Chapter 7. Lesson Lesson 7.1.2

Similar documents
2-1. TILE PATTERN INVESTIGATION: Pattern A. c. By how much is the pattern growing?

Chapter 2 Linear Relationships. Vocabulary

Chapter a. True b. True c. False d. True

Name: Period: Date: Algebra 1 1st Semester Review Which best describes the solution(s) for this equation? 3 ( 8x 12) = 33 2x

Oregon Focus on Linear Equations Lesson 1 Answers

Item Specification Sheet Algebra I Semester Exam

NAME DATE PER. Review #11 Solving Systems of Equations 1. Write the linear function that includes the points (4, 9) and (-2, -6).

A C E. Answers Investigation 2. Applications. Age (wk) Weight (oz) 1. a. Accept any line that approximates the data. Here is one possibility:

Math 1 packet for Coordinate Geometry part 1. Reviewing the basics. The coordinate plane

CORE. Chapter 3: Interacting Linear Functions, Linear Systems. Algebra Assessments

Algebra I Practice Exam

Name: Class: Date: Unit 1. Thinking with Mathematical Models Investigation 2: Linear Models & Equations. Practice Problems

STRAND: GRAPHS Unit 1 Straight Lines

Math 8 Honors Coordinate Geometry part 1 Unit Updated July 29, 2016

Algebra 1 Semester 1 Review

Chapter 10. Lesson is special because any non-zero number divided by itself is 1, and anything multiplied by 1 remains the same.

Unit 3 Review for SchoolNet Test

Chapter 9. Lesson 9.1.1

Grade 7, Unit 2 Practice Problems - Open Up Resources. Lesson 1. Problem 1. Problem 2. Yes, since 3 times 1.5 is 4 and 2 times 1.5 is 3.

SY14-15 Algebra Exit Exam - PRACTICE Version

CHAPTER FIVE. g(t) = t, h(n) = n, v(z) = z, w(c) = c, u(k) = ( 0.003)k,

TEST BANK. How TO USE THIS TEST BANK

4. Based on the table below, what is the joint relative frequency of the people surveyed who do not have a job and have a savings account?

Fall IM I Exam B

Exam 1 Review Sp16 O Brien. Exam 1 Review:

9-3 Constant Rate of Change and Slope

ACCELERATED ALGEBRA ONE SEMESTER ONE REVIEW. Systems. Families of Statistics Equations. Models 16% 24% 26% 12% 21% 3. Solve for y.

Final Review. Intermediate Algebra / MAT135 S2014

Solutions to Intermediate and College Algebra by Rhodes

ALGEBRA 1 SEMESTER 1 INSTRUCTIONAL MATERIALS Courses: Algebra 1 S1 (#2201) and Foundations in Algebra 1 S1 (#7769)

COMMON CORE MATHEMATICS CURRICULUM

Lesson 3 - Linear Functions

Name: Class: Date: Describe a pattern in each sequence. What are the next two terms of each sequence?

Math 8 Unit 5. Writing Equations. Tuesday, November 27; 7:30am Tuesday, December 4; 7:30am. Date Lesson Topic Homework

Solve. Label any contradictions or identities. 1) -4x + 2(3x - 3) = 5-9x. 2) 7x - (3x - 1) = 2. 3) 2x 5 - x 3 = 2 4) 15. 5) -4.2q =

4. Based on the table below, what is the joint relative frequency of the people surveyed who do not have a job and have a savings account?

Answers. Chapter 4 A15

Ch 3 Exam Review. Plot the ordered pairs on the rectangular coordinate system provided. 3) A(1, 3), B(-5, 3)

Pre-Algebra Practice Semester 1 Exam

2-2. Warm Up. Simplify each expression. 1. ( 7)(2.8) ( 9)( 9)

Fundamental Principle of Counting: If event A can occur in m ways and event B can occur in n ways, then both events can occur in m n ways.

CCGPS UNIT 1 Semester 1 COORDINATE ALGEBRA Page 1 of 33. Relationships Between Quantities Name:

KEYSTONE ALGEBRA I REVIEW

1. What are the various types of information you can be given to graph a line? 2. What is slope? How is it determined?

HIGLEY UNIFIED SCHOOL DISTRICT INSTRUCTIONAL ALIGNMENT

Test Booklet. Subject: MA, Grade: HS CAHSEE Math Practice Test. Student name:

Algebra 1, Semester 1 Exam Review

Honors Algebra 2 Summer Packet

GUIDED NOTES 4.1 LINEAR FUNCTIONS

4. The table shows the number of toll booths driven through compared to the cost of using a Toll Tag.

Accelerated Intermediate 2 Summer Math Packet

Moving Straight Ahead - Unit Test Review Sheet

Lesson 3: Linear Functions and Proportionality

For any negative real number x, the statement

On Your Own. Applications. Unit 1. 1 p = 7.5n - 55, where n represents the number of car washes and p represents the profit in dollars.

