Maximum graphs with a unique minimum dominatingset

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Discrete Mathematics 60 (003) 197 03 www.elsevier.com/locate/disc Note Maximum graphs with a unique minimum dominatingset Miranca Fischermann, Dieter Rautenbach ;1, Lutz Volkmann Lehrstuhl II fur Mathematik, RWTH-Aachen, 5056 Aachen, Germany Received January 001; received in revised form 5 September 001; accepted July 00 Abstract We present a conjecture on the maximum number of edges of a graph that has a unique minimum dominatingset. We verify our conjecture for some special cases and prove a weakened version of this conjecture in general. c 00 Elsevier Science B.V. All rights reserved. Keywords: Domination; Size; Unique minimum dominatingset; Extremal graphs 1. Introduction We will consider nite and simple graphs G =(V; E) and use standard graph-theoretical terminology. A dominating set of a graph G is a set of vertices D V such that V N[D; G]=N (D; G) D. The domination number is the minimum cardinality (G) of a dominatingset of G and a dominatingset of G of cardinality (G) isaminimum dominating set. A classical result of Vizing[9] states that a graph of order n and domination number has at most 1 (n )(n + ) edges. This result has been improved in various ways. Fulman [5] improved it by takinginto consideration the maximum degree of the graph and was able to shorten Sanchis s proof [8] of the fact that if the graph G has order n, domination number and maximum degree at most n 1, then G has at most 1 (n )(n + 1) edges (see also [7, Theorem.1]). Correspondingauthor. Tel.: +49-41-80-94999; fax: +49-41-80-9136. E-mail addresses: scherm@math.rwth-aachen.de (M. Fischermann), rauten@math.rwth-aachen.de (D. Rautenbach), volkm@math.rwth-aachen.de (L. Volkmann). 1 Supported by the Deutsche Forschungsgemeinschaft under grant Postdoktorandenstipendium RA 873/1-1. 001-365X/03/$ - see front matter c 00 Elsevier Science B.V. All rights reserved. PII: S001-365X(0)00670-

198 M. Fischermann et al. / Discrete Mathematics 60 (003) 197 03 Fig. 1. In the present paper, we consider the analogous problem for graphs without isolated vertices that have a unique minimum dominating set. Unique minimum dominating sets have been studied, e.g. in [1 4,6]. Let m(n; ) denote the maximum number of edges of a graph G of order n without isolated vertices that has a unique minimum dominatingset of cardinality 1. The case where G is allowed to have isolated vertices obviously reduces to our results. If a graph G of order n without isolated vertices has a unique minimum dominating set D, then it is easy to see that the private exterior neighbourhood epn (v; D; G)=N (v; G)\N [D\{v};G]ofv with respect to D contains at least two vertices for each vertex v D. This observation implies that n 3(G). We propose the followingconjecture. Conjecture 1. If 1 and n 3, then n n 1 ; =1; m(n; )= n (n + 5 n )= ( ); : We rst show that m(n; ) is at least as large as stated in Conjecture 1 by exhibiting (possible) extremal graphs. In Section, we verify Conjecture 1 for = 1 and n =3. Finally, in Section 3, we prove a weakened version of Conjecture 1 for. For 1 and n 3 we dene the graph G(n; ). If = 1, then the edge set of the complement of G(n; ) consists of (n 1)= independent edges if n is odd and of (n 4)= independent edges and a path on three vertices if n is even. Fig. 1 shows the graphs G(3; 1), G(4; 1) and G(5; 1). If, then G(n; )=(V; E) has vertex set V = D P R for disjoint sets D = {x 1 ;x ; :::;x }, P = {y i ;z i 16i6} and R. For 16i6 we have N[x i ;G(n; )] = D {y i ;z i } R, N(y i ;G(n; )) = {x i } and N [z i ;G(n; )] = {x i } {z 1 ;z ;:::;z } R. Furthermore, the subgraph G(n; )[R] ofg that is induced by the set R is a complete graph. Fig. shows the graphs G(7; ) and G(10; 3). It is easy to verify that the graph G(n; ) has a unique minimum dominatingset of cardinality. Furthermore, if = 1, then G(n; ) has ( n ) (n 1)= edges and, if, then G(n; ) has ( n ) (n +( 5)=) edges. This implies that n n 1 ; =1; m(n; ) n (n + 5 ); :

