Law of Definite Proportion** (Proust): A given compound always contains exactly the same proportion of elements by mass.

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# 10 Notes Unit 2: Laws, Properties & Mols Ch. Atoms, Molecules, Ions 5 Chemical Laws: I. Law of Conservation of Mass** (Lavoisier): Mass cannot be created or destroyed. II. III. IV. Law of Definite Proportion** (Proust): A given compound always contains exactly the same proportion of elements by mass. Law of Multiple Proportions** (Dalton): When 2 elements form more than 1 compound, for a fixed mass of one element, the masses of the second element are related to each other by small whole numbers (1, 2, 3 etc.) mass of Fe mass of Cl FeCl 2 56 g 70 g FeCl 3 56 g 105 g 105:70 3:2 (fixed) **Subscripts must be whole numbers! H 2 O, H 2 O 2 Dalton s Atomic Theory**: A) Each element is made up of tiny particles called atoms. B) The atoms of a given element are identical; the atoms of different elements are different. C) A compound always has the same ratio and types of atoms. (like Law of Definite Proportions) D) Chemical reactions involve reorganization of the atoms to form new compounds (the atoms themselves are unchanged). (like Law of Conservation of Mass) V. Avogadro s Hypothesis**: At the same temperature and pressure, equal volumes of different gases contain the same number of particles. (22.4 L = 1 mol = 6.022 X 10 23 molecules of the gas)

Atomic Models J.J. Thompson and the Cathode Ray Tube When a high voltage is applied, a cathode ray is produced. The particles he called electrons were (-), since they went toward an applied (+) electrical field and were repelled by an applied (-) electrical field. **Since electrons were produced from electrodes of various metals, he postulated that all atoms must contain (-) electrons. Millikan s Oil Drop Experiment A falling oil drop can be halted by adjusting a voltage across 2 plates. With the voltage and the mass of an e -, he could calculate the charge on a single e -. (The charge on an oil drop is always a whole number multiple of the charge on a single e -, so an e - is not divisible into other particles.)

#11 Notes Atomic Models continued A) Plum Pudding Model (J.J. Thompson)** All atoms contain (-) electrons. Since atoms are neutral, there must also be (+) somewhere. **(-) electrons are randomly scattered in a spherical cloud of (+) charge. B) Rutherford s Gold Foil Experiment Radioactivity was discovered by Becquerel in 1896. (α - particles are helium atoms) When α particles are shot at an Au atom, the center repels the α particles, so there must be a concentration of charge in the center. Rutherford Model** **A (+) nucleus is surrounded by orbiting (-) electrons. C) Modern Model ** **A (+) nucleus (diameter 10-13 cm), containing (+) protons and neutral neutrons is surrounded by an electron cloud (diameter 10-8 cm). {Tennis ball nucleus 4.5 cm, e- cloud out 4.5 km 2.8 mi} **electrons are in layers of many differently shaped orbitals (s, p, d, f)

Electron Orbital Diagrams I. s orbitals (1 type) II. p orbitals (3 types) III. d orbitals (5 types) IV. f orbitals (7 types)

Isotopes** are atoms of the same element, but with different mass. They contain different amounts of neutrons. Mass Charge Electron 9.109 X10-31 kg -1 Proton 1.672 X10-27 kg +1 Neutron 1.675 X10-27 kg neutral 23 Na Top # = mass # Bottom # = atomic # 11 Atomic # = # of protons = # of electrons Mass # = # of protons + # of neutrons **(mass # atomic # = # of neutrons) {To find mass} {To find neutrons} Given: neutrons protons electrons charge Ca = 40 Ca 40-20 =20 20 20 0 235 U 235 92 = 143 92 92 0 Ca 2+ = 40 Ca 2+ 40-20= 20 20 20-2=18 2+ (+) charge = lose electrons F 1- = 19 F 1-19-9 = 10 9 9+1= 10 1- (-) charge = gain electrons VI. Periodic Table** A) Metals: left side of table Conduct heat and electricity Malleable, ductile Lustrous Lose e - to form (+) ions B) Nonmetals: right side of table Gases or brittle solids Poor conductors Gain e - to form (-) ions C) Metalloids (Semi-metals, Semiconductors): Properties of metals and nonmetals B, Si, Ge, As, Sb, Te, Po, At See Periodic Table with Group Names and label groups/families: Alkali Metals, Alkaline Earth Metals, Transition Metals, Halogens, Noble Gases, Lanthanides, Actinides, Metals, Nonmetals, Metalloids.

