the outbound trip v2 on the inbound trip What is the average speed if you split the trip in n equidistant sections, which you travel in v i Lecture 2 Arrival patterns 4 32

Similar problems arise in traffic Local measurements, spatial average speed needed Weigh speed measurements Inversely proportional to speed Lecture 2 Arrival patterns 5 32

The math Weigh speed measurements (w) Inversely proportional to speed: wi=1/vi Time-average of pace (1/v) Lecture 2 Arrival patterns 6 32

and the effect What is higher time mean speed (A) or space mean speed (B)? Lecture 2 Arrival patterns 7 32

Summary Speed averaging is not trivial Obtain time mean speed from loop detector data by harmonic average (i.e., averaging 1/v) Space mean speed is lower, with differences in practice up to factor 2 Lecture 2 Arrival patterns 8 32

Overview of remainder of lecture Arrival process and relating probability distribution functions Poisson process (independent arrivals) Neg. binomial distribution and binomial distribution Applications facility design (determine length rightor left-turn lane) Time headway distributions Distribution functions and headway models Applications Speed distribution and free speed distributions Lecture 2 Arrival patterns 9 32

Arrival processes Insight into probability distribution of the number of vehicles arriving in a short time interval (e.g. 15 seconds) is important for several applications Example: Length of extra lane for left-turning vehicles at an intersection Probability that queue exceeds roadway space is limited (e.g. 5%) Models for the distribution of vehicles arriving in a short period of time Poisson process Binomial process Negative binomial process No blocking back due to extra lane Blocking back due to extra lane Arrival location x Lecture 2 Arrival patterns 10 32

Poisson process Number of vehicles passing x during certain period of length h N(h) can be described by a stochastic variable Assume independent arrivals Dilute traffic operations w. sufficient passing opportunities No upstream disturbances (e.g. signalized intersection) Then nr of arrivals N(h) is Poisson: Lecture 2 Arrival patterns 11 32

Properties of the Poisson distribution Mean and variance are equal (= µ h ) for a certain period of length h If mean = variance then Poisson is likely And thus independence of arrivals is a good assumptions Lecture 2 Arrival patterns 12 32

Poisson process (2) Examples of Poisson distributions for different periods / intensities µ h = 0.6 µ h = 3 Lecture 2 Arrival patterns 13 32

Poisson and real data (arrivals / 15s) Two-lane rural road in the Netherlands Lecture 2 Arrival patterns 14 32

Poisson and real data (arrivals / 15s) Two-lane rural road in the Netherlands Lecture 2 Arrival patterns 15 32

Poisson and real data (arrivals / 15s) Two-lane rural road in the Netherlands Lecture 2 Arrival patterns 16 32

Poisson process (3): exercise Application to left-turn lane design problem Intensity for left-turning lane during peak-hour = 360 veh/h Duration of the red-phase 50s In 95% of the cycles must be undersaturated How long must the left-lane be? Assume Poisson process; Mean number of arrivals 50 (360/3600) = 5 Thus µ h = 5 veh per h (= qh with q = 360 and h = 50/3600) Number of arrivals N = Poisson Lecture 2 Arrival patterns 17 32

Poisson process (3): exercise Application to left-turn lane design problem Intensity for left-turning lane during peak-hour = 360 veh/h Duration of the red-phase 50s In 95% of the cycles must be undersaturated How long must the left-lane be? Assume Poisson process: Mean number of arrivals 50 (360/3600) = 5 Thus λ = 5 veh per aggregation interval (= qh with q = 360 and h = 50/3600) Number of arrivals N = Poisson Lecture 2 Arrival patterns 18 32

Poisson process (4) From graph: Pr(N 8) = 0.9319 Pr(N 9) = 0.9682 If the length of the left-turn lane can accommodate 9 vehicles, the probability of blocking back = 3.18% Lecture 2 Arrival patterns 19 32

Two other possibilities 1. Vehicles are (mainly) following => binomial distribution 2. Downstream of a regulated intersection => negative binomial distribtution Lecture 2 Arrival patterns 20 32

Binomial process Increase traffic flow yields formation of platoons (interaction) Poisson is no longer valid description Alternative: Binomial process Binomial distribution describes the probability of n successful, independent trials; the probability of success equals p; n 0 = max. number of arrivals within period h Lecture 2 Arrival patterns 21 32

Properties of binomial distribution Mean: n 0 p and variance: n 0 (1 p)p Note that variance < mean No rationale why approach yields reasonable results Choose appropriate model by statistical testing! Lecture 2 Arrival patterns 22 32

