MAT137 Calculus! Lecture 45

Similar documents
MAT137 Calculus! Lecture 48

Taylor and Maclaurin Series. Approximating functions using Polynomials.

AP Calculus Testbank (Chapter 9) (Mr. Surowski)

Taylor and Maclaurin Series. Approximating functions using Polynomials.

e x = 1 + x + x2 2! + x3 If the function f(x) can be written as a power series on an interval I, then the power series is of the form

Taylor and Maclaurin Series

Section 8.7. Taylor and MacLaurin Series. (1) Definitions, (2) Common Maclaurin Series, (3) Taylor Polynomials, (4) Applications.

MAT137 Calculus! Lecture 19

8.7 Taylor s Inequality Math 2300 Section 005 Calculus II. f(x) = ln(1 + x) f(0) = 0

AP Calculus (BC) Chapter 9 Test No Calculator Section Name: Date: Period:

Module 5 : Linear and Quadratic Approximations, Error Estimates, Taylor's Theorem, Newton and Picard Methods

Section Example Determine the Maclaurin series of f (x) = e x and its the interval of convergence.

Taylor and Maclaurin Series. Copyright Cengage Learning. All rights reserved.

Section Taylor and Maclaurin Series

Review of Power Series

MATLAB Laboratory 10/14/10 Lecture. Taylor Polynomials

July 21 Math 2254 sec 001 Summer 2015

Taylor Series. Math114. March 1, Department of Mathematics, University of Kentucky. Math114 Lecture 18 1/ 13

INFINITE SEQUENCES AND SERIES

CHALLENGE! (0) = 5. Construct a polynomial with the following behavior at x = 0:

Lecture 32: Taylor Series and McLaurin series We saw last day that some functions are equal to a power series on part of their domain.

MAT137 Calculus! Lecture 5

MAT137 Calculus! Lecture 20

Math Numerical Analysis

10.1 Sequences. Example: A sequence is a function f(n) whose domain is a subset of the integers. Notation: *Note: n = 0 vs. n = 1.

MAT137 Calculus! Lecture 6

Math 651 Introduction to Numerical Analysis I Fall SOLUTIONS: Homework Set 1

8.5 Taylor Polynomials and Taylor Series

Math 1B, lecture 15: Taylor Series

CALCULUS: Math 21C, Fall 2010 Final Exam: Solutions. 1. [25 pts] Do the following series converge or diverge? State clearly which test you use.

Completion Date: Monday February 11, 2008

Fundamental Theorem of Calculus

Analysis II: Basic knowledge of real analysis: Part V, Power Series, Differentiation, and Taylor Series

Chapter 3 Differentiation Rules

Multiple Choice Review Problems

AP Calculus BC. Free-Response Questions

(c) Find the equation of the degree 3 polynomial that has the same y-value, slope, curvature, and third derivative as ln(x + 1) at x = 0.

Math 113 (Calculus 2) Exam 4

Math 1310 Section 4.1: Polynomial Functions and Their Graphs. A polynomial function is a function of the form ...

Higher Portfolio Quadratics and Polynomials

Ma 530 Power Series II

MATH 1231 MATHEMATICS 1B CALCULUS. Section 5: - Power Series and Taylor Series.

MATH 1231 MATHEMATICS 1B Calculus Section 4.4: Taylor & Power series.

Properties of a Taylor Polynomial

MTH4101 CALCULUS II REVISION NOTES. 1. COMPLEX NUMBERS (Thomas Appendix 7 + lecture notes) ax 2 + bx + c = 0. x = b ± b 2 4ac 2a. i = 1.

AP Calculus BC Scope & Sequence

NUMERICAL METHODS. x n+1 = 2x n x 2 n. In particular: which of them gives faster convergence, and why? [Work to four decimal places.

Chapter 12: Differentiation. SSMth2: Basic Calculus Science and Technology, Engineering and Mathematics (STEM) Strands Mr. Migo M.

Lecture 34: Recall Defn: The n-th Taylor polynomial for a function f at a is: n f j (a) j! + f n (a)

AP Calculus Chapter 9: Infinite Series

Chapter 8: Taylor s theorem and L Hospital s rule

Today s Agenda. Upcoming Homework Section 2.1: Derivatives and Rates of Change

11.11 Applications of Taylor Polynomials. Copyright Cengage Learning. All rights reserved.

MTAEA Differentiation

Chapter 11. Taylor Series. Josef Leydold Mathematical Methods WS 2018/19 11 Taylor Series 1 / 27

1 Question related to polynomials

Let s Get Series(ous)

Aim: How do we prepare for AP Problems on limits, continuity and differentiability? f (x)

Power series and Taylor series

Section 5.8. Taylor Series

Section 9.7 and 9.10: Taylor Polynomials and Approximations/Taylor and Maclaurin Series

Exam 2. Average: 85.6 Median: 87.0 Maximum: Minimum: 55.0 Standard Deviation: Numerical Methods Fall 2011 Lecture 20

Section 4.2: The Mean Value Theorem

TAYLOR AND MACLAURIN SERIES

APPM 1360 Final Exam Spring 2016

Math 115 HW #5 Solutions

Power Series. x n. Using the ratio test. n n + 1. x n+1 n 3. = lim x. lim n + 1. = 1 < x < 1. Then r = 1 and I = ( 1, 1) ( 1) n 1 x n.

