Chapter Finite Difference Method for Ordinary Differential Equations

Similar documents
Chapter Finite Difference Method for Ordinary Differential Equations

Pressure Vessels Thin and Thick-Walled Stress Analysis

Interaction of Lamb Waves with Geometric Discontinuities: An Analytical Approach Compared with FEM

MEEN 617 Handout #11 MODAL ANALYSIS OF MDOF Systems with VISCOUS DAMPING

ME 3560 Fluid Mechanics

Convective Heat Transfer (6) Forced Convection (8) Martin Andersson

Sections 3.1 and 3.4 Exponential Functions (Growth and Decay)

Orthotropic Materials

Lecture 18: Kinetics of Phase Growth in a Two-component System: general kinetics analysis based on the dilute-solution approximation

MECHANICS OF MATERIALS Poisson s Ratio

STUDY OF THE STRESS-STRENGTH RELIABILITY AMONG THE PARAMETERS OF GENERALIZED INVERSE WEIBULL DISTRIBUTION

Convective Heat Transfer (6) Forced Convection (8) Martin Andersson

, on the power of the transmitter P t fed to it, and on the distance R between the antenna and the observation point as. r r t

Today - Lecture 13. Today s lecture continue with rotations, torque, Note that chapters 11, 12, 13 all involve rotations

Chapter 7. Interference

KINEMATICS OF RIGID BODIES

Propagation of Torsional Surface Waves. in Heterogeneous Half-Space. with Irregular Free Surface

Lecture 22 Electromagnetic Waves

7 Wave Equation in Higher Dimensions

General Non-Arbitrage Model. I. Partial Differential Equation for Pricing A. Traded Underlying Security

DESIGN OF TENSION MEMBERS

08.06 Shooting Method for Ordinary Differential Equations

Overview. Overview Page 1 of 8

Dispersive Systems. 1) Schrödinger equation 2) Cubic Schrödinger 3) KdV 4) Discreterised hyperbolic equation 5) Discrete systems.

Scalar Conservation Laws


Lecture-V Stochastic Processes and the Basic Term-Structure Equation 1 Stochastic Processes Any variable whose value changes over time in an uncertain

Integration of the constitutive equation

The sudden release of a large amount of energy E into a background fluid of density

FINITE DIFFERENCE APPROACH TO WAVE GUIDE MODES COMPUTATION

ÖRNEK 1: THE LINEAR IMPULSE-MOMENTUM RELATION Calculate the linear momentum of a particle of mass m=10 kg which has a. kg m s

( ) exp i ω b ( ) [ III-1 ] exp( i ω ab. exp( i ω ba

8.5 Circles and Lengths of Segments

Suppose we have observed values t 1, t 2, t n of a random variable T.

where the coordinate X (t) describes the system motion. X has its origin at the system static equilibrium position (SEP).

Elastic-Plastic Deformation of a Rotating Solid Disk of Exponentially Varying Thickness and Exponentially Varying Density

Lecture 17: Kinetics of Phase Growth in a Two-component System:

Modelling Traffic Flow with Constant Speed using the Galerkin Finite Element Method

AN EVOLUTIONARY APPROACH FOR SOLVING DIFFERENTIAL EQUATIONS

A Mathematical model to Solve Reaction Diffusion Equation using Differential Transformation Method

Coupled Mass Transport and Reaction in LPCVD Reactors

ROTOR SUPPORTED. J. Tůma, J. Škuta, R. Klečka VSB Technical University of Ostrava J. Šimek TECHLAB Praha

Combined Bending with Induced or Applied Torsion of FRP I-Section Beams

Control Volume Derivation

236 CHAPTER 3 Torsion. Strain Energy in Torsion

Reinforcement learning

A Direct Method for Solving Nonlinear PDEs and. New Exact Solutions for Some Examples

Stress Analysis of Infinite Plate with Elliptical Hole

( ) ( ) Weibull Distribution: k ti. u u. Suppose t 1, t 2, t n are times to failure of a group of n mechanisms. The likelihood function is

Program: RFEM 5, RSTAB 8, RF-DYNAM Pro, DYNAM Pro. Category: Isotropic Linear Elasticity, Dynamics, Member

ME 391 Mechanical Engineering Analysis

Computer Propagation Analysis Tools

CSE 5365 Computer Graphics. Take Home Test #1

156 There are 9 books stacked on a shelf. The thickness of each book is either 1 inch or 2

On Control Problem Described by Infinite System of First-Order Differential Equations

Exponential and Logarithmic Equations and Properties of Logarithms. Properties. Properties. log. Exponential. Logarithmic.

