Review Lecture 5. The source-free R-C/R-L circuit Step response of an RC/RL circuit. The time constant = RC The final capacitor voltage v( )

Similar documents
Physics 160 Lecture 3. R. Johnson April 6, 2015

Voltage v(z) ~ E(z)D. We can actually get to this wave behavior by using circuit theory, w/o going into details of the EM fields!

CSE 245: Computer Aided Circuit Simulation and Verification

C From Faraday's Law, the induced voltage is, C The effect of electromagnetic induction in the coil itself is called selfinduction.

Chapter 9 Sinusoidal Steady State Analysis

General Article Application of differential equation in L-R and C-R circuit analysis by classical method. Abstract

Wave Equation (2 Week)

Lecture 2: Current in RC circuit D.K.Pandey

EEEB113 CIRCUIT ANALYSIS I

AC STEADY-STATE ANALYSIS

EE202 Circuit Theory II , Spring. Dr. Yılmaz KALKAN & Dr. Atilla DÖNÜK

(b) (a) (d) (c) (e) Figure 10-N1. (f) Solution:

Chapter 7 Response of First-order RL and RC Circuits

Homework-8(1) P8.3-1, 3, 8, 10, 17, 21, 24, 28,29 P8.4-1, 2, 5

Lecture 13 RC/RL Circuits, Time Dependent Op Amp Circuits

( ) C R. υ in RC 1. cos. ,sin. ω ω υ + +

Voltage v(z) ~ E(z)D. We can actually get to this wave behavior by using circuit theory, w/o going into details of the EM fields!

Chapter 3: Fourier Representation of Signals and LTI Systems. Chih-Wei Liu

Transfer function and the Laplace transformation

Charging of capacitor through inductor and resistor

Elementary Differential Equations and Boundary Value Problems

Boyce/DiPrima 9 th ed, Ch 2.1: Linear Equations; Method of Integrating Factors

REPETITION before the exam PART 2, Transform Methods. Laplace transforms: τ dτ. L1. Derive the formulas : L2. Find the Laplace transform F(s) if.

Lecture 1: Growth and decay of current in RL circuit. Growth of current in LR Circuit. D.K.Pandey

EE 350 Signals and Systems Spring 2005 Sample Exam #2 - Solutions

ES 250 Practice Final Exam

AC STEADY-STATE ANALYSIS

ECE 145A / 218 C, notes set 1: Transmission Line Properties and Analysis

8. Basic RL and RC Circuits

LaPlace Transform in Circuit Analysis

AC STEADY-STATE ANALYSIS

Direct Current Circuits. February 19, 2014 Physics for Scientists & Engineers 2, Chapter 26 1

H is equal to the surface current J S

First Order RC and RL Transient Circuits

Voltage/current relationship Stored Energy. RL / RC circuits Steady State / Transient response Natural / Step response

Why Laplace transforms?

Spring 2006 Process Dynamics, Operations, and Control Lesson 2: Mathematics Review

Chapter 8 The Complete Response of RL and RC Circuits

Control System Engineering (EE301T) Assignment: 2

MEMS 0031 Electric Circuits

EE 434 Lecture 22. Bipolar Device Models

fiziks Institute for NET/JRF, GATE, IIT JAM, JEST, TIFR and GRE in PHYSICAL SCIENCES MATEMATICAL PHYSICS SOLUTIONS are

FOURIER TRANSFORM AND ITS APPLICATION

7. Capacitors and Inductors

Midterm exam 2, April 7, 2009 (solutions)

Sinusoidal Response Notes

Chapter 1 Fundamental Concepts

CHAPTER 12 DIRECT CURRENT CIRCUITS

On the Speed of Heat Wave. Mihály Makai

Electrical Circuits. 1. Circuit Laws. Tools Used in Lab 13 Series Circuits Damped Vibrations: Energy Van der Pol Circuit

Laplace Transforms recap for ccts

8.022 (E&M) Lecture 16

AC Circuits AC Circuit with only R AC circuit with only L AC circuit with only C AC circuit with LRC phasors Resonance Transformers

ECE 2100 Circuit Analysis

Phys463.nb Conductivity. Another equivalent definition of the Fermi velocity is

Circuits and Systems I

ECE 2100 Circuit Analysis

Instructors Solution for Assignment 3 Chapter 3: Time Domain Analysis of LTIC Systems

10. If p and q are the lengths of the perpendiculars from the origin on the tangent and the normal to the curve

RESONANT CAVITY. Supplementary Instructions

Chapter 16: Summary. Instructor: Jean-François MILLITHALER.

Introduction to Fourier Transform

EHBSIM: MATLAB-BASED NONLINEAR CIRCUIT SIMULATION PROGRAM (HARMONIC BALANCE AND NONLINEAR ENVELOPE METHODS)

Fourier Series and Parseval s Relation Çağatay Candan Dec. 22, 2013

3. Alternating Current

V L. DT s D T s t. Figure 1: Buck-boost converter: inductor current i(t) in the continuous conduction mode.

