A mass spectrometer can be used to distinguish between samples of butane and propanal. The table shows some precise relative atomic mass values.

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Butane and propanal are compounds with M r = 58.0, calculated using data from your Periodic Table. (a) A mass spectrometer can be used to distinguish between samples of butane and propanal. The table shows some precise relative atomic mass values. Atom Precise relative atomic mass H.00794 2 C 2.00000 (i) Use data from the table to show that, to 3 significant figures, a more accurate value for the M r of butane is 58. () State why the precise relative atomic mass quoted in the table for the 2 C isotope is exactly 2.00000 (b) Draw a displayed formula for the organic product that is formed when propanal is oxidised by warm Tollens reagent. () () Page of 4

(c) Prop 2 en ol is an isomer of propanal and can be polymerised to form a polymer represented by the following structure. (i) (iii) Draw the structure of prop 2 en ol. Deduce the type of polymerisation that results in the formation of this polymer from prop 2 en ol. There are two functional groups in prop 2 en ol. Each of these functional groups contains a bond with a characteristic absorption range in the infrared spectrum. Use Table A on the Data Sheet to suggest a bond and its absorption range for each of the two functional groups. Bond... Absorption range... Bond 2... Absorption range... () () Page 2 of 4

(d) Compound X is another isomer of propanal. The infrared spectrum of X shows an absorption in the range 680 750 cm. (i) Draw the structure of X. Which of the following, A, B, C or D, represents the type of isomerism shown by X and propanal? Write the correct letter, A, B, C or D, in the box. A B C D chain isomerism E Z isomerism functional group isomerism position isomerism () (Total 9 marks) 2 Glucose can decompose in the presence of microorganisms to form a range of products. One of these is a carboxylic acid (M r = 88.0) containing 40.9% carbon and 4.5% hydrogen by mass. (a) Deduce the empirical and molecular formulas of the carboxylic acid formed. Empirical formula =... Molecular formula =... (4) Page 3 of 4

(b) Ethanol is formed by the fermentation of glucose. A student carried out this fermentation reaction in a beaker using an aqueous solution of glucose at a temperature of 25 C in the presence of yeast. Write an equation for the reaction occurring during fermentation.... () (c) In industry, this fermentation reaction is carried out at 35 C rather than 25 C. Suggest one advantage and one disadvantage for industry of carrying out the fermentation at this higher temperature. Advantage...... Disadvantage...... (d) The method used by the student in part (b) would result in the ethanol being contaminated by ethanoic acid. How does this contamination occur?...... () (e) Give two differences between the infrared spectrum of a carboxylic acid and that of an alcohol other than in their fingerprint regions. Use Table A on the Data Sheet. Difference...... Difference 2...... (Total 0 marks) 3 Isooctane (C 8 H 8 ) is the common name for the branched-chain hydrocarbon that burns smoothly in car engines. The skeletal formula of isooctane is shown below. Page 4 of 4

(a) Give the IUPAC name for isooctane.... () (b) Deduce the number of peaks in the 3 C NMR spectrum of isooctane. 5 6 7 8 () (c) Isooctane can be formed, together with propene and ethene, in a reaction in which one molecule of an alkane that contains 20 carbon atoms is cracked. Using molecular formulas, write an equation for this reaction.... () (d) How do the products of the reaction in part (c) show that the reaction is an example of thermal cracking?... () (e) Deduce the number of monochloro isomers formed by isooctane. Draw the structure of the monochloro isomer that exists as a pair of optical isomers. Number of monochloro isomers... Structure Page 5 of 4

(f) An isomer of isooctane reacts with chlorine to form only one monochloro compound. Draw the skeletal formula of this monochloro compound. () (g) A sample of a monochlorooctane is obtained from a comet. The chlorine in the monochlorooctane contains the isotopes 35 Cl and 37 Cl in the ratio.5 :.0 Calculate the M r of this monochlorooctane. M r =... (h) Isooctane reacts with an excess of chlorine to form a mixture of chlorinated compounds. One of these compounds contains 24.6% carbon and 2.56% hydrogen by mass. Calculate the molecular formula of this compound. Molecular formula =... (3) (Total 2 marks) Page 6 of 4

4 The carboxylic acid 3-methylbutanoic acid is used to make esters for perfumes. The following scheme shows some of the reactions in the manufacture of this carboxylic acid. (a) One of the steps in the mechanism for Reaction involves the replacement of the functional group by bromine. (i) Use your knowledge of organic reaction mechanisms to complete the mechanism for this step by drawing two curly arrows on the following equation. Deduce the name of the mechanism in part (i). Give the IUPAC name of (CH 3 ) 2 CHCH 2 Br Page 7 of 4

(b) Reaction 3 is an acid-catalysed reaction in which water is used to break chemical bonds when the CN functional group is converted into the COOH functional group. Infrared spectroscopy can be used to distinguish between the compounds in this reaction. Deduce the name of the type of reaction that occurs in Reaction 3. Identify one bond in (CH 3 ) 2 CHCH 2 CN and a different bond in (CH 3 ) 2 CHCH 2 COOH that can be used with infrared spectroscopy to distinguish between each compound. For each of these bonds, give the range of wavenumbers at which the bond absorbs. Use Table A on the Data Sheet when answering this question......................... (3) Page 8 of 4

