Class 6 Decimals. Answer t he quest ions. Choose correct answer(s) f rom given choice. Fill in the blanks

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ID : in-6-decimals [1] Class 6 Decimals For more such worksheets visit www.edugain.com Answer t he quest ions (1) At a construction site, there are 19.5 loads of bricks, and the total weight of all the loads together is 466.44 kgs. What is the weight of one load? (2) The corner store sells 129.91 liters of milk on Thursday and 11.32 liters more than this amount on Friday. The f ollowing day, 18.94 liters less milk than on Friday were sold. How many liters of milk did they sell on the Saturday? (3) What are you lef t with when you take away One Tenths six times f rom 1? (4) What number do you get by adding 8 Tenths and 72 Ten thousandths together to 33 Tens? (5) What is the smallest number should be subtracted f rom 15.51 to give a prime number? (6) What is the sum of the numbers two T en thousandths and six Hundredths? Choose correct answer(s) f rom given choice (7) What do you get when you subtract 692.92 f rom 719.23? a. 24.91 b. 28.41 c. 26.31 d. 2.631 Fill in the blanks (8) Solve the f ollowing: A) 10 = 68.805 B) 7.4 x = 56.24 C) 154.58 + 33.87 = D) 1.96 x = 52.92 (9) (29 Ones + 1 Hundredths + Hundredths) x 1 Tenths = 2.907 (10) Each bag of oranges weighs 1.46 kgs. If the total weight of a sack containing oranges bags is 61.32 kgs, then bags are in the sack. (11) 93 Tens + 4 Thousandths = (12) 260.79 + 65.19 + 0.92 =

(13) A snail crawls 34 cm in 22 minutes. It crawls another 98 cm in 65 minutes. The total distance it ID : in-6-decimals [2] crawls is metres. (14) Bala's f ather gave him Rs.188 to spend. He spent Rs.69.24 to buy some toys and Rs.13.18 to buy some books. He now has Rs. lef t. (15) The number nine Tenths can be written as in decimals 2016 Edugain (www.edugain.com). All Rights Reserved Many more such worksheets can be generated at www.edugain.com

Answers ID : in-6-decimals [3] (1) 23.92 kg The number of loads of bricks = 19.5 Total weight of all the loads together = 466.44 kgs In order to f ind the weight of one load, we need to divide the total weight by the number of loads. Theref ore, the weight of one load is 466.44 19.5 = 23.92 kg. (2) 122.29 liters Amount of milk sold on Thursday = 129.91 liters Amount of milk sold on next day (i.e. Friday) = 129.91 + 11.32 = 141.23 liters Amount of milk sold on next day (i.e. Saturday) = 141.23-18.94 = 122.29 liters (3) 0.4 Look at the question caref ully and notice that One Tenths of 1 = 1 10, and six times of 1 10 = 6 10 = 0.6 Now take One Tenths six times f rom 1 or subtracting 0.6 f rom 1 = 1-0.6 = 0.4 Theref ore the lef t value with you, when you take away One Tenths six times f rom 1 is 0.4.

(4) 330.8072 ID : in-6-decimals [4] Let us f irst convert the number names into numerals: 8 Tenths = 8 10 = 0.8 72 Ten thousandths = 72 10000 = 0.0072 33 Tens = 33 10 = 330 Let s f irst add the decimal numbers as below: Lakhs T housands Ones T enths Hundredths T housandths T en thousandths T L L T T H T H H T O. (1/10) (1/100) (1/1000) (1/10000) 0. 8 0 0 0 0. 0 0 7 2 T otal 0. 8 0 7 2 Legend: TL - Ten Lakhs, L - Lakhs, TTH - Ten Thousands, TH - Thousands, H - Hundreds, T - Tens, O - Ones. Let us now add the decimal numbers with the whole number: Lakhs T housands Ones T enths Hundredths T housandths T en thousandths T L L T T H T H H T O. (1/10) (1/100) (1/1000) (1/10000) 0. 8 0 7 2 3 3 0. 0 0 0 0 T otal 3 3 0. 8 0 7 2 Theref ore, by adding 8 Tenths and 72 Ten thousandths together to 33 Tens, we get 330.8072. (5) 2.51