( ) ( ) if t = t. It must satisfy the identity. So, bulkiness of the unit impulse (hyper)function is equal to 1. The defining characteristic is

CHAPTER 6: FIRST-ORDER CIRCUITS

Lecture 4: Laplace Transforms

R.#W.#Erickson# Department#of#Electrical,#Computer,#and#Energy#Engineering# University#of#Colorado,#Boulder#

DEPARTMENT OF ELECTRICAL &ELECTRONICS ENGINEERING SIGNALS AND SYSTEMS. Assoc. Prof. Dr. Burak Kelleci. Spring 2018

Chapter 28 Magnetic Induction

Part 3 System Identification

( ) = Q 0. ( ) R = R dq. ( t) = I t

UNIT #5 EXPONENTIAL AND LOGARITHMIC FUNCTIONS

University of Cyprus Biomedical Imaging and Applied Optics. Appendix. DC Circuits Capacitors and Inductors AC Circuits Operational Amplifiers

6.01: Introduction to EECS I Lecture 8 March 29, 2011

EXERCISE - 01 CHECK YOUR GRASP

PWM-Scheme and Current ripple of Switching Power Amplifiers

MATH 308: Diff Eqs, BDP10 EXAMPLES [Belmonte, 2019] 1 Introduction 1.1 Basic Mathematical Models; Direction Fields

Inductor Energy Storage

Coherence and interactions in diffusive systems. Lecture 4. Diffusion + e-e interations

CHAPTER CHAPTER14. Expectations: The Basic Tools. Prepared by: Fernando Quijano and Yvonn Quijano

5. An object moving along an x-coordinate axis with its scale measured in meters has a velocity of 6t

i L = VT L (16.34) 918a i D v OUT i L v C V - S 1 FIGURE A switched power supply circuit with diode and a switch.

Pulse Generators. Any of the following calculations may be asked in the midterms/exam.

Problem Set #1. i z. the complex propagation constant. For the characteristic impedance:

Reading from Young & Freedman: For this topic, read sections 25.4 & 25.5, the introduction to chapter 26 and sections 26.1 to 26.2 & 26.4.

- If one knows that a magnetic field has a symmetry, one may calculate the magnitude of B by use of Ampere s law: The integral of scalar product

AR(1) Process. The first-order autoregressive process, AR(1) is. where e t is WN(0, σ 2 )

2.4 Cuk converter example

1 1 + x 2 dx. tan 1 (2) = ] ] x 3. Solution: Recall that the given integral is improper because. x 3. 1 x 3. dx = lim dx.

Physics 240: Worksheet 16 Name

Section 2.2 Charge and Current 2.6 b) The current direction is designated as the direction of the movement of positive charges.

4. Which of the following organs develops first?

Lab 10: RC, RL, and RLC Circuits

Chapter 10 INDUCTANCE Recommended Problems:

INDEX. Transient analysis 1 Initial Conditions 1

Circuit Transients time

Lecture 28: Single Stage Frequency response. Context

Transcription:

Rviw Lcur 5 Firs-ordr circui Th sourc-fr R-C/R-L circui Sp rspons of an RC/RL circui v( ) v( ) [ v( 0) v( )] 0 Th i consan = RC Th final capacior volag v() Th iniial capacior volag v( 0 )

Volag/currn-division

Lcur 7 AC Circuis Sinusoids and Phasors

Conns Sinusoids Apliud, angular/cyclic frquncy, argun, priodic funcion Phasors Rcangular/polar/xponnial for, Eulr s idniy, and i-doain/phasor-doain rprsnaion Phasor rlaionships for circui lns R, L, and C Ipdanc and adianc rsisanc and racanc,conducanc and suscpanc Kirchhoff s laws in h frquncy doain Ipdanc cobinaions

Priodic funcions f ( x nt) f ( x) Sinusoids Sinusoidal: or in funcion Ti-varying () and argun, x, of (x) Apliud V Frquncy: angular (rad/s) and cyclic f (H): Priod T (s): T nt nt ( ) us in wih posiiv apliud V ( ) ( ) T f ( x n ) f ( ) ( ) ( x) v( ) V ( ) 0 T phas argun

Phas angl bwn wo signals Sa frquncy: Apliud ay vary Phas diffrnc: Exprss h in h sa for in and V > 0 Phas diffrnc : ou of/in phas lad/lag 5(x+ ) In phas : (x + ) 0 Phas v V ( ) v V ( ) a any i (x+/3) For a givn, V and ar iporan quaniis. lads (x) by /3 (x-/3) lags (x) by /3 Exapl: Calcula h phas angl bwn v = 0 (ω + /3) and v = (ω + /6). Sa which usoid is lading. () Sa for: () Copar: v 0 ( ) 0 ( ) 0 ( ) 3 3 3 v ( ) 0 ( ) 0 ( ) 6 6 3 v 0 ( ) 0 ( ) 3 3 3 v lags v by /3

