Additional Math (4047) Paper 2 (100 marks) y x. 2 d. d d

Similar documents
y cos x = cos xdx = sin x + c y = tan x + c sec x But, y = 1 when x = 0 giving c = 1. y = tan x + sec x (A1) (C4) OR y cos x = sin x + 1 [8]

Chapter 1. Chapter 10. Chapter 2. Chapter 11. Chapter 3. Chapter 12. Chapter 4. Chapter 13. Chapter 5. Chapter 14. Chapter 6. Chapter 7.

Thomas Whitham Sixth Form

Thomas Whitham Sixth Form

Mathematics 1110H Calculus I: Limits, derivatives, and Integrals Trent University, Summer 2018 Solutions to the Actual Final Examination

1973 AP Calculus AB: Section I

Prelim Examination 2011 / 2012 (Assessing Units 1 & 2) MATHEMATICS. Advanced Higher Grade. Time allowed - 2 hours

MATHEMATICS (B) 2 log (D) ( 1) = where z =

1997 AP Calculus AB: Section I, Part A

1997 AP Calculus AB: Section I, Part A

Math 34A. Final Review

are given in the table below. t (hours)

1 1 1 p q p q. 2ln x x. in simplest form. in simplest form in terms of x and h.

7' The growth of yeast, a microscopic fungus used to make bread, in a test tube can be

2008 AP Calculus BC Multiple Choice Exam

AP Calculus BC AP Exam Problems Chapters 1 3

MSLC Math 151 WI09 Exam 2 Review Solutions

Objective Mathematics

PHYS ,Fall 05, Term Exam #1, Oct., 12, 2005

as a derivative. 7. [3.3] On Earth, you can easily shoot a paper clip straight up into the air with a rubber band. In t sec

Grade 12 (MCV4UE) AP Calculus Page 1 of 5 Derivative of a Function & Differentiability

A. Limits and Horizontal Asymptotes ( ) f x f x. f x. x "±# ( ).

AP Calculus Multiple-Choice Question Collection

MAXIMA-MINIMA EXERCISE - 01 CHECK YOUR GRASP

(HELD ON 21st MAY SUNDAY 2017) MATHEMATICS CODE - 1 [PAPER-1]

Things I Should Know Before I Get to Calculus Class

4. (5a + b) 7 & x 1 = (3x 1)log 10 4 = log (M1) [4] d = 3 [4] T 2 = 5 + = 16 or or 16.

The graph of y = x (or y = ) consists of two branches, As x 0, y + ; as x 0, y +. x = 0 is the

Differentiation of Exponential Functions

DIFFERENTIAL EQUATION

[1] (20 points) Find the general solutions of y y 2y = sin(t) + e t. Solution: y(t) = y c (t) + y p (t). Complementary Solutions: y

dy 1. If fx ( ) is continuous at x = 3, then 13. If y x ) for x 0, then f (g(x)) = g (f (x)) when x = a. ½ b. ½ c. 1 b. 4x a. 3 b. 3 c.

Calculus II (MAC )

Solution: APPM 1360 Final (150 pts) Spring (60 pts total) The following parts are not related, justify your answers:

a 1and x is any real number.

Differential Equations

Unit 6: Solving Exponential Equations and More

Calculus Revision A2 Level

TEMASEK JUNIOR COLLEGE, SINGAPORE. JC 2 Preliminary Examination 2017

Numerical methods, Mixed exercise 10

Calculus concepts derivatives

First derivative analysis

Y 0. Standing Wave Interference between the incident & reflected waves Standing wave. A string with one end fixed on a wall

Note If the candidate believes that e x = 0 solves to x = 0 or gives an extra solution of x = 0, then withhold the final accuracy mark.

MATHEMATICS PAPER IIB COORDINATE GEOMETRY AND CALCULUS. Note: This question paper consists of three sections A, B and C.