Binomial process (3) Left-turn example revisited Note: variance < mean! Assume a variance of 2.5 veh 2 / cycle (=50 sec) Determine how long the left-turning lane must be under these assumptions Hint: use the recursive formula in reader (Home work) Lecture 2 Arrival patterns 23 32

Downstream of controlled intersection More likely to have bunched vehicles (Why?) Negative binomial distribution Lecture 2 Arrival patterns 24 32

How to determine model to use? Some guidelines: Are arrivals independent => Poisson distribution Low traffic volumes Consider traffic conditions upstream (but also downstream) Consider mean and variance of arrival process Platooning due to regular increase in intensity? => Binomial Downstream of signalized intersection? => Negative binomial Definitive answer? Use statistical tests (Chi-square tests) to figure out which distribution is best Lecture 2 Arrival patterns 25 32

Time headways A time headway of a vehicle is defined by the period between the passing moment of the preceding vehicle and the vehicle considered Distinction between Net headway (gap): rear bumper front bumper Gross headway: rear bumper rear bumper Headway distribution models generally pertain to a single lane Lecture 2 Arrival patterns 26 32

Example headway distribution two-lane road Site: Doenkade 0.8 histogram 0.6 0.4 0.2 0.0 0 2 4 gross headway W (s) 6 >8 Lecture 2 Arrival patterns 27 32

Exponential distribution Lecture 2 Arrival patterns 28 32

Maximum likelihood Maximum-likelihood method aims to maximize the probability of the parameters given the sample (observation) The likelihood of a single observation h i equals (lambda parameter) The likelihood of an entire sample {h i } equals Lecture 2 Arrival patterns 29 32

Optimisation of parameters The probability of an entire sample {h i } equals ML entails maximizing this likelihood, i.e. Lecture 2 Arrival patterns 30 32

Composite headway models Composite headway models distinguish Vehicles that are driving freely (and thus arrive according to some Poisson process, or whose headways are exponentially distributed) Vehicles that are following at some minimum headway (so-called empty zone, or constrained headway) which distribution is suitable? Lecture 2 Arrival patterns 31 32

Basic idea Combine two distribution functions Contstraint: fraction phi Free: fraction (1-phi) Application: capactiy estimation How? Lecture 2 Arrival patterns 32 32

Estimation: likelyhood or graphically Lecture 2 Arrival patterns 33 32

Summary Arrival distribution: Free flow: headways exponential, nr of per aggregation time: Poisson Following: binomial Calculation of required dedicated lane length Composite headway models => capacity estimation Lecture 2 Arrival patterns 34 32

Binomial process (2) Examples of the binomial process Lecture 2 Arrival patterns 35 32

Cowan s M3 model Drivers have a certain minimum headway x which can be described by a deterministic variable Minimum headway x describes the headway a driver needs for safe and comfortable following the vehicle in front If a driver is not following, we assume that he / she is driving at a headway u which can be described by a random variate U ~ p free (u) The headway h of a driver is the sum of the free headway u and the minimum headway x, and thus H = x+u The free headway is assumed distributed according to the exponential distribution (motivation?) Lecture 2 Arrival patterns 36 32

Cowan s M3 model Probability density function of H ph ( ) = φδ ( x h) + (1 φ) p ( h) = p( h) + p( h) 1 2 Unless there are major upstream disturbances, the free headways are exponentially distributed, i.e. 2 The model thus assumes that all constrained drivers maintain headway x, while the headway of the unconstrained drivers is distributed according to a shifted exponential distribution free ( h x) λ p( h) = (1 φ) p ( h) = (1 φ) Hh ( x) λe for h> x free Lecture 2 Arrival patterns 37 32

Cowan s M3 model Example of Cowan s M3 model (note that h 0 = x) Lecture 2 Arrival patterns 38 32

Branston s headway distribution model Rather that assuming one fixed x for all drivers, we can assume that different drivers maintain different minimum headways Inter-driver differences are reflected by assuming that x is also a stochastic variable X with a specific distribution function p follow (x) This yields the composite headway distribution model of Branston: ph φp h φ p h ( ) = ( ) + (1 ) ( ) follow free λh λs = φp follow( h) + (1 φλ ) e p follow( s) e ds h 0 Lecture 2 Arrival patterns 39 32

Buckley s composite model Drivers have a certain minimum headway x which can be described by a random variable X ~ p follow (x) Minimum headway describes the headway a driver needs for safe and comfortable following the vehicle in front X describes differences between drivers and within a single driver If a driver is not following, we assume that he / she is driving at a headway u which can be described by a random variate U ~ p free (u) The headway h of a driver is then the minimum between the free headway u and the minimum headway x, and thus H = min{x,u} Lecture 2 Arrival patterns 40 32

