Resource reading (If you would like to brush up on stress, strain, and elasticity):

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12.108 Struct. & Prop s. of Earth Mat. Lecture 9 1 Single-crystal elasticity Assigned Reading: Nye JF (1957) Physical Properties of Crystals. Oxford University Press, Oxford, UK (Chapters 5 and 6). Nye, J. F. Elastic behavior of single crystals: Anisotropy, pp. 2415-2423, in Encyclopedia of Materials: Science and Technology, Elsevier Science, 2001 (http://www.elsevier.com/mrwclus/15/show/main.htt) From MIT campus. Resource reading (If you would like to brush up on stress, strain, and elasticity): Malvern LE (1969) Introduction to the Mechanics of a Continuous Medium. Prentice Hall, Englewood Cliffs, NJ. (A rigorous introduction to continuum mechanics.) Oertel G (1996) Stress and Deformation: A handbook on Tensors in Geology. Oxford University Press, New York. (Many problems on which to practice.)

12.533 Rock Physics Le05: Strain/Elasticity, 2003 02 27 2 Elasticity Elastic and inelastic behavior For small strains at constant temperatures, the amount of strain is determined by the magnitude of the stress causing it. Perfectly Elastic: Purely elastic behavior implies thermodynamic reversibility. All the work put into deforming the body is recoverable. Deformation is not timedependent. The relation between stress and strain may be linear or non-linear. Anelastic: Time-dependent behavior in which the material strain is recoverable Plastic and viscoplastic behavior: When a material is deformed to large strains, some of the strain is permanent and not recoverable; this permanent strain is plastic (if time independent) or viscoplastic (if time dependent). Elastic Recoverable Timeindependent Linear Nonlinear Inelastic Anelastic Part. Recov. Timedependent Lin or Nonlin. Plastic Not recover. Time-indep. Visco-plas. time-dep

12.533 Rock Physics Le05: Strain/Elasticity, 2003 02 27 3 200 MPa) Tensile Non-linear Linear Elastic Recoverable σ ( compression Recoverable Elastic Energy 10-3 extension ε Compressive MPa) σ ( Non-elastic Anelastic Heat lost/cycle 10-3 ε

12.533 Rock Physics Le05: Strain/Elasticity, 2003 02 27 4 Anisotropic (Single Crystal) Elasticity Table removed due to copyright reasons Image removed due to copyright reasons

12.533 Rock Physics Le05: Strain/Elasticity, 2003 02 27 5 Coordinate Conventions for Elasticity Tensor The exact values of the elasticity tensor depend on the definition of the coordinate system. The convention used is that the modulii are referred to an othonormal coordinate systems, x 1, x 2, x 3, with unit vectors, ê 1,. These axes are related to the mineral lattice vectors by the following convention Monoclinic Tetragonal, trigonal, hexagonal Orthorhombic and cubic eˆ 2 b eˆ ˆ 1 a, e3 c, eˆ 1 a, e ˆ ˆ 2 b, e3 c, Linear Elastic Equations Given the restrictions of reversibility and linearity, Hooke s law can be written for strain as a function of stress ε ij = c ijkl σ kl (i, j, k, l = 1,...,3 ) ε I = c IJ σ J (I, J = 1,..., 6 σ ij = s ijkl ε kl (i, j, k, l = 1,...,3 ) ε I = c IJ σ J (I, J = 1,..., 6 The matrix notation (right-hand set of equations) reduces the number of subscripts to two, but the equations do not strictly obey tensor transformation rules and require factors of 2 and 4 to be inserted in the relations between s ijkl and s IJ. s Compliance Modulus Stress -1 c Stiffness Constant Stress ) ) The reduction from 81 separate components to 36 occurs because the stress and strain tensors are symmetric. Because the material behavior is thermodynamically reversible, a chemical potential energy, the Helmholtz free energy, can be defined to express the energy of the elastic solid. For this thermodynamic potential to exist, requires the stiffness and compliance tensors and matrices to be symmetric. This limits the number of independent components of the most general elasticity tensor to 21.

