Section 2. Energy Fundamentals

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Transcription:

Section 2 Energy Fundamentals 1

Energy Fundamentals Open and Closed Systems First Law of Thermodynamics Second Law of Thermodynamics Examples of heat engines and efficiency Heat Transfer Conduction, Convection, Radiation Radiation and Blackbodies Electromagnetic Radiation Wien s Law, Stefan-Boltzmann Law 2

Energy Fundamentals To analyze energy flows, Define type of system Use 1st and 2nd Laws of Thermodynamics Pond H2O Open System: energy or matter flow across boundaries Closed System: only energy flows across boundaries 3

First Law of Thermodynamics Energy cannot be created or destroyed Energy balance equation: Energy in = Energy out + Change in internal energy Change in internal energy ΔU commonly due to change in temperature: ΔU = mcδt m = mass c = specific heat ΔT = temperature change 4

Units of specific heat c (definitions): 1 BTU is the energy required to raise the temperature of 1 lb of water by 1 F. 1 calorie is the energy required to raise the temperature of 1 gram of water by 1 C. 1 kilojoule (preferred) Energy Unit mass Temperature For water, c = 1 cal g i C = 4.184 kj kg i K 5

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When a substance changes phase by freezing or boiling, HL = latent heat ΔU = mhl m is the mass of substance Internal energy changes due to phase changes: Changing from solid liquid: Latent Heat of Fusion Changing from liquid gas: Latent Heat of Vaporization HL (fusion of 0 C water) = 333 kj/kg HL (vaporization of 100 C H2O) = 2257 kj/kg 7

8

Example: Global Precipitation Over entire globe (area of globe 5.1x10 14 m 2 ), precipitation averages 1 m/yr. What energy is required to evaporate all of the precipitation if the temperature of the water is 15 C? Specific heat (15 C) 4.184 kj/kg Heat of Vaporization (100 C) Heat of Vaporization (15 C) 2257 kj/kg 2465 kj/kg Heat of Fusion 333 kj/kg 9

Use First Law of Thermodynamics: Energy = Energy + Change in In Out Internal Energy In this case, assume energy out = 0 (no losses, and all energy put into the system is used for evaporation) Energy In = Change in Internal Energy = mh L 10

m = (1m/yr)(5.1 10 14 m 2 )(1000 kg/m 3 ) = 5.1 10 17 kg/yr Energy = (5.1 10 17 kg/yr)(2465 kj/kg) = 1.3 10 21 kj/yr IMPORTANT: use the latent heat for water at 15 C, not 100 C This is ~4000 times larger than world energy consumption! (Global fossil fuel consumption is about 3.5 10 17 kj/yr) 11

Example: An Open System Many practical situation exist where both mass and energy flow across boundaries: heat exchangers, cooling water, flowing rivers Rate of change in stored energy (due to flow) = mcδt where m is the mass flow rate across boundaries of the system of interest 12

A coal-fired powerplant converts one-third of the coal s energy into electricity, with an electrical output rate of 1000 MW (1 MW = 10 6 J/s) The other 2/3 goes back into the environment: 15% to the atmosphere, up the stack 85% into a nearby river The river flows at 100 m 3 /s and is 20 C upstream of the plant If the stream of water that is put back into the river is to be at no more than 30 C, how much water needs to be drawn from the river? 13

Amount of waste heat going into the river: 2000 MW 85% = 1700 MW Rate of change in stored energy due to flow = mcδt J = 1700 10 6 s = 1.700 J 109 s m ( kg/s) = waste heat cδt = 1.700 109 J s 4184 J 10 K = 4.063 104 kg s kg K 14

Second Law of Thermodynamics The entropy of a system tends to increase. Entropy is a measure of disorganization in a system Thermal energy not available for conversion into mechanical work Conversion of heat to work results in some waste heat a heat engine cannot be 100% efficient 15

A coal-fired powerplant is a type of heat engine Burn coal for heat Boil water to make steam Steam turns turbine some of heat in steam converted to electricity Exiting steam is at a lower temperature waste heat Co-generation? 16

Heat Engine Hot reservoir Th Qh Heat to engine Work W Qc Waste heat Cold reservoir Tc Efficiency work heat input = W Q h = η 17

Theoretically, the most efficient heat engine is the Carnot Engine: For Carnot, η = 1 T c T h Tc, Th = absolute temperature, in K or R c = cold, h = hot, h = efficiency As Th increases h increases; as Tc decreases, h increases The larger the difference in temperature, the more efficient the process 18