Buckley s composite model 3 Consider a threshold value h * such that all observed headways h are larger than h * are free headways, i.e. p follow (h) = 0, h > h * Lecture 2 Arrival patterns 41 32

Buckley s composite model 4 Unless there are major upstream disturbances, the free headways are exponentially distributed, i.e. h ph ( ) = (1 φ) p ( h) = Aλe λ for h> h For headways h smaller than h *, we need to correct the total headway. This is done by removing from the exponential distribution the fraction of vehicles that have preferred following times larger than h The fraction of drivers with headway h that are not following equals h Then for h < h * we (1 have θ( hfor )) = the (1 free φ) pheadway follow( η) dη part free 0 * λh λh p2( h) = (1 φ) pfree( h) = (1 θ( h)) Aλe = Aλe (1 φ) pfollow( η) dη 0 h Lecture 2 Arrival patterns 42 32

Buckley s composite model 5 For the total headway distribution, we then get λh ph ( ) = φpfollow( h) + (1 φ) Aλe pfollow( η) dη where A denotes the normalization constant and can be determined from 0 h λη p( η) dη = 1 A= λe pfollow( η) dη Special estimation 0 procedures exist to determine 0 λ, φ and p.d.f. p follow (h) Parametric: specify p.d.f. p follow (h) with unknown parameters Distribution free, non-parametric, i.e. without explicit specification p follow (h) Lecture 2 Arrival patterns 43 32

Determination of h * For h > h *, distribution is exponential, i.e. Consider survival function S(h) Obviously, for h > h * λh, we have [ ] Suppose we have headway sample {h } i Consider the empirical distribution function Now draw h ph ( ) = Aλe λ for h> h λη S( h) = Pr( H > h) = Aλe dη = Ae ˆ 1 Sn ( h ) = 1 Hh ( hi ) n ln Sˆ n( h) h and determine h *, A, and λ * λh ln S( h) = ln Ae = ln( A) λh Lecture 2 Arrival patterns 44 32

Applications of headway distributions Analysis of crossing a street / gap-acceptance Calculate waiting time or delay Capacity estimation (without capacity observations) using composite headway models of Cowan / Branston / Buckley Estimate all parameters of composite headway distribution Assume all vehicles are following (ϕ = 1) to see that (p(h) = p follow (h)), i.e. headway is minimal: we have mean(h) = mean(x) Recall that q = 1/mean(H) Estimate mean headway (mean empty zone) and capacity Vehicle generation for micro-simulation C 1 1 = = mean ( X ) xp ( x ) dx 0 follow Lecture 2 Arrival patterns 45 32

Binomial process (3) Left-turn example revisited Assume a variance of 2.5 veh 2 / cycle (=50 sec) Determine how long the left-turning lane must be under these assumptions Mean number of arrivals 5 : n 0 p = 5 Assume variance of 2.5 veh 2 : n 0 (1 p)p = 2.5 Then we can determine: p = 0.5 and n 0 = 10 Results are very sensitive to variance!! Lecture 2 Arrival patterns 46 32

Binomial process (4) From graph: Pr(N 7) = 0.9453 Pr(N 8) = 0.9893 If the length of the left-turn lane can accommodate 7 vehicles, the probability of blocking back = 5.47% Lecture 2 Arrival patterns 47 32

Negative Binomial distribution Also consider negative Binomial distribution (see course notes) n0 + n 1 n n 0 Pr ( Nh ( ) = n) = p ( 1 p) n Appears to hold when upstream disturbances are present Choose appropriate model by trial and error and statistical testing Lecture 2 Arrival patterns 48 32

Neg. bin. distribtion & observations Two-lane rural road in the Netherlands Lecture 2 Arrival patterns 49 32

Neg. bin. distribtion & observations Two-lane rural road in the Netherlands Lecture 2 Arrival patterns 50 32

Neg. bin. distribtion & observations Two-lane rural road in the Netherlands Lecture 2 Arrival patterns 51 32

Example real-life headway distribution Pedestrian experiments Headways of pedestrians passing a certain cross-section (wide bottleneck scenario) Lecture 2 Arrival patterns 52 32

Exponential distribution (2) Exponential distribution function / survival function 1 mean ( H) = H = q var H 1 q ( ) = 2 Pr 1 0.5 Pr{H # h} 0 2 4 6 8 10 12 14 h Pr{H > h} Lecture 2 Arrival patterns 53 32

