The Method of Substitution. Linear and Nonlinear Systems of Equations. The Method of Substitution. The Method of Substitution. Example 2.

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The Method of Substitution Linear and Nonlinear Systems of Equations Precalculus 7.1 Here is an example of a system of two equations in two unknowns. Equation 1 x + y = 5 Equation 3x y = 4 A solution of this system is an ordered pair that satisfies each equation in the system. Finding the set of all solutions is called solving the system of equations. The Method of Substitution The Method of Substitution We will study four ways to solve systems of equations, beginning with the method of substitution. Method Type of System 1. Substitution Linear or nonlinear, two variables. Graphical method Linear or nonlinear, two variables 3. Elimination Linear, two variables 4. Gaussian elimination Linear, three or more variables Example 1 Solve the system of equations. x y 0 5x 3y 6 Example A total of $5,000 is invested in two funds paying 7% and 4% simple interest. The yearly interest is $1405. How much is invested at each rate? 1

Example 3 Solve the system of equations. x y 5 x 3x y 1 Example 4 Solve the system of equations. x y 3 x 4x y 0 Graphical Approach to Finding Solutions From Example 3, we can see that a system of two equations in two unknowns can have exactly one solution, more than one solution, or no solution. By using a graphical method, you can gain insight about the number of solutions and the location(s) of the solution(s) of a system of equations by graphing each of the equations in the same coordinate plane. The solutions of the system correspond to the points of intersection of the graphs. Graphical Approach to Finding Solutions For instance, the two equations in Figure 7.1 graph as two lines with a single point of intersection; the two equations in Figure 7. graph as a parabola and a line with two points of intersection; and the two equations in Figure 7.3 graph as a line and a parabola that have no points of intersection. One intersection point Two intersection points No intersection points Figure 7.1 Figure 7. Figure 7.3 Example 5 Solve the system of equations by graphing. 4x y 1 3x y 15 Applications The total cost C of producing x units of a product typically has two components the initial cost and the cost per unit. When enough units have been sold so that the total revenue R equals the total cost C, the sales are said to have reached the break-even point. You will find that the break-even point corresponds to the point of intersection of the cost and revenue curves.

Example 6 A small business has an initial investment of $6000. The unit cost of the product is $3.0, and the selling price is $35.0. How many units must be sold to break even? Example 7 From 001 to 008, the population of City A was increasing at a faster rate than the population of City B. Models that approximate the two populations P (in thousands) are P 4947.3 95t P 5118 41.4t where t represents the number of years since 001. According to these two models, when would you expect the populations of these two cities to be equal? The Method of Elimination Two-Variable Linear Systems Precalculus 7. We have studied two methods for solving a system of equations: substitution and graphing. Now we will study the method of elimination. The key step in this method is to obtain, for one of the variables, coefficients that differ only in sign so that adding the equations eliminates the variable. Equation 1 Equation Add equations. Example 1 The Method of Elimination x y 1 x y 7 3

Example x y 1 6x 3y 6 The Method of Elimination In this example, the two systems of linear equations (the original system and the system obtained by multiplying by constants) are called equivalent systems because they have precisely the same solution set. Example 3 Graphical Interpretation of Solutions 3x y 7 x 5y 1 Graphical Interpretation of Solutions A system of linear equations is consistent if it has at least one solution. Example 4 Recognizing Graphs of Linear Systems Match each system of linear equations with its graph in Figure 7.7. Describe the number of solutions and state whether the system is consistent or inconsistent. A consistent system with exactly one solution is independent, whereas a consistent system with infinitely many solutions is dependent. A system is inconsistent if it has no solution. Figure 7.7 4

Example 5 6x 5y 3 1x 10y 5 Example 6 1 1 x y 8 4x y 3 3 8 Example 7 0.03x 0.04y 0.75 0.0x 0.06y 0.90 Example 8 An airplane flying into a headwind travels the 1650-mile flying distance between two cities in 3 hours and 18 minutes. On the return flight, the distance is traveled in 3 hours. Find the air speed of the plane and the speed of the wind, assuming that both remain constant. Example 9 Find the point of equilibrium of the supply and demand equations. p 81 0.55x p 0.15x Demand Supply Multivariable Linear Systems Precalculus 7.3 5

Row-Echelon Form and Back-Substitution Consider the following two systems of linear equations. System of Three Linear Equations in Three Variables: x y + 3z = 9 x + 3y = 4 x 5y + 5z = 17 Equivalent System in Row-Echelon Form: x y + 3z = 9 y + 3z = 5 z = Row-Echelon Form and Back-Substitution The second system is said to be in row-echelon form, which means that it has a stair-step pattern with leading coefficients of 1. After comparing the two systems, it should be clear that it is easier to solve the system in row-echelon form, using back-substitution. Example 1 x y + 5z = y + 3z = 6 z = 3 Gaussian Elimination Two systems of equations are equivalent if they have the same solution set. To solve a system that is not in row-echelon form, first convert it to an equivalent system that is in row-echelon form by using the following operations. Example x y 90 x y 90 Example 3 x y z 6 x y z 3 3x y z 6

Example 4 3x y 4z 1 x y z 3 x 3y 6z 8 Gaussian Elimination As with a system of linear equations in two variables, the solution(s) of a system of linear equations in more than two variables must fall into one of three categories. We have learned that a system of two linear equations in two variables can be represented graphically as a pair of lines that are intersecting, coincident, or parallel. Gaussian Elimination A system of three linear equations in three variables has a similar graphical representation it can be represented as three planes in space that intersect in one point (exactly one solution) [see Figure 7.1], intersect in a line or a plane (infinitely many solutions) [see Figures 7.13 and 7.14], or have no points common to all three planes (no solution) [see Figures 7.15 and 7.16]. Example 5 x y 7z 4 x 3y z 5 3x 7y 36z 5 Solution: one point Solution: one line Solution: one plane Solution: none Solution: none Figure 7.1 Figure 7.13 Figure 7.14 Figure 7.15 Figure 7.16 Nonsquare Systems So far, each system of linear equations you have looked at has been square, which means that the number of equations is equal to the number of variables. In a nonsquare system, the number of equations differs from the number of variables. Example 6 x y 4z 3 4x z 0 A system of linear equations cannot have a unique solution unless there are at least as many equations as there are variables in the system. 7

Example 7 Find the position equation s at v0t an object at the given heights moving vertically at the specified times. At t = 1 second, s = 104 feet. At t = seconds, s = 76 feet. At t = 3 seconds, s = 16 feet. 1 s 0 for Example 8 Find a quadratic equation, y ax bx c, whose graph passes through the points (0,0), (3, -3), and (6,0). Example 9 A small business borrowed $30,000 to renovate its building. Some of the money was borrowed at 7%, some at 9%, and some at 1%. The amount borrowed at 9% was $1000 greater than the amount borrowed at 1%. How much was borrowed at each rate if the total interest owed for the first year was $,960. 8