MATH 1080 Test 2-SOLUTIONS Spring

Additional Math (4047) Paper 1(80 marks)

Prod.C [A] t. rate = = =

Section 11.6: Directional Derivatives and the Gradient Vector

Exercise 1. Sketch the graph of the following function. (x 2

SPH4U Electric Charges and Electric Fields Mr. LoRusso

5. B To determine all the holes and asymptotes of the equation: y = bdc dced f gbd

Mathematics. Complex Number rectangular form. Quadratic equation. Quadratic equation. Complex number Functions: sinusoids. Differentiation Integration

CHAPTER 5. Section 5-1

Problem Set 6 Solutions

JOHNSON COUNTY COMMUNITY COLLEGE Calculus I (MATH 241) Final Review Fall 2016

Examples and applications on SSSP and MST

Multiple Short Term Infusion Homework # 5 PHA 5127

KCET 2016 TEST PAPER WITH ANSWER KEY (HELD ON WEDNESDAY 4 th MAY, 2016)

Exiting from QE. Fumio Hayashi and Junko Koeda. for presentation at SF Fed Conference. March 28, 2014

Homework #3. 1 x. dx. It therefore follows that a sum of the

Calculus II Solutions review final problems

cycle that does not cross any edges (including its own), then it has at least

Answers & Solutions. for MHT CET-2018 Paper-I (Mathematics) Instruction for Candidates

y = 2xe x + x 2 e x at (0, 3). solution: Since y is implicitly related to x we have to use implicit differentiation: 3 6y = 0 y = 1 2 x ln(b) ln(b)

4037 ADDITIONAL MATHEMATICS

Constants and Conversions:

The Transfer Function. The Transfer Function. The Transfer Function. The Transfer Function. The Transfer Function. The Transfer Function

Background: We have discussed the PIB, HO, and the energy of the RR model. In this chapter, the H-atom, and atomic orbitals.

Bifurcation Theory. , a stationary point, depends on the value of α. At certain values

Chapter two Functions

CHAPTER 24 HYPERBOLIC FUNCTIONS

Where k is either given or determined from the data and c is an arbitrary constant.

Combinatorial Networks Week 1, March 11-12

Mock Exam 2 Section A

Massachusetts Institute of Technology Department of Mechanical Engineering

Supplementary Materials

Engineering Differential Equations Practice Final Exam Solutions Fall 2011

MATHEMATICS PAPER IB COORDINATE GEOMETRY(2D &3D) AND CALCULUS. Note: This question paper consists of three sections A,B and C.

Week 3: Connected Subgraphs

Optics and Non-Linear Optics I Non-linear Optics Tutorial Sheet November 2007

10. Limits involving infinity

A Prey-Predator Model with an Alternative Food for the Predator, Harvesting of Both the Species and with A Gestation Period for Interaction

6. ANGLES AND ELEMENTAL TRIGONOMETRY

Text: WMM, Chapter 5. Sections , ,

SECTION where P (cos θ, sin θ) and Q(cos θ, sin θ) are polynomials in cos θ and sin θ, provided Q is never equal to zero.

MA1506 Tutorial 2 Solutions. Question 1. (1a) 1 ) y x. e x. 1 exp (in general, Integrating factor is. ye dx. So ) (1b) e e. e c.

Partial Derivatives: Suppose that z = f(x, y) is a function of two variables.

INTEGRATION BY PARTS

Ch. 24 Molecular Reaction Dynamics 1. Collision Theory

Higher order derivatives

Sundials and Linear Algebra

SIGNIFICANCE OF SMITH CHART IN ANTENNA TECHNOLOGY

Classical Magnetic Dipole

3) Use the average steady-state equation to determine the dose. Note that only 100 mg tablets of aminophylline are available here.

ENJOY MATHEMATICS WITH SUHAAG SIR

Errata. Items with asterisks will still be in the Second Printing

MAT 270 Test 3 Review (Spring 2012) Test on April 11 in PSA 21 Section 3.7 Implicit Derivative

64. A Conic Section from Five Elements.

22/ Breakdown of the Born-Oppenheimer approximation. Selection rules for rotational-vibrational transitions. P, R branches.

