Chapter 21 Electric Charge and Electric Field

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Chapter 21 Electric Charge and Electric Field 21-1 Static Electricity; Electric Charge and Its Conservation Objects can be charged by rubbing 21-1 Static Electricity; Electric Charge and Its Conservation Charge comes in two types, positive and negative; like charges repel and opposite charges attract. 21-1 Static Electricity; Electric Charge and Its Conservation Electric charge is conserved the arithmetic sum of the total charge cannot change in any interaction. 21-2 Electric Charge in the Atom Atom: Nucleus (small, massive, positive charge) Electron cloud (large, very low density, negative charge) 1

21-2 Electric Charge in the Atom Polar molecule: neutral overall, but charge not evenly distributed 21-3 Insulators and Conductors Conductor: Insulator: Charge flows freely Almost no charge flows Metals Most other materials Some materials are semiconductors. Metal objects can be charged by conduction: They can also be charged by induction, either while connected to ground or not: Nonconductors won t become charged by conduction or induction, but will experience charge separation: The electroscope can be used for detecting charge. 2

The electroscope can be charged either by conduction or by induction. The charged electroscope can then be used to determine the sign of an unknown charge. Experiment shows that the electric force between two charges is proportional to the product of the charges and inversely proportional to the distance between them. Coulomb s law: This equation gives the magnitude of the force between two charges. The force is along the line connecting the charges, and is attractive if the charges are opposite, and repulsive if they are the same. Unit of charge: coulomb, C. The proportionality constant in Coulomb s law is then: k = 8.99 x 10 9 N m 2 /C 2. Charges produced by rubbing are typically around a microcoulomb: 1 μc = 10-6 C. 3

Charge on the electron: e = 1.602 x 10-19 C. The proportionality constant k can also be written in terms of ε 0, the permittivity of free space: Electric charge is quantized in units of the electron charge. Conceptual Example 21-1: Which charge exerts the greater force? Two positive point charges, Q 1 = 50 μc and Q 2 = 1 μc, are separated by a distance l. Which is larger in magnitude, the force that Q 1 exerts on Q 2 or the force that Q 2 exerts on Q 1? Example 21-2: Three charges in a line. Three charged particles are arranged in a line, as shown. Calculate the net electrostatic force on particle 3 (the -4.0 μc on the right) due to the other two charges. 4

Example 21-3: Electric force using vector components. Calculate the net electrostatic force on charge Q 3 shown in the figure due to the charges Q 1 and Q 2. Conceptual Example 21-4: Make the force on Q 3 zero. In the figure, where could you place a fourth charge, Q 4 = -50 μc, so that the net force on Q 3 would be zero? The electric field is defined as the force on a small charge, divided by the magnitude of the charge: 5

An electric field surrounds every charge. For a point charge: Force on a point charge in an electric field: Example 21-5: Photocopy machine. A photocopy machine works by arranging positive charges (in the pattern to be copied) on the surface of a drum, then gently sprinkling negatively charged dry toner (ink) particles onto the drum. The toner particles temporarily stick to the pattern on the drum and are later transferred to paper and melted to produce the copy. Suppose each toner particle has a mass of 9.0 x 10-16 kg and carries an average of 20 extra electrons to provide an electric charge. Assuming that the electric force on a toner particle must exceed twice its weight in order to ensure sufficient attraction, compute the required electric field strength near the surface of the drum. Example 21-6: Electric field of a single point charge. Calculate the magnitude and direction of the electric field at a point P which is 30 cm to the right of a point charge Q = -3.0 x 10-6 C. (b) 6

Example 21-7: E at a point between two charges. Two point charges are separated by a distance of 10.0 cm. One has a charge of -25 μc and the other +50 μc. (a) Determine the direction and magnitude of the electric field at a point P between the two charges that is 2.0 cm from the negative charge. (a) If an electron (mass = 9.11 x 10-31 kg) is placed at rest at P and then released, what will be its initial acceleration (direction and magnitude)? Example 21-8: above two point charges. Calculate the total electric field (a) at point A and (b) at point B in the figure due to both charges, Q 1 and Q 2. r E 7

Problem solving in electrostatics: electric forces and electric fields 1. Draw a diagram; show all charges, with signs, and electric fields and forces with directions. 2. Calculate forces using Coulomb s law. 3. Add forces vectorially to get result. 4. Check your answer! 21-8 Field Lines The electric field can be represented by field lines. These lines start on a positive charge and end on a negative charge. 21-8 Field Lines The number of field lines starting (ending) on a positive (negative) charge is proportional to the magnitude of the charge. 21-8 Field Lines Electric dipole: two equal charges, opposite in sign: The electric field is stronger where the field lines are closer together. 21-8 Field Lines The electric field between two closely spaced, oppositely charged parallel plates is constant. 21-8 Field Lines Summary of field lines: 1. Field lines indicate the direction of the field; the field is tangent to the line. 2. The magnitude of the field is proportional to the density of the lines. 3. Field lines start on positive charges and end on negative charges; the number is proportional to the magnitude of the charge. 8

21-10 Motion of a Charged Particle in an Electric Field The force on an object of charge q in an electric field E uur is given by: F uur = qe uur Therefore, if we know the mass and charge of a particle, we can describe its subsequent motion in an electric field. 21-10 Motion of a Charged Particle in an Electric Field Example 21-15: Electron accelerated by electric field. An electron (mass m = 9.11 x 10-31 kg) is accelerated in the uniform field E uur (E = 2.0 x 10 4 N/C) between two parallel charged plates. The separation of the plates is 1.5 cm. The electron is accelerated from rest near the negative plate and passes through a tiny hole in the positive plate. (a) With what speed does it leave the hole? (b) Show that the gravitational force can be ignored. Assume the hole is so small that it does not affect the uniform field between the plates. 21-10 Motion of a Charged Particle in an Electric Field r Example 21-16: Electron moving perpendicular to E. Suppose an electron traveling rwith speed v 0 = 1.0 x 10 7 m/s enters a uniform electric field E, which is at right angles to v 0 as shown. Describe its motion by giving the equation of its path while in the electric field. Ignore gravity. Summary of Chapter 21 Two kinds of electric charge positive and negative. Charge is conserved. Charge on electron: e = 1.602 x 10-19 C. Conductors: electrons free to move. Insulators: nonconductors. 9

Charge is quantized in units of e. Objects can be charged by conduction or induction. Coulomb s law: Summary of Chapter 21 Electric field is force per unit charge: Summary of Chapter 21 Electric field of a point charge: Electric field can be represented by electric field lines. Static electric field inside conductor is zero; surface field is perpendicular to surface. 10