Quivers supporting graded twisted Calabi-Yau algebras Jason Gaddis Miami Unversity Joint with Dan Rogalski J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
Calabi-Yau algebras Let A be an algebra over an algebraically closed, characteristic zero field k. Let A e = A k A op be the enveloping algebra of A. The algebra A is said to be twisted Calabi-Yau (CY of (global dimension d if A has a finite resolution by finitely-generated projectives in A e -MOD (homologically smooth and Ext i A e(a, Ae = { 0 i d A µ A where µ A is the Nakayama automorphism of A. A is Calabi-Yau if µ A = id A. i = d J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
CY algebras in nature A connected (N-graded algebra is twisted CY if and only if it is Artin-Schelter regular [Reyes-Rogalski-Zhang]. Ore extensions of twisted CY algebras are twisted CY [Liu-Wang-Wu]. Normal extensions of CY algebras are CY [Chirvasitu-Kanda-Smith]. J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
CY algebras in nature Skew group algebras A#G where A = k[x 1,..., x n ] and G SL n (A finite are CY [Iyama-Reiten]. Additional results for A p-koszul CY [Wu-Zhu] and/or H an involutory CY Hopf [Liu-Wu-Zhu]. Mutations (in the sense of Fomin-Zelevinsky of CY algebras are CY [Vitoria, Zeng]. Others: dimer models, NCCRs,... J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
Vacualgebras Let Q = (Q 0, Q 1 be a finite quiver and kq its path algebra. For a path p kq, denote by s(p the source of p and by t(p the target of p. Given an automorphism σ of Q 0, we say ω = c k p k kq is a σ-twisted superpotential if ω is closed under cyclic permutation and s(p k = σ(t(p k for all k with c k 0. When σ = id Q0, ω is said to be a superpotential. For each a Q 1 we define the derivation operator δ a on paths p via the rule δ a p = a 1 p where a 1 p = 0 if s(p a. J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
Vacualgebras An algebra of the form kq/( a ω : a Q 1 where ω is a (twisted superpotential is said to be a vacualgebra. Theorem (Bocklandt, Reyes-Rogalski If A is graded twisted CY of global dimension 3, then A is a vacualgebra on a strongly connected quiver with homogeneous superpotential. Question Which quivers support such algebras? J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
CY algebras of finite growth Let A = kq/( a ω : a Q 1 be graded twisted CY of global dimension 3 with Q 0 = n and deg(ω = s. The adjacency matrix of a quiver Q is (M Q ij = # of arrows from vertex i to j. The matrix polynomial of Q is defined to be p Q (t = I n M Q t + M T Q Pt s 1 Pt s where P is the permutation matrix (of the vertices determined by the Nakayama automorphism µ A. The matrix-valued Hilbert-series of A is H A (t = 1/p Q (t. J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
CY algebras of finite growth Theorem (Reyes-Rogalski Suppose A = kq/( a ω : a Q 1 is graded twisted CY of global dimension 3 and finite GK dimension. Let P be the permutation matrix corresponding to the Nakayama automorphism µ A. Every coefficient matrix in H A (t is nonnegative. Every root of p Q (t is a root of unity. M Q and P commute. If P = I and M Q is normal, then either deg(ω = 3 and ρ(m Q = 3 or deg(ω = 4 and ρ(m Q = 2. Moreover, GKdim(A = the multiplicity of 1 as a root of p Q (t. J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
Questions Question Which quivers have adjacency matrices with a good Hilbert series? Question Of the quivers in the last question, which quivers have superpotentials that produce CY algebras of global dimension 3 and finite GK dimension? J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