12.533 Rock Physics Le05: Strain/Elasticity, 2003 02 27 6 Symmetry causes further restrictions: Crystal symmetry requires further reductions in the number of the stiffnesses and compliances Triclinic 21 Monoclinic 13 Orthorhombic 9 Tetragonal 7,6 Trigonal 7,6 Hexagonal 5 Cubic 3 Isotropic 2

12.533 Rock Physics Le05: Strain/Elasticity, 2003 02 27 8 Stiffness Moduli Cubic C ii C 44 C 12 (GPa) Remark ρ Tm ( C) Gold (Au) 191 42 162 metal 19.3 1063 Halite NaCl 165 34 47 halide 2.2 801 Spinel (Mg Al 2 0 4 ) 283 155 155 Al 2 0 4 3.6 2135 Wustite (Fc0) 246 45 149 Oxide 5.73 ~1400 Periclase (MgO) 294 155 93 Oxide 3.6 2800 α-iron (Fe) Grossular Garnite 3 230 322 117 105 135 91 metal Al. Silicate 7.9 3.6 1408 (~1400) Pyrite FeS 2 361 105 34 Sulfide 5.0 Diamond 1079 578 124 covalent 3.5 (3652 Hexagonal C 11 C 33 C 44 C 12 C 13 Remark ρ Tm ( C) Graphite (C) 1060 36.5 0.3 180 15 Sp 2 bonding 2.26 (3652) Ice-I (H 2 0) 13.5 15 3.0 65 6 hydrogen 0.9 0 β quartz (S:0 2 ) 117 110 36 16 33 framework - 1470- Trigonal C 11 C 33 C 44 C 12 C 13 C 14 Remark ρ Τm ( C) Calcite (CaC03) 144 84 33.5 53.9 51-20.5 carbonate (1339 C) Hematite (Fe 2 0 3 ) 242 227 85.7 54.6 15.4-125 oxide ~1550 Corundum (Al 2 0 3 ) 497 501 147 162 116-22 oxide 1840 α-quartz (Si0 2 ) 86.5 107 58 7 12-18 framework (1470) Orthorhombic C 11 C 22 C 33 C 44 C 55 C 66 C 12 C 13 C 23 Remark ρ Perovskite (MgSi0 3 ) 515 525 435 179 202 175 117 117 139 Clspckd Olivine (Mg 2 Si0 4 ) 328 200 235 67 81 81 69 69 73 Isolated 3.20 Fayalite (Fe 2 Si0 4 ) 266 168 232 32.3 47 57 94 92 92 Isolated 4.38 Enstatite (MgSi0 3 ) 224 178 214 78 76 82 72 54 53 Chain 3.20 Ferrosilite (FeSi0 3 ) 198 136 175 59 58 49 84 72 55 Chain 4.00 Wadsleyite 4 360 383 273 112 118 98 75 110 105 Chain 3.47 Sources: Simmons, M. G., and H. Wang, Single crystal elastic constants and calculated aggregate properties, MIT Press, 1975. Bass, J. D., Elasticity of Minerals, Glasses, and Melts, pp.45-63, in Mineral Physics and crystallography: a handbook of physical constants, edited by T. J. Ahrens, AGU, Washington, DC., 1995. 3 (Mg,Fe,Mn) 3 Al 2 Si 3 O 12 4 β (Mg 2 SiO 4 )

