ELECTROCHEMISTRY I. The science concerned with the study of electron transfer across phase boundary

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ELECTROCHEMISTRY I The science concerned with the study of electron transfer across phase boundary Electrode: Is a conducting material immersed in a media. Electrode potential: Is the potential difference across formed across the phase boundary or the double layer. Double Layer: Is the arrangement of positive and negative charges Spontaneous process: Is a process that occurs naturally [ Cold to Hot, Up to Down, ] Electrolytic Solution Pressure of a Metal P: Is the tendency of a metal to go into solution as ions. Osmotic Pressure p: Is the tendency of the metal ions to deposit on the metal. Example 1 P > p The metal will continue to dissolve into ions and the electric field will increase around the electrode (at boundary ) until equilibrium is reached. If p > P the ions will deposit until equilibrium is reached. Sign Convention: The SI units are used and hence the European convention [IUPAC] i.e. the electrode potential is given the sign of the charge on the metal side. Contrary to the American convention. Example 2 Zn Zn 2+ + 2e - E o Zn/Zn 2 is -ve and equals - 0.76 v vs NHE Anodes and Cathodes Zn metal is more easily oxidized than Cu metal. Cu ions are more easily reduced than Zn ions. Thus the spontaneous reaction in a voltaic cell is the sum of two half reactions Zn Zn 2+ + 2e - Cu 2+ + 2e - Cu Zn + Cu 2+ Zn 2+ + Cu The Zn in this example is the anode and the Cu is the cathode. The anode is the sight of oxidation while the cathode is the site of reduction. How could you tell in general which of two metals will be the cathode and which will be the

Zn ANODE CATHODE Cu Anodic oxidation di ssol ut i on of Zn Cathodic reduction deposition of Cu anode. The one with -ve value of potential in the e.m.s. is the anode when existing with one with +ve value of potential. The more -ve is the anode when the two are -ve. When the two are +ve the less positive is the anode. TYPES [KINDS] OF REVERSIBLE ELECTRODES 1-Electrode of the first kind An element in contact and in equilibrium with its ions a- Metal-metal ions electrode M / M n+ Ex. Zn / Zn 2+ Ag / Ag + b- The Gas electrode A gas in contact with its own ions in solution. In this case the electrode is not a conducting material Pt or another unattackable metal which can attain a rapid equilibrium with the gas is used for the purpose of contact. H 2 / H +, Pt Cl 2 / Cl -, Pt O 2 / OH -, Pt c- The Amalgam Electrode An amalgam of a certain metal in contact with a solution containing its own ions Na(Hg) / Na + Cd(Hg) / Cd 2+ 2-Electrode of the second kind A metal covered with one of its sparingly soluble salt immersed in a solution containing the anions of this salt. Ag / AgCl / Cl - ( Silver-Silver chloride electrode ) Hg / Hg 2 Cl 2 / Cl - ( Calomel electrode ) Mechanisms

Ag Ag + + e - Ag + + Cl - AgCl Ag + Cl - AgCl + e - 2Hg 2Hg + + 2e - 2Hg + + 2C l- Hg 2 Cl 2 2Hg + 2Cl - Hg 2 Cl 2 + 2e - 3-Electrode of the third type It is an inert electrode immersed in a solution containing two oxidation states of a same species. It is important to notice that the inert electrode takes and gives electrons without the actual participation in the electrode reaction. Fe 2+ / Fe 3+, Pt Fe 2+ Fe 3+ + e - Ÿ STANDARD CELLS A standard cell can be easily prepared in a laboratory, can be stored without any change in EMF and is nearly temperature independent. Weston Cadmium Cell This is an H type cell consisting of two limbs The LHS limb contains Cd amalgam covered with crystals of 3CdSO 4.8H 2 O. The RHS contains Hg with solid Hg 2 SO 4 and covered with crystals of 3CdSO 4.8H 2 O. The whole cell is filled with a saturated solution of CdSO 4. The EMF of this cell is 1.01807 v at 25 o C and decrease about 4X10-5 v / degree. Mechanism Cd Cd 2+ + 2e - Hg 2 2+ + 2e - 2Hg The cell is represented as follows 12.5% Cd (Hg) /3CdSO 4.8H 2 O / CdSO 4 (aq. sat.)/hg 2 SO 4 (s) /Hg DERIVATION OF THE NERNST EQUATION The Nernst equation can be derived in several ways two ways are discussed. The derivation on Thermodynamic basis and the derivation on kinetic basis. Thermodynamic Basis The activity is related to the free energy by dg = RT d ln a G = G o + RT ln a (1) G o is the free energy of the system when the activity is unity and is known as the standard free energy. Consider the following equation M = M +n+ ne - Applying equation 1

