SHW6-01 Total: 28 marks

Similar documents
SHW6-R1 1M+1A 1M+1A 1M+1A. 11. (a) 14. (a) With the notations in the figure, With the notations in the figure, AG BH 800 m Consider ACG.

SHW 1-01 Total: 30 marks

Math 9 Chapter 8 Practice Test

Udaan School Of Mathematics Class X Chapter 10 Circles Maths

Triangles. 3.In the following fig. AB = AC and BD = DC, then ADC = (A) 60 (B) 120 (C) 90 (D) none 4.In the Fig. given below, find Z.

2 13b + 37 = 54, 13b 37 = 16, no solution

Set 5 Paper 2. Set 5 Paper 2. 1 Pearson Education Asia Limited 2017


Worksheet A VECTORS 1 G H I D E F A B C

Set 2 Paper (a) (i) (ii) (b) The coordinates of R = ( 5, (a) Range = 8 2 (3) (b) New Mean. New variance

21. Prove that If one side of the cyclic quadrilateral is produced then the exterior angle is equal to the interior opposite angle.


complicated calculations, similar to HKDSE difficult types ** Please answer any 30 questions ** Level 1 In the figure, sin θ =

Individual Events 1 I2 x 0 I3 a. Group Events. G8 V 1 G9 A 9 G10 a 4 4 B


11 is the same as their sum, find the value of S.

VAISHALI EDUCATION POINT (QUALITY EDUCATION PROVIDER)

Question Bank Tangent Properties of a Circle

Class IX Chapter 8 Quadrilaterals Maths

Class IX Chapter 8 Quadrilaterals Maths

PAST QUESTIONS ON VECTORS P1

"Full Coverage": Non-Right Angled Triangles

( y) ( ) ( ) ( ) ( ) ( ) Trigonometric ratios, Mixed Exercise 9. 2 b. Using the sine rule. a Using area of ABC = sin x sin80. So 10 = 24sinθ.

NELSON SENIOR MATHS SPECIALIST 11

1.1 Exercises, Sample Solutions

Set 2 Paper 1. Set 2 Paper 1. 1 Pearson Education Asia Limited Section A(1) (4) ( m. 1M m

2010 Euclid Contest. Solutions

Mathematics CLASS : X. Time: 3hrs Max. Marks: 90. 2) If a, 2 are three consecutive terms of an A.P., then the value of a.

9 th CBSE Mega Test - II

Visit: ImperialStudy.com For More Study Materials Class IX Chapter 12 Heron s Formula Maths

Triangles. Example: In the given figure, S and T are points on PQ and PR respectively of PQR such that ST QR. Determine the length of PR.

Solutions Key Right Triangles and Trigonometry

Answers: ( HKMO Final Events) Created by: Mr. Francis Hung Last updated: 2 September 2018

TRIGONOMETRY SINE AND COSINE RULES & AREA OF TRIANGLE. Leaving Cert Revision

Inspiration and formalism

Exercise 10.1 Question 1: Fill in the blanks (i) The centre of a circle lies in of the circle. (exterior/ interior)

2, find the value of a.

2012 GCSE Maths Tutor All Rights Reserved

CHAPTER 7 TRIANGLES. 7.1 Introduction. 7.2 Congruence of Triangles

Solutionbank M1 Edexcel AS and A Level Modular Mathematics

6 CHAPTER. Triangles. A plane figure bounded by three line segments is called a triangle.

0615geo. Geometry CCSS Regents Exam In the diagram below, congruent figures 1, 2, and 3 are drawn.

Class IX - NCERT Maths Exercise (10.1)

Set 6 Paper 1. Set 6 Paper 1. 1 Pearson Education Asia Limited Section A(1) (Pyth. Theorem) (b) 24units Area of OPQ. a b (4)


CBSE CLASS X MATH -SOLUTION Therefore, 0.6, 0.25 and 0.3 are greater than or equal to 0 and less than or equal to 1.

Geometry Honors Review for Midterm Exam


Angles of Elevation and Depression

Class IX Chapter 7 Triangles Maths. Exercise 7.1 Question 1: In quadrilateral ACBD, AC = AD and AB bisects A (See the given figure).

