Chapter 23. Gauss s Law

Similar documents
Chapter 2 Gauss Law 1

CH 23. Gauss Law. A. Gauss law relates the electric fields at points on a (closed) Gaussian surface to the net charge enclosed by that surface.

Chapter 21 Chapter 23 Gauss Law. Copyright 2014 John Wiley & Sons, Inc. All rights reserved.

Electric Flux. If we know the electric field on a Gaussian surface, we can find the net charge enclosed by the surface.

Look over. Examples 11, 12, 2/3/2008. Read over Chapter 23 sections 1-9 Examples 1, 2, 3, 6. 1) What a Gaussian surface is.

E. not enough information given to decide

How to define the direction of A??

Chapter 22 Gauss s Law. Copyright 2009 Pearson Education, Inc.

Chapter 23. Gauss Law. Copyright 2014 John Wiley & Sons, Inc. All rights reserved.

Chapter 22 Gauss s Law. Copyright 2009 Pearson Education, Inc.

Chapter 22 Gauss s Law

University Physics (Prof. David Flory) Chapt_24 Sunday, February 03, 2008 Page 1

PHYS102 - Gauss s Law.

Chapter (2) Gauss s Law

Lecture 13. PHYC 161 Fall 2016

Chapter 24. Gauss s Law

AP Physics C - E & M

LECTURE 15 CONDUCTORS, ELECTRIC FLUX & GAUSS S LAW. Instructor: Kazumi Tolich

PH 222-2C Fall Gauss Law. Lectures 3-4. Chapter 23 (Halliday/Resnick/Walker, Fundamentals of Physics 8 th edition)

3/22/2016. Chapter 27 Gauss s Law. Chapter 27 Preview. Chapter 27 Preview. Chapter Goal: To understand and apply Gauss s law. Slide 27-2.

Electric Field Lines. lecture 4.1.1

Physics Lecture: 09

Lecture 4-1 Physics 219 Question 1 Aug Where (if any) is the net electric field due to the following two charges equal to zero?

Questions Chapter 23 Gauss' Law

Physics 114 Exam 1 Spring 2013

Chapter 23: Gauss Law. PHY2049: Chapter 23 1

PHYSICS. Chapter 24 Lecture FOR SCIENTISTS AND ENGINEERS A STRATEGIC APPROACH 4/E RANDALL D. KNIGHT

Lecture 14. PHYC 161 Fall 2016

Gauss s Law. Phys102 Lecture 4. Key Points. Electric Flux Gauss s Law Applications of Gauss s Law. References. SFU Ed: 22-1,2,3. 6 th Ed: 16-10,+.

Chapter 21: Gauss law Tuesday September 13 th. Gauss law and conductors Electrostatic potential energy (more likely on Thu.)

PHY102 Electricity Topic 3 (Lectures 4 & 5) Gauss s Law

Physics 2B. Lecture 24B. Gauss 10 Deutsche Mark

IMPORTANT: LABS START NEXT WEEK

Essential University Physics

Flux. Flux = = va. This is the same as asking What is the flux of water through the rectangle? The answer depends on:

Homework 4 PHYS 212 Dr. Amir

Chapter 28. Gauss s Law

Gauss s Law. Chapter 22. Electric Flux Gauss s Law: Definition. Applications of Gauss s Law

week 3 chapter 28 - Gauss s Law

Quiz. Chapter 15. Electrical Field. Quiz. Electric Field. Electric Field, cont. 8/29/2011. q r. Electric Forces and Electric Fields

Experiment III Electric Flux

Chapter 24. Gauss s Law

3 Chapter. Gauss s Law

Electric flux. Electric Fields and Gauss s Law. Electric flux. Flux through an arbitrary surface

Chapter 24. Gauss s Law

Phys 2102 Spring 2002 Exam 1

Chapter 24 Gauss Law

Phys102 General Physics II. Chapter 24: Gauss s Law

Fall 2004 Physics 3 Tu-Th Section

Electric Field and Gauss s law. January 17, 2014 Physics for Scientists & Engineers 2, Chapter 22 1

Chapter 22. Dr. Armen Kocharian. Gauss s Law Lecture 4

Ch 24 Electric Flux, & Gauss s Law

1. ELECTRIC CHARGES AND FIELDS

The Basic Definition of Flux

24 Gauss s Law. Gauss s Law 87:

Gauss s Law. Name. I. The Law: , where ɛ 0 = C 2 (N?m 2

Ampere s Law. Outline. Objectives. BEE-Lecture Notes Anurag Srivastava 1

Physics 114 Exam 1 Fall 2015

Chapter 21: Gauss s Law

Physics 114 Exam 1 Fall 2016

Electric Flux and Gauss Law

Chapters 21 and 22: Giancoli, 4 th Edition Electrostatics

Electric Flux and Gauss s Law

Electricity & Magnetism Lecture 4: Gauss Law

Physics 1214 Chapter 17: Electric Charge and Electric Field

Reading: Chapter 28. 4πε r. For r > a. Gauss s Law

Motion of a charged particle in an electric field. Electric flux

A) 1, 2, 3, 4 B) 4, 3, 2, 1 C) 2, 3, 1, 4 D) 2, 4, 1, 3 E) 3, 2, 4, 1. Page 2

Gauss s Law. Lecture 3. Chapter Course website:

VU Mobile Powered by S NO Group All Rights Reserved S NO Group 2012

Sample Question: A point in empty space is near 3 charges as shown. The distances from the point to each charge are identical.

Conductors in Electrostatic Equilibrium

Physics 202: Spring 1999 Solution to Homework Assignment #3

Chapter 17 & 18. Electric Field and Electric Potential

Practice Questions Exam 1/page1. PES Physics 2 Practice Exam 1 Questions. Name: Score: /.