#12 Notes VII. Bonds Chemical Bonds are the force that holds atoms together. Covalent Bonds: are when electrons are shared. (molecules have covalent bonds) Ionic Bonds: are when electrons are transferred. (ionic solids/ salts have ionic bonds) NaCl Loses 1 e - Gains 1 e - Na + Cl - NaCl Na s e - is transferred to the Cl. Cations (+) Anions (-) Polyatomic Ions: are covalently bonded atoms with a charge NH 4 1+, SO 4 2- VIII. Writing Formulas for Ionic Compounds The ions charges must (be multiplied to) make neutral compounds. Ex. 1) sodium nitrate Na 1+ -1 NO 3 NaNO 3 Ex. 2) magnesium chloride Mg 2+ Cl 1- MgCl 2 X1 X2 +2-2 = 0 Ex. 3) iron III hydroxide Fe 3+ OH -1 Fe(OH) 3 X1 X3 +3-3 = 0 Ex. 4) lithium phosphate Li 1+ 3- PO 4 Li 3 PO 4 X3 X1 +3-3 = 0 Ex. 5) cobalt III sulfite Co 3+ 2- SO 3 Co 2 (SO 3 ) 3 X2 X3 +6-6 = 0 Ex. 6) chromium II phosphate Cr 2+ 3- PO 4 Cr 3 (PO 4 ) 2 X3 X2 +6-6 = 0 Ex. 7) nickel II arsenide Ni 2+ As 3- Ni 3 As 2 X3 X2 +6-6

Notes #13 X. Writing Formulas for Covalent Molecules These compounds contain 2 nonmetals (both (-)), so they will share electrons in different combinations. Prefixes: mono (1), di (2), tri (3), tetra (4), penta (5), hexa (6), hepta (7), octa (8), nano (9), deca (10). **mono only used on 2 nd element Ex. 1) sulfur tetrafluoride S 2- F 1- SF 4 Ex. 2) dinitrogen tetroxide N 3- O 2- N 2 O 4 Ex.3) carbon monoxide C? O 2- CO XI. Naming Ionic Compounds Ex. 1) Sr(OH) 2 strontium hydroxide Ex. 2) Cu(ClO 2 ) 2 copper II chlorite 1- ClO 2 X 2 = -2, so Cu must be +2 Ex. 3) CrBr 3 chromium III bromide Br 1- X 3 = -3, so Cr must be +3 Ex. 4) Fe 2 (SO 4 ) 3 iron III sulfate 2- SO 4 X 3 = -6, so Fe side must be +6, But there are 2 Fe, so each must be +3 Ex. 5) Cr 2 O 3 chromium III oxide O 2- X 3 = -6, so Cr side must be +6, But there are 2 Cr, so each must be +3 Ex. 6) Co 3 (PO 4 ) 2 cobalt II phosphate 3- PO 4 X 2 = -6, so Co side must be +6, But there are 3 Co, so each must be +2 Ex. 7) Ba(NO 3 ) 2 barium nitrate

