Technote 6. Op Amp Definitions. April 1990 Revised 11/22/02. Tim J. Sobering SDE Consulting

Similar documents
55:041 Electronic Circuits

Design of Analog Integrated Circuits

Lecture 5: Operational Amplifiers and Op Amp Circuits

The three major operations done on biological signals using Op-Amp:

ME2142/ME2142E Feedback Control Systems. Modelling of Physical Systems The Transfer Function

Chapter 6. Operational Amplifier. inputs can be defined as the average of the sum of the two signals.

ELG3150 DGD 6 P9.5; P9.7; P9.13; P9.18; AP9.5; DP9.2

Physics 102. Final Examination. Spring Semester ( ) P M. Fundamental constants. n = 10P

Limitations for Op Amps due to input signal

Objective of curve fitting is to represent a set of discrete data by a function (curve). Consider a set of discrete data as given in table.

Section I5: Feedback in Operational Amplifiers

Exercises for Frequency Response. ECE 102, Winter 2011, F. Najmabadi

Asynchronous Sequen<al Circuits

Solution of Tutorial 5 Drive dynamics & control

Faculty of Engineering

Waveshapping Circuits and Data Converters. Lesson #17 Comparators and Schmitt Triggers Section BME 373 Electronics II J.

CHAPTER 3: FEEDBACK. Dr. Wan Mahani Hafizah binti Wan Mahmud

Introduction to Electronic circuits.

OVERVIEW Using Similarity and Proving Triangle Theorems G.SRT.4

PHYSICS 536 Experiment 12: Applications of the Golden Rules for Negative Feedback

332:221 Principles of Electrical Engineering I Fall Hourly Exam 2 November 6, 2006

Performance Evaluation of Cross-Flow Heat Exchanger in Coal-Fired Power Plant under Particulate Condition

Schedule. ECEN 301 Discussion #17 Operational Amplifiers 1. Date Day Class No. Lab Due date. Exam

Lecture 20a. Circuit Topologies and Techniques: Opamps

Circuits Op-Amp. Interaction of Circuit Elements. Quick Check How does closing the switch affect V o and I o?

OP AMP CHARACTERISTICS

Position and Speed Control. Industrial Electrical Engineering and Automation Lund University, Sweden

EE 215A Fundamentals of Electrical Engineering Lecture Notes Operational Amplifiers (Op Amps) 8/6/01 Reviewed 10/04

WYSE Academic Challenge Regional Physics 2008 SOLUTION SET

Diodes Waveform shaping Circuits. Sedra & Smith (6 th Ed): Sec. 4.5 & 4.6 Sedra & Smith (5 th Ed): Sec. 3.5 & 3.6

Diodes Waveform shaping Circuits

Introduction of Two Port Network Negative Feedback (Uni lateral Case) Feedback Topology Analysis of feedback applications

CHAPTER 11. Solutions for Exercises. (b) An inverting amplifier has negative gain. Thus L

EE C245 ME C218 Introduction to MEMS Design

Physics 121 Sample Common Exam 2 Rev2 NOTE: ANSWERS ARE ON PAGE 7. Instructions:

BRIEF NOTES ADDITIONAL MATHEMATICS FORM

EE 221 Practice Problems for the Final Exam

Lesson 5. Thermomechanical Measurements for Energy Systems (MENR) Measurements for Mechanical Systems and Production (MMER)

SMARANDACHE GROUPOIDS

Lecture 2 Feedback Amplifier

CURRENT FEEDBACK AMPLIFIERs

Designing Information Devices and Systems I Discussion 8B

CHAPTER 20: Second Law of Thermodynamics

ragsdale (zdr82) HW6 ditmire (58335) 1 the direction of the current in the figure. Using the lower circuit in the figure, we get

Common Gate Amplifier

Dead-beat controller design

Mathematics Extension 1

Feedback Principle :-

Linear Amplifiers and OpAmps

ANALOG ELECTRONICS 1 DR NORLAILI MOHD NOH

fiziks Institute for NET/JRF, GATE, IIT JAM, M.Sc. Entrance, JEST, TIFR and GRE in Physics

ECEN 4872/5827 Lecture Notes

Part a: Writing the nodal equations and solving for v o gives the magnitude and phase response: tan ( 0.25 )

Revision: August 19, E Main Suite D Pullman, WA (509) Voice and Fax

4. Eccentric axial loading, cross-section core

ME306 Dynamics, Spring HW1 Solution Key. AB, where θ is the angle between the vectors A and B, the proof