Cumulative curves Calculation of delays and queues 24-3-2014 Delft University of Technology Challenge the future

Cumulative vehicle plots Cumulative flow function N x (t): number of vehicles that have passed cross-section x at time instant t N x (t): step function that increases with 1 each time instant vehicle passes Horizontal axis: trip times Vertical axis: vehicle count (storage) time (s) N () x 1 t N () x 2 t time (s) Lecture 2 Arrival patterns 55 32

Examples of cumulative curves? 1 N 2 3 4 5 6 time Lecture 2 Arrival patterns 56 32

Construction of cumulative curves Lecture 2 Arrival patterns 57 32

Information in cumulative curves N dn/dt =??flow time Lecture 2 Arrival patterns 58 32

Cumulative vehicle plots 3 Flow = number of vehicles passing x (observer) during T What is the flow in this case? 2500 2000 Observer 1 1500 N 1 (8.0) = 1500 1000 N 1 (7.5) = 1000 500 T = 0.5 h 0 6.5 7 7.5 8 8.5 9 9.5 time (h) Lecture 2 Arrival patterns 59 32

Information in cumulative curves N A B 2 time Which line corresponds with detector 1? 1 Lecture 2 Arrival patterns 60 32

Lecture 2 Arrival patterns 61 32

Information in cumulative curves N 1 2 2 N Travel time time 1 Lecture 2 Arrival patterns 62 32

Intermezzo - capacity Capacity is the maximum flow on a cross section What determines the capacity Nr of lanees Minimum headway influenced by Speed limit 1.5 s/veh = 2400 veh/h Lecture 2 Arrival patterns 63 32

Bottleneck in section Lecture 2 Arrival patterns 64 32

What if bottleneck is present N A B 2 Travel time time Flow limited to capacity Travel time increses More vehicles in the section 1 Lecture 2 Arrival patterns 65 32

Delay = area N A B 2 time Total delay = sum delay over vehicles Total delay = sum # extra vehicles in section 1 Lecture 2 Arrival patterns 66 32

Controlled intersection Lecture 2 Arrival patterns 67 32

Delay (2) Capacity Capacity Lecture 2 Arrival patterns 68 32

cumulative counts Real-life curves 2500 2000 1500 Observer 1 Observer 8 1000 Number of vehicles between observer 1 and 8 Travel time vehicle 1000 500 Travel time vehicle 500 0 6.5 7 7.5 8 8.5 9 9.5 time (h) Number of vehicles between observers can be used to determine density! Lecture 2 Arrival patterns 69 32

cumulative counts Application Applications: identification of stationary periods (constant flow) In this case, cumulative curves are (nearly) straight lines 2200 2100 2000 1900 Red phase Observer 8 1800 1700 Reduced flow during green phase 1600 Saturation flow during green phase 8.25 8.3 8.35 8.4 8.45 8.5 8.55 8.6 8.65 8.7 8.75 time (h) Lecture 2 Arrival patterns 70 32

Oblique curves Amplify the features of the curves by applying an oblique scaling rate q 0 Use transformation: N2=N-q0t Lecture 2 Arrival patterns 71 32

Oblique curves Notice that density can still be determined directly from the graph; accumulation of vehicles becomes more pronounced This holds equally for stationary periods For flows note that q 0 needs to be added to the flow determined from the graph by considering the slope op the slanted cumulative curve Lecture 2 Arrival patterns 72 32

Use of oblique curves Can delay be read directly from oblique cumulative curves A=yes B=no Can travel times be read directly from oblique cumulative curves? A=yes B=no Lecture 2 Arrival patterns 73 32

Delay determination simpeler Lecture 2 Arrival patterns 74 32

Deeper analysis Capacity Capacity Bottleneck Capacity Demand Demand Lecture 2 Arrival patterns 75 32

Simplest queuing model Vertical queuing model Given the following demand profile, and capacity, give the (translated) cumulative curves (and determine the delay) Lecture 2 Arrival patterns 76 32

Answer: cumulative curves Lecture 2 Arrival patterns 77 32

Answer: flow representation Lecture 2 Arrival patterns 78 32

Identifying capacity drop Lecture 2 Arrival patterns 79 32

Identifying capacity drop Using oblique (slanted) cumulative curves show that capacity before flow breakdown is larger than after breakdown (-300 veh/h) Lecture 2 Arrival patterns 80 32

Learning goals You now can: Construct (slanted) fundamental diagrams Use these to calculate: delays, travel times, density, flow In practice shortcoming: Data is corrupt, and errors accumulate Test yourself: tomorrow in excersise Lecture 2 Arrival patterns 81 32