Algebra 2 Level 2 Summer Packet

A C E. Applications. Applications Connections Extensions. Student 1 Student Below are some results from the bridge experiment in a CMP class.

Lesson 1. Unit 6 Practice Problems. Problem 1. Solution

THIS IS A CLASS SET - DO NOT WRITE ON THIS PAPER

Linear Functions, Equations, and Inequalities

Algebra - Chapter 5 Review

x y

Graphing and Writing Linear Equations Review 3.1, 3.3, & 4.4. Name: Date: Period:

MAT 111 Final Exam Fall 2013 Name: If solving graphically, sketch a graph and label the solution.

Chapter y= x f(4)= f(x)= x a. 0 b. 3 and 0 c. x 0.5, , 9, and t

Rate of Change and slope. Objective: To find rates of change from tables. To find slope.

Algebra Supplement Homework Packet #1

1. The area of the surface of the Atlantic Ocean is approximately 31,830,000 square miles. How is this area written in scientific notation?

Algebra I STAAR Practice Test A

Topic 1. Solving Equations and Inequalities 1. Solve the following equation

Bridge to College Mathematics

b(n) = 4n, where n represents the number of students in the class. What is the independent

3. A beam or staircase frame from CSP costs $2.25 for each rod, plus $50 for shipping and handling.

ALGEBRA I EOC REVIEW PACKET Name 16 8, 12

Name: Class: Date: ID: A. c. the quotient of z and 28 z divided by 28 b. z subtracted from 28 z less than 28

Chapter 4 ( 2, 2 ). Chapter 4 Opener. Section 4.1. Big Ideas Math Blue Worked-Out Solutions. Try It Yourself (p. 141) = = = = 15. The solution checks.

Section 1 Force and Motion: Review

Linear Relations and Functions

Strategic Math. General Review of Algebra I. With Answers. By: Shirly Boots

Grade 8 + DIGITAL. EL Strategies. DOK 1-4 RTI Tiers 1-3. Flexible Supplemental K-8 ELA & Math Online & Print

Pre-Algebra Chapter 8 Linear Functions and Graphing

8 th Grade Domain 2: Algebra and Functions (40%) Sara

Algebra 1 Fall Semester Final Review Name

Other Course Material by AskDrCallahan

Eureka Math. Grade 8, Module 4. Student File_B. Contains Exit Ticket, and Assessment Materials

Semester Exam Review Answers

CHAPTER 6 Notes: Functions A mathematical model is an equation or formula in two variables that represents some real-world situation.

Unit 12 Practice Problems. US Customary Unit. Practical reason for wanting to know. Aspect of bottle. Metric unit. 1- dimensional.

Name. Algebra I Period

Describing Mo tion. Speed and Velocity. What is speed?

Version C Pre-Algebra Practice Semester 1Exam

Chapter 1: Expressions, Equations, and Functions

The slope, m, compares the change in y-values to the change in x-values. Use the points (2, 4) and (6, 6) to determine the slope.

Math Algebra I FORMATIVE MINI ASSESSMENT. Read each question and choose the best answer. Be sure to mark all of your answers.

Algebra 1 ECA Remediation Diagnostic Homework Review #1

UNIT 8: LINEAR FUNCTIONS WEEK 31: Student Packet

4. Solve for x: 5. Use the FOIL pattern to multiply (4x 2)(x + 3). 6. Simplify using exponent rules: (6x 3 )(2x) 3

Units and Dimensional Analysis

Algebra Chapter 4 (pearson) review

MATH 8 CATALINA FOOTHILLS SCHOOL DISTRICT

Transcription:

Chapter 7 Lesson 7.1.1 7-. Customer A should order y=4x instead; Customer B should order y= x+ instead; Customer C s order is correct; Customer D s table is not linear, so the customer should revise his or her order; Customer E s order is correct; Customer F s order is not linear either, since a line must have constant growth everywhere. 7-4. a. See diagrams at right. b. y=5x+1; 51 tiles Figure 0 Figure 4 7-5. a. b. 1 c. 7-6. a. 50 5 416.7 pounds of food b. 700 45 15.6 hours 7-7. x: (1, 0) and y: (0, 6) 7-8. a. y=8 6x b. x = 1 6 y+ 8 6 c. x = 7-9. Let t = number of teddy bears and d = number of dogs. Then t +d =56 and d =t +17, so t =11 and d =4. Thus, he has 11 teddy bears. Lesson 7.1. 7-1. Answers can vary depending on data and the trend line that is chosen. 7-1. a. 16 b. c. undefined d. 0 7-14. a. 5 b. 1 c. the positive value of x c d. 6 e. 8 f. the positive value of y f 7-15. a. b. 1 7-16. a. (, 0.5) b. infinite solutions because the lines coincide 7-17. x =15, y=9 7-18. a. The baby is growing 1.5 inches per month; it is the slope (m). b. It was inches long when it was born; it is the y-intercept (b). c. 7.5 inches d. 11 months after it was born, so in December 44 Algebra Connections

Lesson 7.1. 7-19. a. Both have tiles in Figure 0. However, A grows by tiles and B grows by 6 tiles. B is steeper. c. Typical response. It tells how much a pattern grows each figure. The steeper the line, the greater or faster the growth. d. A. y=x+, B. y=6x+ 7-0. 7 = 9 7-1. a. b. 4 c. 1 or 0.5 d. divide y by x e. y= 1 x+ 7-. a. 6 4 = =1.5 ; Both give the same result. b. 4.5; The ratio must be equal. c. 1.5; This height is equal to the slope. 7-. If y=0, then the line is horizontal; if x =0, then the line is vertical. 7-4. a. Essie is correct; y= means that the vertical change is and that the line is pointing downward. b. yes; 4 = 4 c. y= 4 x+9 7-5. Possible response. It is a parabola because it has an x -term. (This conclusion is acceptable at this point.) 7-6. r =y and r+y=14 ; r =9 and y=1 7-7. any horizontal line that is not y = 0 7-8. a. 5.5 b. 4 c. 5 d. 7-9. Let x represent the number of hours she swims. Then x+x =4.5 and x =1.5. Thus, she will swim for 1.5 hours and play volleyball for hours. 7-0. a. 5x x 1 b. 4x +18x Answer Key 45

Lesson 7.1.4 7-1. a. B is the steepest; C is the least steep. b. Downward; y is. c. A. m = 1, B. m =, C. m = 1, D. m = 5 d. Possible responses. The value of slope indicates how steep the graph is. The larger the slope, the steeper the line. If the slope is positive, the line travels upward from left to right, while a negative slope indicates that the line travels downward from left to right. e. In this case, she is correct. The steepest line (B) has the largest value for slope (). Note that for negative slope, the steeper the line, the more negative (smaller) the slope. 7-. a. A is the steepest; B is steeper than C. b. A. x = 1, y= ; B. x =, y= ; C. x =, y= ; D. x = 5, y= 1 c. A. m =, B. m =, C. m =, D. m = 1 5 d. It would point downward from left to right because its slope is negative. e. It would point downward from left to right because its slope is negative. It would be steeper. 7-. A. m = 1, B. m =, C. m =, D. m =0 7-4. a. The line should have slope m =6. b. m = 5 c. m = d. m =0 7-5. a. The slope of each is 1. b. no c. y= 1 7-7. a. line a. y=x, line b. y=x+ b. It would lie between lines a and b, because its y-intercept is at (0, 1). c. It would travel downward but would have the same y-intercept as the line from part (b). 7-8. a. ( 1, 7) b. ( 1, ) c. These coincide, so there are an infinite number of points of intersection. 7-9. a. 1 b. 0 c. 8 d. no solution 7-40. a. 6(1x 1)=78x 16 b. (x+)(x 5)= x x 15 7-41. 55 hops c. 4(4x 6x+1)=16x 4x+4 d. (x )(x+4)=x +10x 8 7-4. y= 4 x 4 46 Algebra Connections