2-vertex quivers (P = I Suppose A = kq/( a ω : Q 0 = 2, a Q 1 is graded twisted CY of global dimension 3 and finite GK dimension. Define θ(m Q := d dt det (p Q(t. t=1 ( a b Then θ(m Q = 0 when GKdim(A <. Write M Q =. Since c d θ(m Q = (b c 2, then b = c and so M Q is symmetric. If deg(ω = 3, then M Q = If deg(ω = 4, then M Q = ( 1 2 or 2 1 ( 1 1 or 1 1 ( 2 1. 1 2 ( 0 2. 2 0 J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
Bad example Let Q be the quiver. 5 4 2 The Hilbert series corresponding to Q suggests polynomial growth for a degree 3 superpotential. However, a Gröbner basis argument shows that Q has no such superpotential. J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
3-vertex quivers Proposition (G-Rogalski Let A = kq/( a ω : a Q 1 where A is graded twisted Calabi-Yau of global dimension 3 and finite GK dimension with deg(ω = 3 or 4. The number of loops at each vertex of Q does not exceed 6 deg(ω. To prove this, we use the Golod-Shafarevich inequality: If B is a quadratic algebra with n generators and d relations, then H B (t (1 nt + dt 2 1. J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
3-vertex quivers (P = I Suppose A = kq/( a ω : Q 0 = 3, a Q 1, deg(ω = 3 is graded twisted CY of global dimension 3 and finite GK dimension. The matrix polynomial of Q, p Q (t = I 3 M Q t + M T Q t 2 I 3 t 3, is antipalindromic. Hence, roots appear in inverse pairs. By the hypothesis on GK dimension, 1 is a root of p Q (t of multiplicity at least 3. Hence, det(p Q (t = (1 t 3 r(t where 3 r(t = (1 k i t + t 2, k i R, k i 2. i=1 J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
3-vertex quivers (P = I Write M Q = [m ij ] i,j=0...3 and set λ = m ii, β = m ii m jj, γ = m ij m ji. i>j i>j Setting det(p Q (t = (1 t 3 r(t we find, λ = k 1 + k 2 + k 3 + 3, γ = β (k 1 k 2 + k 1 k 3 + k 2 k 3 2λ + 3. For every choice of m ii, we can find the maximum possible value m of γ. Then solve for the k i for every choice of γ, 0 γ m. J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
3-vertex quivers (P = I - Example Suppose Q has three loops at each of at least two vertices. This determines β and λ. The maximum value of γ is 0. Thus, 3 a 0 M Q = 0 3 b, α 3. c 0 α Then θ(m Q = 0 implies a = 0 or a(α 3 + 3bc = 0. Hence α < 3. We can now check that the Hilbert series has negative entries unless α = 0, a = b = c = 1. This matrix can be checked directly to find that it has roots not lying on the unit circle. J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
3-vertex quivers (P = I - Example Suppose Q has no loops. Then the maximum value of γ is 3. One can show as before that no good matrices exist when γ > 0. Write, 0 a 0 M Q = 0 0 b. c 0 0 The Hilbert series corresponding to Q is good if and only if (a, b, c = (3x, 3y, 3z where (x, y, z is a solution to Markov s equation: x 2 + y 2 + z 2 = 3xyz. Question Do all such quivers have good superpotentials? YES! J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
Mutations Let Q be a quiver without loops or oriented 2-cycles and fix a vertex v. Steps: 1 For every pair of arrows a, b Q 1 with t(a = v and s(b = v, create a new arrow [ba] : s(a t(b. 2 Reverse each arrow with source or target at v. 3 Remove any maximal disjoint collection of oriented 2-cycles. The resulting quiver Q, is called a mutation of Q. There is also a method to mutate the corresponding superpotential. By a result of Vitoria, two vacualgebras related by mutation are derived equivalent. Thus, if one is the CY, so is the other by a recent result of Zeng. J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