G m =G m 0 + RT ln a m, G m n+ = G mn+ o + RT ln a mn+ G = G p - G r G = (G m n+ = G mn+ o + RT ln a mn+ ) - (G m = G m o + RT ln a m ) G = ( G mn+ o - G m 0 ) + RT ln a mn+ / a m G = G o + RT ln a mn+ / a m (2) Since G = -nfe deviding 2 by -nf One obtains the Nernst equation Kinetic Basis E = E o + RT/nF ln a mn+ / a m Consider the following equation M M n+ + ne - The rate of the forward reaction v f = k a m e αnfe/rt The rate of the backward reaction v b = k a mn+ e -(1-α)nFE/RT at equilibrium v f = v b and hence the following series of equation can be derived k a m e αnfe/rt = k a mn+ e -(1-α)nFE/RT e αnfe/rt / e -(1-α)nFE/RT = k / k. a mn+ / a m e nfe/rt = k / k. a mn+ / a m n F E / R T = ln k / k + ln a mn+ / a m E = R T / n F ln k / k + R T / n F ln a mn+ / a m E = E o + RT/nF ln a mn+ / a m The generalized form of Nernst equation is E = E o + RT/nF ln Π a (Oxidant) / Π a(reductant) or E = E o + 2.303RT/nF log Π a (Oxidant) / Π a(reductant)

Π means the product of activities of various species Example aa + bb cc + dd + ne - E = E o + 2.303 R T / n F log (ac) c (ad) d / (aa) a (ab) b APPLICATION OF NERNST EQUATION ON DIFFERENT TYPES OF ELECTRODES TYPES OF GALVANIC CELLS An assembly of two electrodes or in another word of two half cells produces what so called a galvanic cell or voltaic cell that has the ability of producing an electric current. Each of the half -reaction contributes to the total voltage of the cell. I An example of a simple galvanic cell is the Daniel cell composed of two compartments (half-cells) Zn and Cu. As Cu is less reactive than zinc with a standard emf of +0.34 it acts as the cathode, on the other had Zn -0.76 acts as the anode the net emf E of the cell(if acu 2+ and a Zn 2+ are both unity) is thus equal to E = E o c - E o a = E R - E L = 0.34-0.76 = 1.1 v If these electrodes are connected externally through a resistance and a galvanometer, the equilibrium is disturbed and a current flows through the circuit. This flow of current is accompanied by an increase in Zn 2+ concentration and a consecutive decrease in Cu 2+ concentration will occur As the Zn 2+ concentration increases the electrode potential of this half- cell will increase and thus will shift to more +ve potential. As the Cu 2+ concentration decreases, the potential becomes less than 0.34 and thus will shift to more -ve potential. After a time t the EMF of this cell will decrease until it reaches zero and the current will stop flowing and the cell is said to be completely discharged. -0.76 Potential EMF zero 0.34 Time t

Oxidation-Reduction Cells A Pt Sn 2+ / Sn 4+ Anode Fe 2+ / Fe 3+ Cathode These are cells in which the electrodes are redox electrodes. Anodic reaction is Sn 2+ Sn 4+ + 2e - Cathodic reaction is 2 Fe 3+ + 2e - 2Fe 2+ The net reaction Sn 2+ + 2 Fe 3+ Sn 4+ + 2Fe 2+ This means that Sn2+ reduces Fe 3+ since it has higher oxidation potential. EMF of the cell = E cathode E anode = 0.77 ( 0.15) = 0.92 V EMF = Ecathode Eanode = E Fe + RT 2 /Fe 3 2F 3+ afe ln afe 2+ E Sn 2+ /Sn 4+ + RT 2F ln a 4+ Sn a Sn 2+