12.108 Struct. & Prop s. of Earth Mat. Lecture 9 9 Tetragonal C 11 C 33 C 44 C 66 ` C 12 C 13 Remark ρ T m ( C) Zircon (ZrSi 0 4 ) Stishovite (Si 0 2 ) 424 453 489 776 131 252 48 302 70 211 149 203 Framework 4.7 4.20 (1540 decp) high α-cristobalite (Si 0 2 ) 59.4 42.4 67 26 4-4.4 Framework 2.335 pressure 1713 Monoclinic C 11 C 22 C 33 C 44 C 55 C 66 C 12 C 13 C 23 C 15 C 25 C 35 C 46 Remark ρ T m ( C) Albite (NaAlSi 3 O 8 ) 74 131 128 17 30 32 36 39 31-6.6-13 -20-25 Framework 2.62 1100 C Anorthite (CaAl 2 Si 2 O 8 ) 124 205 156 24 40 42 66 50 42-19 -7-18 -1 Framework 2.76 1550 C Microcline (KSi 3 AlO 8 ) 67 169 118 14 24 36 45 27 20 -.2 - -15-2 Framework 2.56 1150 C 12. 3 Labradorite 5 99 158 150 22 35 37 63 49 27-25 -11-12 -5 Framework 2.70 1280 C Diopside (CaMgSi 2 O 6 ) 204 175 238 68 59 71 84 88 48-19 -20-34 -11 Chain 3.31 1390 C Hedenbergite (CaFeSi 2 O 6 ) Hornblende 6 222 116 176 160 249 192 55 57 63 32 60 37 69 45 79 61 86 66 12 4.3 13-2.5 26 10-10 -6.2 Chain Chain 3.65 3.12 Coesite (SiO 2 ) 161 230 232 68 73 59 82 103 36-36 2.6-39 9.9 Framework 2.911 (1713) 5 Albite 30-50%, Anorthite 70-50% 6 (Ca,Na)2-3 (Mg,Fe,Al) 5 (Al,Si) 8 O 2 (OH) 2

12.108 Struct. & Prop s. of Earth Mat. Lecture 9 10 Elastic stiffness or compliance in an arbritrary direction Vector Transformation Express the components of a vector in a new coordinate system that has been rotated. The components of the vector in the new system are ' E i = a ij E j where E i are the components of the vector in the old system, a ij are the direction cosines between the old and new coordinate systems, and E j are the components in the new system. Tensor Transformation: Tensors of the second rank transform in much the same way as vectors: ' E = a a E i j ik jl kl Tensors of the fourth rank (like stiffness or compliance) transform as ' s ijkl = a im a jn a ko a lp s mnop Thus, the Young s modulus (c 1111 ) could be calculated in any arbitrary direction.

12.533 Rock Physics Le05: Strain/Elasticity, 2003 02 27 12 Relations among moduli, stiffnesses and compliances In isotropic elastic materials, the most commonly used elastic (moduli, constants, stiffnesses, compliances) are Young s Modulus, the Bulk modulus, the Volumetric compressibility, Poisson s ratio, and the Lame parameters. Young s Modulus w l ½ dw ½ dl The relation between the load on a bar and the fractional stretch of a bar along its long axis is known as Young s modulus. σ 1 σ = Eε l l ε = l 1 σ l E where the subscript l is used to indicate the direction in which the measurement is made, but in an isotropic material the direction is immaterial. In an anisotropic material, the equivalent measurement depends on the direction (relative to some fixed axes in the material) in which the measurement is made). When the measurement is made along the 1 axis in a single crystal, the equivalent modulus (stiffness, compliance) is σ = c ε equivalently σ = c ε or ε = s σ 11 1111 11 1 11 1 11 1111 11 When the Young s modulus measurement is made in the 1 direction, E = 1/ s 1111 When the measurement is made in another direction D 1/ E = adiadj a Dk a Dl s ijkl where a Di is the direction cosine between D and the axis i.

