Calculus for the Life Sciences

Similar documents
Applications of the Derivative - Graphing. Body Temperature Fluctuation during the Menstrual Cycle

Calculus for the Life Sciences

Outline. Formic Acid

Suppose that f is continuous on [a, b] and differentiable on (a, b). Then

AP Calculus AB. Chapter IV Lesson B. Curve Sketching

MAT 122 Homework 7 Solutions

Calculus 221 worksheet

f (x) = 2x x = 2x2 + 4x 6 x 0 = 2x 2 + 4x 6 = 2(x + 3)(x 1) x = 3 or x = 1.

Bob Brown Math 251 Calculus 1 Chapter 4, Section 1 Completed 1 CCBC Dundalk

Polynomial Functions. x n 2 a n. x n a 1. f x = a o. x n 1 a 2. x 0, , a 1

Calculus for the Life Sciences

Analysis of Functions

1) The line has a slope of ) The line passes through (2, 11) and. 6) r(x) = x + 4. From memory match each equation with its graph.

Announcements. Topics: Homework: - sections , 6.1 (extreme values) * Read these sections and study solved examples in your textbook!

f'(x) = x 4 (2)(x - 6)(1) + (x - 6) 2 (4x 3 ) f'(x) = (x - 2) -1/3 = x 2 ; domain of f: (-, ) f'(x) = (x2 + 1)4x! 2x 2 (2x) 4x f'(x) =

3.5: Issues in Curve Sketching

APPLICATIONS OF DIFFERENTIATION

Sections 4.1 & 4.2: Using the Derivative to Analyze Functions

1. Which one of the following points is a singular point of. f(x) = (x 1) 2/3? f(x) = 3x 3 4x 2 5x + 6? (C)

AP Calculus Worksheet: Chapter 2 Review Part I

Polynomial functions right- and left-hand behavior (end behavior):

Calculus for the Life Sciences

Math 131 Final Review May 2010

1S11: Calculus for students in Science

Outline. Calculus for the Life Sciences. Crow Predation on Whelks. Introduction. Lecture Notes Optimization. Joseph M. Mahaffy,

Section 1.3 Rates of Change and Behavior of Graphs

Test 3 Review. y f(a) = f (a)(x a) y = f (a)(x a) + f(a) L(x) = f (a)(x a) + f(a)

Bob Brown Math 251 Calculus 1 Chapter 4, Section 4 1 CCBC Dundalk

AB Calc Sect Notes Monday, November 28, 2011

The coordinates of the vertex of the corresponding parabola are p, q. If a > 0, the parabola opens upward. If a < 0, the parabola opens downward.

MATH 115 QUIZ4-SAMPLE December 7, 2016

Math 1314 Lesson 12 Curve Sketching

Applications of Derivatives

Review Guideline for Final

Curve Sketching. Warm up

Math 2204 Multivariable Calculus Chapter 14: Partial Derivatives Sec. 14.7: Maximum and Minimum Values

A.P. Calculus Holiday Packet

Math 108, Solution of Midterm Exam 3

March 5, 2009 Name The problems count as marked. The total number of points available is 131. Throughout this test, show your work.

Mathematics Lecture. 6 Chapter. 4 APPLICATIONS OF DERIVATIVES. By Dr. Mohammed Ramidh

The First Derivative Test for Rise and Fall Suppose that a function f has a derivative at every poin x of an interval A. Then

Student Study Session Topic: Interpreting Graphs

Math 131. Increasing/Decreasing Functions and First Derivative Test Larson Section 3.3

Math Section TTH 5:30-7:00pm SR 116. James West 620 PGH

RF2 Unit Test # 2 Review Quadratics (Chapter 6) 1. What is the degree of a quadratic function?

AP CALCULUS AB Study Guide for Midterm Exam 2017

Math 118, Summer 1999 Calculus for Students of Business and Economics Midterm

4.1 Analysis of functions I: Increase, decrease and concavity

What makes f '(x) undefined? (set the denominator = 0)

Mon 3 Nov Tuesday 4 Nov: Quiz 8 ( ) Friday 7 Nov: Exam 2!!! Today: 4.5 Wednesday: REVIEW. In class Covers

Section 3.1 Extreme Values

3.Applications of Differentiation

Week 12: Optimisation and Course Review.

Graphs of Polynomial Functions

Polynomial Functions

Precalculus Lesson 4.1 Polynomial Functions and Models Mrs. Snow, Instructor

Section 3.2 Polynomial Functions and Their Graphs

ExtremeValuesandShapeofCurves

Unit V Applications of Derivatives

Unit V Applications of Derivatives

Section 5-1 First Derivatives and Graphs

4.1 - Maximum and Minimum Values

Section 12.2 The Second Derivative

Lecture 9 - Increasing and Decreasing Functions, Extrema, and the First Derivative Test

14 Increasing and decreasing functions

CHAPTER 3 APPLICATIONS OF THE DERIVATIVE

MATH 2053 Calculus I Review for the Final Exam

UNLV University of Nevada, Las Vegas

Precalculus. How to do with no calculator 1a)

Learning Target: I can sketch the graphs of rational functions without a calculator. a. Determine the equation(s) of the asymptotes.

ch 3 applications of differentiation notebook.notebook January 17, 2018 Extrema on an Interval

Daily WeBWorK. 1. Below is the graph of the derivative f (x) of a function defined on the interval (0, 8).

April 9, 2009 Name The problems count as marked. The total number of points available is 160. Throughout this test, show your work.

Math Numerical Analysis

UNLV University of Nevada, Las Vegas

Outline Calculus for the Life Sciences II. Pollution in a Lake 1. Introduction. Lecture Notes Numerical Methods for Differential Equations

Chapter 3 Prerequisite Skills. Chapter 3 Prerequisite Skills Question 1 Page 148. a) Let f (x) = x 3 + 2x 2 + 2x +1. b) Let f (z) = z 3 6z 4.

Cumulative Review. Name. 13) 2x = -4 13) SHORT ANSWER. Write the word or phrase that best completes each statement or answers the question.

8/6/2010 Assignment Previewer

Final Exam Review Packet

Final Exam Review Packet

4 3A : Increasing and Decreasing Functions and the First Derivative. Increasing and Decreasing. then

5.1 Polynomial Functions

Section 4.3 Concavity and Curve Sketching 1.5 Lectures. Dr. Abdulla Eid. College of Science. MATHS 101: Calculus I

Exam 3 MATH Calculus I

MATH 162 R E V I E W F I N A L E X A M FALL 2016

MA 137 Calculus 1 with Life Science Applications Monotonicity and Concavity (Section 5.2) Extrema, Inflection Points, and Graphing (Section 5.

4.2: What Derivatives Tell Us

Question 1. Find the coordinates of the y-intercept for. f) None of the above. Question 2. Find the slope of the line:

Final Examination 201-NYA-05 May 18, 2018

Matrix Theory and Differential Equations Homework 2 Solutions, due 9/7/6

Calculus The Mean Value Theorem October 22, 2018

Section 0.2 & 0.3 Worksheet. Types of Functions

Math Essentials of Calculus by James Stewart Prepared by Jason Gaddis

3.2. Polynomial Functions and Their Graphs. Copyright Cengage Learning. All rights reserved.

Math 16A Second Midterm 6 Nov NAME (1 pt): Name of Neighbor to your left (1 pt): Name of Neighbor to your right (1 pt):

MA1021 Calculus I B Term, Sign:

Higher-Degree Polynomial Functions. Polynomials. Polynomials

Absolute and Local Extrema. Critical Points In the proof of Rolle s Theorem, we actually demonstrated the following

Transcription:

Calculus for the Life Sciences Joseph M. Mahaffy, jmahaffy@mail.sdsu.edu Department of Mathematics and Statistics Dynamical Systems Group Computational Sciences Research Center San Diego State University San Diego, CA 92182-7720 http://www-rohan.sdsu.edu/ jmahaffy Spring 2017 (1/41)

Outline 1 Application of The Derivative Body Temperature Fluctuation 2 Cubic Polynomial Quartic Polynomial Absolute Population Example (2/41)

Applications of the Derivative Applications of the Derivative Sketching Graphs Finding Optimal Values or Steepest parts of a Function (3/41)

Menstrual Cycle Body Temperature Fluctuation Body Temperature Fluctuation during the Menstrual Cycle Mammals regulate their body temperature in a narrow range to maintain optimal physiological responses Variations in body temperature occur during exercise, stress, infection, and other normal situations Neurological control of the temperature Variations include Circadian rhythms (a few tenths of a degree Celsius) Menstrual cycle - Ovulation often corresponds to the sharpest rise in temperature (4/41)

Body Temperature Fluctuation Female Basal Body Temperature 1 Female Basal Body Temperature Female Body Temperature 36.7 36.6 36.5 T ( o C) 36.4 36.3 36.2 36.1 36 0 5 10 15 20 25 t (Days) (5/41)

Body Temperature Fluctuation Female Basal Body Temperature 2 Female Basal Body Temperature The best cubic polynomial fitting the data above is T(t) = 0.0002762t 3 +0.01175t 2 0.1121t +36.41 Want to find the high and low temperatures Determine the time of peak fertility when the temperature is rising most rapidly (6/41)