= ( E Fe 2 + /Fe 3+ E Sn 2+ /Sn 4 + ) RT 2F afe 3+.a Sn 4+ ln afe 2+.aSn 2+ E cell = E cell RT 2F ln K where K = afe3+.asn 4+ afe 2 +.asn 2+ Multiply by -2F, EMF of the cell G = -nfe K: is the equilibrium constant of the cell reaction. At equilibrium G = Zero G o = RT lnk but G o = -nfe o n FE o cell = RT lnk Since n, F, E o, R and T are known, we can calculate the equilibrium constant of the cell reaction "K". Concentration Cells Cathode Anode Salt Bridge a2 a1 Cu CuSO 4 a 2 > a 1 Anodic Reaction Cu( a 1 ) = Cu 2+ ( a 1 )+ 2e Cathodic Reaction Cu 2 ( a 2 ) + 2e = Cu( a 2 ) Overall Cell Reaction Cu(a 1 ) + Cu 2+ (a 2 ) = Cu 2 + (a 1 ) + Cu(a 2 ) EMF = E c - E a

= E + RT 2F lna 2 E RT 2F lna 1 = RT 2F (lna 2 ln a 1 ) = RT 2F ln a 2 a 1 EMF = RT 2F ln a 2 a 1 If a 1 = a 2 = ln a 2 = Zero a 1 EMF = Zero i.e. no current pass. Concentration Cell (Chlorine-Hydrogen Cell) Cl 2 H2 HCl m = molarity Anodic Reaction: H 2 = 2H 2 + + 2e Cathodic Reaction: Cl 2 + 2e = 2Cl E H 2 /H = E H 2 /H + + RT 2F ln a 2 + H PH 2 anode = RT 2F ln a 2 H + E Cl 2 /Cl = E Cl2 /Cl + RT 2F ln P Cl 2 2 Cathode a Cl = E RT Cl2 /Cl 2F ln a 2 Cl

EMF = E cathode - E anode = E Cl RT 2 /Cl 2F ln a 2 Cl RT 2F ln a +2 Cl + assume that γ H + = γ Cl EMF = E Cl2 /Cl RT F ln[ H+ ]Cl [ ] sin ce [ H + ]= [ Cl ]= m = E Cl 2 /Cl 2RT F ln m2 = E Cl 2 /Cl 2RT F ln m where "m" is the molarity of HCl Concentration Cell without Transport (Helmholtz double Cell) H 2 Cl 2 Cl 2 H 2 HCl m1 HCl m2 m1 > m2 This cell will react to decrease m1 This cell will react to increase m2 2H + + 2e = H 2 H 2 = 2H + + 2e 2Cl = Cl 2 + 2e Cl 2 + 2e = 2Cl 2H + + 2Cl = H 2 + Cl 2 H 2 + Cl 2 = 2H + + 2Cl

E 1 = E 2RT F ln m 1 E 2 = E 2RT F ln m 2 EMF (Combination) = E 2 E 1 (E 2 > E 1 ) N.B. Free energy of dilution = 2RT F ln m 1 m 2 Concentration Cell with Transport G = -nfe of concentration cell without transport G = 2RT ln m 1 m 2 H2 H2 Porous membrane H2 P1 H2 P2 HCl (a) m1 m1 > m1 > m2 Cathodic Reaction 2H + + 2e = H 2 HCl m2 m2 m HCl P1 > P2 Anodic Reaction H 2 = 2H + + 2e No Net Reaction Cl - is transported by diffusion and or migration from cathode compartment to anode compartment. t - Cl is the transport number which is defined as the fraction of the total current which is carried by the particular ion. Therefore, the EMF of concentration cell with transport would be: E = 2RT F t Xln m 1 Cl m 2

