The effect of residual kinetic energy on apparent ion temperature in ICF implosions. T. J. Murphy

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LA-UR-15-27714 The effect of residual kinetic energy on apparent ion temperature in ICF implosions T. J. Murphy National ICF Diagnostics Working Group Meeting October 6-8, 2015

Outline Basic kinetics of fusion reactions Ion temperature effects on neutron spectrum energy width Effects of fluid velocity on neutron spectrum Directed motion Expanding or contracting spherical shells Random distribution of energies Comparison with past experiments DD vs DT temperatures Model for residual kinetic energy Slide 2

Main points The energy distribution of fusion neutron is determined by the velocity of the center-of-mass of the reacting particles Fluid motion a fraction of the thermal velocity can lead to substantial broadening of the neutron distribution This broadening affects the DT and DD neutrons differently Energy going into fluid motion has several times the effect of thermal energy at broadening the spectrum Slide 3

Fusion product energies are determined by kinetics of the reaction D n In the center of mass frame, conservation of energy and momentum results in a narrow neutron energy spread. α T E ' n = m a m a + m n ( Q + K) Q comes from the smaller mass of the alpha and n than for the two hydrogen isotopes. [Q = ( m d + m t m α m n )c 2 ] K is the kinetic energy of the reacting particles and is determined from the overlap of the cross section with the distribution of relative velocities between the reacting species. The distribution of values of K contributes a minimal amount to the neutron energy distribution. Slide 4

Some spread comes from the width of the Gamow peak, but not much For a Maxwellian plasma, the ion energy falls as exp(-e/kt) The fusion cross section rises rapidly with energy The Gamow peak is the product, showing the peak value of K and the spread Distribution Function exp(-e/kt) 1.0 0.8 0.6 0.4 0.2 0.0 0 1.0 10 1 kev 3 kev 10 kev D+T->n+α Cross Section 20 30 Energy (kev) 40 4 3 2 1 0 50 Cross Section (barns) For DT FWHM of K Neutron portion 1 kev 4.7 kev 3.8 kev 3 kev 11.9 kev 9.5 kev 10 kev 31.8 kev 25.4 kev Gamov Peak (normalized) 0.8 0.6 0.4 0.2 0.0 0 10 20 30 Energy (kev) 40 1 kev 3 kev 10 kev 50 Slide 5

Motion of the center-of-mass changes the neutron energy in the lab frame v n n θ v cm E n = 1 2 m n ( v n + v cm ) 2 v' n = 1 2 m ( n v 2 2 n + 2v n v cm cosθ + v ) cm = 1 ' 2 m v 2 n n 1+ 2 v! cm cosθ + v $ ) cm # & () v n " v n % 2 *, +, So the change in the neutron energy due to the center-of-mass motion is: ΔE n E n # $ & % 2 v cm v n ' cosθ ) ( = m n v# n v cm cosθ ΔE n is proportional to v cm (NOT v cm2 ) Slide 6

Two Maxwellians can be expressed in terms of relative and center-of-mass velocities For Maxwellians of a given temperature: # f D exp m v 2 & D D % ( $ 2kT ' # f T exp m 2 Tv T & % ( $ 2kT ' Thus, two Maxwellians have a center-ofmass distribution with a width: σ V = kt M The product is given by: # f D f T exp m v 2 2 D D + m T v T & % ( $ 2kT ' # exp µv2 + MV 2 & % ( $ 2kT ' Where: µ = m D m T m D + m T M = m D + m T v = v D v T V = m Dv D + m T v T m D + m T ( ) " exp MV 2 % " $ ' = exp M V 2 x +V 2 2 y +V z # 2kT & $ # 2kT % ' & Slide 7

From the width of the center-of-mass distribution, the neutron width can be found ΔE n = E n " # % $ 2 v cm v n & cosθ ( ' = m n v" n v cm cosθ σ V = kt M Setting using v cm,z = v cm cos θ, and the width of the distribution of v cm,z, σ v,z =kt/m, gives: " 2 σ n = E n! $ # v! n kt M % ' & Since:! We get: v n = 2 E! n m n σ n = 2m nkt E n! M See, for example, H. Brysk, Plasma Phys. 15, 611 (1973). Slide 8

The spreading due to the center-of-mass is the dominant contribution Ion Temperature (kev) Gamow Peak FWHM (kev) Brysk FWHM (kev) 1 3.8 177 3 9.5 306 10 25.4 559 Slide 9

From the measured neutron width, an ion temperature is inferred σ tof = dt σ n From the previous slide: de n σ n = 2m nkt E n! t = d m = d n M v n 2E n Thus: kt = M σ 2 n 2m n E n! σ n is often measured using the time-offlight broadening of the neutron signal. dt de n = d 2 σ tof = d m n 2E n! FWHM tof = # " m n 2E n 3 2 ln2 M kt M m n E n $ &d % kt See, for example, Murphy, Chrien, and Klare, RSI 68, 610 (1997). Slide 10