Typical Powerplant Energy output = 1000 MW Pressurized steam boiler = 600 C = 873 K Cooled to ambient temperature = 20 C = 293 K η max = 1 293 873 = 0.66 = 66% Real-world efficiencies in U.S. powerplants average 33% (range ~ 25 to 40% depending on age of plant) 19

Some conversions Kilowatt-hour (KWH or kw-hr) 1 W = 1 J/s 1 J = 1 W s 1 Watt-hour = 1 W 3600 s = 3600 J 1 kw-hr = 1000 1 W 3600 s = 3.6 # 10 6 J = 3.6 MJ 20

Example (Prob. 1.31) A 15W compact fluorescent lamp (CFL) provides the same light as a 60W incandescent lamp. Electricity costs the end user 10 per kw-hr. a. If an incandescent lamp costs 60 and the CFL costs $2, what is the payback period? b. Over the 9000-hr lifetime, what would be saved in carbon emissions? (280 g carbon emitted per kw-hr) c. At a (proposed) carbon tax of $50/tonne, what is the equivalent dollars saved as carbon emissions? (1 tonne = 1000 kg) 21

Energy saved with the CFL: (60W 15W)(9000 hr) = 405 kw-hr At 10 per kw-hr, this is $40 over the lifetime of the lamp. Payback period: As an example, use 6 hr/day usage. Then 60W 15W ( ) 6 hr = $0.027 saved per day $2/$0.027 per day = 74 days or about 2.5 months Emissions savings: ( ) day $0.10 kw-hr 1 1000 W-hr kw-hr ( ) (280 g carbon/kw-hr)(405 kw-hr) = 113400 g C 0.113 T $50/T = $5.65 22

Example Could the temperature difference between the top and bottom of a lake be used as a cheap, renewable source of a megawatt of electricity? Say the temperatures are 25 C and 15 C, maintained by sunlight (~ 500 W/m 2 ) and the lake has an area of 10 4 m 2. Are the first and second laws of thermodynamics obeyed? [first: energy is conserved; second: entropy of systems increase and there is a limit on the efficiency of any process] 23

Evaluate maximum efficiency, then calculate energy output η = 1 T c T h η max = 1 288 298 = 0.034 What is the maximum possible energy output from this system, given the solar energy input? ( 500 W ) ( 10 4 m 2 )( 0.034) = 170000 W = 0.17 MW m 2 24

Example A very efficient gasoline engine runs at 30% efficiency. If the engine expels gas into the atmosphere, which has a temperature of 300 K, what is the temperature of the cylinder immediately after combustion? If 837 J of energy are absorbed from the hot reservoir during each cycle, how much energy is available for work? η = 1 T c T h η = W Q h 25

Heat Transfer Heat transfer always occurs between hot and cold objects Conduction: heat transfer occurs when there is direct physical contact; kinetic energy is transferred when atoms or molecules collide 26

Convection: heat transfer is mediated by the flow of a fluid Free convection occurs without human intervention; forced convection requires mechanical pumping of the fluid Radiation: heat transfer mediated by the propagation of electromagnetic radiation (such as light) 27

Radiation All objects radiate energy continuously in the form of electromagnetic waves, if their temperature is greater than 0 K Type of radiation depends on wavelength λ Wavelength 28

29

Blackbody Radiation Blackbodies absorb and emit at all wavelengths Amount of radiation emitted depends on temperature Stefan-Boltzmann Law E = σ AT 4 E = total blackbody emission rate (W) σ = Stefan-Boltzmann constant = 5.67 10 8 W/m 2 K 4 T = temperature (K) A = surface area of blackbody (m 2 ) 30

A more familiar form uses the energy flux F, where F = E/A W/m 2 F = σt 4 Wien s Law λ max µm ( ) = 2898 µm K T (K) 31

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33

Example: Human Body as an Energy Converter How high can you climb on the energy from a liter of milk? One liter of milk contains about 2.4 10 6 J. ( 2.4 10 6 J) 1 kj 1000 J 1 cal = 574 cal 4.184 kj Work needed to move your body = mgh where m = your mass, g = acceleration due to gravity, h = change in height 34

Work available from milk = (metabolic efficiency)q = εq where Q is the internal energy of the milk Example input values: m = 50 kg (110 lb), efficiency ~ 100% εq = mgh ( 1.0) ( 2.4 10 6 J) = ( 50 kg) ( 9.8 m s 2 )h h = 4900 m Considering that Mt. Whitney has an elevation gain of about 3000 m, does this sound reasonable? 35