(b) P 1 > P 2 e a = e + RT 2F ln a 2 1 H P 1H2 e c = e + RT 2F ln a 2 + H P 2 H 2 EMF of the cell = e c e a = RT 2F ln P 2 P 1 THERMODYNAMICS OF GALVANIC CELLS The factors which influence the EMF of the cell are usually the concentration, pressure and temperature 1- Concentration (Pressure) effect on EMF E = E o + RT/nF ln Π a oxidant /Π a reductant If the concentration is varied in either oxidant or reductant the EMF will consequently vary. The pressure variation acts similarly for gas reactions. 2- Effect of Temperature on EMF (δg/δt)p = -S (δ G/δT)p = - S but G = -nfe nfe(δe/δt)p = S and since G = H - T S G = H -TnF(δE/δT)p nft(δe/δt)p = H - G δe/δt is the temperature coefficient. H, is the heat content change in the reaction which is the measure of the chemical energy produced by the cell. G is the free energy change and its a measure for the quantity of useful electrical work which is produced y the cell reaction. G = -nfe. If δe/δt = 0 G = H i.e. Quantitative conversion of the chemical energy change into useful electrical energy. If δe/δt > o i.e. the EMF of the cell increase with rise of temperature H> G But - H is the chemical energy change of the reaction and - G is the electrical energy or useful work thus - G> - H therefore the useful work is more than the chemical work of the cell reaction, thus the cell absorbs heat from the surrounding and transfer it to electrical energy.

If δe/δt < o H < G - H > - G in this case the cell heats i.e. the conversion of the chemical energy into electrical energy is not quantitative and some of the chemical energy is lost to the surrounding the form of heat energy. ELECTROCHEMISTRY OF IRREVERSIBLE PROCESSES M M 2+ + 2e - In a reversible reaction there is always a dynamic equilibrium. The reaction does not stop but proceeds with equal rates in both forward and backward directions at the same time. Thus for an electrode dipped in its ions the number of electrons generated by an anodic reaction at a certain time is equal to the number of electrons consumed by the cathodic reaction hence no net current is observed at equilibrium i.e. no net charge flow exists across the electrical double layer. Now if this system is subjected to any disturbance, the rate of one process will exceed the other and thus a net flow of electrical charge across the phase boundary will exist until another equilibrium is reached or achieved under the new conditions. Polarization Overpotential - Overtension The overpotential is defined as the magnitude of the difference of the electrode potential when current flows from the reversible value. At equilibrium there is no net current flowing in the electrode and what we measure is the equilibrium or reversible electrode potential, on the other hand when a net current anodic or cathodic flows out of the electrode or into the electrode the potential becomes different from the equilibrium potential, the magnitude of this difference is the overpotential. If the irreversible potential is more anodic as compared, to the equilibrium potential the electrode is said to be Anodically Polarized and the polarization is known as Anodic Polarization. The contrary is true if the irreversible electrode potentials less anodic or cathodic, the electrode is then Cathodically Ppolarized and the polarization is called Cathodic Polarization. The magnitude of polarization is given by η η = E irrev - E rev where η is the overpotential or polarization THE VOLMER - TAFEL RELATION The current is given by Faraday s law I = n F. rate Thus the anodic current expression is given by i a = n F a r k f e (1 - α)n F E / R T

i c = nf a p k b e - α n F E / R T at equilibrium E = E rev and i a = i c and no net current flow in the circuit. This current at equilibrium is called the exchange current i o, thus one can write i o = n F a r k f e (1 - α)n F E / R T = nf a p k b e - α n F E / R T and since E = Erev + η one can write the following i a = n F a r k f e (1 - α)n F (Erev + η ) / R T i a = n F a r k f e (1 - α)n F (Erev) / R T e (1 - α) n F η / R T i a = i o e i o (1 - α) n F η / R T By the same way one may say i c = i o e - α n F η / R T and the net current is given by i net = i a - i c = i o [ e (1 - α) n F η / R T - e - α n F η / R T ] The Volmer - Tafel relation is obtained thisw relation simply gives the net current under polarization in terms of kinetic parameters.