Physics 208 Test 2 Spring 2000

Similar documents
3. A solid conducting sphere has net charge of +6nC. At electrostatic equilibrium the electric field inside the sphere is:

Physics 420 Fall 2004 Quiz 1 Wednesday This quiz is worth 6 points. Be sure to show your work and label your final answers.

Chapter 23 Term083 Term082

The Electric Field of a Finite Line of Charge The Electric Field of a Finite Line of

9/10/2018. An Infinite Line of Charge. The electric field of a thin, uniformly charged rod may be written:

Exam 1 Solution. Solution: Make a table showing the components of each of the forces and then add the components. F on 4 by 3 k(1µc)(2µc)/(4cm) 2 0

Worksheet for Exploration 24.1: Flux and Gauss's Law

University Physics (Prof. David Flory) Chapt_24 Sunday, February 03, 2008 Page 1

Physics 208, Spring 2015 Exam #1

Phys 2102 Spring 2002 Exam 1

AP Physics C. Gauss s Law. Free Response Problems

2 Which of the following represents the electric field due to an infinite charged sheet with a uniform charge distribution σ.

PHYS 2135 Exam I February 13, 2018

Practice Questions Exam 1/page1. PES Physics 2 Practice Exam 1 Questions. Name: Score: /.

E. not enough information given to decide

HOMEWORK 1 SOLUTIONS

Phys102 General Physics II. Chapter 24: Gauss s Law

How to define the direction of A??

a. On the circle below draw vectors showing all the forces acting on the cylinder after it is released. Label each force clearly.

Chapter 21. Electric Fields

AP Physics C Electricity & Magnetism Mid Term Review

Physics 222, Spring 2010 Quiz 3, Form: A

Gauss s Law. Name. I. The Law: , where ɛ 0 = C 2 (N?m 2

Chapter (2) Gauss s Law

7. A capacitor has been charged by a D C source. What are the magnitude of conduction and displacement current, when it is fully charged?

Questions Chapter 23 Gauss' Law

Physics 122 Spring 2012 Test 2

Version: A. Earth s gravitational field g = 9.81 N/kg Vacuum Permeability µ 0 = 4π 10 7 T m/a

INDIAN SCHOOL MUSCAT Department of Physics Class : XII Physics Worksheet - 1 ( ) Electric Charges and Fields

Chapter 2 Gauss Law 1

1. ELECTRIC CHARGES AND FIELDS

Physics II Fiz Summer 2017

Physics Exam I

INDIAN SCHOOL MUSCAT FIRST TERM EXAMINATION PHYSICS

Physics 2212 GH Quiz #2 Solutions Spring 2015

Profs. D. Acosta, A. Rinzler, S. Hershfield. Exam 1 Solutions

Chapter 22 Gauss s Law. Copyright 2009 Pearson Education, Inc.

Fall 12 PHY 122 Homework Solutions #2

Physics 9 WS E3 (rev. 1.0) Page 1

Roll Number SET NO. 42/1

The third charge has to be along the line joining the two charges, outside the two charges, and closer to the weaker.

Physics 102. First Midterm Examination Fall Semester 2015/2016. November 3, 2015 Time: 6.30 p.m p.m. Name. Student No..

INGENIERÍA EN NANOTECNOLOGÍA

Physics 9 Spring 2011 Midterm 1 Solutions

Gauss s Law. Chapter 22. Electric Flux Gauss s Law: Definition. Applications of Gauss s Law

Chapter 21 Chapter 23 Gauss Law. Copyright 2014 John Wiley & Sons, Inc. All rights reserved.

Form #221 Page 1 of 7

+2Q -2Q. (a) 672 N m 2 /C (b) 321 N m 2 /C (c) 105 N m 2 /C (d) 132 N m 2 /C (e) 251 N m 2 /C

VU Mobile Powered by S NO Group All Rights Reserved S NO Group 2012

AP Physics C. Electric Potential and Capacitance. Free Response Problems

Physics 212 Exam I Sample Question Bank 2008 Multiple Choice: choose the best answer "none of the above" may can be a valid answer

Chapter 23. Gauss Law. Copyright 2014 John Wiley & Sons, Inc. All rights reserved.

Mid Term Exam. Electricity and Magnetism PHY204

PRACTICE EXAM 1 for Midterm 1

Chapter 24 Solutions The uniform field enters the shell on one side and exits on the other so the total flux is zero cm cos 60.

