Instructions Please answer the five problems on your own paper. These are essay questions: you should write in complete sentences.

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Instructions Please answer the five problems on your own paper. These are essay questions: you should write in complete sentences.. Recall that P 3 denotes the vector space of polynomials of degree less than 3. Let S denote the two-dimensional subspace of P 3 consisting of polynomials p(x) such that p() = p(). Find a basis for S, and explain how you know that your answer is a basis. Solution. A polynomial in P 3 has the form ax + bx + c for certain constants a, b, and c. Such a polynomial belongs to the subspace S if a + b + c = a + b + c, or c = a + b + c, or = a + b, or b = a. Thus the polynomials in the subspace S have the form a(x x)+c. In other words, the two polynomials x x and are a spanning set for S. These two polynomials are also a linearly independent set since neither of these two polynomials is a scalar multiple of the other. Therefore the set {x x, } is a basis for the subspace S.. Recall that R denotes the vector space of all matrices with real entries. (a) Show that the set of all symmetric matrices with real entries is a subspace of R. (Recall that a matrix A is symmetric if A = A T.) (b) What is the dimension of this subspace? How do you know? Solution. This problem is essentially problem 6 from Chapter Test B for Chapter 3 on page 73 of the textbook. a b (a) A symmetric matrix has the form for certain scalars b c a, b, and c. Evidently the sum of two matrices of this form is another matrix of the same type, and a scalar multiple of such a matrix is another matrix of the same type. Thus the set of symmetric matrices is closed under addition and closed under scalar multiplication, so the symmetric matrices do form a subspace of the space of matrices. October 8, 8 Page of 5 Dr. Boas

a b (b) Since = a + b + c, we see that the b c ( ) three symmetric matrices,, and form a spanning set for the subspace of all symmetric matrices. Moreover, these three matrices are a linearly independent set since each has a where the other two have s. Thus we have identified a basis for the subspace of symmetric matrices. This basis consists of three elements, so the dimension of our subspace equals three. 3. Give an example of a linear transformation [ ] L: R R whose kernel equals the span of the vector. (There are many correct answers.) Solution. There are infinitely many correct solutions. Two examples written as formulas are x x x L = x x x and L =. x x x The same two examples written in terms of matrix multiplication are L(x) = x and L(x) = x. [ ] [ ] 4. Suppose that u = and u 3 =. If L: R R is a linear transformation such that L(u ) = u and L(u ) = u, find the matrix representation of L with respect to the standard basis. Solution. x Method (using similar matrices). The matrix representation of ( the) transformation L with respect to the given nonstandard basis is. The transition matrix from the nonstandard basis to the standard basis is. The transition matrix from the standard basis to 3 October 8, 8 Page of 5 Dr. Boas

the nonstandard basis is the inverse matrix, or. 3 3 The matrix representation of L with respect to the standard basis is then, 3 3 which works out to. 6 5 Check: =, 6 5 3 3 = =. 6 5 4 Method (bare hands). a b = c d 3 3 a b We seek a matrix such that c d a b and =. c d 4 Multiplying out these relations produces four linear equations for the four unknowns a, b, c, and d. Solving the equations yields a =, b =, c = 6, and d = 5. Method 3 ((working ) directly in standard coordinates). that e = = 3 = u 3 3u, so L(e ) = L(u ) 3L(u ) = u 6u =. 6 Observe This vector is the first column of( the ) matrix ( representation ) of L in the standard basis. Similarly, e = = + = u 3 + u, so L(e ) = L(u ) + L(u ) = u + 4u =. 5 October 8, 8 Page 3 of 5 Dr. Boas

This vector is the second column of the matrix representation of L in the standard basis. 5. Rose and Colin are studying a certain 3 4 matrix A. They use a TI-89 calculator to find the following reduced row echelon forms for the matrix A and for the transpose A T : and. Use this information to say as much as you can about the null space, the row space, and the column space of the original matrix A. [Can you determine the dimension of each subspace? Can you determine a basis for each subspace?] Solution. From the reduced row echelon form of the matrix A, you can read off that the two vectors and form a basis for the row space of A, which thus has dimension. It follows that the column space of A also has dimension, and the first and third columns of the original matrix A form a basis for the column space of A. Although the original matrix A is not given, we can nonetheless exhibit a basis for the column space by observing that the column space of A equals the row space of the transpose matrix A T. The reduced row echelon form for A T reveals that the two vectors and form a basis for the column space of A. (Notice that in this example, the first and third columns of the reduced row echelon form of A definitely do not form a basis for the column space of A.) Either from the rank-nullity theorem or from observing the two free variables in the reduced row echelon form of A, we deduce that the null October 8, 8 Page 4 of 5 Dr. Boas

space of A has dimension. The two vectors and form a basis for the null space. October 8, 8 Page 5 of 5 Dr. Boas