12.533 Rock Physics Le05: Strain/Elasticity, 2003 02 27 13 Some typical values of compressibility and Poisson s ratio Rock/Material Compressibility (10-5 MPa -1 ) Poisson s Ratio Obsidian 2.9-3. 0.12-0.16 Granite 1.9-2.0 0.23-0.27 Diorite 1.4-1.7 0.26-0.29 Gabbro 1.1-1.3 0.27-0.31 Diabase 1.2-1.4 0.27-0.30 Dunite 0.8-0.9 0.26-0.28 Slate 1.9-2.3 0.15-0.20 Limestone 1.3-1.4 0.27-0.30 Dolomite 1.0-1.1 0.30 Quartzite 2.4-2.6 0.12-0.15 Mica Schist 2.1-2.3 0.15-0.20 Feldspathic Gneiss 1.8-2.2 0.15-0.20 Amphibolite 1.1-1.3 0.28-0.30 Oligoclase 1.5-1.6 0.29 Anorthosite 1.2-1.4 0.31 Rocksalt 4.3 0.25 Anhydrite 1.8 0.30 Ice 12 0.36 Steel 0.6 0.28-0.29 Aluminum 1.3 0.34-0.36

12.533 Rock Physics Le05: Strain/Elasticity, 2003 02 27 15 Poisson s Ratio ε ν l ε l for an isotropic material σ l = Eεl ε 22 ε 22 ν s 22111 = = = = s 21 σ 11 Eε 11 E For rocks, Poisson s ratio is commonly 0.25. In some materials, it may be very small or even negative. Can you think of a common use for a material with a low or negative Poisson s ratio? For an incompressible material, Poisson s ratio is 0.5. Why? Is it possible for ν to be even larger than that? Rigidity Modulus h µε shear = σ shear dl 1 When the body and the crystal axes are aligned, s 44 = µ Lamé Constants For an isotropic material, the stress strain relations are often written: σ = (λ + 2µ ε + λε + λε 1 ) 1 2 3 2 1 ) 2 3 3 1 2 ) 3 σ = λε + (λ + 2µ ε + λε σ = λε + λε + (λ + 2µ ε From the equations above it is clear that if the crystal axis 1 is aligned with the exterior axis 1 then 2µ + = c and c 1122 = λ λ 1111

12.533 Rock Physics Le05: Strain/Elasticity, 2003 02 27 16 Compressibility Consider imposition of pressure σ ij = pδ ij Then the equation for the strain is ε ij = ps ijkl δ kl define ε = ps iikk ii and β T = =s iikk p Write the equation for the isothermal compressibility for a cubic crystal. β T cubic = 3(s 11 + 2s 12 ) Does the compressibility depend on the direction of measurement? The bulk modulus is the inverse of the compressibility.

12.533 Rock Physics Le05: Strain/Elasticity, 2003 02 27 17 Relations among Various Moduli and Elastic Constants Name Symbol Definition S/C Units Relations Inv. Young s 1/E Normal Strain S 1111 Stress -1 λ + µ Modulus Normal Stress µ (3λ + 2µ ) Poisson s Ratio ν,σ Normal Strain S 2211 --- λ Norm. Strain /S 1111 2(λ + µ) Shear Modulus µ, G Shear Stress C 1212 Stress E Shear Strain 2(1 +ν ) Lame Const. λ Response of C 1111 Stress Eν Stress to λ = ( 1 +ν )(1 ν ) Volum.Change Compressibility B Dilation/Pressure Stress -1 E = λ + 2 µ 3(1 2ν ) 3 Equivalent formulations for isotropic elastic materials in principal stress representation: 1 ν ν ε 11 = σ 11 σ 22 σ 33 E E E σ 1 = (λ + 2µ ) ε 1 + λε 2 + λε 3 1 ν ε 22 = σ 11 ν σ 22 σ 33 σ 2 = λε 1 + (λ + 2µ ) ε 2 + λε 3 E E E ν ν 1 σ 3 = λε 1 + λε 2 + (λ + 2µ ) ε 3 ε = σ σ + σ 33 11 22 33 E E E In general: ε ij = 1 +ν σ ν ij δ σ E E ij kk σ ij = λδ ij ε kk + 2µε ij