QUEEN S COLLEGE. Yearly Examination, Mathematics Paper II. Secondary 5 Date: 23 June, Time: 8:30-9:30 Full Marks: 80

RD Sharma Solutions for Class 10 th

Trig Practice 08 and Specimen Papers

Circle and Cyclic Quadrilaterals. MARIUS GHERGU School of Mathematics and Statistics University College Dublin

Higher Order Thinking Skill questions

Starting with the base and moving counterclockwise, the measured side lengths are 5.5 cm, 2.4 cm, 2.9 cm, 2.5 cm, 1.3 cm, and 2.7 cm.

HKDSE2018 Mathematics (Compulsory Part) Paper 2 Solution 1. B 4 (2 ) = (2 ) 2. D. α + β. x x. α β 3. C. h h k k ( 4 ) 6( 2 )

Question 1: In quadrilateral ACBD, AC = AD and AB bisects A (See the given figure). Show that ABC ABD. What can you say about BC and BD?

8. Quadrilaterals. If AC = 21 cm, BC = 29 cm and AB = 30 cm, find the perimeter of the quadrilateral ARPQ.

S Group Events G1 a 47 G2 a *2

Class IX Chapter 7 Triangles Maths

Year 11 Math Homework

1. Prove that the parallelogram circumscribing a circle is rhombus.

AB AB 10 2 Therefore, the height of the pole is 10 m.

10. Circles. Q 5 O is the centre of a circle of radius 5 cm. OP AB and OQ CD, AB CD, AB = 6 cm and CD = 8 cm. Determine PQ. Marks (2) Marks (2)

Similarity of Triangle

CAPS Mathematics GRADE 11. Sine, Cosine and Area Rules

Mathematics Secondary IV May May Practice Exam. Competency Two Uses Mathematical Reasoning. Science Option ANSWER KEY

MATHEMATICS. Time allowed : 3 hours Maximum Marks : 100 QUESTION PAPER CODE 30/1/1 SECTION - A

Solution 1: (i) Similar (ii) Similar (iii) Equilateral (iv) (a) Equal (b) Proportional

nx + 1 = (n + 1)x 13(n + 1) and nx = (n + 1)x + 27(n + 1).

IB Math SL 1: Trig Practice Problems: MarkScheme Circular Functions and Trig - Practice Problems (to 07) MarkScheme

Concurrency and Collinearity

BOARD QUESTION PAPER : MARCH 2016 GEOMETRY

LLT Education Services

INSTRUCTIONS. F.3 2 nd Maths Examination (1011) P1/14

CHAPTER TWO. 2.1 Vectors as ordered pairs and triples. The most common set of basic vectors in 3-space is i,j,k. where

UNIT 1: SIMILARITY, CONGRUENCE, AND PROOFS. 1) Figure A'B'C'D'F' is a dilation of figure ABCDF by a scale factor of 1. 2 centered at ( 4, 1).

Coordinate Geometry and Pythagorean Theorem Practice [197 marks]

CHAPTER 10 TRIGONOMETRY

Geometry Problem Solving Drill 08: Congruent Triangles

Chapter 3. - parts of a circle.

J JUL - 25-JUL 2016 HOUSEHOLD FINANCES RESEARCH

Solutions to Exercises

SOLUTIONS SECTION A SECTION B

CBSE MATHEMATICS (SET-2)_2019

CHAPTER 5 : THE STRAIGHT LINE

MT EDUCARE LTD. SUMMATIVE ASSESSMENT Roll No. Code No. 31/1

Suggested problems - solutions

Suggested Solutions MATHEMATICS COMPULSORY PART PAPER 1. Question No Marks TAK SUN SECONDARY SCHOOL MOCK EXAMINATION ONE FORM 5

Class 6 Geometry. Answer the questions. For more such worksheets visit (1) If AB and DE are parallel, find the value of ACB.

Chapter (Circle) * Circle - circle is locus of such points which are at equidistant from a fixed point in

P1 Vector Past Paper Questions

MODEL QUESTION PAPERS WITH ANSWERS SET 1

UNIFORM TEST 1 MATHEMATICS Compulsory Part PAPER 1 (Section A)

Core Mathematics 2 Trigonometry (GCSE Revision)

1 / 23

Vectors Practice [296 marks]

SSC CGL Tier 1 and Tier 2 Program

Triangle Congruence and Similarity Review. Show all work for full credit. 5. In the drawing, what is the measure of angle y?