Lesson 7.1.5 7-4. a. This is not enough information. An infinite number of lines pass through (, 5). b. This is enough information. y= x. c. This is enough information. y=x+4. d. This is not enough information. An infinite number of lines, all parallel to each other, have slope of 4. e. This is enough information. y= 4 x+5. f. You need the slope and a point or two points to determine a unique line. 7-44. a. 1 ; parallel lines must have the same growth factor. b. They are equal. c. It should have a slope of and pass through (0, 5). d. y= 1 x 6 7-45. a. She subtracted the x- and y-coordinates. b. c. 4 = d. 6 = 1 d e. The student did not make x negative and forgot to divide y by x. 7-46. The steepest line is vertical. Its slope is undefined since its x is 0. 7-47. No; she would be on the same page as Sam on page 10, but there are only 00 pages in the book. Sam only needs 9 minutes and 45 seconds to finish the book, while Jimmica needs 0 minutes. 7-48. a. See graph at right. b. (, ) 7-49. a. m = b. m =0.5 c. undefined 7-50. a. 4 b. no solution c. 0.5 d. 4 7-51. a. y = x 4 b. x = y 4 = 1 y+ c. x = 1 d. x = 7 7-5. x-intercepts. (, 0) and (4, 0); y-intercept. (0, 4) Lesson 7..1 7-55. A person cannot be different distances from the motion detector at the same time. 7-56. $,98,000 7-57. a. 4 b. 16 c. It would get steeper. 7-58. a. There is no solution, so the lines do not intersect. b. Yes; both lines have the same slope. y= x 10 7-59. y=x, y= x 7-60. Answers vary. Possible solutions. 5x(x 1), 5(x x), x(15x 5), etc. 7-61. a. 4 b. (0, 5) c. y= 4 x 5 Answer Key 47 y x

Lesson 7.. 7-6. a. Leslie. y=x, Kristin. y= 5 x+8, Evie. y= 5 4 x+6 b. After 8 seconds, both racers were 16 meters from the starting line. c. Leslie won in 10 seconds, Kristin took 0 seconds and Evie took 11. seconds. d. Her slope is. Her slope represents her rate of travel. 5 e. She traveled meters every seconds and got a 1-meter head start. 7-6. a. The customer started walking slowly toward the motion detector from 4 feet away, stopped for about 4 seconds, and then walked away from the machine at a faster rate b. The customer started from.5 feet in front of the machine and walked quickly away, stopped for about 4 seconds, and then started to walk slowly toward the machine c. The customer started walking quickly toward the machine from about 10 feet away, after seconds, stopped for 4 seconds, and then started walking slowly toward the machine. 7-64. a. The slope represents the number of feet a tree grows per year, and the y-intercept represents the height when the measuring began (perhaps when it was planted), m = feet per year, b = (0, 4) b. The slope represents the amount of money being spent from a bank account each month, while the y-intercept represents the beginning balance, m = 10 dollars per month, b=(0,170) c. The slope represents the distance that can be traveled on a gallon of gas, m = miles per gallon, b = (0, 0). 7-65. a. Elizabeth won the race, finishing in 5 seconds. b. Barbara: y= x+, Elizabeth:y=4x c. 5 meters every seconds, or 5 meters per second d. seconds after the start of the race, when each is 6 meters from the starting line 7-66. a. 0 pounds b. The graph should show a line with positive slope. Units labeled on the axes should be in pounds (vertical axis) and feet (horizontal axis). c. 4 pounds d. 9 feet 7-67. x-intercept. (, 0), y-intercept. (0, 10) 7-68. a. 1 b. c. 7-69. y=x 7-70. Let t = number of t-shirts and s = number of shorts. Then 1t +8s =780 and t +s=77 ; t =41 and s =6 ; they sold 41 t-shirts. 48 Algebra Connections

Lesson 7.. 7-71. Rider A: y= x, Rider B: y= 1 x+10, Rider C: y= x+4, Rider D: y= 5 x+1, Elizabeth: y= 1 4 x+10, Leslie: y=x 4 ; Rider D wins the race. Solution graph is shown at right. Distance from Starting Line D Leslie A C B Elizabeth 7-7. a. Rider D; Elizabeth b. Rider D. 5 meters every seconds; Elizabeth. 1 meter every 4 seconds c. 8 seconds after the start of the race, Rider A, Rider C, Elizabeth, and Leslie were all 1 meters from the starting line. 7-7. (, 15) 7-74. a. (4, 0) and (0, ) b. (8, 0) and (0, 4) Time (seconds) 7-75. a. 1 b. 1 c. d. 1 5 e. The line travels downward from left to right, so m = 1. 7-76. a. 4 b. c. 1 d. 7-77. a. 1x b. 8x+7 c. x d. 5x+7 y 7-78. C Answer Key 49