(6) 0.0602 ID : in-6-decimals [5] Two Ten thousandths = 2 10000 and six Hundredths = 6 100 Theref ore the sum of the numbers two Ten thousandths and six Hundredths = 6 100 = 2 1 + 6 100 10000 = 2 + 600 10000 = 602 10000 = 0.0602 2 10000 + (7) c. 26.31 Decimals with the same number of decimal places are called Like Decimals. T he numbers given here are theref ore Like Decimals. We need to subtract 692.92 f rom 719.23. Theref ore, 719.23 must be placed on top and 692.92 below. The digits of the two numbers must be placed according to their place values. Let us now do the subtraction of the two numbers digit by digit, starting f rom the hundredths and borrowing if needed: Thousands Hundreds Tens Ones. Tenth Hundredth 7 1 9. 2 3-6 9 2. 9 2 0 2 6. 3 1 Hence, when we subtract 692.92 f rom 719.23, we get 26.31.

(8) A) B) C) D) 688.05 7.6 188.45 27 ID : in-6-decimals [6] (9) (10) 6 42 The weight of each bag of oranges = 1.46 kgs Total weight of oranges bags in a sack = 61.32 kgs Number of oranges bags in the sack = 61.32 1.46 = 42 bags Hence, there are 42 bags in the sack.

(11) 930.004 ID : in-6-decimals [7] First, let us convert the number names into numerals as below: 93 Tens = 93 10 = 930 4 Thousandths = 4 1000 = 0.004 Let s now add the two numbers: Lakhs T housands Ones T enths Hundredths T housandths T en thousandths T L L T T H T H H T O. (1/10) (1/100) (1/1000) (1/10000) 9 3 0. 0 0 0 0 0. 0 0 4 0 T otal 9 3 0. 0 0 4 0 Legend: TL - Ten Lakhs, L - Lakhs, TTH - Ten Thousands, TH - Thousands, H - Hundreds, T - Tens, O - Ones. Thus, 93 Tens + 4 Thousandths = 930.004

(12) 326.9 ID : in-6-decimals [8] Decimals with the same number of decimal places are called Like Decimals. T he numbers given here are theref ore Like Decimals. In order to add the given Like Decimals, let us arrange the digits according to their place value, that is one below the other to make sure that the decimals are also placed exactly one below the other. This way, we will place the ones below the ones, the tenths below the tenths and so on. The decimal point in the answer will be placed as being placed in the addends. Let us add the numbers digit by digit starting f rom the hundredths and carry over if needed: Thousands Hundreds Tens Ones. Tenth Hundredth 2 6 0. 7 9 6 5. 1 9 + 0. 9 2 3 2 6. 9 0 Step 5 Hence, when we add the decimals 260.79, 65.19, and 0.92 we get 326.9 (13) 1.32 The total distance (in cm) the snail crawls: 34 cm + 98 cm = 132 cm Let us now convert the distance 132 cm (centimetres) into distance in meters as below. We know that: 100 cm = 1 m Theref ore, 132 cm = 132 m = 1.32 m 100 Hence, the snail crawls 1.32 m in the total time.

(14) 105.58 ID : in-6-decimals [9] The amount of money that Bala's f ather gave him = Rs.188 The amount that Bala spent in buying toys = Rs.69.24 The amount that Bala spent in buying books = Rs.13.18 Let us add the amount he spent in buying toys and books to f ind his total expense: Toys Books = Rs.69.24 = Rs.13.18 T otal expense = Rs.82.42 Step 5 In order to f ind the amount lef t with him, we need to subtract the amount Bala's f ather gave and the amount Bala spent. Step 6 Bef ore subtracting the two numbers, let us make sure they are written as Like Decimals. Decimals with the same number of decimal places are called Like Decimals. Thus, let us write Rs.188 as Rs.188.00, and subtract Rs.82.42 f rom it Step 7 Let us subtract the amount Bala spent (Rs.82.42) f rom the amount his f ather gave (Rs.188) digit by digit. The numbers must be placed according to their place values. The greater number must be placed on top and the lesser one below: Thousands Hundreds Tens Ones. Tenth Hundredth 1 8 8. 0 0-8 2. 4 2 1 0 5. 5 8 Step 8 Hence, Bala is lef t with Rs.105.58.

(15) 0.9 ID : in-6-decimals [10] Let s f irst convert the number name into number/f raction. So, nine Tenths can be written as: 9 10 By converting the f raction into decimals, we get: 9 = 0.9 10 Theref ore, the number nine Tenths in decimal f orm is 0.9.