Transcription:

SHW6-0 Total: 8 arks Review Exercise 3. Area of C ()(8)sin 9 9.9 BC CA. Let s. 4 9 0 s. Area of C 3. s( s )( s BC)( s CA).(. 4)(. 9)(. 0) 8.0 BAC 80 By the sine forula, BAC 4 80 ( su of ) BC sinc sin A 0 a sin sin80 a 4.0 4. By the cosine forula, PQ QR PR cos PQR ( PQ)( QR) 7 6 cos (7)(6) 44.4 6. By the cosine forula, b c a cos A bc 8 0 (8)() A.77.8 a c b cos B ac 0 8 (0)() B 4.4096 4.4 A B C 80 C 80.77 4.4096 8.8 ( su of ) 7. (a) With the notations in the figure, BAQ P (alt. s, QA // BP) 3 The copass bearing of B fro A S(90 3)W S8W (b) With the notations in the figure, +. By the cosine forula, b a b c 7 4 (7)(4) cos 4.0400.04 0 ac cos B A 00.86 b c a cos A bc.0400 4 7 (.0400)(4) A B C 80 C 80 00.86 4 34. ( su of ) + RCB PBC (alt. s, RC // BP) 8 ACB 80 70 (3 8) ( su of ) 60 The true bearing of A fro C 70 RCB ACB 70 8 60 348

8. (a) With the notations in the figure, 9. With the notations in the figure, (b) PAR P 80 (adj. s on st. line) 6 P 80 P In P, by the sine forula, sin P sin P AP BP sin P sin 0 k 9 k 0sin sin P 9 P 38.68 or 80 38.68 38.7 (cor. to 3 sig.fig.) or 4 (rejected) The copass bearing of P fro B is N38.7 E. P BPT 38. 68 (alt. s, // PT) The true bearing of B fro P is (80 + 38.68 ), i.e. 9. HPR PHS 6 (alt. s, PR // SH) In HPR, HR sin HPR HP 80 sin 6 HP 80 HP sin 6 90.606 HPQ HPR 80 (adj. s on st. line) HPQ 6 80 HPQ 8 In HPQ, by the cosine forula, HQ HQ PQ HP 0 90.606 (0)(90.606) cos8 9.708 ( PQ)( HP)cos HPQ By the cosine forula, HQ PQ HP cos HQP ( HQ)( PQ) 9.708 0 90.606 (9.708)(0) HQP 6.7 The angle of elevation of H fro the an at Q is 6.7.

SHW 6-A Total: arks. (a) Consider ADH. AD DH (Pyth. theore) 4 4 3.66 Consider AGH. AG GH (Pyth. theore) AG ( 3) 48 6.93 4 + (b) The angle between AG and the plane ADHE is G. Consider AGH. GH tan G 4 3 G 3.3 The angle between AG and the plane ADHE is 3.3.. (a) Consider BEC. BE cos CBE BC 80 cos3 BC BC 97.660 97.7 Consider BCD. BC sin BDC BD 97.660 sin 40 BD BD.93 (cor to 3 sig. fig.) Consider AFD. DF tan DAF AF DF tan 3 80 DF 6.066 6.0 ++ (b) The angle between BD and BF is DBF. DF sin DBF BD 6.066.93 DBF.6 The angle between BD and BF is.6. (c) F is the projection of D on the plane EF. BF is the projection of BD on the plane EF. The angle between BD and BF is the sae as the angle between BD and the plane EF. 3. (a) The angle between EG and AG is AGE. Consider EFG. EG EF FG (Pyth. theore) EG 6 0 Consider EAG. EA tan AGE EG 0 0 AGE 6.6 The angle between EG and AG is 6.6. (b) The angle between AG and CDHG is AGD. Consider CDG. DG CD CG (Pyth. theore) DG 6 0 36 Consider ADG. AD tan AGD DG 36 AGD 3. The angle between AG and CDHG is 3.. (c) The angle between HG and CD is D. Consider ADH. DH tan D AD 0 D 39.8 The angle between HG and CD is 39.8.. (a) The angle between OH and OE is EOH. Consider C. AC BC (Pyth. theore) AC 0 0 OC = Consider OCH. OH OC CH (Pyth. theore) OH 7 Siilarly, OE = 0 7 3

Consider OEH. By the cosine forula, OH OE EH coseoh ( OH)( OE) 7 7 7 7 EOH 48. (cor. to 3 sig.fig.) The angle between OH and OE is 48.. M+ (b) Let I be the projection of O on the plane GHEF. The angle between OH and the plane GHEF is OHI. 0 IH = OC = Consider OHI. OI tan OHI IH 0 OHI 4.7 The angle between OH and the plane GHEF is 4.7. 4

SHW 6-B Total: 8 arks. The angle between the planes ACDE and BCDF is ACB. By the sine forula, AC sinacb sinc 7 sin ACB sin40 sin 40 sin ACB 7 ACB 7.0 The angle between the planes ACDE and BCDF is 7.0.. The angle between the planes ACFD and BCFE is ACB. By the cosine forula, BC AC cos ACB ( BC)( AC) 9 7 (9)() ACB 39.4 The angle between the planes ACFD and BCFE is 39.4. 3. (a) V is an isosceles triangle. VM AM = 8 = 4 Consider AMV. AM VM VA (Pyth. theore) VM 8 4 48 6.93 (b) C is an isosceles triangle. CM The angle between the planes V and C is CMV. By the cosine forula, VM CM VC cos CMV ( VM )( VC) ( CMV 70. 48) ( ( 48)( 48) 8 48) The angle between the planes V and C is 70.. ()() cos 4 8.490 8.4 4. (a) Consider CDF. By the cosine forula, CF CD DF ( CD)( DF) cos CDF CF (b) Consider ADF. AF AF AD DF (Pyth. theore) 8 44. (c) The angle between AC and AF is CAF. Consider CAF. AC AF 44 By the cosine forula, AC AF CF coscaf ( AC)( AF) ( 44) 44)( 44) CAF 3.0 The angle between AC and AF is 3.0.. (a) (i) Consider C. AC AC ( ( 44) 8.490 BC (Pyth. theore) 8 6 0 OC AC (prop. of rectangle) 0 (ii) The angle between VC and the plane CD is VCO. Consider VCO. VO tan VCO OC VCO 67.4 The angle between VC and the plane CD is 67.4. (b) VBC and OBC are isosceles triangles. VM BC and OM BC The angle between the planes VBC and CD is VMO. OM 4 VO tan VMO OM 4 VMO 7.6 The angle between the planes VBC and CD is 7.6.

SHW6-C Total: 7 arks. (a) Consider O. OB sin O OB sin 40 0 OB 0sin 40 Consider OBT. OT tan OBT OB OT tan 0sin 40 OT 0sin 40 tan 0 The height of the tower OT is 0. (b) Consider O. OA cos O OA cos 40 0 OA 0 cos 40 Consider OAT. OT tan OAT OA 0sin 40 tan 0 cos 40 OAT 0. The angle of elevation of T fro A is 0... (a) Consider POQ. With the notations in the figure, O OQ = Q + OQP (ext. of ) 60 = + OQP OQP = 4 By the sine forula, OQ sin OQP sin Q OQ sin 4 sin OQ 9.06 9. (b) Consider VOQ. VO tan VQO OQ 0 9.06 VQO 6.4 The angle of elevation of V fro Q is 6.4. 3. (a) Consider B. tan HBA 8 tan 0 8 tan 0 76.994 Consider C. 76.9 By the cosine forula, AC BC ( )( AC) cosc AC (76.994) 3.9 7 3.6 (b) Consider ACH. tan ACH ACH (76.994)(7) cos AC 8 3.9 40.7 + The angle of elevation of H fro C is 40.7.

4. (a) Consider H. OH tan H tan 4 tan 4 Consider ORH. OH tan ORH OR tan 4 OR OR Consider POR. OR tan R tan 4 tan 4 R 4 The true bearing of R fro P is 80 4 = 6. (b) Consider POR. cosr PR cos4 tan 4 3OQ OQ sin 4 Consider OQH. OH tan OQH OQ sin 4 OQH 67.6 The angle of elevation of H fro Q is 67.6.