Mutations Theorem (G-Rogalski The triple (3x, 3y, 3z is a solution to Markov s equation if and only if the corresponding quiver can be obtained from the quiver with adjacency matrix 0 3 0 0 0 3 3 0 0 by successive mutations. These mutations provide the only examples of non-normal matrices whose quivers support a good superpotential (in the 3-vertex case. J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
3-vertex quivers (P = I Theorem (G-Rogalski Let A = kq/( a ω : a Q 1, Q 0 = 3 be graded twisted CY of global and GK dimension 3 with deg(ω = 3 or 4. If P = I, then M Q is one the matrices below. deg(ω = 3 : deg(ω = 4 : ( 2 1 1 1 0 1, 1 1 0 ( 1 1 0 0 1 1, 1 0 1 ( 2 1 1 1 1 0, 1 0 1 ( 1 1 1 1 0 0, 1 0 0 ( 1 1 1 1 1 1, 1 1 1 ( 0 1 1 1 0 1, 1 1 0 ( 1 1 1 1 2 0, 1 0 2 ( 1 0 1 0 1 1. 1 1 0 ( 0 a 0 0 0 b c 0 0 The indeterminates a, b, c are positive integers satisfying the equation a 2 + b 2 + c 2 = abc., J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
3-vertex quivers (P = I All quivers in the above theorem except for ( 1 1 1 1 2 0 1 0 2 and ( 1 0 1 0 1 1 1 1 0 are McKay quivers for some group action on an AS regular algebra in 6 deg(ω variables. Question Are there (twisted CY algebras on the other quivers? J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
3-vertex quivers (P = I - Remaining Quivers Let Q be the quiver with adjacency matrix M Q = ( 1 1 1 1 2 0. 1 0 2 Let Q be the quiver with adjacency matrix M Q I. Then Q supports a twisted CY algebra B of global and GK dimension 2 [Reyes-Rogalski]. It follows that A = B[t] is a twisted graded CY algebra supported on Q with global and GK dimension 3, and deg(ω = 3. J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
3-vertex quivers (P = I - Remaining Quivers Let Q be the quiver below. x 2 x 1 1 3 2 x 3 Set A = kq/( a ω : a Q 1 with x 5 ω = 1 2 x 4 1 + x 2 1 x 2 x 5 + x 2 x 5 x 2 x 5 + x 2 x 6 x 4 x 5 + x 4 x 6 x 4 x 6 + x 2 3 x 4 x 6 + 1 2 x 4 3. Then Ω = x1 2 + x 2x 5 + x 5 x 2 + x 4 x 6 + x 6 x 4 + x3 2 + is a normal element in A and B = A/(Ω is a twisted CY algebra of global and GK dimension 2 [Reyes-Rogalski]. Thus, A is a graded twisted CY algebra supported on Q with global and GK dimension 3, and deg(ω = 4. x 4 x 6 J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
2-vertex quivers (P I Proposition (G-Rogalski Let A = kq/( a ω : a Q 1, Q 0 = 2 be graded twisted CY of global and GK dimension 3 with deg(ω = 3 or 4. If P = ( 0 1 1 0 is the matrix corresponding to the Nakayama automorphism of A, then M Q is one of the following: deg(ω = 3 : ( 1 2 2 1, ( 2 1 1 2, ( 0 3 3 0, deg(ω = 4 : ( 1 1 1 1. J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
3-vertex quivers (P I Proposition (G-Rogalski Let A = kq/( a ω : a Q 1, Q 0 = 3 be graded twisted CY of global dimension 3 and finite GK dimension with deg(ω = 3 or 4. If P = ( 0 1 0 0 0 1 1 0 0 is the matrix corresponding to the Nakayama automorphism of A, then M Q is one of the following: deg(ω = 3 : deg(ω = 4 : ( 2 1 0 0 2 1, 1 0 2 ( 0 1 1 1 0 1, 1 1 0 ( 1 0 2 2 1 0, 0 2 1 ( 1 1 0 0 1 1, 1 0 1 ( 0 2 1 1 0 2, 2 1 0 ( 1 0 1 1 1 0, 0 1 1 ( 1 1 1 1 1 1, 1 1 1 ( 0 2 0 0 0 2. 2 0 0 J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
3-vertex quivers (P I Proposition (G-Rogalski Let A = kq/( a ω : a Q 1, Q 0 = 3 be graded twisted CY of global dimension 3 and finite GK dimension with deg(ω = 3 or 4. If P = ( 1 0 0 0 0 1 0 1 0 is the matrix corresponding to the Nakayama automorphism of A, then M Q is one of the following: deg(ω = 3 : deg(ω = 4 : ( 2 1 1 1 1 0, 1 0 1 ( 1 1 1 1 0 0, 1 0 0 ( 2 1 1 1 0 1, 1 1 0 ( 0 1 1 1 1 0, 1 0 1 ( 1 1 1 1 1 1, 1 1 1 ( 0 1 1 1 0 1. 1 1 0 J. Gaddis (Miami Twisted graded CY algebras January 12, 2018
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