Body Temperature Fluctuation Female Basal Body Temperature 3 Maximum and Minimum for T(t) = 0.0002762t 3 +0.01175t 2 0.1121t +36.41 The high and low temperatures occur when the curve has slope of zero Find the derivative equal to zero The derivative of the temperature is T (t) = 0.0008286t 2 +0.02350t 0.1121 Note that the derivative is a different function from the original function (7/41)

Body Temperature Fluctuation Female Basal Body Temperature 4 Maximum and Minimum The roots of the derivative (quadratic equation) are Thus, t = 6.069 and 22.29 days Minimum at t = 6.069 with T(6.069) = 36.1 C Maximum at t = 22.29 with T(22.29) = 36.7 C There is only a 0.6 C difference between the high and low basal body temperature during a 28 day menstrual cycle by the approximating function The data varied by 0.75 C (8/41)

Body Temperature Fluctuation Female Basal Body Temperature 5 Maximum Increase in Temperature The maximum increase in temperature is when the derivative is at a maximum This is the vertex of the quadratic function, T (t) The maximum occurs at the midpoint between the roots of the quadratic equation Alternately, the derivative of T (t) or the second derivative of T(t) equal to zero gives the maximum The second derivative is T (t) = 0.0016572t +0.02350 (9/41)

Body Temperature Fluctuation Female Basal Body Temperature 6 Maximum Increase in Temperature The second derivative is zero at the Point of Inflection at t = 14.18 with T(14.18) = 36.4 C The maximum rate of change in body temperature is T (14.18) = 0.054 C/day This model suggests that the peak fertility occurs on day 14, which is consistent with what is known about ovulation (10/41)

Body Temperature Fluctuation Maxima, Minima, and 1, Increasing and Decreasing The derivative is zero at critical points for the graph of a smooth function Definition: A smooth function f(x) is said to be increasing on an interval (a,b) if f (x) > 0 for all x (a,b). Similarly, a smooth function f(x) is said to be decreasing on an interval (a,b) if f (x) < 0 for all x (a,b) (11/41)

Body Temperature Fluctuation Maxima, Minima, and 2 Maxima, Minima, and (12/41)

Body Temperature Fluctuation Maxima, Minima, and 3 A high point of the graph is where f(x) changes from increasing to decreasing A low point on a graph is where f(x) changes from decreasing to increasing If f(x) is a smooth function, then either case has the derivative passing through zero Definition: A smooth function f(x) is said to have a local or relative maximum at a point c, if f (c) = 0 and f (x) changes from positive to negative for values of x near c. Similarly, a smooth function f(x) is said to have a local or relative minimum at a point c, if f (c) = 0 and f (x) changes from negative to positive for values of x near c. (13/41)

Body Temperature Fluctuation Maxima, Minima, and 4 Definition: If f(x) is a smooth function with f (x c ) = 0, then x c is said to be a critical point of f(x) Critical points help find the local high and low points on a graph Some critical points are neither maxima or minima (14/41)

Body Temperature Fluctuation Example Graphing a Polynomial 1 Graphing a Polynomial Consider f(x) = x 3 6x 2 15x+2 Find critical points, maxima, and minima Sketch a graph of the function (15/41)

Body Temperature Fluctuation Example Graphing a Polynomial 2 With the function f(x) = x 3 6x 2 15x+2 we have the derivative f (x) = 3x 2 12x 15 = 3(x+1)(x 5) The critical points (f (x) = 0) are x c = 1 or 5 Since f( 1) = 10, a local maximum occurs at ( 1,10) Since f(5) = 98, a local minimum occurs at (5, 98) The y-intercept is (0, 2) (16/41)

Body Temperature Fluctuation Example Graphing a Polynomial 3 This gives enough for a reasonable sketch of the graph Note the x-intercepts are very hard to find 20 f(x) = x 3 6x 2 15x + 2 ( 1,10) 0 20 y 40 60 80 (5, 98) 100 4 2 0 2 4 6 8 x (17/41)

Body Temperature Fluctuation Since the derivative is itself a function, then if it is differentiable, one can take its derivative to find the second derivative often denoted f (x) If the first derivative is increasing or the second derivative is positive, then the original function is concave upward If the first derivative is decreasing or the second derivative is negative, then the original function is concave downward The second derivative is a measure of the concavity of a function For smooth functions, the maxima generally occur where the function is concave downward, while minima occur where the function is concave upward (18/41)

