In this section we want to learn how to solve equations containing radicals, like 5 x 4 = 9. In order to do this we need the following property.

Similar documents
7.6 Radical Equations and Problem Solving

Using the distance formula Using formulas to solve unknowns. Pythagorean Theorem. Finding Legs of Right Triangles

Pythagoras theorem (8 9)

5-7 The Pythagorean Theorem

Determine whether the given lengths can be side lengths of a right triangle. 1. 6, 7, , 15, , 4, 5

Block 2 ~ The Pythagorean Theorem Self-Assessment. Progress (shade this in) Name Per. Track your understanding. Lesson #

Solving an equation involves undoing these things. We work backward through this verbal model.

Skills Practice Skills Practice for Lesson 3.1

In this section we want to apply what we have learned about functions to real world problems, a.k.a. word problems.

How can you find decimal approximations of square roots that are not rational? ACTIVITY: Approximating Square Roots

1 Rational Exponents and Radicals

Note-Taking Guides. How to use these documents for success

2.5 Absolute Value Equations and Inequalities

Radicals and connections to geometry

Prerequisites. Introduction CHAPTER OUTLINE

Introductory Algebra Chapter 9 Review

Math Review Packet. for Pre-Algebra to Algebra 1

A.5. Solving Equations. Equations and Solutions of Equations. Linear Equations in One Variable. What you should learn. Why you should learn it

Math Analysis Chapter 2 Notes: Polynomial and Rational Functions

Evaluate nth Roots and Use Rational Exponents. p Evaluate nth roots and study rational exponents. VOCABULARY. Index of a radical

Why Doesn t the Moon Hit us? In analysis of this question, we ll look at the following things: i. How do we get the acceleration due to gravity out

Example: x 10-2 = ( since 10 2 = 100 and [ 10 2 ] -1 = 1 which 100 means divided by 100)

A Quick Algebra Review

221 MATH REFRESHER session 3 SAT2015_P06.indd 221 4/23/14 11:39 AM

Name: Date: Period: Calculus Honors: 4-2 The Product Rule

AP Calculus AB Chapter 4 Packet Implicit Differentiation. 4.5: Implicit Functions

Radical Equations and Inequalities

DIFFERENTIATION RULES

M098 Carson Elementary and Intermediate Algebra 3e Section 11.3

Warmup 2/(The length of the third side of this triangle, rounded to the nearest whole number)

ACCESS TO SCIENCE, ENGINEERING AND AGRICULTURE: MATHEMATICS 1 MATH00030 SEMESTER / Lines and Their Equations

Answers. Investigation 2. ACE Assignment Choices. Applications. Problem 2.5. Problem 2.1. Problem 2.2. Problem 2.3. Problem 2.4

Page 1. These are all fairly simple functions in that wherever the variable appears it is by itself. What about functions like the following, ( ) ( )

LESSON #34 - FINDING RESTRICTED VALUES AND SIMPLIFYING RATIONAL EXPRESSIONS COMMON CORE ALGEBRA II

Mini-Lecture 7.1 Radicals and Radical Functions

The Pythagorean Theorem and Its Converse

2014 Summer Review for Students Entering Algebra 2. TI-84 Plus Graphing Calculator is required for this course.

Lesson 4.1 (Part 1): Roots & Pythagorean Theorem

2.4 Radical Equations

EXPONENT REVIEW!!! Concept Byte (Review): Properties of Exponents. Property of Exponents: Product of Powers. x m x n = x m + n

Applications Using Factoring Polynomials

Module 2, Section 2 Solving Equations

MITOCW MIT18_01SCF10Rec_24_300k

Summer Packet Geometry PAP

LESSON 9.1 ROOTS AND RADICALS

Unit 3 NOTES Honors Common Core Math 2 1. Day 1: Properties of Exponents

Algebra 1 Semester 2 Final Exam Part 2

Part II) Practice Problems

AP Calculus BC Summer Assignment 2018

NOTES: Chapter 11. Radicals & Radical Equations. Algebra 1B COLYER Fall Student Name:

Mini-Lecture 5.1 Exponents and Scientific Notation

4.5 Linearization Calculus 4.5 LINEARIZATION. Notecards from Section 4.5: Linearization; Differentials. Linearization

Geometry Warm Up Right Triangles Day 8 Date

Algebra 1 FINAL EXAM REVIEW Spring Semester Material (by chapter)

Chapter 8: Radical Functions

Section 4.6 Negative Exponents

a b a b ab b b b Math 154B Elementary Algebra Spring 2012

Solution. Using the point-slope form of the equation we have the answer immediately: y = 4 5 (x ( 2)) + 9 = 4 (x +2)+9

Chapter 8 RADICAL EXPRESSIONS AND EQUATIONS

Unit 5 ICM/AB Applications of the Derivative Fall Nov 10 Learn Velocity and Acceleration: HW p P ,103 p.

Ch. 12 Rational Functions

Astronomy 102 Math Review

Core Connections Algebra 2 Checkpoint Materials

8.3 Zero, Negative, and Fractional Exponents

MAT029C. 8.2 Multiplying and Simplifying with Radical Expressions.