Chapter 24. Gauss s Law

HOMEWORK 1 SOLUTIONS

Gauss s Law. Lecture 4. Chapter 27. Channel 61 (clicker) Physics II

Chapter 24 Solutions The uniform field enters the shell on one side and exits on the other so the total flux is zero cm cos 60.

Coulomb s Law Pearson Education Inc.

Chapter 22: Gauss s Law

Physics 2049 Exam 1 Solutions Fall 2002

Chapter 15. Electric Forces and Electric Fields

Conductors in Electrostatic Equilibrium

Electric Flux. To investigate this, we have to understand electric flux.

Fall 12 PHY 122 Homework Solutions #2

2. Gauss Law [1] Equipment: This is a theoretical lab so your equipment is pencil, paper, and textbook.

Problems. 686 Chapter 24 Gauss s Law

Gauss Law 1. Name Date Partners GAUSS' LAW. Work together as a group on all questions.

Quiz Fun! This box contains. 1. a net positive charge. 2. no net charge. 3. a net negative charge. 4. a positive charge. 5. a negative charge.

Physics 202, Lecture 3. The Electric Field

Electrostatics. Electrical properties generated by static charges. Introduction

Gauss s Law. Johann Carl Friedrich Gauss

Physics 9 WS E3 (rev. 1.0) Page 1

Gauss s Law. David J. Starling Penn State Hazleton PHYS 212

Chapter 15. Electric Forces and Electric Fields

More Gauss, Less Potential

Name Date Partners. Lab 2 GAUSS LAW

PHYSICS - CLUTCH CH 22: ELECTRIC FORCE & FIELD; GAUSS' LAW

Chapter 21. Electric Fields

Transcription:

Chapter 23 Gauss s Law

23.1 What is Physics?: Gauss law relates the electric fields at points on a (closed) Gaussian surface to the net charge enclosed by that surface. Gauss law considers a hypothetical (imaginary) closed surface enclosing the charge distribution. This Gaussian surface, as it is called, can have any shape, but the shape that minimizes our calculations of the electric field is one that mimics the symmetry of the charge distribution.

23.2: Flux Fig. 23-2 (a) A uniform airstream of velocity is perpendicular to the plane of a square loop of area A.(b) The component of perpendicular to the plane of the loop is v cos θ,where θ is the angle between v and a normal to the plane. (c) The area vector A is perpendicular to the plane of the loop and makes an angle θ with v. (d) The velocity field intercepted by the area of the loop. The rate of volume flow through the loop is Φ= (v cos θ)a. This rate of flow through an area is an example of a flux a volume flux in this situation.

Electric Flux and Gauss s Law Electric flux is a measure of the electric field perpendicular to a surface:

23.3: Electric Flux The electric flux through a Gaussian surface is proportional to the net number of electric field lines passing through that surface. Fig. 23-3 A Gaussian surface of arbitrary shape immersed in an electric field. The surface is divided into small squares of area ΔA. The electric field vectors E and the area vectors ΔA for three representative squares, marked 1, 2, and 3, are shown. The exact definition of the flux of the electric field through a closed surface is found by allowing the area of the squares shown in Fig. 23-3 to become smaller and smaller, approaching a differential limit da. The area vectors then approach a differential limit da.the sum of Eq. 23-3 then becomes an integral:

Example, Flux through a closed cylinder, uniform field:

23.4 Gauss s Law: Gauss law relates the net flux of an electric field through a closed surface (a Gaussian surface) to the net charge q enc that is enclosed by that surface. The net charge q enc is the algebraic sum of all the enclosed positive and negative charges, and it can be positive, negative, or zero. If q enc is positive, the net flux is outward; if q enc is negative, the net flux is inward.

Example, Relating the net enclosed charge and the net flux:

23.5 Gauss s Law and Coulomb s Law: Figure 23-8 shows a positive point charge q, around which a concentric spherical Gaussian surface of radius r is drawn. Divide this surface into differential areas da. The area vector da at any point is perpendicular to the surface and directed outward from the interior. From the symmetry of the situation, at any point the electric field, E, is also perpendicular to the surface and directed outward from the interior. Thus, since the angle θ between E and da is zero, we can rewrite Gauss law as This is exactly what Coulomb s law yielded.

Distribution of Charge Since excess charge on a conductor is free to move, the charges will move so that they are as far apart as possible. This means that excess charge on a conductor resides on its surface, as in the upper diagram.

Electric Field within a Conductor When electric charges are at rest, the electric field within a conductor is zero.

Conductor immersed in an Electric Field The electric field is always perpendicular to the surface of a conductor if it weren t, the charges would move along the surface.

23.6 A Charged Isolated Conductor: Figure 23-9b shows the same hanging conductor, but now with a cavity that is totally within the conductor. A Gaussian surface is drawn surrounding the cavity, close to its surface but inside the conducting body. Inside the conductor, there can be no flux through this new Gaussian surface. Therefore, there is no net charge on the cavity walls; all the excess charge remains on the outer surface of the conductor. If an excess charge is placed on an isolated conductor, that amount of charge will move entirely to the surface of the conductor. None of the excess charge will be found within the body of the conductor. Figure 23-9a shows, in cross section, an isolated lump of copper hanging from an insulating thread and having an excess charge q. The Gaussian surface is placed just inside the actual surface of the conductor. The electric field inside this conductor must be zero. Since the excess charge is not inside the Gaussian surface, it must be outside that surface, which means it must lie on the actual surface of the conductor.

Example, Spherical Metal Shell, Electric Field, and Enclosed Charge:

Example, Gauss s Law and an upward streamer in a lightning storm: