Power Flow in Electromagnetic Waves. The time-dependent power flow density of an electromagnetic wave is given by the instantaneous Poynting vector

Similar documents
ECE 546 Lecture 02 Review of Electromagnetics

Schedule. Time Varying electromagnetic fields (1 Week) 6.1 Overview 6.2 Faraday s law (6.2.1 only) 6.3 Maxwell s equations

Chapter 32. Maxwell s Equations and Electromagnetic Waves

ECE 2100 Circuit Analysis

Lecture 6: Phase Space and Damped Oscillations

Supplementary Course Notes Adding and Subtracting AC Voltages and Currents

Chapter 30. Inductance

MAGNETIC FIELDS CURRENT & RESISTANCE

( ) ( ) ( ) ( ) ( z) ( )

Supplementary Course Notes Adding and Subtracting AC Voltages and Currents

Sections 15.1 to 15.12, 16.1 and 16.2 of the textbook (Robbins-Miller) cover the materials required for this topic.

Q1. A string of length L is fixed at both ends. Which one of the following is NOT a possible wavelength for standing waves on this string?

CHAPTER 5. Solutions for Exercises

Part a: Writing the nodal equations and solving for v o gives the magnitude and phase response: tan ( 0.25 )

Revision: August 19, E Main Suite D Pullman, WA (509) Voice and Fax

Flipping Physics Lecture Notes: Simple Harmonic Motion Introduction via a Horizontal Mass-Spring System

Chapter 6. Dielectrics and Capacitance

Chapter 9 Vector Differential Calculus, Grad, Div, Curl

39th International Physics Olympiad - Hanoi - Vietnam Theoretical Problem No. 1 /Solution. Solution

Chapter 8. The Steady Magnetic Field 8.1 Biot-Savart Law

Flipping Physics Lecture Notes: Simple Harmonic Motion Introduction via a Horizontal Mass-Spring System

ECE 2100 Circuit Analysis

Lecture 7: Damped and Driven Oscillations

37 Maxwell s Equations

ELECTROSTATIC FIELDS IN MATERIAL MEDIA

Short notes for Heat transfer

4F-5 : Performance of an Ideal Gas Cycle 10 pts

Module 4: General Formulation of Electric Circuit Theory

Chapter 2 GAUSS LAW Recommended Problems:

Function notation & composite functions Factoring Dividing polynomials Remainder theorem & factor property

Q1. In figure 1, Q = 60 µc, q = 20 µc, a = 3.0 m, and b = 4.0 m. Calculate the total electric force on q due to the other 2 charges.

Phys102 Second Major-102 Zero Version Coordinator: Al-Shukri Thursday, May 05, 2011 Page: 1

Computational modeling techniques

Phys101 Final Code: 1 Term: 132 Wednesday, May 21, 2014 Page: 1

ENGI 4430 Parametric Vector Functions Page 2-01

Kinetics of Particles. Chapter 3

Chapter 3 Kinematics in Two Dimensions; Vectors

Series and Parallel Resonances

Physics 2B Chapter 23 Notes - Faraday s Law & Inductors Spring 2018

Lecture 5: Equilibrium and Oscillations

CLASS XI SET A PHYSICS

Differentiation Applications 1: Related Rates

Q x = cos 1 30 = 53.1 South

Yeu-Sheng Paul Shiue, Ph.D 薛宇盛 Professor and Chair Mechanical Engineering Department Christian Brothers University 650 East Parkway South Memphis, TN

LEARNING : At the end of the lesson, students should be able to: OUTCOMES a) state trigonometric ratios of sin,cos, tan, cosec, sec and cot

MODULE 1. e x + c. [You can t separate a demominator, but you can divide a single denominator into each numerator term] a + b a(a + b)+1 = a + b

Q1. A) 48 m/s B) 17 m/s C) 22 m/s D) 66 m/s E) 53 m/s. Ans: = 84.0 Q2.

Chapter 2. Coulomb s Law and Electric Field Intensity

Figure 1a. A planar mechanism.

Chapter 5: Force and Motion I-a

GAUSS' LAW E. A. surface

(1.1) V which contains charges. If a charge density ρ, is defined as the limit of the ratio of the charge contained. 0, and if a force density f

Equilibrium of Stress

Coupled Inductors and Transformers

Thermodynamics Partial Outline of Topics

Chapter 4. Unsteady State Conduction

Physics 212. Lecture 12. Today's Concept: Magnetic Force on moving charges. Physics 212 Lecture 12, Slide 1

Calculus Placement Review. x x. =. Find each of the following. 9 = 4 ( )

Synchronous Motor V-Curves

ChE 471: LECTURE 4 Fall 2003

!"#$%&'()%"*#%*+,-./-*+01.2(.* *!"#$%&"'(()'*+,"-'.'