Which of the following is the SI unit of gravitational field strength?

AMPERE'S LAW. B dl = 0

Department of Physics. PHYS MAJOR 2 EXAM Test Code: 015. Monday 1 st May 2006 Exam Duration: 2hrs (from 6:30pm to 8:30pm)

A) 4 B) 3 C) 2 D) 5 E) 6

(D) Blv/R Counterclockwise

Exam 1: Physics 2113 Spring :00 PM, Monday, February 3, Abdelwahab Abdelwahab Lee Zuniga Tzanov Zuniga Sec 1 Sec 2 Sec 3 Sec 4 Sec 5 Sec 6

PHYSICS 222 Fall 2009 EXAM 1: October 1, :00pm 10:00pm

Phys102 Second Major-133 Zero Version Coordinator: A.A.Naqvi Tuesday, August 05, 2014 Page: 1

ELECTROSTATICS (Important formulae and Concepts) I Electric charges and Coulomb s law

Physics 222 Quiz 3 Electric Field of Distributed Charge, Form: A

Class XII Chapter 1 Electric Charges And Fields Physics

Chapter 22 Gauss s Law. Copyright 2009 Pearson Education, Inc.

PHYSICS 122D, Winter 2009, Version A Exam 2, PAGE 1

PH Physics 211 Exam-2

1. (a) +EA; (b) EA; (c) 0; (d) 0 2. (a) 2; (b) 3; (c) 1 3. (a) equal; (b) equal; (c) equal e; (b) 150e 5. 3 and 4 tie, then 2, 1

PHY294 Exam #1 Name: Student #: Show work for problems where indicated. Include units in answer.

1. Four equal and positive charges +q are arranged as shown on figure 1.

Homework 4: Hard-Copy Homework Due Wednesday 2/17

PH 222-2C Fall Gauss Law. Lectures 3-4. Chapter 23 (Halliday/Resnick/Walker, Fundamentals of Physics 8 th edition)

CH 23. Gauss Law. A. Gauss law relates the electric fields at points on a (closed) Gaussian surface to the net charge enclosed by that surface.

Chapter 23 Electric Potential. Copyright 2009 Pearson Education, Inc.

Exam 1 Solutions. Note that there are several variations of some problems, indicated by choices in parentheses. Problem 1

2014 F 2014 AI. 1. Why must electrostatic field at the surface of a charged conductor be normal to the surface at every point? Give reason.

March 11. Physics 272. Spring Prof. Philip von Doetinchem

PHYS 2212 (Modern) Review. Electric Force and Fields

Chapter 21: Gauss law Tuesday September 13 th. Gauss law and conductors Electrostatic potential energy (more likely on Thu.)

1. Short Answer (25 points total)

Phys222 W16 Exam 2: Chapters Key. Name:

Chapter 23. Electric Fields

Chapter 1 The Electric Force

AP Physics C Mechanics Objectives

Physics 121 Common Exam 1, Sample Exam 4 (Fall 2011)

2R R R 2R. Phys Test 1

Phys102 Second Major-181 Zero Version Coordinator: Kunwar, S Monday, November 19, 2018 Page: 1

Supplemental Questions 12U

Lecture 4-1 Physics 219 Question 1 Aug Where (if any) is the net electric field due to the following two charges equal to zero?

Welcome. to Electrostatics

Phys 0175 Practice Midterm Exam II Feb 25, 2009

Module 2 : Electrostatics Lecture 7 : Electric Flux

Chapter 22 Gauss s Law

Chapter 22 Gauss s law. Electric charge and flux (sec &.3) Gauss s Law (sec &.5) Charges on conductors (sec. 22.6)

Downloaded from

Second Year Electromagnetism Summer 2018 Caroline Terquem. Vacation work: Problem set 0. Revisions

Gauss s Law. Phys102 Lecture 4. Key Points. Electric Flux Gauss s Law Applications of Gauss s Law. References. SFU Ed: 22-1,2,3. 6 th Ed: 16-10,+.

