A Geometric of Numerical Solution of Nonlinear Equations and Error by Urabe's Proposition

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Publ. RIMS, Kyoto Univ. Vol. 5 (1969), pp.jl-9 A Geometric of Numerical Solution of Nonlinear Equations and Error by Urabe's Proposition By Yoshitane SHINOHARA* 1. Introduction In his paper [1], Rybashov proposed a method of approximate solution by an analogue computer of a system of nonlinear equations ( ) F(x) = {f k (x 19 x 2, -, * )} = 0 (fe = l, 2, -, «). However his method can be practised easily on a digital computer and by doing so, we can get a more accurate solution of nonlinear equations. In the present note, we shall describe a method to practise Rybashov's method on a digital computer and illustrate our method with a system of transcendental equations which appears in making a map of Japan by a simple conic projection. In numerical solution of nonlinear equations, after finding an approximate solution in any way, it is also important to verify the existence of an exact solution and to know the error bound of the approximate solution obtained. In the present note, we shall show that we can indeed verify the existence of an exact solution and know the error bound of the approximate solution obtained from the approximate solution itself by the use of Urabe's proposition [2]. The author expresses his hearty gratitude to Professor Urabe for his kind guidance and constant advice. Received March 5, 1969. Communicated by M. Urabe. * Technical College of Tokushima University.

2 Yoshitane Shinohara 2. The Method of Computation From equations of the system (E\ we choose n l equations, say, (2.1) f*(x 19 x 2, -,x n ) = 0 (a = 1,2, -,H-1). The condition necessary for a system of equations (2. 1) is only that the rank of the matrix (dfjdxt) (a = 1,2,, n l ; * = 1,2,,«) is equal to w 1. The system of equations (2.1) then determines a curve for which from (2. 1) we have C : x = x(s), (2.2) fj /-.^ = 0 ' = i o# z - as (a = l,2,-,fi-l). Put (2. 3) D, = (-I)*'- i»"...»--i (i = l, 2, -..,»), 0(^1 > ""> ^f-i> -^f+i > ""> ^») then from (2. 2) we have (2.4) d -J ± = * D * (i = l,2, -,»), a5 where X is an arbitrary parameter. Let us choose a parameter 5 so that 5 may be an arc length of the curve C. Then we readily see that X is given by (2.5) X=±[2Z>n- 1/ '. 1=1 Hence from (2. 4), for the curve C, we have a system of differential equations of the form (2.6) ^ = X(x). ds Now we take a point x=x^ on the curve C and suppose jc c0) =jc(0). Then we can compute the curve C integrating numerically equation (2. 6) by a step-by-step method, say, the Runge-Kutta method. Let jc co (/=!, 2, ) be the approximate value of jc(s)

Geometric Method of Numerical Solution of Nonlinear Equations 3 obtained at the /-th step by the numerical integration. Then we may have /«[jc CO) ]-/ M [jc (1) ]^0. Otherwise we continue the numerical integration of (2.6) until we have (2.7) fn[*'- l^-f»[*"] <) Once we have had (2.7) for some /, we check if / w [x c/ ~ ir ] or l/wex^ll is smaller than a specified positive number 8. If this is not satisfied, we multiply the step-size of the numerical integration by 2~ p (p^t) and repeat the numerical integration starting from the value x a ~^. If we repeat this process, then after a finite number of repetitions we shall have (28) /-C* c - l5 ]-/-C* c/5 ]^O f ( lac*"- 1 ']! or /,[^ provided on the curve C there is a simple solution of (E), that is, a solution of (E) for which the Jacobian of F(x) with respect to x does not vanish. The value JC C/ ~ ID or jc cn satisfying (2.8) gives an approximate solution of the given system of equations (E). Starting from JC C/ ~ ID or x a \ we then can compute a solution of (E) by, say, Newton's method. However, if is very small, jc c/ ~ 1} or x c/) itself will give an accurate approximate solution of (E). Remark 1. In the course of the numerical integration of (2.6), it may happen that (2.9) I/J> CI >] I ^fiat some /-th step for some positive integer a^n I, where f is a prescribed positive number. When (2.9) happens, one however can correct jc c/) so that the corrected value i c/) may satisfy inequalities for all or = 1,2,,»!. To do so, it suffices to apply Newton's method to (2.1) starting from jc=jc c/) leaving one of xf n 's (/ =!, 2,, ri) fixed. Remark 2. To find a point x=x^ on the curve C, it suffices