Phys102 First Major-122 Zero Version Coordinator: Sunaidi Wednesday, March 06, 2013 Page: 1

Phy 213: General Physics III 6/14/2007 Chapter 28 Worksheet 1

Electric Current and Resistance

Solution to HW14 Fall-2002

Compressibility Effects

Lecture 24: Flory-Huggins Theory

Fields and Waves I. Lecture 3

Chapter 14. Nanoscale Resolution in the Near and Far Field Intensity Profile of Optical Dipole Radiation

Interference is when two (or more) sets of waves meet and combine to produce a new pattern.

General review: - a) Dot Product

Lyapunov Stability Stability of Equilibrium Points

Chapter 23 Electromagnetic Waves Lecture 14

20 Faraday s Law and Maxwell s Extension to Ampere s Law

PHYS College Physics II Final Examination Review

Preparation work for A2 Mathematics [2017]

NUMBERS, MATHEMATICS AND EQUATIONS

Kinematic transformation of mechanical behavior Neville Hogan

CBSE Board Class XII Physics Set 1 Board Paper 2008 (Solution)

Preparation work for A2 Mathematics [2018]

Phys101 First Major-131 Zero Version Coordinator: Dr. A. A. Naqvi Wednesday, September 25, 2013 Page: 1

Plan o o. I(t) Divide problem into sub-problems Modify schematic and coordinate system (if needed) Write general equations

Work, Energy, and Power

A) 0.77 N B) 0.24 N C) 0.63 N D) 0.31 N E) 0.86 N. v = ω k = 80 = 32 m/s. Ans: (32) 2 = 0.77 N

Chapter VII Electrodynamics

Thermodynamics and Equilibrium

Root locus ( )( ) The given TFs are: 1. Using Matlab: >> rlocus(g) >> Gp1=tf(1,poly([0-1 -2])) Transfer function: s^3 + 3 s^2 + 2 s

( ) + θ θ. ω rotation rate. θ g geographic latitude - - θ geocentric latitude - - Reference Earth Model - WGS84 (Copyright 2002, David T.

Springs in parallel. Two springs in parallel. Springs in series. Springs in series. Resonance. Forced vibrations and resonance. 2 C. 2 1/2 m.

ScholarlyCommons. University of Pennsylvania. Andrea Alù University of Pennsylvania. Nader Engheta University of Pennsylvania,

Chapters 29 and 35 Thermochemistry and Chemical Thermodynamics

Cambridge Assessment International Education Cambridge Ordinary Level. Published

Phys102 Final-061 Zero Version Coordinator: Nasser Wednesday, January 24, 2007 Page: 1

SPH3U1 Lesson 06 Kinematics

4) What is the magnitude of the net electric field at the center of the square?

Introduction: A Generalized approach for computing the trajectories associated with the Newtonian N Body Problem

Higher Mathematics Booklet CONTENTS

( ) ( ) Pre-Calculus Team Florida Regional Competition March Pre-Calculus Team Florida Regional Competition March α = for 0 < α <, and

LECTURES 4 AND 5 THREE-PHASE CONNECTIONS (1)

Transcription:

Pwer Flw in Electrmagnetic Waves Electrmagnetic Fields The time-dependent pwer flw density f an electrmagnetic wave is given by the instantaneus Pynting vectr P t E t H t ( ) = ( ) ( ) Fr time-varying fields it is imprtant t cnsider the time-average pwer flw density 1 T 1 T Pt () = Pt () dt= Et () Ht () dt T 0 T 0 where T is the perid f bservatin. Amangawa, 006 Digital Maestr Series 89

Cnsider time-harmnic fields represented in terms f their phasrs E( t) = Re{ E exp( jω t) } = Re{E} csωt Im{E} sinωt Ht ( ) = Re H exp( jω t) = Re{H} csωt Im{H} sinωt { } The time-dependent Pynting vectr can be expressed as the sum f the crss-prducts f the cmpnents Et ( ) Ht ( ) = Re{E} Re{H} cs ωt + Im{E} Im{H} sin ωt Re{E} Im{H} + Im{E} Re{H} csωtsin ωt ( ) csωt sinω t= sin ω t ) (Nte that: 1 Amangawa, 006 Digital Maestr Series 90

The time-average pwer flw density can be btained by integrating the previus result ver a perid f scillatin T. The pre-factrs cntaining field phasrs d nt depend n time, therefre we have t slve fr the fllwing integrals: 1 T 1 t sinωt cs ω tdt= T 0 T + = 4ω 1 T 1 t sinωt sin ω tdt= T 0 T = 4ω T 0 T 0 1 1 1 T 1 sin ωt csωt sin ω t dt= T 0 = T ω T 0 0 Amangawa, 006 Digital Maestr Series 91

The final result fr the time-average pwer flw density is given by 1 T Pt () = Et () Ht () dt T 0 1 = Re{E} Re{H} + Im{E} Im{H} ( ) Nw, cnsider the fllwing crss prduct f phasr vectrs * E H = Re{E} Re{H} + Im{E} Im{H} + j ( Im{E} Re{H} Re{E} Im{H} ) Amangawa, 006 Digital Maestr Series 9