Body Temperature Fluctuation : Let f(x) be a smooth function. Suppose that f (x c ) = 0, so x c is a critical point of f. If f (x c ) < 0, then x c is a relative maximum. If f (x c ) > 0, then x c is a relative minimum. If f (x c ) = 0, then we get no information about the function at the critical point x c (19/41)

Body Temperature Fluctuation Example Graphing a Polynomial 4 Continuing the example f(x) = x 3 6x 2 15x+2 The second derivative is f (x) = 6x 12 Recall the critical points occurred at x c = 1 and 5 The second derivative at the critical point x c = 1 gives f ( 1) = 18 The function is concave downward at 1, so this is a relative maximum The second derivative at the critical point x c = 5 gives f (5) = 18 The function is concave upward, so this is a relative minimum (20/41)

Body Temperature Fluctuation When the second derivative is zero, then the function is usually changing from concave upward to concave downward or visa versa This is known as a point of inflection A point of inflection is where the derivative function has a maximum or minimum, so the function is increasing or decreasing most rapidly From an applications point of view, if the function is describing a population, then the point of inflection would be where the population is increasing or decreasing most rapidly The point of inflection measures when the change of a function is its greatest or smallest (21/41)

Body Temperature Fluctuation Example Graphing a Polynomial 5 Continuing the example f(x) = x 3 6x 2 15x+2 The second derivative is f (x) = 6x 12 The point of inflection is f (x) = 0, which is when x = 2 The point of inflection occurs at (2, 44) (22/41)

Cubic Polynomial Quartic Polynomial Absolute Population Example Example Graphing a Cubic Polynomial 1 Graphing a Polynomial: Consider y(x) = 12x x 3 Find the intercepts Find critical points, maxima, and minima Find the points of inflection Sketch the graphs of the function, its derivative, and the second derivative Skip Example (23/41)

Cubic Polynomial Quartic Polynomial Absolute Population Example Example Graphing a Cubic Polynomial 2 The y-intercept for y(x) = 12x x 3 is (0,0) The x-intercepts satisfy x(12 x 2 ) = 0 x = 0,±2 3 (24/41)

Cubic Polynomial Quartic Polynomial Absolute Population Example Example Graphing a Cubic Polynomial 3 : The derivative of y(x) = 12x x 3 is y (x) = 12 3x 2 = 3(x 2 4) The critical points satisfy y (x c ) = 0, so x c = 2 and x c = 2 Evaluating the original function at the critical points y( 2) = 16 and y(2) = 16 The extrema for the function are ( 2, 16) and (2,16) Clearly, ( 2, 16) is a minimum and (2,16) is a maximum (25/41)

Cubic Polynomial Quartic Polynomial Absolute Population Example Example Graphing a Cubic Polynomial 4 Point of Inflection: The second derivative of y(x) = 12x x 3 is y (x) = 6x The second derivative test gives y ( 2) = 12 is concave upward, so x c = 2 is a minimum y (2) = 12 is concave downward, so x c = 2 is a maximum The Point of Inflection occurs at x p = 0 Concavity of the curve changes at (0,0) (26/41)

Cubic Polynomial Quartic Polynomial Absolute Population Example Example Graphing a Cubic Polynomial 5 Graphs of y(x), y (x), and y (x) Derivatives of f(x) = 12x x 3 40 30 20 f(x) f (x) f (x) 10 y 0 10 20 30 40 5 4 3 2 1 0 1 2 3 4 5 x (27/41)

Cubic Polynomial Quartic Polynomial Absolute Population Example Example Graphing a Quartic Polynomial 1 Graphing a Polynomial: Consider y(x) = x 4 8x 2 Find the intercepts Find critical points, maxima, and minima Find the points of inflection Sketch the graphs of the function, its derivative, and the second derivative Skip Example (28/41)

Cubic Polynomial Quartic Polynomial Absolute Population Example Example Graphing a Quartic Polynomial 2 The y-intercept for y(x) = x 4 8x 2 is (0,0) The x-intercepts satisfy x 2 (x 2 8) = 0 x = 0,±2 2 (29/41)

Cubic Polynomial Quartic Polynomial Absolute Population Example Example Graphing a Quartic Polynomial 3 : The derivative of y(x) = x 4 8x 2 is y (x) = 4x 3 16x = 4x(x 2)(x+2) The critical points satisfy y (x c ) = 0, so x c = 2, 0, 2 Evaluating the original function at the critical points y( 2) = 16, y(0) = 0, and y(2) = 16 The extrema for the function are ( 2, 16), (0,0), and (2, 16) Clearly, ( 2, 16) and (2, 16) are minima and (0,0) is a maximum (30/41)

