CHAPTER 7: Chemical Equilibrium

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CHAPTER 7: Chemical Equilibrium Chemical Reactions and Equilibrium Calculating Equilibrium Constants The Reaction Quotient Calculation of Gas-Phase Equilibria The effect of External Stresses: Le Châtelier s Principle Heterogeneous Equilibrium Extraction and Separation Processes

Chemical Equilibrium Many reactions go to completion, e.g., NaCl fully dissolves in water, but Ca(OH) 2 does not Chemical equilibrium is the balance between products and reactants. Can be affected by conditions (e.g., higher solubility at higher T) Equilibrium is dynamic, like phase equilibria of chapter 6 --- individual reactant and product molecules frequenly switch palaces This chapter quantifies the chemical equilibrium concept

Gas-Phase Equilibrium 2 NO 2 (g) N 2 O 4 (g) (red-brown) (colorless) How much NO 2 and N 2 O 4 will depend on conditions Double arrow suggests reaction ( Rx ) goes in both directions Equilibrium achieved when forward Rx happens exactly as often as reverse Rx For any amounts of NO 2 and N 2 O 4 the pressures are always in a fixed ration equal to the equilibrium constant (for a given T, etc) (P N2O4 / P ref ) k = ---------------------- Pref = 1 atm, only incl. (P NO2 / P ref ) 2 to cancel units; usually drop keep partial pressures in atm Note: k is unitless

Why is the denominator squared? Use coefficients from balanced chemical equations, e.g., a A (g) + + b B (g) c C (g) + + d D(g) for gases A, B, C, D, with coefficients a, b, c, d, gives P Cc x x P d D Product pressures k = ------------------------ P Aa x x P b B Reactant pressures note: pressures raised to power of coefficients in balanced chemical equation! If we measure all partial pressures P A,P B, P C, P D we can easily compute k.

Gas equilibrium example If k=8.8 at 25 o C for the 2NO 2 N 2 O 4 Rx, and we start with a partial pressure of 0.8 atm of NO 2, how much NO 2 is converted to N 2 O 4 (in atm) at fixed T (when equilibrium is reached)? Partial Pressures: 2 NO 2 N 2 O 4 Initial: 0.8 0 Final:?? (equilib)

Example, cont d

Gas concentrations instead of partial pressures Can also work these problem using gas concentrations, [A] = n A / V = P A / RT (P N2O4 / P ref ) K = ---------------- (P NO2 / P ref ) 2 becomes K = ( [N 2 O 4 ] RT / P ref ) [N 2 O 4 ] -------------------------- = ---------- x (RT / P ref ) -1. ( [NO 2 ] RT / P ref ) 2 [NO 2 ] 2

More generally a A(g) + b B(g) c C(g) + d D(g) [C] c [D] d K = ---------- x (RT/P ref ) c+d-a-b [A] a [B] b useful to use R=0.08206 L atm mol -1 K -1 will cancel T & P ref units

Example CH 4 (g) + H 2 O(g) CO(g) + 3H 2 (g) At equilibrium at 900K, the concentrations of H 2, CO, and H 2 O are all 0.00642 mol L -1. What s the concentration of CH 4 (g) if K=0.172?

Reaction quotient Reaction keeps shifting forwards or backwards until the partial pressures or concentrations match K a A + b B c C + d D (all gas phase) K = [P Cc P Dd / P Aa P Bb ] eq defined for P A, P B, P C, P D at equilibrium What if the P s haven t reached equilibrium yet? Then call it Q, the reaction quotient Q = [P Cc P Dd / P Aa P Bb ] for any P s If Q<K, need more product to reach equilibrium. If Q>K, need more reactants to reach equilibrium.

Reaction quotients example Consider N 2 (g) + 3H 2 (g) 2NH 3 (g) If P N2 = 55atm, P H2 = 11atm, P NH3 = 22atm initially, is the final pressure of NH 3 greater or smaller than its initial pressure? K=1.9x10-4

Le Châtelier s Principle Last example shows we can make the reaction go forwards or backwards by adding more reactants or products; this is the law of mass action This is an example of a more general principle: Le Châtelier s Principle A system in equilibrium which is subjected to a stress reacts in a way to counteract the stress

Law of Mass Action Using Le Châtelier s Principle to make a Rx go forward or backward by adding more of a reactant/product Industry uses the law of mass action in the synthesis of ammonia N 2 (g) + 3H 2 (g) 2 NH 3 (g) Can drive the Rx to completion by continually removing NH 3

Other forms of Châtelier s Principle Changing volume: If we decrease the volume of a reaction vessel, the presure goes up, and the system will try to reduce stress by reducing pressure by making fewer gas molecules N 2 (g) + 3H 2 (g) 2NH 3 (g) If P goes up, Rx shifts to the right to make pressure decrease again

Other forms of Châtelier s Principle Changing temperature: Some reactions require heat (endothermic). Raising the temperature supplies more heat, drives Rx forward. Opposite for exothermic. N 2 (g) + 3H 2 (g) 2NH 3 (g) + heat This is an exothermic Rx (gives off heat). Rx goes backwards if T goes up (system tries to reduce extra heat). Opposite happens if T goes down (system tries to make more heat)

Heterogeneous Equilibrium How do we write a rate constant for a Rx like O 2 (g) + 2 H 2 O(l) 2 H 2 O 2 (aq)?? Use activities For gases, activity is just the partial pressure (more precisely, P/P ref ) For dissolved species, activity is concentration in mol L -1 Pure solids and liquids have activity = 1 K = [H 2 O 2 ] 2 / (P O2 x 1)

Equilibrium in Extraction Extraction: 2 solvents A and B, add solute C. C will dissolve in both A and B, but the amount in A vs B is determined by the equilibrium constant K = [C] A / [C] B. Can extract polar solutes from nonpolar solvents by washing with water or a polar solvent Iodine travels from the upper aqueous phase to the lower CCl 4 phase preferentially

Chromatography Achieve equilibrium between a stationary phase (e.g., column of water adsorbed to silica gel) and a mobile phase (solution containing one or more solutes) Solute A travels faster down the column because it has less affinity for water in the gel than for the solvent it s in. B is attracted more to the water, so it moves slower. K A = [A] water / [A] solvent, K B = [B] water / [B] solvent