By cmbining the previus results, ne can btain the fllwing time average rule 1 T 1 Pt () = Et () Ht () dt= Re E H T 0 We als call cmplex Pynting vectr the quantity 1 P= E H { * } NOTE: the cmplex Pynting vectr is nt the phasr f the timedependent pwer nr that f the time-average pwer density! Pt () = Re P Pt () = Re Pexp( jωt) Phasr ntatin cannt be applied t the prduct f tw timeharmnic functins (e.g., P( t )), even if they have same frequency. * { } dn't try { } ( ) Amangawa, 006 Digital Maestr Series 93

Cnsider a 1-D electr-magnetic wave mving alng the z-directin, with a specified electric field amplitude E E x( z) = Eexp( αz)exp( jβz) E H ( ) y z = exp( αz)exp( jβz)exp( jτ) η The time-average pwer flw density is αz αz e e Re Pwer in a lssy medium decays as exp(-α z)! * z j z E z j z j 1 { * } 1 α β α β τ Pt ( ) = Re E H = Re Ee e e e e η 1 { jτ} 1 = E e = E cs τ η η Amangawa, 006 Digital Maestr Series 94

Cnsider the same wave, with a specified amplitude fr the magnetic field H ( z) = H exp( αz)exp( jβz) y E ( z) = η H exp( αz)exp( jβz)exp( jτ) x The time-average pwer flw density is expressed as α β α β τ 1 Pt () = Re η He e He e e 1 αz = η H e cs τ { z j z * z j z j } If α is the attenuatin cnstant fr the electrmagnetic fields α is the attenuatin cnstant fr pwer flw. Amangawa, 006 Digital Maestr Series 95

If the wave is generated by an infinitesimally thin sheet f unifrm current J s (embedded in an infinite material with cnductivity σ) we have fr prpagatin alng the psitive z-directin (nrmal t the plane f the current sheet):i Js J H = E = η J z Pt () s α = ηe csτ 8 s Fr this ideal case, an identical wave exists, prpagating alng the negative z-directin and carrying the same amunt f pwer. Amangawa, 006 Digital Maestr Series 96

Pynting Therem Cnsider the divergence f the time-dependent pwer flw density Pt () = Et () Ht () = Ht () Et () Et () Ht () ( ) The curls can be expressed by using Maxwell s equatins H E Pt () = µ Ht () σet () Et () εet () t t 1 1 = σe () t ε E () t µ H () t t t Density f dissipated pwer Rate f change f stred electric energy density Rate f change f stred magnetic energy density This is the differential frm f Pynting Therem. Amangawa, 006 Digital Maestr Series 97

Nw, integrate the divergence f the time-dependent pwer ver a specified vlume V t btain the integral frm f Pynting therem V Pt () dv = Pt () ds = S Pwer Flux thrugh S 1 1 = σe () t dv εe () t dv µ H () t dv t t V V V Pwer dissipated in vlume Rate f change f electric energy stred in vlume Rate f change f magnetic energy stred in vlume Amangawa, 006 Digital Maestr Series 98

Typical applicatins P in () t α =? P ut () t 1 m L Watts Put () t = Pin ()exp( t αl) m 1 Put () t Nepers α= ln L Pin( t) m Amangawa, 006 Digital Maestr Series 99

Example: Watts Watts Pin() t = 30 ; P () 5 ; 0 m ut t = L = m m Nepers α = 0.0448 m Pay attentin t the lgarithms: () () ln Put t Pin t = ln Pin() t Put () t Amangawa, 006 Digital Maestr Series 100

SURFACE A SURFACE B A P in ( t) = Pwer IN B P ut ( t) = Pwer OUT Area = Area(A) = Area(B) Pwer IN = Pt ( ) ds= Pt ( ) Area A Pwer OUT = Pt ( ) ds= Pt ( ) Area Pt () = Pt () exp( αl) B B A A Pwer dissipated between A and B? Pwer dissipated = Pwer IN Pwer OUT B L A B Amangawa, 006 Digital Maestr Series 101

Example Area = 5 m 8.44637 General Lssy medium Electrmagnetic Fields ; L= 1.0 cm; f = 1.0 GHz; E = 10 V/m ε=ε ; µ=µ ; σ= 0.45755 S/m σ = ωε η= 130.88 0.75rad = 130.88 41.534 α = 40.0 Ne/m; Pin( t) = 0.86 W/m ; P () t = P () t exp( α L) = 0.1845 W/m ; ut B in A Pwer IN = Area Pin( t) Pwer OUT = Area Pt ( ) 1.43 W 0.643 W Pwer dissipate d = Pwer IN Pwer OUT = B = = 0.7876 W Amangawa, 006 Digital Maestr Series 10