4 Yoshitane Shinohara to find a solution of the system (2.1) consisting of n l equations after asigning a suitable value to some one of jtr/s (* = 1, 2,,«) Our method is clearly applicable to systems consisting of n l equations. Repeating such a process, the problem thus is reduced to finding a solution of a single equation. Remark 3. If we continue the numerical integration of (2.6) through the approximate solution obtained or begin the numerical integration of (2.6) in the reverse direction, then we shall have (2.8) again provided there is another simple solution of (E} on the curve C. Continuing our process, we thus can get numerically all finite simple solutions of (E) lying on the curve C. Urabe's proposition [2]. Let 3 e Urabe's Proposition (3.1) F(x) = 0 be a given real system of equations and suppose that F(x) is continuously differentiate with respect to x in a region 1 of the x-space. Assume that equation (3.1) possesses an approximate solution x=x such that the Jacobian matrix J(x) of F(x] with respect to x is nonsingular for x=x and there are a positive constant and a nonnegative number «;<! satisfying the following conditions for any norm of vectors and matrices: (3.2) (ii)!!/(*)-/(*)! ^ for any M (iii) where r and M(^0) are numbers such that (3.3) \\F(x)\\^r and \\J~\x)\\ ^ Equation (3.1) then possesses one and only one solution x=x fl and we have in

Geometric Method of Numerical Solution of Nonlinear Equations (3.4),,* -,, ^ Mr For the proof, see [2], pp. 124-125. The proposition gives conditions under which the existence of an approximate solution implies the existence of an exact solution, and the error estimate of an approximate solution can be got from itself without knowing an exact solution. Hence by verifying the conditions of the above proposition for an approximate solution obtained by computation, we can know the existence of an exact solution and at the same time get the error bound of the approximate solution obtained by computation. 4. An Example In order to make a map of Japan by a simple conic projection, it is necessary to find a function y(x) which satisfies the first order differential equation (4.1) and the boundary condition ax sin x (4.2) /(«) =/( ) sin 6 for an appropriate positive constant 17. In (4.2), 0 is a solution of the equation (4. 3) y"(0) = 0, and a = 44, (3 = 66. As readily seen, the general solution of (4.1) can be given by (4. 4) y= y n (x} = 2 tan-"(*/2) [ where x± may be supposed without loss of generality to be equal to 55 -(44 -t-66 )/2. From the boundary condition /(a) =/( ), it

6 Yoshitane Shinohara readily follows that (4. 5) C, = [sin a tan^a/2) f tan*(x/2)dx -sin/3.tan"(/3/2).r tan^/2)^]) [sin/3-tan%(3/2) - sin a-tan^/2)]. Now, differentiating equation (4.1) with respect to x, we see that equation (4.3) is equivalent to the equation (4.6) From the boundary condition y'(/3')=->]'y(d')/sind, we further have (4.7) 2-^L-.y v (f)) = -?-y,(0). sm /3 sin 0 Thus we see that for solving the initial problem, it suffices to solve numerically the system of equations (4.8) for the function y^x) given by (4.4) and (4.5). We shall now apply our method to the above system of equations. According to (2.4)~(2.5), for the curve C determined by ) = 0, we have (49)? = _ B } ^ ' ds VF* + FI' ds and solving the equation F(0, 0) = 0 numerically, we get (4. 10) rj = 0, 9 = 0.95114 50249, which can be assumed to be an initial value for the solution of (4.9) corresponding to s = 0. We specify the values of 8 and f so that (4. 11) 6-10- 9, f = 10-8.