ELG4139: Op Amp-based Active Filters

FEEDBACK AMPLIFIERS. v i or v s v 0

GUC (Dr. Hany Hammad) 9/19/2016

GAUSS ELIMINATION. Consider the following system of algebraic linear equations

Fast Feedback Strategies for Longitudinal Beam Stabilization

2. VECTORS AND MATRICES IN 3 DIMENSIONS

Applied Statistics Qualifier Examination

3.1 Exponential Functions and Their Graphs

Institute for Competitive Examinations

Applying Kirchoff s law on the primary circuit. V = - e1 V+ e1 = 0 V.D. e.m.f. From the secondary circuit e2 = v2. K e. Equivalent circuit :

Part I: Basic Concepts of Thermodynamics

3.2.2 Kinetics. Maxwell Boltzmann distribution. 128 minutes. 128 marks. Page 1 of 12

, where. This is a highpass filter. The frequency response is the same as that for P.P.14.1 RC. Thus, the sketches of H and φ are shown below.

Microelectronics Circuit Analysis and Design. NMOS Common-Source Circuit. NMOS Common-Source Circuit 10/15/2013. In this chapter, we will:

Rank One Update And the Google Matrix by Al Bernstein Signal Science, LLC

ME 3600 Control Systems Frequency Domain Analysis

Consequently, the temperature must be the same at each point in the cross section at x. Let:

200 points 5 Problems on 4 Pages and 20 Multiple Choice/Short Answer Questions on 5 pages 1 hour, 48 minutes

Topics Covered AP Calculus AB

Lecture 7 Circuits Ch. 27

EEO 401 Digital Signal Processing Prof. Mark Fowler

Chapter 4 Homework solution: P4.2-2, 7 P4.3-2, 3, 6, 9 P4.4-2, 5, 8, 18 P4.5-2, 4, 5 P4.6-2, 4, 8 P4.7-2, 4, 9, 15 P4.8-2

Strong Bisimulation. Overview. References. Actions Labeled transition system Transition semantics Simulation Bisimulation

Fast Feedback Reactivity Effects

CTN 2/23/16. EE 247B/ME 218: Introduction to MEMS Design Lecture 11m2: Mechanics of Materials. Copyright 2016 Regents of the University of California

1. Ideal OP Amps. +V cc. R o. v 1 v 2. v o. R d 2 1. V cc. Ideal Characteristics A = (gain is infinite) (no offset voltage) R

CYLINDER MADE FROM BRITTLE MATERIAL AND SUBJECT TO INTERNAL PRESSURE ONLY

Solutions to Problems. Then, using the formula for the speed in a parabolic orbit (equation ), we have

State space systems analysis (continued) Stability. A. Definitions A system is said to be Asymptotically Stable (AS) when it satisfies

ARITHMETIC OPERATIONS. The real numbers have the following properties: a b c ab ac

Network Analysis and Synthesis. Chapter 5 Two port networks

Torsion, Thermal Effects and Indeterminacy

R(3, 8) P( 3, 0) Q( 2, 2) S(5, 3) Q(2, 32) P(0, 8) Higher Mathematics Objective Test Practice Book. 1 The diagram shows a sketch of part of

Lesson 2. Thermomechanical Measurements for Energy Systems (MENR) Measurements for Mechanical Systems and Production (MMER)

4. Introduction and Chapter Objectives

Why symmetry? Symmetry is often argued from the requirement that the strain energy must be positive. (e.g. Generalized 3-D Hooke s law)

Let s start from a first-order low pass filter we already discussed.

4.4 Areas, Integrals and Antiderivatives

The Operational Amplifier and Application

Mathematics Extension 2

5.1 Properties of Inverse Trigonometric Functions.

LINKÖPINGS TEKNISKA HÖGSKOLA. Fluid and Mechanical Engineering Systems

Use 10 m/s 2 for the acceleration due to gravity.

PH2200 Practice Exam I Summer 2003

Transcription:

Technte 6 prl 990 Resed /22/02 Op mp Dentns Tm J. Sberng SDE Cnsultng sdecnsultng@pbx.cm 990 Tm J. Sberng. ll rghts resered.