Taylor Series and Maclaurin Series

Math 0230 Calculus 2 Lectures

MAT137 Calculus! Lecture 9

The degree of the polynomial function is n. We call the term the leading term, and is called the leading coefficient. 0 =

AP Calculus AB. Free-Response Questions

AP Calculus BC 2013 Scoring Guidelines

AP Calculus BC. Free-Response Questions

Math 113 Final Exam Practice

Math 473: Practice Problems for Test 1, Fall 2011, SOLUTIONS

LIMITS AT INFINITY MR. VELAZQUEZ AP CALCULUS

BC Exam 1 - Part I 28 questions No Calculator Allowed - Solutions C = 2. Which of the following must be true?

MA4001 Engineering Mathematics 1 Lecture 15 Mean Value Theorem Increasing and Decreasing Functions Higher Order Derivatives Implicit Differentiation

MA 137 Calculus 1 with Life Science Applications Linear Approximations (Section 4.8)

PRACTICE PROBLEMS FOR MIDTERM I

Lesson 31 - Average and Instantaneous Rates of Change

Jim Lambers MAT 460 Fall Semester Lecture 2 Notes

MATHEMATICS AP Calculus (BC) Standard: Number, Number Sense and Operations

MATH 1372, SECTION 33, MIDTERM 3 REVIEW ANSWERS

Semester University of Sheffield. School of Mathematics and Statistics

Chapter 4: More Applications of Differentiation

AP Calculus BC 2015 Free-Response Questions

TEST CODE: MIII (Objective type) 2010 SYLLABUS

Exam 1. (2x + 1) 2 9. lim. (rearranging) (x 1 implies x 1, thus x 1 0

Student Study Session. Theorems

Section 4.3 Concavity and Curve Sketching 1.5 Lectures. Dr. Abdulla Eid. College of Science. MATHS 101: Calculus I

Families of Functions, Taylor Polynomials, l Hopital s

X. Numerical Methods

Infinite Series. Copyright Cengage Learning. All rights reserved.

f (r) (a) r! (x a) r, r=0

Math 107H Fall 2008 Course Log and Cumulative Homework List

Downloaded from

MATH 163 HOMEWORK Week 13, due Monday April 26 TOPICS. c n (x a) n then c n = f(n) (a) n!

SYSTEMS OF NONLINEAR EQUATIONS

Transcription:

official website http://uoft.me/mat137 MAT137 Calculus! Lecture 45 Today: Taylor Polynomials Taylor Series Next: Taylor Series

Power Series Definition (Power Series) A power series is a series of the form n=0 a n x n = a 0 + a 1 x + a 2 x 2 + a 3 x 3 + (1) where x is a variable and the a n s are constants called the coefficients of the series. More generally, a series of the form n=0 a n (x x 0 ) n = a 0 + a 1 (x x 0 ) + a 2 (x x 0 ) 2 + a 3 (x x 0 ) 3 + (2) is called a power series in (x x 0 ) or power series centred at x 0. Remark In equation (2), we adopt the convention (x x 0 ) 0 = 1 even when x = x 0.

Representations of Function as Power Series Example 1 Prove that is the series a n x n and b n x n both converge to the same n=1 n=1 sum for every value of x, then a n = b n for every n.

Representations of Function as Power Series Example 2 If f is a function that admits a power series representation, and it s such that f (0) = 1 and f (x) = f (x) for all x R. Find the power series representation for f.

Linear Approximation We know that if f is differentiable at x 0 the tangent line to the graph at (x 0, f (x 0 )) y = f (x 0 ) + f (x 0 )(x x 0 ) is the best linear approximation to the graph close to the point of tangency. 1 f (x) P1(x) 0.5 1 1 The are two properties that make the tangent line a good approximation close to the point of tangency: P 1 (x 0 ) = f (x 0 ) P 1 (x 0) = f (x 0 )

What is a good approximation? Definition A function g is an approximation of order n for a function f, as x x 0, when f (x) g(x) lim x x 0 (x x 0 ) n = 0 This means that the error of this approximation approaches 0 faster than (x x 0 ) n as x x 0.