Structural Dynamics and Earthquake Engineering

Millennium Theory Equations Original Copyright 2002 Joseph A. Rybczyk Updated Copyright 2003 Joseph A. Rybczyk Updated March 16, 2006

Combinatorial Approach to M/M/1 Queues. Using Hypergeometric Functions

On The Estimation of Two Missing Values in Randomized Complete Block Designs

[ ] 0. = (2) = a q dimensional vector of observable instrumental variables that are in the information set m constituents of u

ENGI 4430 Advanced Calculus for Engineering Faculty of Engineering and Applied Science Problem Set 9 Solutions [Theorems of Gauss and Stokes]

EN221 - Fall HW # 7 Solutions

Method of Moment Area Equations

Circular Motion. Radians. One revolution is equivalent to which is also equivalent to 2π radians. Therefore we can.

At the end of this lesson, the students should be able to understand

Q & Particle-Gas Multiphase Flow. Particle-Gas Interaction. Particle-Particle Interaction. Two-way coupling fluid particle. Mass. Momentum.

Hybrid Musical Instruments: Artistically Inspired, Mathematically Explored

dt = C exp (3 ln t 4 ). t 4 W = C exp ( ln(4 t) 3) = C(4 t) 3.

The shortest path between two truths in the real domain passes through the complex domain. J. Hadamard

CSE-4303/CSE-5365 Computer Graphics Fall 1996 Take home Test

Ordinary Differential Equations

IMPROVED DESIGN EQUATIONS FOR ASYMMETRIC COPLANAR STRIP FOLDED DIPOLES ON A DIELECTRIC SLAB

r r r r r EE334 Electromagnetic Theory I Todd Kaiser

Representing Knowledge. CS 188: Artificial Intelligence Fall Properties of BNs. Independence? Reachability (the Bayes Ball) Example

ME 304 FLUID MECHANICS II

Shooting Method for Ordinary Differential Equations Autar Kaw

Lecture 5. Chapter 3. Electromagnetic Theory, Photons, and Light

Chapter 12: Kinematics of a Particle 12.8 CURVILINEAR MOTION: CYLINDRICAL COMPONENTS. u of the polar coordinate system are also shown in

Computers and Mathematics with Applications

Anomalous transport regimes and asymptotic concentration distributions in the presence of advection and diffusion on a comb structure

Molecular Evolution and Phylogeny. Based on: Durbin et al Chapter 8

NUMERICAL SIMULATION FOR NONLINEAR STATIC & DYNAMIC STRUCTURAL ANALYSIS

Earthquake, Volcano and Tsunami

r P + '% 2 r v(r) End pressures P 1 (high) and P 2 (low) P 1 , which must be independent of z, so # dz dz = P 2 " P 1 = " #P L L,

The Production of Polarization

e 2t u(t) e 2t u(t) =?

KINGS UNIT- I LAPLACE TRANSFORMS

Servomechanism Design

International Journal of Mathematical Archive-5(6), 2014, Available online through ISSN

Influence of Velocity Slip on the Peristaltic Pumping of a Jeffrey Fluid in a Non Uniform Annulus

Spring Ammar Abu-Hudrouss Islamic University Gaza

Risk tolerance and optimal portfolio choice

Lecture 10: Wave equation, solution by spherical means

M E FLUID MECHANICS II

, u denotes uxt (,) and u. mean first partial derivatives of u with respect to x and t, respectively. Equation (1.1) can be simply written as

PHYS PRACTICE EXAM 2

ECSE Partial fraction expansion (m<n) 3 types of poles Simple Real poles Real Equal poles

Module 2 F c i k c s la l w a s o s f dif di fusi s o i n

Heat Conduction Problem in a Thick Circular Plate and its Thermal Stresses due to Ramp Type Heating

Transcription:

