Number of people in family Frequency

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1) 40 students are asked about the number of people in their families. The table shows the results. Number of people in family 2 3 4 5 6 7 Frequency 1 1 17 12 6 3 (a) Find (i) the mode, (ii) the median, Answer(a)(i) [1] Answer(a)(ii) [1] (iii) the mean. Answer(a)(iii) [3] (b) Another n students are asked about the number of people in their families. The mean for these n students is 3. Find, in terms of n, an expression for the mean number for all (40 + n) students. Answer(b) [2]

2) (a) The table shows how many books were borrowed by the 126 members of a library group in a month. Number of books 11 12 13 14 15 16 Number of members (frequency) 35 28 22 18 14 9 Find the mode, the median and the mean for the number of books borrowed. Answer(a) mode = median = mean = [6] (b) The 126 members record the number of hours they read in one week. Frequency density 15 The histogram shows the results. 10 5 0 5 8 10 12 16 20 Time (hours) h

2 continued ) (i) Use the information from the histogram to complete the frequency table. Number of hours (h) 0 I h Y 5 5 I h Y 8 8 I h Y 10 10 I h Y 12 12 I h Y 16 16 I h Y 20 Frequency 20 24 10 [3] (ii) Use the information in this table to calculate an estimate of the mean number of hours. Show your working. 3) The masses of 60 potatoes are measured. The table shows the results. Mass (m grams) 10 I m Y 20 20 I m Y 40 40 I m Y 50 Frequency 10 30 20 (a) Calculate an estimate of the mean. Answer(a) g [4]

3 continued) (b) On the grid, draw an accurate histogram to show the information in the table. 2 Frequency density 1 0 10 20 30 40 50 m Mass (grams) [3]

4) The table below shows the marks scored by a group of students in a test. Mark 11 12 13 14 15 16 17 18 Frequency 10 8 16 11 7 8 6 9 (a) Find the mean, median and mode. Answer(a) mean = median = mode = [6] (b) The table below shows the time (t minutes) taken by the students to complete the test. Time (t) 0 I=t Y=10 10 I=t Y=20 20 I=t Y=30 30 I=t Y=40 40 I=t Y=50 50 I=t Y=60 Frequency 2 19 16 14 15 9 (i) Cara rearranges this information into a new table. Complete her table. Time (t) 0 I=t Y=20 20 I=t Y=40 40 I=t Y=50 50 I=t Y=60 Frequency 9 [2] (ii) Cara wants to draw a histogram to show the information in part (b)(i). Complete the table below to show the interval widths and the frequency densities. Interval width Frequency density 0 I=t Y=20 20 I=t Y=40 40 I=t Y=50 50 I=t Y=60 10 0.9 [3]

4 continued) (c) Some of the students were asked how much time they spent revising for the test. 10 students revised for 2.5 hours, 12 students revised for 3 hours and n students revised for 4 hours. The mean time that these students spent revising was 3.1 hours. Find n. Show all your working. Answer(c) n = [4]

5) Time (t mins) 0 I t Y 20 20 I t Y 35 35 I t Y 45 45 I t Y 55 55 I t Y 70 70 I t Y 80 Frequency 6 15 19 37 53 20 The table shows the times taken, in minutes, by 150 students to complete their homework on one day. (a) (i) In which interval is the median time? Answer(a)(i) [1] (ii) Using the mid-interval values 10, 27.5,..calculate an estimate of the mean time. Answer(a)(ii) min [3] (b) (i) Complete the table of cumulative frequencies. Time (t mins) Cumulative frequency t Y 20 t Y 35 t Y 45 t Y 55 t Y 70 t Y 80 6 21 [2] (ii) On the grid, label the horizontal axis from 0 to 80, using the scale 1 cm represents 5 minutes and the vertical axis from 0 to 150, using the scale 1 cm represents 10 students. Draw a cumulative frequency diagram to show this information. [5] 5 continued on next page )

(c) Use your graph to estimate (i) the median time, Answer(c)(i) min [1] (ii) the inter-quartile range, Answer(c)(ii) min [2] (iii) the number of students whose time was in the range 50 I t Y 60, Answer(c)(iii) [1] (iv) the probability, as a fraction, that a student, chosen at random, took longer than 50 minutes, Answer(c)(iv) [2] (v) the probability, as a fraction, that two students, chosen at random, both took longer than 50 minutes. Answer(c)(v) [2]

6) 200 180 160 140 120 Cumulative frequency 100 80 60 40 20 0 1 2 3 4 5 6 7 8 9 10 Mass (kilograms) m The masses of 200 parcels are recorded. The results are shown in the cumulative frequency diagram above. (a) Find (i) the median, Answer(a)(i) kg [1] (ii) the lower quartile, Answer(a)(ii) kg [1] (iii) the inter-quartile range, Answer(a)(iii) kg [1] (iv) the number of parcels with a mass greater than 3.5 kg. Answer(a)(iv) [2]

(b) (i) Use the information from the cumulative frequency diagram to complete the grouped frequency table. Mass (m) kg 0 I m Y 4 4 I m Y 6 6 I m Y 7 7 I m Y 10 Frequency 36 50 (ii) Use the grouped frequency table to calculate an estimate of the mean. [2] Answer(b)(ii) kg [4] (iii) Complete the frequency density table and use it to complete the histogram. Mass (m) kg 0 I m Y 4 4 I m Y 6 6 I m Y 7 7 I m Y 10 Frequency density 9 16.7 40 35 30 Frequency density 25 20 15 10 5 0 1 2 3 4 5 6 7 8 9 10 Mass (kilograms) m [4]