PHYA2. General Certificate of Education Advanced Subsidiary Examination January Mechanics, Materials and Waves. (JAN13PHYA201) WMP/Jan13/PHYA2

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Centre Number Surname Candidate Number For Examiner s Use Other Names Candidate Signature Examiner s Initials Physics A Unit 2 For this paper you must have: a pencil and a ruler a calculator a Data and Formulae Booklet (enclosed). General Certificate of Education Advanced Subsidiary Examination January 2013 Mechanics, Materials and Waves Friday 18 January 2013 9.00 am to 10.15 am PHYA2 Question 1 2 3 4 5 6 7 TOTAL Mark Time allowed 1 hour 15 minutes. Instructions Use black ink or black ball-point pen. Fill in the es at the top of this page. Answer all questions. You must answer the questions in the spaces provided. around each page or on a blank page. Do all rough work in this book. Cross through any work you do not want to be marked. Show all your working. Information The marks for questions are shown in brackets. The maximum mark for this paper is 70. You are expected to use a calculator where appropriate. A Data and Formulae Booklet is provided as a loose insert. You will be marked on your ability to: use good English organise information clearly use specialist vocabulary where appropriate. (JAN13PHYA201) PHYA2

2 Answer all questions in the spaces provided. 1 The world record for a high dive into deep water is 54 m. 1 (a) Calculate the loss in gravitational potential energy (gpe) of a diver of mass 65 kg falling through 54 m. loss in gpe =... J 1 (b) Calculate the vertical velocity of the diver the instant before he enters the water. Ignore the effects of air resistance. velocity =... m s 1 1 (c) Calculate the time taken for the diver to fall 54 m. Ignore the effects of air resistance. time =... s (02)

3 1 (d) Explain, with reference to energy, why the velocity of the diver is independent of his mass if air resistance is insignificant. 9 Turn over for the next question Turn over (03)

4 2 A snowboarder slides down a slope, as shown in Figure 1. Between B and C her acceleration is uniform. Figure 1 snowboarder A 25 B 1.5 m W C D 2.0 m 25 E 2 (a) The snowboarder travels 1.5 m from B to C in a time of 0.43 s and her velocity down the slope at C is 5.0 m s 1. Calculate her velocity down the slope at B. velocity =... m s 1 2 (b) The combined mass of the snowboarder and snowboard is 75 kg and the angle of the slope is 25 o. 2 (b) (i) Calculate the component of the weight of the snowboarder and snowboard acting down the slope. weight component =... N (04)

5 2 (b) (ii) At D the snowboarder has reached a constant velocity. She moves a distance of 2.0 m at constant velocity between D and E. Calculate the work done against resistive forces as she moves from D to E. work done =... J (1 mark) 2 (c) State and explain what happens to the gravitational potential energy lost between D and E...... 9 Turn over for the next question Turn over (05)

6 3 (a) State the principle of moments. 3 (b) Figure 2 shows a bicycle brake lever that has been pulled with a 35 N force to apply the brake. Figure 2 tension brake cable 110 mm force applied by cyclist 25 mm pivot brake lever 35 N handle bar 3 (b) (i) Calculate the moment of the force applied by the cyclist about the pivot. State an appropriate unit. moment =... unit... (06)

7 3 (b) (ii) Calculate the tension in the brake cable. Assume the weight of the lever is negligible. tension =... N 3 (c) In order to maintain a constant velocity of 15 m s 1 downhill, the cyclist applies the brake. The power developed by the braking force is 2.8 kw. Calculate the total average frictional force between the brake blocks and the wheel rim. frictional force =... N 11 Turn over for the next question Turn over (07)

8 4 Figure 3 shows a tower crane that has two identical steel cables. The length of each steel cable is 35 m from the jib to the hook. tower crane Figure 3 jib 35 m steel cables hook load 4 (a) Each cable has a mass of 4.8 kg per metre. Calculate the weight of a 35 m length of one cable. weight =... N 4 (b) The cables would break if the crane attempted to lift a load of 1.5 10 6 N or more. Calculate the breaking stress of one cable. cross-sectional area of each cable = 6.2 10 4 m 2 breaking stress =... Pa (08)

9 4 (c) When the crane supports a load each cable experiences a stress of 400 MPa. Each cable obeys Hooke s law. Ignore the weight of the cables. Young modulus of steel = 2.1 10 11 Pa 4 (c) (i) Calculate the weight of the load. 4 (c) (ii) The unstretched length of each cable is 35 m. Calculate the extension of each cable when supporting the load. weight =... N extension =... m 4 (c) (iii) Calculate the combined stiffness constant, k, for the two cables. stiffness constant =... N m 1 4 (c) (iv) Calculate the total energy stored in both stretched cables. energy stored =... J 13 Turn over (09)

10 5 Figure 4 shows a section of a typical glass step-index optical fibre used for communications. Figure 4 light ray 14.1 normal line air cladding core cladding 9.54 normal line X 5 (a) Show that the refractive index of the core is 1.47. 5 (b) The refracted ray meets the core-cladding boundary at an angle exactly equal to the critical angle. (1 mark) 5 (b) (i) Complete Figure 4 to show what happens to the ray after it strikes the boundary at X. 5 (b) (ii) Calculate the critical angle. critical angle =...degrees (1 mark) (10)

11 5 (b) (iii) Calculate the refractive index of the cladding. refractive index =... 5 (c) Give two reasons why optical fibres used for communications have a cladding. reason 1... reason 2... 8 Turn over for the next question Turn over (11)

12 6 Discuss the formation of stationary waves on a string or rope. Your account should include: a labelled diagram of a stationary wave the conditions necessary for stationary waves to form a definition of the terms node and antinode an explanation of how nodes and antinodes form. The quality of written communication will be assessed in your answer................ (6 marks) 6 (12)

13 7 Figure 5 shows the paths of microwaves from two narrow slits, acting as coherent sources, through a vacuum to a detector. position of central maximum Figure 5 detector perpendicular distance between slits and detector slits 7 (a) Explain what is meant by coherent sources. 7 (b) (i) The frequency of the microwaves is 9.4 GHz. Calculate the wavelength of the waves. wavelength =... m Turn over (13)

14 7 (b) (ii) Using Figure 5 and your answer to part (b)(i), calculate the path difference between the two waves arriving at the detector. path difference =... m (1 mark) 7 (c) State and explain whether a maximum or minimum is detected at the position shown in Figure 5. 7 (d) The experiment is now rearranged so that the perpendicular distance from the slits to the detector is 0.42 m. The interference fringe spacing changes to 0.11 m. Calculate the slit separation. Give your answer to an appropriate number of significant figures. slit separation =... m 7 (e) With the detector at the position of a maximum, the frequency of the microwaves is now doubled. State and explain what would now be detected by the detector in the same position. END OF QUESTIONS 14 (14)

15 There are no questions printed on this page DO NOT WRITE ON THIS PAGE ANSWER IN THE SPACES PROVIDED (15)

16 There are no questions printed on this page DO NOT WRITE ON THIS PAGE ANSWER IN THE SPACES PROVIDED Copyright 2013 AQA and its licensors. All rights reserved. (16)