XII. Naming Covalent Molecules Ex. 1) NO 2 N 3- O 2- prefixes: nitrogen dioxide (mono never used on 1 st element) **Only the 2 nd name gets the -ide. Ex. 2) ICl 3 I 1- Cl 1- iodine trichloride **Think of metalloids as negative. Metalloids (-) with Nonmetals (-) are covalent: SiCl 4 silicon tetrachloride Metalloids (-) with Metals (+) are ionic: Fe 3 As 2 iron II arsenide XIII. Mixed Examples Ex. 1) K 2 Cr 2 O 7 Cr 2 O 2-7 potassium dichromate Ex. 2) PF 5 P 3- F 1- phosphorus pentafluoride Ex. 3) Pb(SO 4 ) 2 lead IV sulfate 2- SO 4 X 2 = -4, so Pb must be +4 Ex. 4) N 2 O N 3- O 2- dinitrogen monoxide Ex.5) BeF 2 beryllium fluoride

#14 Notes Ch. Stoichiometry I. Atomic Mass Atomic mass on the periodic table is the average mass of the naturally occurring isotopes weighted by their natural abundance. (This includes electrons and is not rounded to whole numbers, like the atomic mass # in the last chapter.) Mass Spectrometers show the relative abundance by mass. Ex. 1) Calculate the average atomic mass of Ne. (% as decimal) (mass) + (% as decimal) (mass) + (% as decimal) (mass) = average atomic mass (0.9048) (19.9924 g) + (0.0027) ( 20.9938 g) + (0.0925) ( 21.9914 g) = 18.09 + 0.05668 + 2.034 = 20.18 g ** or 20.18 amu (atomic mass units) This is the mass for one mol of the substance (6.022 X10 23 atoms). II. The Mole (Mol) Molar mass is the mass of 1 mol of a compound. Ex.1) Find the molar mass of MgF 2. 1 mol Mg = 24.305 g 2 mol F = 2 (18.9884g) = 37.9768 g 62.2818 g in one mol of MgF 2 = 62.2818 g/mol MgF 2

Ex. 2) Find the molar mass of Fe 2 (SO 4 ) 3 2 Fe = 2 (55.847 g) 3 S = 3 ( 32.064 g) 12 O = 12 ( 15.999 g) 399.8788 g in 1 mol of Fe 2 (SO 4 ) 3 = 399.8788 g/mol Fe 2 (SO 4 ) 3

#15 Notes II. Conversions with the Mol 1 dozen = 12 1 mol = 6.022 X10 23 107.868 g Ag = 1 mol 1 mol = 6.022 X10 23 atoms Ag (element) (atomic mass) NaCl: 22.9898g Na 35.453 g Cl 58.443 g NaCl = 1 mol 1 mol = 6.022 X10 23 molecules NaCl (compound) (molar mass) A) Grams Mols Ex. 1) Convert 45.3 g C 2 H 6 to mols. 45.3 g C 2 H 6 1 mol = 1.51 mol C 2 H 6 30.069 g 2 C + 6 H B) Mols Grams Ex. 2) Convert 0.459 mols Pb(AsO 4 ) 2 to grams. 0.459 mols Pb(AsO 4 ) 2 485.026 g = 222.6 = 223 g Pb(AsO 4 ) 2 1 mol 1 Pb + 2 As + 8 O C) Grams Atoms/Molecules Ex. 3) Convert 59.32 g Ca 3 (PO 4 ) 2 to molecules. 59.32 g Ca 3 (PO 4 ) 2 1 mol 6.022 X10 23 molecules = 1.152 X10 23 molecules 310.174 g 1 mol Ca 3 (PO 4 ) 2 3 Ca + 2 P + 8 O

D) Atoms/Molecules Grams Ex. 4) Convert 4.59 X10 24 molecules MgCl 2 to grams. 4.59 X10 24 molecules MgCl 2 1 mol 95.211 g = 726 g MgCl 2 6.022 X10 23 molecules 1 mol 1 Mg + 2 Cl **H 2 = 2 H, O 2 = 2 O *End of Notes* (Assignments #16-17 are Review Assignments. There are no notes for these assignments.)