Transcription:

Aitional Math (07) Prpar b Mr Ang, Nov 07 Fin th valu of th constant k for which is a solution of th quation k. [7] Givn that, Givn that k, Thrfor, k Topic : Papr (00 marks) Tim : hours 0 mins Nam :

Aitional Math (07) (i) Show that tan tan. [] Without using a calculator, fin th valu of ach of th constants a an b for which (i) Lt tan, cos sin cos sin cos tan sc tan a b cos sin cos cos. [] sc tan tan tan tan tan tan tan tan a, b Prpar b Mr Ang, Nov 07

Aitional Math (07) (i) 9 B consiring th gnral trm in th binomial pansion of p, whr p is a constant, plain wh thr ar no vn powrs of in this pansion. [] Givn that th cofficint of in th pansion of p is twic th cofficint of 7. Fin th valu of p. [] 9 9 9r (i) Lt T p r r whr r = 0,,,, 9 r r 9 9r 9r p r 9 9r 7 r p r Sinc r is a non-ngativ intgr, so r is an vn non-ngativ intgr. 7 r is thrfor an o intgr. As a rsult, th powr of cannot b an vn numbr. For th trm, 7 r, r. 9 th cofficint of p 9 For th 7 trm, 7 r 7, r. 9 p 9 p 9 8 p th cofficint of 7 9 9 9 8 p 7 p p p p 0 p 0 7 p p 0 or p p 0, as th cofficint of is twic th cofficint of 7. p p Prpar b Mr Ang, Nov 07

Aitional Math (07) Th curv has a minimum point M. (i) Show that th -coorinat of M satisfis th quation 9. [] Point A(, 7) an B(, 7) li on th curv mt at th point P.. Th tangnts to th curv at A an B Dtrmin, with working, whthr th -coorinat of P is gratr or lss than th -coorinat of M. [] (i) Givn, Lt 0, 0 9 A(, 7) an B(, 7) Whn, Equation of tangnt at A, 7 9 Whn, 8 Equation of tangnt at B, 7 8 8 Solving simultanous quation 9 8 7 Sinc 9 8, M M 7 an 9 8, thrfor P is lss than M. Prpar b Mr Ang, Nov 07

Aitional Math (07) (i) Solv th quation log log log. [] 7 Solv th quation log 00 lg, giving our answr to significant figurs. [] (i) log log log log 7 log log 7 7 7 7 7 log log log log 00 lg lg00 lg lg lg lg lg 0 or 0 or 0. 09 ( s.f.) Prpar b Mr Ang, Nov 07

Aitional Math (07) Th quation of a curv is m c 9, whr m an c ar constants. Th lin m c is tangnt to th curv at th point P. (i) Fin th positiv valu of m. [] Using this valu of m, an givn that th curv passs through (, 9), fin th coorinats of P. [] Th straight lin L mts th curv at on point onl. (iii) Givn that L is not a tangnt to th curv, what can b uc about L? [] (i) Solving simultanous quations m c 9 m 0 Th iscriminant = 0, m 9 0 m m m or m 7 (rjct) 9 an m c Lt m, (, 9), c 9 9 c 9 0 0 P, (iii) L must b a vrtical lin. Prpar b Mr Ang, Nov 07

Aitional Math (07) 7 (a) Th prcntag, P, of carbon- rmaining in a pic of fossilis woo is givn b kt P 00, whr k is a constant an t is masur in ars. It taks 70 ars for th carbon- to b ruc to half of th original amount. Calculat (i) th valu of k, [] th prcntag of carbon- which woul inicat a fossil ag of 8000 ars. [] (b) Th siz, S, an intnsit, I, of a naturall occuring vnt ar connct b th I formula S lg, whr c is a constant, Calculat, to cimal plac, th siz of th c vnt which has intnsit 0 tims that of an vnt of siz.. [] (a) (i) 0 Whn t 0, P 0 00, 0 00 Whn t 70, P 0, k 70 0 00 k 70 0. ln 0. 70k ln 0. k 70 k.0 ( s.f.) Whn t 8000, P P k 0 P P0 P P 0 8000 8000 k 0.80 ( s.f.) prcntag of carbon- is 8% (b) Givn that I S lg, whn S., c. I c0 whn,. I 0c0, S lg S lg 0. S. 0c0 c. Prpar b Mr Ang, Nov 07 7