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

Transcription:

Spring 2000 Problems 1-5. Multiple Choice/Short Answer (5 points each / 25 points total) no explanation required, but no partial credit either. However, a bonus of up to two points may be awarded if an explanation is offered that is correct and consistent with your answer. 1. A proton (mass = 1.67 x 10-27 kg, charge = +e) moves 0.050 m in the +X direction through a uniform electric field E which increases its speed from v 0 = 2.0 x 10 6 m/s to 3v 0. The magnitude and direction of E are (in N/C) (A) 0.42, +X direction (B) 3.3 x 10 6,+X direction (C) 3.3 x 10 6, -X direction (D) 1.7 x 10 6,+X direction (E) 1.7 x 10 6, -X direction 2. Two point charges, -30 µc and +10 µc, are both inside a (closed) Gaussian surface. A third point charge, +20 µc, is outside the Gaussian surface. The net flux through the Gaussian surface is, (in Nm2/C) (A) zero (B) -2.3 x 10 6 (C) +2.3 x 10 6 (D) +4.5 x 10 6 (E) -4.5 x 10 6 3. A thin wire is charged uniformly with l.5 coulombs per meter. A cylindrical Gaussian surface with end caps is centered on the wire as shown. Its radius is r and its length is L. Applying Gauss's law to this closed surface gives (E is the magnitude of the field at the surface of the cylinder) (A) E (π r 2 L) = (λ L)/ε 0 (B) E (r L) = (λ L)/ε 0 (C) E (π r 2 ) = (λ L)/ε 0

(D) E (π r 2 L) = (λ π r2)/ε 0 (E) E (2πr L) = (λ L)/ε 0 4. A +20 µc point charge moves 2 m parallel to a uniform electric field of magnitude 6.0 x 10 5 N/C. The work done on the charge by the electric field is (A) 48 Nm (B) 12 Nm (C) 6.0 Nm (D) 24 Nm (E) 1.2 x 10 6 Nm 5. A circular ring of charge is made by joining four-quarter circles, each having the same magnitude of charge as the others. Each quarter circle has its net charge uniformly distributed over its length. Let the field at the center of the circle due to one quarter circle be E 1. The magnitude of the total electric field at the center is then (A) zero (B) E1 (C) 2 E1 (D) 3 E1 (E) 4 E1 6. Essay (15 points): You may use diagrams and equations but no calculations for this problem. A positively charged conducting sphere of radius 2m is inside a conducting shell as shown below. There is an air gap between the two spheres. The spherical conducting shell has no net charge on it. Sketch a graph of the E-field as a function of the radial distance r (an E-field vs. r graph). Explain why the graph appears as you have drawn it. 1

7. (GOAL Problem: 20 points) For the following problem, do the G and O steps of GOAL only. Your O step should include a statement of the main physics principles used, why you are using them, and how you would use them to solve the problem. Do not solve the problem.. You have landed a summer job working with an Astrophysics group investigating the origin of high-energy particles in the galaxy. The group you are joining has just discovered a large spherical nebula with a radius 1.0 million km. The nebula consists of about 5 x 10 9 hydrogen nuclei (protons) which appear to be distributed uniformly in the shape of a sphere (the protons are distributed uniformly throughout the sphere. At the center of this sphere of positive charge is a very small neutron star. Your group had detected electrons emerging from the nebula. A friend of yours has a theory that the electrons are coming from the neutron star. To test that theory, she asks you to calculate the E-field inside the nebula as a function of radial distance. From the inside cover of your trusty physics text you find that the charge of a proton (and an electron) is 1.6 x 10-19 C, the mass of the proton is 1.7 x 10-27 kg, and the mass of the electron is 9.1 x 10-31 kg. Find the E-field at a distance of half the radius of the nebula. GOAL Problem-solving Protocol Gather information: What is known? What are you looking for? Predict a reasonable answer with units. (Consider limiting cases.) Organize your approach: Draw a diagram(s) labeled with variables from G step. Classify the problem according to the general physics principle(s) used. Describe how you will use the general principle(s) to solve the problem. 2

8. (20 points) Two very large positively charged sheets are placed a distance 3d apart (only a small portion of the plates is shown). The sheet on the left has an area charge density of +3σ 0 and the sheet on the right has area charge density -σ 0. A. Find the net electric field vector at points A (at a distance d to the right of the right plate) and B (at a distance d to the left of the right plate). B. What is the minimum amount of work you would have to do to move an electron from the + sheet to the negative sheet. +3σ 0 3

8. Suppose a hole is made in the middle of the positive plate in problem 8. If an electron were released from the middle of the ( ) plate, it would accelerate towards the positive plate. What speed would the electron have when it passed through the hole in the positive plate. (This is one of the simplest forms of particle accelerator.) + 4