Divisibility Rules Algebra 9.0

Introduction. So, why did I even bother to write this?

Section 7.1 Objective 1: Solve Quadratic Equations Using the Square Root Property Video Length 12:12

= = =

Chapter 13: universal gravitation

MLK Day!!! Solving Equations with Radicals Day 1. Practice. Solving Equations with Radicals Day 2. Practice. Applications of Radicals.

Campus Academic Resource Program The Pythagorean Theorem

1.6-Quadratic Equations

Chapter 4 Polynomial and Rational Functions

A Review of the Mathematics Used In AST 301

Lesson 6 Plane Geometry Practice Test Answer Explanations

Visit us at: for a wealth of information about college mathematics placement testing!

Radicals and Pythagorean Theorem Date: Per:

Guidelines for implicit differentiation

Essential Question How can you cube a binomial? Work with a partner. Find each product. Show your steps. = (x + 1) Multiply second power.

Review of Exponent Rules

2. Which of the following expressions represents the product of four less than three times x and two more than x?

Trigonometric ratios:

Core Connections Algebra 2 Checkpoint Materials

THE QUADRATIC QUANDARY

Polynomial and Rational Functions

Basic ALGEBRA 2 SUMMER PACKET

Lesson Plan by: Stephanie Miller

Let's See What we can Remember?

Physics E-1ax, Fall 2014 Experiment 3. Experiment 3: Force. 2. Find your center of mass by balancing yourself on two force plates.

AP Calculus. Applications of Derivatives. Table of Contents

Section 4.3: Quadratic Formula

NAME DATE PERIOD. Study Guide and Intervention. Solving Radical Equations and Inequalities

Name: Period: Unit 3 Modeling with Radical and Rational Functions

Math 302 Module 6. Department of Mathematics College of the Redwoods. June 17, 2011

Scientific Literacy & the Scientific Method

Algebra/Trigonometry Review Notes

4.1 Implicit Differentiation

The Pythagorean Theorem

ACCUPLACER MATH 0311 OR MATH 0120

Transcription:

.7 Solving Radical Equations In this section we want to learn how to solve equations containing radicals, like. In order to do this we need the following property. n-th Power Property n n If a b, then a b. Basically, this property tells us we can raise both sides of any equation to any power we would like. However, we must be careful. There are several places where we can make serious mistakes. First, we need to make sure that we really are raising the entire side to the nth power and not just each term individually. Also, when using the nth power property there is the possibility that we end up with solutions that don t check, called etraneous solutions. The reason we get these on occasion has to do with the logical construction of the property. The property tells us that if n n something is a solution to a b then it must also be a solution to a b. That doesn t mean n n that if something is a solution to a b that it is a solution to a b. To rectify this, we simply check our answers and throw away the ones that do not work. So, always remember, be careful to raise the entire side to the n-th power, and we must always check our answers. Eample : Solve. a. b. c. Solution: a. We can use the n-th power property to get rid of the radical. Since we have a square root, we should use the second power, i.e. we should square both sides of the equation. Then we can solve like usual. We get ( ) () 7 Now we must check our answer. We do this in the original equation. If the value does not check, then we eliminate it and would have no solution. We get 7 7. Since the value checks, our solution is set { } b. Again, we need to raise both sides of the equation to a suitable power to get rid of the radical. This time we will use the rd power since we have a cube root. We get

Now we check the solution. ( ) ( ). Since the value checks the solution set is { } c. Finally, we need to raise both sides to the th power since we have a th root. We get Check: ( ) Since it does not check, can not be a solution to the equation. Therefore, we have the equation has no solution. Now, sometimes the equation is a bit more complicated. What we need to know is that before raising both sides to the n-th power, we must always isolate the radical epression first. That way we are assured that it will cancel when we use the eponent. Also, sometimes, after raising both sides to the n-th power, we end up with a radical still in the equation. In this situation, we need to again isolate the radical and again use the eponent. We keep repeating this process until all the radicals are gone. Then we solve as usual. Eample : Solve. a. b. c. Solution: a. First thing we need to do is isolate the radical. Once we have done that we can square both sides of the equation as we did in eample. Then, of course, we finish solving and check.

() Check: The value checks. Therefore the solution set is { }. b. Notice this time that one of the radicals is already isolated. Therefore we can go ahead and square both sides. Must, however be very careful with squaring the right side since it has two terms. It generally makes it easier to square properly by writing the entire side out twice and then multiplying as we learned in section.. We get Notice that we are left with another equation that has a radical. Therefore, we need to isolate again and square again. In this case however, it is easier to simply isolate the term containing the radical and the carefully square both sides. We can then continue solving as usual. Check:

Since the solution checks, the solution set is { }. c. Finally, we must start by isolating one of the two radicals in this equation. We will choose to isolate the positve one. Generally we isolate the more complicated radical in order to eliminate it first. However, either could be isolated and still produce the correct solutions. Once we have isolated the radical then we can square both sides very carefully and then continue as usual. We get Recall, to solve an equation that has a squared term we must solve by factoring. That is, we get all terms on one side, factor and set each factor to zero. This gives 0 0 0 0 and Now we must check both answers and keep only those which work Check: 7 So, does not check but does. Therefore, the is an etraneous solution. So our solution set is {. }

Finally we want to see some applications of radicals. The first of these requires the Pythagorean theorem. We state it below. The Pythagorean Theorem In any right triangle, if a and b are the lengths of the legs of the triangle and c is the length of the hypotenuse, then we have the following b a c a b c or alternately c a a b c c b b a Other types of applications require us to interpret and use a given formula. Eample : Find the missing side of the right triangle if c ft, a 0 ft. Solution: First we start by drawing the picture ft So we can see that we are clearly missing side b. Therefore we can use the formula b 0 ft c a. We get b ( 0) 0 So b ft. ft. Eample : The equation for the time of one pendulum swing (called the period of the pendulum) is given by T π where T is the time in seconds and is the length in feet. Find the length of a pendulum of a clock that has a period of. seconds. Solution:

We simply need to put the value of. into the formula for T and solve for by using the techniques we learned in this section. We proceed as follows T π. π. π. π. π. π Now we put this into our calculator to get 7. feet. Upon checking this value, we find that it does check and therefore the length of the pendulum is 7. feet..7 Eercises Solve....... 7.. 7. 0. ( )..... 7. 0. 0. 7. 0 0. 0. 7.. 7... 7... b b 0.. z z... t ( t ).. 7. 7 7.. 0... 7.. 7.. 7 7. 0

. 7 0. 0 0. 0 Solve for the indicated variable.. v d for d. d. h for h. v as. v as for s. d t for g. g 7. y h k for. y h k for h for a d t for d g Find the missing side of the right triangle.. a, b 0. b 7, c. b 0m. a 0 yds, c 0 yds, c 0m. A ten foot ladder is leaning against a wall. How far is the bottom of the ladder from the wall when the ladder reaches a height of feet?. A foot ladder is leaning against a building. How high up the building does the ladder reach if the bottom of the ladder is feet from the building?. The diagonal of a TV is inches. The width of the TV is 0 inches. What is the height of the TV?. A computer monitor has a width of inches and a height of 0 inches. What is the length of the diagonal of the monitor? 7. A stereo receiver is in a corner of a foot by foot room. Speaker wire will run under a rug, diagonally, to a speaker in the far corner. If a foot slack is needed at each end, how long of a piece of wire should be used?. A baseball diamond is a square which is 0 feet on the side. What is the distance from first base to third base?. The formula for the speed of a falling object is v d where is the speed of the object d in feet per second and is the distance the object has fallen, in feet. What distance has an object fallen if its speed is 0 feet per second? 70. The formula for the speed of a falling object is v d where is the speed of the object d in feet per second and is the distance the object has fallen, in feet. What distance has an object fallen if its speed is 7 feet per second? 7. The formula for the distance a lookout can see is d. h v v where d is the distance in miles and h is the height of the lookout above the water, in feet. How high will the periscope have to go to see a ship that is. miles away? 7. The formula for the distance a lookout can see is d. h where d is the distance in miles and h is the height of the lookout above the water, in feet. How high will the periscope have to go to see an island that is. miles away?

7. The equation for the period of the pendulum is given by T π where T is the time in seconds and is the length in feet. Find the length of a pendulum of a clock that has a period of seconds. 7. The equation for the period of the pendulum is given by T π where T is the time in seconds and is the length in feet. Find the length of a pendulum that has a period of 7. seconds. 7. The formula for the distance required of a moving object to reach a specific velocity is v as where v is the velocity of the object, a is the acceleration of the object and s is the distance required. What distance is required for an car to reach a velocity of 0 miles per hour if the acceleration is miles per square second? 7. The formula for the distance required of a moving object to reach a specific velocity is v as where v is the velocity of the object, a is the acceleration of the object and s is the distance required. What distance is required for an car to reach a velocity of 7 kilometers per hour if the acceleration is 0 kilometers per square second? 77. The formula for the demand for a certain product is given by p 0 0.0 where is the number of units demanded per day and p is the price per unit. What is the demand if the price is $7.? 7. The formula for the demand for a certain product is given by p 0 0.00 where is the number of units demanded per day and p is the price per unit. What is the demand if the price is $.70? 7. The formula for the escape velocity of a satellite is h v gr where v is the velocity, r h g is the force of gravity, r is the planets radius and h is the height of the satellite above the planet. What is the height above the Earth would the Space Shuttle be if the gravitational pull is 0.00 km/sec and the escape velocity is. km/sec? (The radius of the earth is about 0 km) 0. The formula for the escape velocity of a satellite is h v gr where v is the velocity, r h g is the force of gravity, r is the planets radius and h is the height of the satellite above the planet. What is the height above the Earth would a satellite be if the gravitational pull is 0.00 km/sec and the escape velocity is. km/sec? (The radius of the earth is about 0 km)