Chape 8.7 Finie Diffeence Mehod fo Odinay Diffeenial Eqaions Afe eading his chape, yo shold be able o. Undesand wha he finie diffeence mehod is and how o se i o solve poblems. Wha is he finie diffeence mehod? The finie diffeence mehod is sed o solve odinay diffeenial eqaions ha have condiions imposed on he bonday ahe han a he iniial poin. These poblems ae called bonday-vale poblems. In his chape, we solve second-ode odinay diffeenial eqaions of he fom d y f (, y, y' ), a b, () d wih bonday condiions y( a) y a and y( b) yb () Many academics efe o bonday vale poblems as posiion-dependen and iniial vale poblems as ime-dependen. Tha is no necessaily he case as illsaed by he following eamples. The diffeenial eqaion ha govens he deflecion y of a simply sppoed beam nde nifomly disibed load (Fige ) is given by d y q( L ) () d EI whee locaion along he beam (in) E Yong s modls of elasiciy of he beam (psi) I second momen of aea (in ) q nifom loading inensiy (lb/in) L lengh of beam (in) The condiions imposed o solve he diffeenial eqaion ae y ( ) () y ( L) Clealy, hese ae bonday vales and hence he poblem is consideed a bonday-vale poblem. 8.7.

8.7. Chape 8.7 y q L Fige Simply sppoed beam wih nifom disibed load. Now conside he case of a canileveed beam wih a nifomly disibed load (Fige ). The diffeenial eqaion ha govens he deflecion y of he beam is given by d y q( L ) () d EI whee locaion along he beam (in) E Yong s modls of elasiciy of he beam (psi) I second momen of aea (in ) q nifom loading inensiy (lb/in) L lengh of beam (in) The condiions imposed o solve he diffeenial eqaion ae y ( ) (6) dy ( ) d Clealy, hese ae iniial vales and hence he poblem needs o be consideed as an iniial vale poblem. y q L Fige Canileveed beam wih a nifomly disibed load.

Finie Diffeence Mehod 8.7. Eample The deflecion y in a simply sppoed beam wih a nifom load q and a ensile aial load T is given by d y Ty q( L ) (E.) d EI EI whee locaion along he beam (in) T ension applied (lbs) E Yong s modls of elasiciy of he beam (psi) I second momen of aea (in ) q nifom loading inensiy (lb/in) L lengh of beam (in) y q T T L Fige Simply sppoed beam fo Eample. Given, T 7 lbs, q lbs/in, L 7 in, E Msi, and I in, a) Find he deflecion of he beam a ". Use a sep size of " and appoimae he deivaives by cenal divided diffeence appoimaion. b) Find he elaive e eo in he calclaion of y (). Solion a) Sbsiing he given vales, d y 7y () (7 ) 6 6 d ( )() ( )() d y 6 7 y 7. (7 ) (E.) d d y Appoimaing he deivaive a node i by he cenal divided diffeence d appoimaion,

8.7. Chape 8.7 i i i Fige Illsaion of finie diffeence nodes sing cenal divided diffeence mehod. d y y y y d ( ) We can ewie he eqaion as yi yi yi 6 7 y 7. (7 ) i i i ( ) Since, we have nodes as given in Fige i i i (E.) i i i i (E.) 7 Fige Finie diffeence mehod fom o 7 wih. The locaion of he nodes hen is 7 Wiing he eqaion a each node, we ge Node : Fom he simply sppoed bonday condiion a, we obain y (E.) Node : Rewiing eqaion (E.) fo node gives y y y 6 7 y 7. (7 ) () 7.6y.y.6y 7. ()(7 ).6y.y.6y 9.7 (E.6) Node : Rewiing eqaion (E.) fo node gives y y y 6 7 y 7. (7 ) () 7.6y.y.6y 7. ()(7 ).6y.y.6y 9.7 (E.7) Node : Fom he simply sppoed bonday condiion a 7, we obain y (E.8)

Finie Diffeence Mehod 8.7. Eqaions (E.-E.8) ae simlaneos eqaions wih nknowns and can be wien in mai fom as y.6..6 y 9.7.6..6 y 9.7 y The above eqaions have a coefficien mai ha is idiagonal (we can se Thomas algoihm o solve he eqaions) and is also sicly diagonally dominan (convegence is gaaneed if we se ieaive mehods sch as he Gass-Siedel mehod). Solving he eqaions we ge, y y.8 y.8 y y ) y( ) y.8" ( The eac solion of he odinay diffeenial eqaion is deived as follows. The homogeneos pa of he solion is given by solving he chaaceisic eqaion 6 m m. Theefoe,.. yh Ke K e The paicla pa of he solion is given by y p A B C Sbsiing he diffeenial eqaion (E.) gives d y p 6 7 y 7. (7 ) p d d 6 7 ( A B C) ( A B C) 7. (7 ) d 6 7 A ( A B C) 7. (7 ) 6 6 6 7 A B (A C).6 7. Eqaing ems gives 6 7 A 7. 6 B.6 6 A C Solving he above eqaion gives A.7 B 8. C.7