(c) When 3-methylbutanoic acid reacts with ethanol in the presence of an acid catalyst, an equilibrium is established. The organic product is a pleasant-smelling ester. (CH 3 ) 2 CHCH 2 COOH + CH 3 CH 2 OH (CH 3 ) 2 CHCH 2 COOCH 2 CH 3 an ester + H 2 O The carboxylic acid is very expensive and ethanol is inexpensive. In the manufacture of this ester, the mole ratio of carboxylic acid to ethanol used is to 0 rather than to. (i) Use Le Chatelier s principle to explain why a to 0 mole ratio is used. In your explanation, you should not refer to cost. (Extra space)... (3) Explain how a catalyst increases the rate of a reaction. (Extra space)... (Total 2 marks) Page 9 of 4

Mark schemes (a) (i) C 4 H 0 M r = 4(2.00000) + 0(.00794) = 58.07940 or 58.0794 or 58.079 or 58.08 and 58. Working is essential, leading to the final value of 58. which must be stated in addition to one of the four numbers underlined By definition OR The standard / reference (value / isotope) Reference to 2 C alone is not enough (b) All bonds and atoms must be drawn Give credit for the displayed formula for the anion (c) (i) H 2 C = CHCH 2 OH Any correct representation including correct use of sticks. Require the double bond to be shown Addition (polymerisation) ONLY this answer (iii) M C = C (in range) 620 to 680 (cm ) M2 O H (in range) 3230 to 3550 (cm ) Award one mark for two correct ranges but a failure to draw out the C = C or O H bonds (d) (i) CH 3 COCH 3 Any correct representation including correct use of sticks 2 C [9] Page 0 of 4

2 (a) Percentage of oxygen by mass = 00 40.9 4.5 = 54.6 % Divide by A r C H O = 3.4 = 4.5 = 3.4 Divide by smallest = Nearest whole number ratio = 3.32 3 3 = 3 : 3.96 : 3 Nearest integer ratio = 3 : 4 : 3 Empirical formula C 3 H 4 O 3 Empirical formula mass = 88 = molecular formula mass Therefore, molecular formula is same as the empirical formula - C 3 H 4 O 3 (b) C 6 H 2 O 6 2C 2 H 5 OH + 2CO 2 (c) (d) (e) Advantage ethanol is produced at a faster rate Disadvantage more energy is used / required in the reaction Air gets in / oxidation occurs Alcohol OH absorption in different place (3230 3550 cm ) from acid OH absorption (2500 3000 cm ) The C=O in acids has an absorption at 680 750 cm [0] 3 (a) 2,2,4-trimethylpentane (b) 5 (c) C 20 H 42 C 8 H 8 + 2C 3 H 6 + 3C 2 H 4 Page of 4

(d) (e) Mainly alkenes formed 4 (monochloro isomers) (f) (g) C 8 H 7 35Cl = 96.0 + 7.0 + 35.0 = 48.0 and C 8 H 7 37Cl = 96.0 + 7.0 + 37.0 = 50.0 Both required M r of this C 8 H 7 Cl = 48.8 (h) = 2.05 : 2.56 : 2.05 Simplest ratio = = :.25 : Whole number ratio ( 4) = 4 : 5 : 4 MF = C 8 H 0 Cl 8 [2] Page 2 of 4

4 (a) (i) M double-headed curly arrow from the lone pair of the bromide ion to the C atom of the CH 2 Penalise additional arrows. M2 double-headed arrow from the bond to the O atom As follows 2 M nucleophilic substitution M both words needed (allow phonetic spelling). M2 -bromo(-2-)methylpropane M2 Require correct spelling in the name but ignore any hyphens or commas. 2 (b) M hydrolysis For M give credit for hydration on this occasion only. M2 C N with absorption range 2220 2260 (cm ) Credit mark from M2 and M3 for identifying C N and either O H(acids) or C=O or C O without reference to wavenumbers or with incorrect wavenumbers. M3 O H(acids) with absorption range 2500 3000 (cm ) OR C=O with absorption range 680 750 (cm ) OR C O with absorption range 000 300 (cm ) Apply the list principle to M3 3 Page 3 of 4

(c) (i) M Yield / product OR ester increases / goes up / gets more M2 (By Le Chatelier s principle) the position of equilibrium is driven / shifts / moves to the right / L to R / in the forward direction / to the product(s) M3 requires a correct statement in M2 (The position of equilibrium moves) to oppose the increased concentration of ethanol to oppose the increased moles of ethanol to lower the concentration of ethanol to oppose the change and decrease the ethanol If no reference to M, marks M2 and M3 can still score BUT if M is incorrect CE=0 If there is reference to pressure award M ONLY. 3 M Catalysts provide an alternative route / pathway / mechanism OR surface adsorption / surface reaction occurs M2 For M, not simply provides a surface as the only statement. M may be scored by reference to a specific example. that has a lower / reduced activation energy OR lowers / reduces the activation energy Penalise M2 for reference to an increase in the energy of the molecules. For M2, the student may use a definition of activation energy without referring to the term. Reference to an increase in successful collisions in unit time alone is not sufficient for M2 since it does not explain why this has occurred. 2 [2] Page 4 of 4