Collective motion of the source leads to upshift in one direction, down shift in the other Our previous expression, which was used for the center of mass velocity of two particles, can be applied to the plasma as a whole: ΔE n = E n " # % $ 2 v cm v n & cosθ ( ' = m n v" n v cm cosθ M Gatu-Johnson et al report measurements of this effect on NIF shots using the MRS. Cryo-layered implosions PDD Exploding pushers M. Gatu-Johnson et al, Phys Plasmas 20, 042707 (2013). Slide 11

Now consider an ensemble of fluid elements with a Gaussian distribution of velocities Why Gaussian? Continuous distribution of velocities Characterized by a single number Simplifies the math Using: # ΔE n = E n " 2 v & f,z % ( $ ' v n σ n, f = m n v" n σ v, f = 2m n E n " σ v, f Convolving the contributions of thermal CM and fluid CM, we can show: σ n 2 = σ 2 n,th +σ 2 n, f = 2m n E! kt M + 2m n E n! σ 2 v, f = 2m n E! " kt M +σ % $ 2 v, f ' # & Slide 12

Interpreting the measured neutron width as due entirely to ion temperature over estimates T i Using the relationship: kt = We can show: M σ 2 n 2m n E n! Thus, a Gaussian fluid velocity increases the apparent ion temperature an amount proportional to the sum of the masses of the reactants. M # kt app = 2m n E! % kt 2m n E n! M +σ 2 v, f $ = kt + Mσ 2 v, f & ( ' σ v, f = kt app kt M Slide 13

How much energy is contained in the fluid velocity? Thermal energy? The kinetic energy can be calculated: E k = V 1 ρv 2 f k 2 ( v)d 3 v Using a Gaussian distribution: f k ( v ) f = 1 ( 2 2πσ ) v 3/2 f v 2 e v f 2 /2σ v 2 The thermal energy is given by: E th = V 3 ( 2 n i + n e )kt For hydrogenic species, n i =n e, so: E th = 3kT ρvn A A Which integrates to: E k = 3 2 ρσ 2 vv Slide 14

The fraction of energy in fluid velocity affects the apparent ion temperature " σ 2 n = 2m n E! kt M +σ % $ 2 v, f ' # & = 2m n E! v 2 n = m2! n ρv " $ # E th 3M A ( A * )* 3 A 1 + A 2 ρvn A + 2 3 E k ρv ( ) E th + 2 3 E k = m2v! 2 n n ρv E ( A tot * )* 3 A 1 + A 2 % ' & + -,- ( ( ) 1 f rke) + 2 3 f rke Note: The factor in front of E k is 2/3 + -,- The factor in front of E th is: 2.5/[3(5)] for DT 2.5/[3(4)] for DD Factor of 4.0 for DT Factor of 3.2 for DD Energy into kinetic energy is 3.2 to 4.0 times as important in spreading the neutron energy than is thermal energy. Slide 15

Increased kinetic energy fraction raises apparent ion temperature while lowering actual ion temperature 10 kj into 50 µm radius plasma at 50 g/cm 3 Slide 16

Conclusions: Stagnation in ICF implosions is often incomplete Ion temperature determination from neutron spectra usually assumes a stationary plasma Residual motion can significantly affect the inference of an ion temperature Comparison of DD and DT ion temperatures in DT plasmas can provide a measure of the fluid velocities Slide 17

Slide 18

Imploding/exploding shell of fusing material A uniformly expanding or contracting shell of fusing material will have a single velocity, but all directions. In this case, cos θ is uniformly distributed between -1 and 1, so based on the expression: ΔE n = E n " # % $ 2 v cm v n & cosθ ( ' ΔE n is uniformly distributed between E n " # % $ 2 v cm v n & # ( < ΔE n < E n " 2 v cm % ' $ v n & ( ' If the shell has a finite temperature, then the neutron energy distribution is a convolution of the Gaussian with the square function described above. Slide 19

Gas bag targets In the early 1990 s, LLNL and LANL performed long scale length plasma experiments to understand LPI effects relevant to NIF. A subset of these were filled with deuterated hydrocarbon gas. Neutron spectra had a broad component not seen in spectra from implosions. aluminum washer fill tubes polyimide skin /.75mm GXI imaging Streaked imaging J '... 4.50 mm..."--""'---h\: --""----*-... 2.50 mm carbon fibers Kalantar et al, Phys Plasmas 2, 3161 (1995). Slide 20

Gas bag neutron spectra could be fit with a temperature and an expansion velocity The convolution of a Gaussian and a square function can be written: f(e) = apple 1 E E 0 erf n + m n v n v p f 4m n vnv 0 f 2 0 apple p 0 E E 0 erf n m n v n v p f 2 Intensity (arb. units) 1 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 Appelbe and Chittenden provide a formal, accurate derivation of this distribution. v f = 0 v f = 3 x 10 5 m s 1 v f = 6 x 10 5 m s 1 T i = 0.5 kev 0.1 This provided a good fit to GASBAG spectra: 0.75 kev, 7.8 10 7 cm/s expansion. 0 2.2 2.25 2.3 2.35 2.4 2.45 2.5 2.55 2.6 2.65 2.7 2.75 x 10 6 E n (ev) Appelbe and Chittenden, Plasma Phys Control. Fusion 53, 045002 (2011). Slide 21