Cubic Polynomial Quartic Polynomial Absolute Population Example Example Graphing a Quartic Polynomial 4 The second derivative of y(x) = x 4 8x 2 is y (x) = 12x 2 16 The second derivative test gives y ( 2) = 32 is concave upward, so x c = 2 is a minimum y (0) = 16 is concave downward, so x c = 0 is a maximum y (2) = 32 is concave upward, so x c = 2 is a minimum (31/41)

Cubic Polynomial Quartic Polynomial Absolute Population Example Example Graphing a Quartic Polynomial 5 : Since the second derivative of y(x) = x 4 8x 2 is y (x) = 12x 2 16 = 4(3x 2 4) The points of inflection occur when y (x) = 0 3x 2 p 4 = 0, when x p = ± 2 3 Inflection points are x p (±1.155, 8.889) (32/41)

Cubic Polynomial Quartic Polynomial Absolute Population Example Example Graphing a Quartic Polynomial 6 Graphs of y(x), y (x), and y (x) Derivatives of f(x) = x 4 8x 2 20 15 10 f(x) f (x) f (x) 5 y 0 5 10 15 20 3 2 1 0 1 2 3 x (33/41)

Cubic Polynomial Quartic Polynomial Absolute Population Example Absolute 1 Absolute : Often we are interested in finding the largest or smallest population over a period of time Definition: An absolute minimum for a function f(x) occurs at a point x = c, if f(c) f(x) for all x in the domain of f. Definition: Similarly, an absolute maximum for a function f(x) occurs at a point x = c, if f(c) f(x) for all x in the domain of f. (34/41)

Cubic Polynomial Quartic Polynomial Absolute Population Example Absolute 2 Smooth functions on a closed interval always have an absolute minimum and an absolute maximum Theorem: Suppose that f(x) is a continuous, differentiable function on a closed interval I = [a,b], then f(x) achieves its absolute minimum (or maximum) on I and its minimum (or maximum) occurs either at a point where f (x) = 0 or at one of the endpoints of the interval This theorem says to find the function values at all the critical points and the endpoints of the interval, then this small set of values contains the absolute minimum and absolute maximum (35/41)

Cubic Polynomial Quartic Polynomial Absolute Population Example Example Study of a Population 1 Study of a Population The ocean water is monitored for fecal contamination by counting certain types of bacteria in a sample of seawater Over a week where rain occurred early in the week, data were collected on one type of fecal bacteria The population of the particular bacteria (in thousand/cc), P(t), were best fit by the cubic polynomial where t is in days P(t) = t 3 +9t 2 15t+40, (36/41)

Cubic Polynomial Quartic Polynomial Absolute Population Example Example Study of a Population 2 Study of a Population Find the rate of change in population per day, dp/dt What is the rate of change in the population on the third day? Find relative and absolute minimum and maximum populations of the bacteria over the time of the surveys Determine when the bacterial count is most rapidly increasing Sketch a graph of this polynomial fit to the population of bacteria When did the rain most likely occur? (37/41)

Cubic Polynomial Quartic Polynomial Absolute Population Example Example Study of a Population 3 Rate of Change in Population: The derivative of P(t) = t 3 +9t 2 15t+40 is Evaluating this on the third day dp dt = 3t2 +18t 15 dp(3) dt = 12( 1000/cc/day) (38/41)

Cubic Polynomial Quartic Polynomial Absolute Population Example Example Study of a Population 4 : We found dp dt = 3t2 +18t 15 = 3(t 1)(t 5) The critical points are t c = 1 and t c = 5 Relative Minimum at t c = 1 with P(1) = 33( 1000/cc) Relative Maximum at t c = 5 with P(5) = 65( 1000/cc) The endpoint values are P(0) = 40 and P(7) = 33 By the theorem above The absolute maximum occurs at t = 5 with P(5) = 65 The absolute minimum occurs at t = 1 and 7 with P(1) = P(7) = 33 (39/41)

Cubic Polynomial Quartic Polynomial Absolute Population Example Example Study of a Population 5 Point of Inflection: The bacteria is increasing most rapidly when the second derivative is zero Since P (t) = 3t 2 +18t 15, the second derivative is P (t) = 6t+18 = 6(t 3) The population is increasing most rapidly at t = 3 with P(3) = 49( 1000/cc) This maximum increase is P (3) = 12( 1000/cc/day) (40/41)

Cubic Polynomial Quartic Polynomial Absolute Population Example Example Study of a Population 6 Graph of P(t) = t 3 +9t 2 15t+40, From the graph, we can guess that the rain fell on the second day of the week with storm runoff polluting the water in the days following 70 60 Population of Bacteria P(t) (x1000/cc) 50 40 30 20 10 0 0 1 2 3 4 5 6 7 t (days) (41/41)