M. Fischermann et al. / Discrete Mathematics 60 (003) 197 03 199 Fig... Some special cases It is easy to verify Conjecture 1 for = 1 as follows. Let G be a graph of order n without isolated vertices that has a unique minimum dominatingset of cardinality = 1. Since G has a unique vertex of degree n 1 and all remainingvertices have degree at most n, the desired bound follows. Note that if a graph G of order n without isolated vertices has a unique minimum dominatingset of cardinality, then its maximum degree is at most n 1 and Sanchis s result implies that G has at most ( n +1 ) edges which is larger than the bound given in Conjecture 1. The next special case that we consider is n =3. Theorem 1. Let G =(V; E) be a graph without isolated vertices with a unique minimum dominating set of cardinality and order n =3. Then m = E 6 ( n n + 5 ) = + : Proof. Let D = {x 1 ;x ;:::;x } be the unique minimum dominatingset of G and let P i = epn(x i ;D;G) for 16i6. Since P i for 16i6 and n =3, we have P i = for 16i6. Let P i = {p i;p i } for 16i6. If there is some 16i6 such that p ip i E, then (D\{x i }) {p i} D is a minimum dominatingset of G, which is a contradiction. If there are some 16j k6 such that there are two independent edges between P i and P j, say p ip j;p i p j E, then (D\{x i ;x j }) {p i;p j } D is a minimum dominating set of G, which is a contradiction. If there are some 16i j6 such that x i x j, p ip j and p ip j E, then (D\{x j }) {p i} D is a minimum dominatingset of G, which is a contradiction. This implies that for all 16i j6 there are at most two edges between P i and P j and if there are two such edges, then they are incident. Furthermore, if x i x j E, then there is at most one edge between P i and P j. Let l for l 0 be the number of pairs {i; j} with 16i j6 such that there are exactly l edges between P i and P j. By the above reasonings, we obtain that l = 0 for

00 M. Fischermann et al. / Discrete Mathematics 60 (003) 197 03 all l 3 and m(g[d])6 0 + 1. This implies that m = E = + m(g[d])+0 0 +1 1 + 6 + 0 + 1 +0 0 +1 1 + 6 +( 0 + 1 + ) = + : This completes the proof. 3. A weakened version of Conjecture 1 In order to motivate the weakened version of Conjecture 1, we dene the following property of graphs: A graph G without isolated vertices is said to have property ( ), if G has a minimum dominatingset D such that there is no set D V dierent from D with D = D and epn(x; D; G) N [D ;G]; x D i.e. no set of (G)= D vertices that is dierent from D dominates the private exterior neighbourhoods of the vertices in D. Let m(n; ) denote the maximum number of edges of a graph G of order n without isolated vertices that has domination number and property ( ). It is easy to see that the graph G(n; ) has property ( ). Furthermore, a graph G that has property ( ) also has a unique minimum dominatingset. For this implies ( n n + 5 ) 6 m(n; )6m(n; ): We will now prove the followingtheorem. Theorem. If, then m(n; )=( n ) (n +( 5)=). Proof. It remains to prove that m(n; )6( n ) (n +( 5)=). Therefore, let G be a graph of order n without isolated vertices that has domination number and property ( ). Let D = {x 1 ;x ;:::;x } be the unique minimum dominatingset and for 16i6 let P i = epn(x i ;D;G). As above P i for 16i6. Let R = V \(D P i). Let n 0 = R and n i = P i for 16i6. We assume that n 1 n n 3 n. We will estimate the number of edges of G.