Approximating Functions Theorem Assume that the functions f and g have all their derivatives. The following two statements are equivalent: 1 g is an approximation of order n for f as x x 0. In other words: f (x) g(x) lim x x 0 (x x 0 ) n = 0 2 g (x 0 ) = f (x 0 ) g (x 0 ) = f (x 0 ) g (x 0 ) = f (x 0 ) g (n) (x 0 ) = f (n) (x 0 )

Taylor Polynomials For a fucntion f with an n th order derivative at the point x 0, we may approximate f with a polynomial. Definition Let f be a function. Let x 0 R. Let n N. The n th Taylor polynomial for f at x 0 is the polynomial of smallest possible degree that is an approximation of order n for f as x x 0. Equivalently, it is the polynomial P of smallest possible degree that satisfies f (k) (a) = P (k) (a) 0 k n The Taylor series for f at x 0 is the power series S centred at x 0 that satisfies f (k) (a) = P (k) (a) k 0

Taylor Polynomials The n th Taylor polynomial for f at x 0 is a polynomial of the form P n (x) = a 0 + a 1 (x x 0 ) + a 2 (x x 0 ) 2 + a 3 (x x 0 ) 3 + + a n (x x 0 ) n such that P (k) n (x 0 ) = f (k) (x 0 ) for all 0 k n To find such a polynomial we need to find the value of the constants a 0, a 1,..., a n.

Taylor Polynomials The n th Taylor polynomial for f at x 0 is a polynomial of the form P n (x) = a 0 + a 1 (x x 0 ) + a 2 (x x 0 ) 2 + a 3 (x x 0 ) 3 + + a n (x x 0 ) n such that P (k) n (x 0 ) = f (k) (x 0 ) for all 0 k n To find such a polynomial we need to find the value of the constants a 0, a 1,..., a n. a k = f (k) (x 0 ) k! for all 0 k n

Taylor Polynomials and Taylor Series Definition (Taylor and Maclaurin Series) Let f be a function with at least n derivatives, then the n th Taylor polynomial for f at x 0 is the polynomial n k=0 f (k) (x 0 ) (x x 0 ) k k! Let f be a function with derivative of all orders on an interval (a R, a + R) for some R > 0. Then, the Taylor Series of f at x 0 (or centred at x 0 ) is n=0 f (n) (x 0 ) (x x 0 ) n n!

Taylor Polynomials and Taylor Series Example 3 Find the Taylor series for f (x) = e x at x 0 = 0.

Taylor Polynomials and Taylor Series Example 3 Find the Taylor series for f (x) = e x at x 0 = 0.

Taylor Polynomials and Taylor Series Example 4 Find the Taylor series for f (x) = sin x at x 0 = 0.

Taylor Polynomials and Taylor Series Example 4 Find the Taylor series for f (x) = sin x at x 0 = 0.

Taylor Polynomials and Taylor Series Example 4 Find the Taylor series for f (x) = sin x at x 0 = 0. Example 5 Find the Taylor series for f (x) = cos x at x 0 = 0.

Convergence of Taylor Series Recall that Definition We defined the remainder of a convergent series of constants to be the difference of the sum S of the series and a term s n from the sequence of partial sums, i.e. R n = S s n The remainder measures the error made in using s n to approximate S. Definition (The Remainder of a Function) Let f be a function with nth order derivative at every point on an open f (k) (x 0 ) interval containing x 0, and let P n (x) = n n=0 k! (x x 0 ) k, the nth Taylor polynomial for f at x 0. We define the nth remainder for f to be R n (x) = f (x) P n (x).

Convergence of Taylor Series Example 6 The 5th Taylor polynomial for f (x) = sin x at 0 is P 5 (x) = x x 3 3! + x 5 5!. Therefore, R 5 (x) = sin x (x x 3 3! + x 5 5! ).

Convergence of Taylor Series If lim n R n (x) = 0 on some interval I, then the Taylor Polynomials become better and better approximations for the function f as we include more terms of higher degree. Even more, in this case, the Taylor series is an alternative representation for f on the interval I, i.e. f (x) = n=0 f (n) (x 0 ) (x x 0 ) n for all x I n!

Convergence of Taylor Series Theorem (Taylor s Theorem) Let f be a function that can be differentiated n + 1 times in some open interval I containing x 0, and let R n (x) be the nth remainder for f at x = x 0. Then x (x t) n R n (x) = f (n+1) (t) dt n! x 0

Convergence of Taylor Series Theorem (Taylor s Theorem) Let f be a function that can be differentiated n + 1 times in some open interval I containing x 0, and let R n (x) be the nth remainder for f at x = x 0. Then x (x t) n R n (x) = f (n+1) (t) dt n! x 0 The next theorem gives us a more useful tool for understanding the remainder. Theorem (Lagrange s Form for the Remainder) Let f be a function that can be differentiated n + 1 times in some open interval I containing x 0, and let R n (x) be the nth remainder for f at x = x 0. Then for each x I, there exists c between x 0 and x such that R n (x) = f (n+1) (c) (n + 1)! (x x 0) n+1.

Convergence of Taylor Series Example 7 Show that e x = k=0 1 k! x k for all x R

Convergence of Taylor Series Example 8 Show that sin x = k=0 ( 1) k (2k + 1)! x 2k+1 for all x R