8.7.6 Chape 8.7 The paicla solion hen is y p.7 8..7 The complee solion is hen given by.. y.7 8..7 Ke K e Applying he following bonday condiions y ( ) y ( 7) we obain he following sysem of eqaions K K.7.9K.8997K.7 These eqaions ae epesened in mai fom by K.7.9.8997K.7 A nmbe of diffeen nmeical mehods may be ilized o solve his sysem of eqaions sch as he Gassian eliminaion. Using any of hese mehods yields K.77666 K.9777 Sbsiing hese vales back ino he eqaion gives.. y.7 8..7.776666 e.9777 e Unlike ohe eamples in his chape and in he book, he above epession fo he deflecion of he beam is displayed wih a lage nmbe of significan digis. This is done o minimize he ond-off eo becase he above epession involves sbacion of lage nmbes ha ae close o each ohe. b) To calclae he elaive e eo, we ms fis calclae he vale of he eac solion a y.. () y( ).7() 8.().7.776666 e. ().9777 e y ( ). The e eo is given by E = Eac Vale Appoimae Vale E. (.8) E. The elaive e eo is given by Te Eo % Te Vale. %. %

Finie Diffeence Mehod 8.7.7 Eample Take he case of a pesse vessel ha is being esed in he laboaoy o check is abiliy o wihsand pesse. Fo a hick pesse vessel of inne adis a and oe adis b, he diffeenial eqaion fo he adial displacemen of a poin along he hickness is given by d d (E.) d d The inne adis a and he oe adis b 8, and he maeial of he pesse vessel is ASTM A6 seel. The yield sengh of his ype of seel is 6 ksi. Two sain gages ha ae bonded angenially a he inne and he oe adis mease nomal angenial sain as.776 / a / b.86 (E.a,b) a he maimm needed pesse. Since he adial displacemen and angenial sain ae elaed simply by, (E.) hen.776.87' ' a b.86 8.769' ' The maimm nomal sess in he pesse vessel is a he inne adis E d ma a d a whee E Yong s modls of seel (E= Msi) Poisson s aio (.) The faco of safey, FS is given by Yield sengh of seel ma a and is given by (E.7) FS (E.8) a) Divide he adial hickness of he pesse vessel ino 6 eqidisan nodes, and find he adial displacemen pofile b) Find he maimm nomal sess and faco of safey as given by eqaion (E.8) c) Find he eac vale of he maimm nomal sess as given by eqaion (E.8) if i is given ha he eac epession fo adial displacemen is of he fom C C. Calclae he elaive e eo.

8.7.8 Chape 8.7 Solion a i b i- i+ n a i- i i+ b Fige Nodes along he adial diecion. a) The adial locaions fom a o b ae divided ino n eqally spaced segmens, and hence esling in n nodes. This will allow s o find he dependen vaiable nmeically a hese nodes. A node i along he adial hickness of he pesse vessel, d i i i (E.9) d d i i (E.) d Sch sbsiions will conve he odinay diffeenial eqaion ino a linea eqaion (b wih moe han one nknown). By wiing he esling linea eqaion a diffeen poins a which he odinay diffeenial eqaion is valid, we ge simlaneos linea eqaions ha can be solved by sing echniqes sch as Gassian eliminaion, he Gass-Siedel mehod, ec. Sbsiing hese appoimaions fom Eqaions (E.9) and (E.) in Eqaion (E.) i i i i i i (E.) i i i i i (E.) i i i Le s beak he hickness, b a, of he pesse vessel ino n nodes, ha is a is node i and b is node i n. Tha means we have n nknowns. We can wie he above eqaion fo nodes,..., n. This will give s n eqaions. A he edge nodes, i and i n, we se he bonday condiions of

