Logarithmic and Exponential Equations and Change-of-Base

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Logarithmic and Exponential Equations and Change-of-Base MATH 101 College Algebra J. Robert Buchanan Department of Mathematics Summer 2012

Objectives In this lesson we will learn to solve exponential equations in which the bases are the same, solve exponential equations in which the bases are not the same, solve equations involving logarithms, and use the change-of-base formula and a calculator to evaluate logarithmic expressions.

Review: Properties of Exponents Theorem If a and b are positive real numbers and if x and y are any real numbers, then: 1 b 0 = 1 2 b x = 1 b x 3 b x b y = b x+y b x 4 b y = bx y 5 (b x ) y = b xy 6 (a b) x = a x b x 7 ( a b ) = ax b x

Properties of Equations with Exponents and Logarithms Theorem For b > 0 and b 1, 1 If b x = b y, then x = y. 2 If x = y, then b x = b y. 3 If log b x = log b y, then x = y (for x > 0 and y > 0) 4 If x = y, then log b x = log b y (for x > 0 and y > 0).

Solving an Equation with Same Base If an equation involves exponential expressions on both sides of the equals symbol and the bases are the same, then the exponents must be the same. 3 2x 2 +3 = 3 x+6

Solving an Equation with Same Base If an equation involves exponential expressions on both sides of the equals symbol and the bases are the same, then the exponents must be the same. 3 2x 2 +3 = 3 x+6 2x 2 + 3 = x + 6 2x 2 x 3 = 0 (2x 3)(x + 1) = 0 x = 3 2 or x = 1

Solving Exponential Equations with Different Bases If the bases are different on the two sides of an equation involving exponential expressions, we may take the logarithm of both sides to solve the equation. 3 10 2.1x = 83.5

Solving Exponential Equations with Different Bases If the bases are different on the two sides of an equation involving exponential expressions, we may take the logarithm of both sides to solve the equation. 3 10 2.1x = 83.5 10 2.1x = 27.83 log 10 2.1x = log 27.83 2.1x = 1.44457 x = 0.687888

Solving Equations with Logarithms We may use the properties of logarithms to solve equations involving logarithms. 2 log x 15 = 0

Solving Equations with Logarithms We may use the properties of logarithms to solve equations involving logarithms. 2 log x 15 = 0 2 log x = 15 log x = 15 2 10 log x = 10 15/2 x = 10 15/2 31, 622, 776.6

Change-of-Base Formula Question: how do we use a calculator to evaluate logarithms with bases other than e or 10?

Change-of-Base Formula Question: how do we use a calculator to evaluate logarithms with bases other than e or 10? Theorem For a, b, x > 0 with a 1 and b 1 then Proof. log b x = log a x log a b. b log b x = x log a b log b x = log a x log b x (log a b) = log a x log b x = log a x log a b

s Since nearly every scientific calculator includes a natural logarithm LN key, we may use it to help us calculate logarithms in any other base. log 4 36 = ln 36 ln 4 = 3.58352 1.38629 = 2.58496

s Since nearly every scientific calculator includes a natural logarithm LN key, we may use it to help us calculate logarithms in any other base. log 4 36 = ln 36 ln 4 = 3.58352 1.38629 = 2.58496 We can check our work: 4 2.58496 = 36