M. Fischermann et al. / Discrete Mathematics 60 (003) 197 03 01 There are exactly n i edges between D and P i. There are at most ( )+ ( n0 )+n 0 edges in G[D R]. Let 16i6. Since there is no vertex p i P i such that P i N[p i ;G], there are at most ( ni ) n i= edges in G[P i ]. Since there is no vertex r i R such that P i N (r i ;G), there are at most n 0 (n i 1) edges between P i and R. Now let 16i j6. Since there is no vertex p i P i such that P j N(p i ;G), there are at most n i (n j 1) edges between P i and P j. Furthermore, if n i =, then also n j = and it is easy to see that there is at most one edge between P i and P j. Altogether we obtain that m = E 6f(n 0 ;n 1 ;:::;n ) for a function f dened as follows: f(n 0 ;n 1 ;:::;n )= = n i + + + n0 + n 0 + (n 0 n i n 0 )+ n ( 1) 16i j6 n i ( ) ni ni (n i n j max{n i ; 3}) ni n 0 ( i) max{n i ; 3}: Claim. Let, n i for 16i6 and n 0 0 be integers. Let n = + i=0 n i and let n 1 n n 3 n. If =, n 1 = n 4, n 1 and n are even, then f(n 0 ;n 1 ;:::;n )6 ( n n + 5 ) +1: Otherwise ( n f(n 0 ;n 1 ;:::;n )6 n + 5 ) : Proof of claim. If there is some 16i6 1 such that n i 4 and n i n i+1, then f(n 0 ;n 1 ;:::;n i ;:::;n ) 6 f(n 0 +1;n 1 ;:::;n i 1;:::;n ) ( 1) ni + ni 1 + ( i) 6 f(n 0 +1;n 1 ;:::;n i 1;:::;n ): Similarly, if = and n 1 n +, then f(n 0 ;n 1 ;n ) f(n 0 +;n 1 ;n ) and, if =, n 1 = n + 1 and n is even, then f(n 0 ;n 1 ;n ) f(n 0 +1;n 1 1;n ).

0 M. Fischermann et al. / Discrete Mathematics 60 (003) 197 03 We will consider two special cases. First, let n 1 = n = = n l = 3 and n l+1 = n l+ = = n = for some 06l6. We obtain n f(n 0 ;n 1 ;:::;n )= ( 1)( + l) ( + l) (n (3 + l)) 3 ( 1 ) ( +1) = ( n n + 5 ) : Now let n 1 = n = = n 4: For = 1 [n 1 (mod )] we obtain n f(n 0 ;n 1 ;:::;n )= ( 1)n 1 n1 n 0 ( 1 ) ( +1) n 1 n = ( 1)n 1 n 1 n 0 ( 1 ) ( +1) n 3 = 1 n 1 n 0 n 3 = 1 n 1 (n (n 1 +1)) n 1 = 1 n 1 (n ) n 6 ( 4) (n ) = ( n ) (n + 4) : If = and n 1 = n 5 are odd or if 3, then this implies f(n 0 ;n 1 ;:::;n )6( n ) (n +( 5)=). If = and n 1 = n are even, then this implies f(n 0 ;n 1 ;n )6( n ) (n +( 5)=)+1. In view of the above remarks, this completes the proof of the claim. n 1 In order to complete the proof of the theorem, it remains to consider the case where =, n 1 = n 4, n 1 and n are even and m = f(n 0 ;n 1 ;:::;n ). In this case, G[P 1 ] and G[P ] are complete graphs in which perfect matchings have been removed and G[P 1 ;P ] is a complete bipartite graph in which a perfect matching has been removed. (The graph G[P 1 ;P ] has vertex set P 1 P and contains all edges of G that join a vertex in P 1 and a vertex in P.) If D = {p 1 ;p 1 } consists of two non-adjacent vertices in P 1, then (P 1 P ) N [D ;G] which is a contradiction. Hence if =, n 1 = n 4, n 1

M. Fischermann et al. / Discrete Mathematics 60 (003) 197 03 03 and n are even, then m6f(n 0 ;n 1 ;:::;n ) 1. In view of the claim, this completes the proof. References [1] M. Fischermann, Block graphs with unique minimum dominating sets, Discrete Math. 40 (001) 47 51. [] M. Fischermann, D. Rautenbach, L. Volkmann, A note on the complexity of graph parameters and the uniqueness of their realizations, J. Combin. Math. Combin. Comput. [3] M. Fischermann, L. Volkmann, Unique minimum domination in trees, Australas. J. Combin. 5 (00) 117 14. [4] M. Fischermann, L. Volkmann, Cactus graphs with unique minimum dominating sets, Utilitas Math., to appear. [5] J. Fulman, A generalization of Vizing s theorem on domination, Discrete Math. 16 (1994) 403 406. [6] G. Gunther, B. Hartnell, L.R. Markus, D. Rall, Graphs with unique minimum dominatingsets, Congr. Numer. 101 (1994) 55 63. [7] T.W. Haynes, S.T. Hedetniemi, P.J. Slater, Fundamentals of Domination in Graphs, Marcel Dekker, Inc., New York, 1998. [8] L.A. Sanchis, Maximum number of edges in connected graphs with a given domination number, Discrete Math. 87 (1991) 65 7. [9] V.G. Vizing, A bound on the external stability number of a graph, Dokl. Akad. Nauk. SSSR 164 (1965) 79 731.