Finie Diffeence Mehod 8.7.9 a n b This gives a oal of n eqaions. So we have n nknowns and n linea eqaions. These can be solved by any of he nmeical mehods sed fo solving simlaneos linea eqaions. We have been asked o do he calclaions fo n, ha is a oal of 6 nodes. This gives b a n 8.6 " A node i, a ",.87" (E.) A node i,.6.6" (E.).6.6.6.6.6.6.6.6.7778.88.7 (E.) A node, A node, A node, A node,.6.6 i 6.".6.6 6..6 6..6 6..6.7778.8.66 (E.6) 6..6 i 6.8".6.6 6.8.6 6.8.6 6.8.6.7778.8.9 (E.7) 6.8.6 i 7..6.6 7..6 7..6 7..6.7778.799. (E.8) i 7..6 8.769 (E.9) b Wiing Eqaion (E.) o (E.9) in mai fom gives

8.7. Chape 8.7.7778.88.7778.7.8.7778.66.8.7778.9.799.87 =..769 The above eqaions ae a i-diagonal sysem of eqaions and special algoihms sch as Thomas algoihm can be sed o solve sch a sysem of eqaions..87.66..7.68.769 b) To find he maimm sess, i is given by Eqaion (E.7) as E d ma a d a 6 E psi..87 a d a d.66.87.6.767 The maimm sess in he pesse vessel hen is 6.87 ma.. 767..7 psi So he faco of safey FS fom Eqaion (E.8) is 6 FS.6896.7 c) The diffeenial eqaion has an eac solion and is given by he fom C C (E.) whee C and C ae fond by sing he bonday condiions a a and b.

Finie Diffeence Mehod 8.7. C ( a) ( ).87 C() C ( b) ( 8).769 C(8) 8 giving C.6 C. 6 Ths.6.6 (E.) d.6.6 (E.) d E d ma a d a.6 6.6.6..6..8 psi The e eo is E.8.7 7.689 The absole elaive e eo is.8.7.8.7% Eample The appoimaion in Eample d i i d is fis ode accae, ha is, he e eo is of O( ). The appoimaion d i i i (E.) d is second ode accae, ha is, he e eo is O Miing hese wo appoimaions will esl in he ode of accacy of O and O, ha is O. So i is bee o appoimae

8.7. Chape 8.7 d d i i (E.) becase his eqaion is second ode accae. Repea Eample wih he moe accae appoimaions. Solion a) Repeaing he poblem wih his appoimaion, a node i in he pesse vessel, d i i i d ( ) d i i d Sbsiing Eqaions (E.) and (E.) in Eqaion (E.) gives i i i i i i i i i i i i i A node i, a " i (E.) (E.) (E.).87" (E.6) A node i,.6.6" A node,.6.6.6.6.6.6.6.6.697.87.966 (E.7).6.6 6. i ".6 A node, (E.8).86.9 6..6.6.6 6..6 6..6 6..6 i 6. 8".6 A node, (E.9).77.9 6.8.6.6.6 6.8.6 6.8.6 6.8.6 i 7. ".66 A node, (E.) 7..78.89 7..6.6.6.6 7..6 i 7..6 8" / b.769 " (E.) Wiing Eqaions (E.6) h (E.) in mai fom gives

Finie Diffeence Mehod 8.7..697.87.6.966.86.6.9.77.66.9.78.87 =.89.769 The above eqaions ae a i-diagonal sysem of eqaions and special algoihms sch as Thomas algoihm can be sed o solve sch eqaions..87".6".9 ".689".86 ".769 " d b) d a.87.6.9 (.6).9 6.87 ma..9..666 psi Theefoe, he faco of safey FS is 6 FS.666.7 c) The e eo in calclaing he maimm sess is E.8.666 8 psi The elaive e eo in calclaing he maimm sess is 8.8.6% Table Compaisons of adial displacemens fom wo mehods. eac s ode nd ode

8.7. Chape 8.7.87.87..87..6.6.66.6.6. 6....6.9.876 6.8.68.7.87.689.6 7..8.68.9.86 9.66 8.769.769..769. ORDINARY DIFFERENTIAL EQUATIONS Topic Finie Diffeence Mehods of Solving Odinay Diffeenial Eqaions Smmay Tebook noes of Finie Diffeence Mehods of solving odinay diffeenial eqaions Majo Geneal Engineeing Ahos Aa Kaw, Cong Ngyen, Lke Snyde Dae Decembe, 9 Web Sie hp://nmeicalmehods.eng.sf.ed