Op mp Dentns Pge 2 Op mp Dentns Ths Technte summrzes the bsc pertnl mpler dentns nd cmpres the del Op mp ssumptns wth the perrmnce rel mplers. Open Lp Gn: () Fgure. Op mp n pen-lp cngurtn Clsed Lp Gn (nertng): r: cl cl ( n) ( n) α (2) (3) Fgure 2. Inertng Op mp cngurtn Inertng mpler blck dgrm: α Σ Fgure 3. Inertng Op mp blck dgrm Clsed Lp Gn (nn-nertng): r: cl cl ( nn) ( nn) (4) (5) Fgure 4. Nn-Inertng Op mp cngurtn Cpyrght 990 Tm J. Sberng. ll rghts resered.

Op mp Dentns Pge 3 Nn-nertng mpler blck dgrm: Σ Lp Gn: Fgure 5. Nn-nertng Op mp blck dgrm l (6) Fgure 6. Dentn lp gn Feedbck Fctr: 2 (7) 2 ( ) α (8) Fgure 7. Dentn eedbck ctr Dertn cl, Inertng mpler Reerrng t Fgure 2 be nd pplyng KCL t the nertng nde: 0 (9) 0 (0) () cl ( n) (2) Cpyrght 990 Tm J. Sberng. ll rghts resered.

Resed /9/02 Pge 4 Cpyrght 990 Tm J. Sberng. ll rghts resered. cl n (3) cl n (4) Recgnzng tht nd α (5) α cl n (6) s cl n α (7) Nte tht Equtn (6) cn ls be expressed s: cl n (8) Dertn cl, Nn-nertng mpler 0 (9) 0 (20) (2) cl nn (22) cl nn (23)

Resed /9/02 Pge 5 Recgnzng tht (24) cl ( nn) (25) s ( nn) cl Equtn (25) cn ls be expressed s: cl ( nn) (27) Equtns (8) nd (27) re ery useul n exmnng the gn errr s unctn requency s the errr term ppers n the sme rm n bth equtns. Ths shws why hgh pen lp gn s mprtnt nd ls why t s ten necessry t select n Op mp wth hgh pen-lp gn nd/r hgher then expected bndwdth. Gn _ Errr (28) Settlng tme s relted, but seprte, prmeter. Due t the delys n prpgtn sgnl thrugh the nternl pmp crcutry, the utput tkes tme t rech t s nl lue. Ths s prtculr cncern r step nputs when slew rte, ersht nd rngng my dmnte the utput respnse. Gn (db) OPEN LOOP GIN (26) CL CLOSED-LOOP BNDWIDTH CLOSED LOOP GIN CL LOG Fgure 8. Open Lp nd Clsed Lp Mgntude Respnses. Cpyrght 990 Tm J. Sberng. ll rghts resered.

Resed /9/02 Pge 6 Idel Op mp ssumptns: R R Fgure 9. Op mp Equlent Crcut Idel Chrcterstc Crcut Eect N current lws n the nputs Ibs(,) 0 r n ltge gn s nnte, 0 N utput ltge r zer nput s 0 Output mpednce s zer ut 0 Frequency respnse s lt nd nnte BW r Dely 0 nd GBW Slew Rte s nnte BW r Dely 0 nd GBW CMRR s nnte Unlmted nput ltge rnge PSRR s nnte Immune t PS set nd rtns Nse ree Output due t sgnl nly Tble. Idel Op mp Chrcterstcs Reltes:. Bs currents cuse sets nd drt. 2. Fnte pen lp gn nd nte bndwdth result n gn errrs exmne lp gn term,, n Equtns (6) nd (25). 3. Input resstnce (mpednce) ntrduces errrs ppers n prllel wth. 4. Output resstnce (mpednce) ntrduces errrs ppers s ltge dder wth nd the ld. 5. Oset ltge ppers t the utput multpled by the nse gn. Oset ltge ls drts er tme due t temperture chnges. 6. Bs currents cuse sets nd re nt mtched between the nputs. They ls drt er tme due t temperture chnges. 7. Pwer supply msmtch cuses sets ppers s cmmn mde ltge t the nput. 8. CMRR s nt nnte s the nput ltge rnge s lmted nd nnlnertes pper n the putput s result cmmn mde ltges, prtuculrly n the nn-nertng cngurtn. 9. Rel Op mps he nse. 0. Op mps he grup dely,.e. nt ll requences experence the sme tme dely thrugh the crcut. Ths results n dstrtn.. Fnte slew rte cn result n utput dstrtn. Cpyrght 990 Tm J. Sberng. ll rghts resered.