Lesson 7..1 7-79. While the graph will only approximate the solution, a table helps show that the chick weighed 51.6 grams when it was born and will weigh 140 grams after 17 days 7-80. a. It grows 5. grams per day, so the slope of the line is 5.. b. slope. m =5. ; should pass through (9, 98.4) c. Units on the axes should be in grams (vertical axis) and days (horizontal axis). d. While the y-intercept is (0, 51.6), answers close to 50 grams are acceptable. e. when the chick is 17 days old 7-81. a. The chick weighed 98.4 grams after 9 days. b. On Day 0, the chick weighed 51.6 grams. c. Colleen s chick weighed 51.6 grams when hatched. The chick will weigh 140 grams when it is 17 days old. For this problem, a table can produce exact results, while the graph is approximate. 7-8. a. The variable m is the slope, or the chick s daily rate of growth, 5. grams per day; b is the y-intercept, or the chick s weight when hatched, which is unknown. b. The slope is 5., so y=5.x+b. The y-intercept is still unknown. c. Possible response. A point on a line is a solution to the equation, so when substituting the x- and y-values into the equation, the equation is still true. d. Substituting x =9 and y=98.4 into the equation, the equation becomes 98.4 =5.(9)+b. After solving, b=51.6 and y=5.x+51.6. e. The equation is exact. f. Starting with 140 =5.x+51.6, the solution becomes x =17 days. 7-8. a. y= x 5 b. y=0.5x 14 7-84. Mt. Everest was 8750.05 meters tall in the year 0; y=0.05x+8750.05. 7-85. a. y=1.5x+0.5 b. Answers vary, but solutions should lie on y=1.5x+0.5. 7-86. 11 11 1 10 15 5 1 1 6 1 6 14 7 5 7-87. a. ( 7, 11) b. ( 8, 10) 7-88. a. 14 b. 5 c. d. 11 7-89. a. (.5, 0) and (0,.) b. y = 1 4. 7-90. a. ; (0, 5) b. 5 ; (0, 0) 4 c. 0; (0, ) d. 4; (0, 7) e. 4 ; (0, 1) f. 1 ; (0, 6) 5 50 Algebra Connections

Lesson 7.. 7-91. b. c. Answers vary. d. They are opposite reciprocals. e. 5. 7-9. a. y= 5 x 8 b. y= x+1 7-9. line L. y= 1 6 x+6; line M. y= x+1; (6, 5) 7-94. Lines A and E are perpendicular, so the slope of line E is 5 6. 7-96. a. 0.75 meters b. Dean. y= x+5, Carlos. 4 y= x c. after 0 seconds 7-97. a. The slope represents the cost per mile for a ride in a taxi, m = $.50 per mile; b. The slope represents the gallons per minute of water draining from a tub, m = 4 gallons per minute. 7-98. If d = number of Democrats, then d+(d +0)+1=45, and d = 0 Democrats. Thus, there were 0 + 0 = Republicans. 7-99. ( 5, 0) and (, 0) 7-100. a. x +5x b. 15x x c. 5x 7x+10 d. 00x 50 7-101. B Lesson 7.. 7-10. a. m = b. Substitute the point into the equation y=x+b in order to solve for b; y=x+10. c. No; both will give the same equation. d. Substitute both points into the equation to verify that both are solutions. 7-104. b. Although there are many possible solutions, the points for 1961 and 1989 are good choices. This will create a line. y=9.8x 194.8. c. See part (b) above. e. Answers will vary. In the case stated in part (b), the y-intercept is (0, 194.8); Dizzyland did not exist in the year 0. f. Answers will vary. Approximately the year 060. 7-105. a. y= 1 x+4 b. y= x+76 5 7-106. y= 9 4 x+9 7-107. (11, ) 7-108. a. There are no x-intercepts; y- intercept. (0, 10). b. (, 1) 7-109. a. 8 b. 56 c. d. 6 7-110. a. m = 5 6 b. m = 0 c. m = 5 6 d. undefined, e. m = 4 f. m = 1 4 g. m = 4 h. m = 6 5 ; Lines (b) and (d) are perpendicular; lines (e) and (f) are perpendicular; lines (a) and (c) are parallel. Answer Key 51

Lesson 7..4 7-111. Logo A: y=, y=x+, y= 1 x+, y= x+6, y= 1 x+6, y= x 6, y= 1 x+10 ; Logo B: y=, y=x, y= 4 x, y= x+6, y= 4 x+6, y= 4 x, y= 4 x+9 7-11. a. (y+4)(+5x)=6y+0x+10xy+1 b. (5+x)(x )=4x +4x 15 7-11. If b = number of brownies sold and c = the number of cookies sold, then b+.50c=18 and b=c+ ; she sold 41 brownies. 7-114. a. y= x+1 b. y = 11 c. y= x 7-115. a. The slope represents the change in height of a candle per minute, m = 0 cm per minute b. The slope represents the gallons per month of water being removed from a well, m = 900 gallons per month. 7-116. 4 4 1 16 4 4 8 11 8 7 1 7 6 7-117. a. 15x b. 8x c. 6x d. 7x 5 Algebra Connections