Expansion/contraction can greatly affect the apparent ion temperature Chrien s CD shell implosions match the simulated neutron yield, but apparent T ion is off by a factor of three. Summed spectra from all deuterated GASBAG targets: Gaussian fit gives 3.5 kev Shell fit gives 1.6 kev, 8.1 10 7 cm/s Murphy, Chrien, and Klare, RSI 68, 614 (1997); Chrien et al, Phys Plasmas 5, 768 (1998). Slide 22

Examples: Landen Ge-doped, highconvergence Nova implosions O. L. Landen, et al [Phys. Plasmas 3, 2094 (1996)] reported: Temperatures 30% greater than calculated for indirectly driven capsule experiments performed on the Nova laser Simulated yield was 3 4 times the observed yield. Attribute the effects to a smaller emitting core than calculated with less burn in the cooler regions outside the core so that the burn-averaged ion temperature is higher than calculated. Slide 23

Examples: Chrien CD shell implosions Chrien et al imploded H-filled CD shells with varying surface roughness. Yield agreed with simulations; T i did not. Assuming simulated T i (0.6 kev) is correct and measured T i (1.4 kev) is affected by motion, σ v, f = kt app kt M Gives a velocity of 1.4 10 7 cm/s. R. E. Chrien, N. M. Hoffman, J. D. Colvin, C. J. Keane, O. L. Landen, and B. A. Hammel, Phys. Plasmas 5, 768 (1998). Slide 24

Examples: Rigg implosions with 3 He 10 1 Rigg et al imploded capsules with deuterium and 3 He fill. They measured the yield of D(d,n) 3 He and 3 He(d,p) 4 He. The ratio of the rates of these reactions is temperature dependent. Temperature from neutron spectroscopy exceeded that from yield ratios by 0.7 to 1.7 kev. Using σ v, f = kt app kt M Gives a velocity of 1.7 ± 0.4 10 7 cm/s. J. R. Rygg, J. A. Frenje, C. K. Li, F. H. Seguin, R. D. Petrasso, J. A. Delettrez, V. Y. Glebov, V. N. Goncharov, D. D. Meyerhofer, S. P. Regan, T. C. Sangster, and C. Stoeckl, Phys. Plasmas 13, 052702 (2006). D 3 He/DD reaction rate ratio 10 0 10-1 10-2 10-3 10-4 10-5 10-6 10-7 10-8 10-9 10-10 0.1 2 4 6 2 4 6 2 4 1 10 6 100 Temperature (kev) Slide 25

Examples: Cyro-layered implosions on NIF Jones et al describe detailed modeling of cryogenic layered experiments on NIF. Simulations gave 3.4 kev expected ion temperature Measurements gave 4.43 kev. Assuming the simulation is correct, using: σ v, f = kt app kt M Gives a velocity of 1.4 10 7 cm/s. O. S. Jones et al, Phys. Plasmas 19, 056315 (2012). Slide 26

Examples: High-foot shots on NIF O. A. Hurricane et al report both DD and DT ion temperatures in their Nature paper. The ratio of T idt to T idd is 1.16 for one shot and 1.23 for a second. 1.23 is near the value (1.25) when fluid velocity dominates the width. Park et al report DT ion temperatures that exceed simulated by 1.25±0.16 kev (4.2 vs 2.95), and DD ion temperatures that exceed simulated by 0.9±0.2 kev (3.7 vs 2.8). σ v, f = kt Gives a velocity of app kt Using DT: 1.55 ± 0.10 10 7 cm/s M DD: 1.46 ± 0.16 10 7 cm/s Thus, a single velocity of ~1.5 10 7 cm/s brings the temperatures into agreement with each other and with simulations. Shell velocity was 3.12 10 7 cm/s O. A. Hurricane et al, Nature 506, 0343 (2014). H.-S. Park et al, Phys. Rev. Lett. 112, 055001 (2014). Slide 27

Things not considered but possibly relevant Kinetic effects Separation of D and T, increasing one relative to the other in hotter regions Long mean free paths relative to ion temperature gradient, hot ions escaping into cold plasma resulting in net outward motion Different temperatures for D and T Inaccuracies in the response function of current-mode neutron detectors Slide 28

LLNL believes that they see apparent ion temperature anisotropies Different apparent ion temperatures are seen on different detectors at different locations Temperatures ranged from, for example, 2 to 4 kev on a single shot They believe that this may be an indication of anisotropic fluid motion in the burning plasma Working to develop models to determine fluid motions from observed ion temperatures Limited to low-mode by the analysis techniques Limited views prevent detailed analysis Slide 29

Can experiments be performed to test this? Perform implosions with ~1% T and ~1% 3 He in deuterium Use yield ratios of D 3 He to DD to get actual ion temperatures Compare DD and DT apparent ion temperatures to obtain fluid motion, and therefore corrected ntof ion temperatures Vary the fluid motion through: Drive asymmetry [Thomas & Kares, PRL 109, 075004 (2012)] Capsule roughness [Landen et al, JQSRT 54, 245 (1995)] Capsule shape [Dodd et al, LA-UR-13-20274] Slide 30