Phasors A phasor is a coplx nubr ha rprsns h apliud (V ) and phas () of a usoid. Coplx nubrs - hr rprsnaions Rcangular: Polar: Exponnial: Phasor rprsnaion - usoid v() ral par: v( ) V R V R V x y r r Rcangular Èxponnial V V V V V ω is iplicily prsn

On circl,, Priod T = i/circl = / Sinor: roaing phasor A circl of radius V Sinor: V on h coplx plan v() is h procion of h or on h ral axis. Th valu of h or a i = 0 is h phasor V of v(). Procion A coplx nubr: agniud and dircion - vcor counrclockwis

Phasor diagra Diagra/coplx nubr Magniud and phas V V ω is iplicily prsn

Ti doain and phasor(frquncy) doain To rprsn signals v(), i(): Ti doain: v ) V ( Ti dpndn Always ral Phasor (frqncy) doain: V V Ti indpndn Gnrally coplx is consan. Circui rspons dpnds on ( ) Exapl: Givn i () = 4 (ω + /6) and i () = 5 (ω /3), find hir su. i ( I ) I, i( ) I i I ( 6 3 4, I 5 ) 5( 3 5 6 5 I I 4( 6... 6 6 4 5 5 ) 6? ) 5 5( ) 6 5 5( 6 in and I > 0 i( ) I ( ) 5 ) 6

Drivaiv and ingral in phasor doain v( ) V ( ) V V dv( ) d ( ) V V ( ) d d V ( ) V ( ) 3 V ( ) V ( ) V V V V Exapl: Ug h phasor approach, drin h currn i() in a circui dscribd by h ingrodiffrnial quaion. = di 4i 8 id 3 50 ( ) d 3 4I Frquncy doain 8I 3 I 50 3 dv ( ) d v() V V Usful in finding h sady-sa soluion: sa frquncy!

Phasor rlaionships for circui lns v and i in phas i lads v by / i( ) I ( ) I v( ) RI ( ) V RI RI Oh law holds v( ) V ( ) dv( ) i( ) C CV ( ) d CV ( ) V V I V CV I C i has a phas +/ CV v lads i by / i( ) I ( ) di( ) v( ) L LI ( ) d LI ( ) I V LI LI v has a phas +/

Ipdanc and adianc opposiion o h flow of usoidal currn V RI V LI V ZI Z V V I I C Ipdanc Phasor Volag Phasor Currn Coplx quaniy, bu no a phasor Z C Adianc I Y Z V S

Mor abou Ipdanc 0 Capacior, Inducor: Capacior, Inducor: Z C Z L Z C Z 0, L, an opn circui a shor circui 0,, a shor circui an opn circui Circui rspons dpnds on h frquncy! Z is a coplx quaniy Rcangular for (x+y) Rsisanc Z R X Y G Z Conducanc Racanc Currn lads volag X 0, capaciiv/lading racanc...( Z ) C X 0, induciv/ lagging racanc...( Z L) B Suscpanc No: G dos no always qual o /R

Kirchhoff s laws in h frquncy doain Boh KVL and KCL hold in h frquncy doain Ti doain v v... vn 0 i v R( V ) i i n R( V ) R( V )... R( Vn ) n R( V V... Vn ) n ( V V... V ) 0 R ( ) Vi ( i ) n v i Us h R of a coplx quaniy o rprsn h signal 0 0 Frquncy doain V n V... Vn 0 0 KVL KCL V V... V I I... In n 0 0

Ipdanc cobinaions Cobinaion of Ipdanc is siilar o rsisanc circuis. KVL V V Z Z q V I V... Vn Z I Z q Z I... Z n Z... Zn I Z Z... Z n I Volag/currn division holds. Y- and -Y ransforaions as wll

Exapl: Ipdanc Find h inpu ipdanc of h circui Assu ha h circui opras a ω = 50 rad/s. Z = Ipdanc of h -F capacior Z = Ipdanc of h 3- rsisor in sris wih h 0-F capacior Z 3 = Ipdanc of h 0.-H inducor in sris wih h 8-rsisor Z C Z L

Exapl: Solv h circui Drin v o () in h circui Sp : Phasor-doain quivaln Sp : Volag-division Z Z Sp 3: convr o i-doain

Appndix: Mahaics Trigonory A B B A C C B A B A B A B A B A B A B A an, whr, Coplx nubrs, * r y x r r r r r r y y x x y y x x

Lcur 8 AC Circuis Sinusoidal Sady-Sa Analysis