Geometric Method of Numerical Solution of Nonlinear Equations 7 In the numerical integration of (4.9), we start with step-size 2~ 5 and multiply the step-size by 2~ 3 when the second inequality of (2.8) is detected to be unfulfilled. On the computer TOSBAC 3400, we have got ; (4.12)? C54D = 0.57355 02977, 0 C54) = 0.94679 70998 ; 7? C53 > = 0.57355 02976, 9^ = 0.94679 70998 ; 0 /3C53)\ /~V,V,('54') /3C 5 4)\ ^x C\, C7 )*^J\J], t/ ) ^ U, o, ^CM)) = _0.43655 74569xlO- 10, 543, 6> C54) ) = 0.43655 74569 x 10-10. For the purpose of making a map, it is unnecessary to find all solutions, but it suffices to get any one of the solutions. Hence we have stopped the computation after having found the above (i? c54}, 0 C54) ). In order to get an error bound for the approximate solution (4. 14) x = {^, 3} = to^ we apply Urabe's proposition to the equation (4.8) using the Euclidean norms. Put (4.15) x = to, 0}, F(x) = {F(ri, 0), G(n, 0)}, then from (4.13) readily follows (4.16)!F(±) <0.437x v / 2 xlo- 10 <r = 0.437x 1.415xlO' 10. Put then for jc=jfc, we have /(*) = rf,(i7,0) _G,(?, 0) /(je) = T - 0.74233 20101X10' 2-0.98257 30255 X10 L 0.24747 58356x10 0.18917 48980x10- J-\x) = T 0.77797 54129xlO- 10 0.40407 98559x10 L - 0.10177 36060 x 10-0.30528 15454 x 10~ 2 J, and hence

8 Yoshitane Shinohara Then, com- (4.17) 1 /-'(*) <M =1.096. Let 1 be the region such that (4.18) n={x = (i7, 0): where 71=0.01745 32925 (0.01745 32925 radian = 1 ). puting the values of /(x) J(x)\\ for grid points we see that (i = 0, ±1, -, ±8; j=q, ±1, -., ±80, -81, -82, -, -88), (4.19) /(x)-/(x) <: 0.890 for any xeo. Put (4. 20) S = 0.0174, then evidently (4.21) n s c n, and we have (4.19) for any xen So Hence by (4.16), (4.17), (4.19) and (4.20), we see that the conditions (ii) and (iii) of (3.2) in Urabe's proposition are fulfilled if there is a positive number «<1 satisfying the following inequalities: (4. 22) 0.890 ^ 1.096 x 0.437 x 1.415 xlq- 10 < Q om These inequalities are equivalent to the inequalities that is, 0.890 X 1.096 rg * 1 - L096 X ' 437 X L415 x 10", (4. 23) 0.97544 g «^ 0.99999 999610 Hence, indeed, there is a positive number *;<! satisfying (4.22). This proves that all the conditions of Urabe's proposition are ful-

Geometric Method of Numerical Solution of Nonlinear Equations 9 filled by the approximate solution x=x. Thus we see that equation (4.8) possesses one and only one exact solution x=x in 1$ and that (4.24) i jfc_- ^ where K is an arbitrary number satisfying (4.23). From (4.23) and (4.24), we then see that (4.25) ^-x ^ which gives an error bound for the approximate solution x=x = {^\0^} given by (4.12). For the function $(x)=y$(x) y we have and jk(<*) = 0.99072 83110, /(/?) = 0.99072 83110, n0 = 0.99072 83109. These show that y=$(x) satisfies the given boundary conditions accurately. Remark. In the above computation, we have used the following formulas : tan (x/2)-dx ' + V l o g t, } where ^.-tan(^./2) (f = l,2). References [ 1 ] PuSamoB, M. B., 06 O.HHOM wieto^e pemehna Mo6aju,Hof sajia^n OTBiCKanna Eopsefi KOHG^HHX ypabnehhh npn nomonp sjrektpohhoft MOflean, ABTOMaT. n Tejreaiex. 23 (1962), 1396-1398. C 2 ] Urabe, M., Galerkin's procedure for nonlinear periodic systems, Arch. Rational Mech. Anal. 20 (1965), 120-152.