Aitional Math (07) 8 (a) A particl movs along th curv ln in such a wa that th -coorinat of th particl is incrasing at a constant rat of 0.0 units pr scon. Fin th rat at which th -coorinat of th particl is incrasing at th instant whn 7. [] (b) Th quation of a curv is 8. (i) Eplain wh th curv has onl on stationar point an wh this is a point of inflion. [] Writ own th coorinats of th stationar point. [], 0. 0 t t t (a) Givn that ln 0.0 0 t 0. units pr scon t (b) Givn that 8,, 7, (i) Lt 0, 0, singl stationar point. Whn 0., 0. 0. 0 Whn 0., 0. 0. 0 Th curv rmains crasing aroun th stationar point. Hnc, it is a point of inflion. Whn 0., 8 Th stationar point is ( 0., 8) Prpar b Mr Ang, Nov 07 8

Aitional Math (07) 9 Th iagram shows a trapzium with vrtics A(, ), B(0, p), C(, ) an D. Th sis AB an DC ar paralll an th angl DAB is 90. Angl ABO is qual to angl CBO. (i) Eprss th graints of th lins AB an CB in trms of p an hnc, or othrwis, show that p =. [] Fin th coorinats of th point D. [] (iii) Fin th ara of th trapzium ABCD. [] (i) graint of th lins AB, graint of th lins CB, Hnc p m AB m CB p p p p p p 0 p p 0 Prpar b Mr Ang, Nov 07 9

Aitional Math (07) graint of th lins AB, m AB Sinc AB//DC, m m DC AB Equation of DC, Sinc AB AD, m AD mab Equation of AD, Solving simultanous quation an Substitut into. D, (iii) ara of th trapzium ABCD 9 squar units Prpar b Mr Ang, Nov 07 0

Aitional Math (07) 0 It is givn that sin an cos. (i) Stat th amplitu an th prio, in grs, of (a), (b). [] For th intrval 0 0, solv th quation, [] (iii) sktch, on th sam iagram, th graphs of an, [] (iv) fin th st of valus of for which 0. [] (i) (a) for, amplitu = ; prio = 0 (b) for, amplitu = ; prio = 80 solv th quation, sin cos sin cos sin sin sin sin sin 0 sin sin or sin (no solution) Principal angl, sin 8. 7 80 8. 7 or 0 8. 7 8. or. 8 (.p.) Prpar b Mr Ang, Nov 07

Aitional Math (07) (iii) sktch, on th sam iagram, th graphs of an, sin cos (iv) From th graphs in part (iii), for th st of valus of for which 0. 0 8. or.8 0 Prpar b Mr Ang, Nov 07

Aitional Math (07) Th iagram shows an ara of rough groun borr b a straight roa XY. Th point O is such that OX = km, OY = km an angl XOY = 90. A cross-countr runnr lavs O an rachs P on th roa XY aftr running for km in a straight lin inclin at an angl to OY. (i) Eprss th shortst istanc of P from OX an from OY in trms of. [] Show that 0 cos sin. [] (iii) Eprss 0 cos sin in th form R cos, whr R > 0 an is acut. [] (iv) Fin th valu of. [] (i) P from OX, cos, P from OY, sin. (iii) B similar triangls, cos sin sin 0 cos 0 cos sin R 0 tan 0 cos sin cos 0 Prpar b Mr Ang, Nov 07

Aitional Math (07) (iv) cos cos Principal angl, 9. 97 9. 97 or 0 9. 97 9. 97 0 9. 97 9.97 tan 0 9.97 tan 80. 98 0. 98 Sinc 0 90, rjcts 0. 98 80. 9 (.p.) Prpar b Mr Ang, Nov 07