Physics 122, Fall September 2012

Similar documents
Today in Physics 122: getting V from E

Physics 122, Fall October 2012

PHYS 1444 Section 501 Lecture #7

PHYS 1444 Lecture #5

$ i. !((( dv vol. Physics 8.02 Quiz One Equations Fall q 1 q 2 r 2 C = 2 C! V 2 = Q 2 2C F = 4!" or. r ˆ = points from source q to observer

Flux. Area Vector. Flux of Electric Field. Gauss s Law

17.1 Electric Potential Energy. Equipotential Lines. PE = energy associated with an arrangement of objects that exert forces on each other

Capacitors and Capacitance

Voltage ( = Electric Potential )


Gauss Law. Physics 231 Lecture 2-1

CHAPTER 10 ELECTRIC POTENTIAL AND CAPACITANCE

Potential Energy. The change U in the potential energy. is defined to equal to the negative of the work. done by a conservative force

Gauss s Law Simulation Activities

CHAPTER 25 ELECTRIC POTENTIAL

Phys 222 Sp 2009 Exam 1, Wed 18 Feb, 8-9:30pm Closed Book, Calculators allowed Each question is worth one point, answer all questions

Electric Field, Potential Energy, & Voltage

(Sample 3) Exam 1 - Physics Patel SPRING 1998 FORM CODE - A (solution key at end of exam)

Physics 313 Practice Test Page 1. University Physics III Practice Test II

Electrostatic Potential

Algebra-based Physics II

EM-2. 1 Coulomb s law, electric field, potential field, superposition q. Electric field of a point charge (1)

Phys102 Second Major-182 Zero Version Monday, March 25, 2019 Page: 1

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS

(r) = 1. Example: Electric Potential Energy. Summary. Potential due to a Group of Point Charges 9/10/12 1 R V(r) + + V(r) kq. Chapter 23.

( ) Make-up Tests. From Last Time. Electric Field Flux. o The Electric Field Flux through a bit of area is

Objectives: After finishing this unit you should be able to:

Hopefully Helpful Hints for Gauss s Law

Kinetic energy, work, and potential energy. Work, the transfer of energy: force acting through distance: or or

Force and Work: Reminder

Electrostatics (Electric Charges and Field) #2 2010

ELECTROSTATICS::BHSEC MCQ 1. A. B. C. D.

Welcome to Physics 272

Chapter 21: Gauss s Law

University Physics (PHY 2326)

Prepared by: M. S. KumarSwamy, TGT(Maths) Page - 1 -

Physics 2212 GH Quiz #2 Solutions Spring 2016

Today s Plan. Electric Dipoles. More on Gauss Law. Comment on PDF copies of Lectures. Final iclicker roll-call

2. Electrostatics. Dr. Rakhesh Singh Kshetrimayum 8/11/ Electromagnetic Field Theory by R. S. Kshetrimayum

Module 05: Gauss s s Law a

! E da = 4πkQ enc, has E under the integral sign, so it is not ordinarily an

Physics 1502: Lecture 4 Today s Agenda

Physics 2102 Lecture: 07 TUE 09 FEB

PHY2061 Enriched Physics 2 Lecture Notes. Gauss Law

F = net force on the system (newton) F,F and F. = different forces working. E = Electric field strength (volt / meter)

Physics 122, Fall December 2012

Electrostatics. 3) positive object: lack of electrons negative object: excess of electrons

Phys-272 Lecture 17. Motional Electromotive Force (emf) Induced Electric Fields Displacement Currents Maxwell s Equations

Objects usually are charged up through the transfer of electrons from one object to the other.

EELE 3331 Electromagnetic I Chapter 4. Electrostatic fields. Islamic University of Gaza Electrical Engineering Department Dr.

Your Comments. Do we still get the 80% back on homework? It doesn't seem to be showing that. Also, this is really starting to make sense to me!

Lecture 8 - Gauss s Law

Review for Midterm-1

Exam 1. Exam 1 is on Tuesday, February 14, from 5:00-6:00 PM.

ELECTRIC FIELD. decos. 1 dq x.. Example:

PHYS 2135 Exam I February 13, 2018

Charges, Coulomb s Law, and Electric Fields

Review: Electrostatics and Magnetostatics

Chapter 23: GAUSS LAW 343

Physics 2B Chapter 22 Notes - Magnetic Field Spring 2018

Phys 1215, First Test. September 20, minutes Name:

MASSACHUSETTS INSTITUTE OF TECHNOLOGY Physics Department Physics 8.07: Electromagnetism II September 15, 2012 Prof. Alan Guth PROBLEM SET 2

Review. Electrostatic. Dr. Ray Kwok SJSU

Faraday s Law (continued)

2 E. on each of these two surfaces. r r r r. Q E E ε. 2 2 Qencl encl right left 0

Review of Potential Energy. The Electric Potential. Plotting Fields and Potentials. Electric Potential of a Point Charge

An o5en- confusing point:

18.1 Origin of Electricity 18.2 Charged Objects and Electric Force

Physics 2A Chapter 10 - Moment of Inertia Fall 2018

Gauss s Law: Circuits

Φ E = E A E A = p212c22: 1

Magnetic Field. Conference 6. Physics 102 General Physics II

Chapter Sixteen: Electric Charge and Electric Fields

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS

Chapter 22 The Electric Field II: Continuous Charge Distributions

Electricity Revision ELECTRICITY REVISION KEY CONCEPTS TERMINOLOGY & DEFINITION. Physical Sciences X-Sheets

q r 1 4πε Review: Two ways to find V at any point in space: Integrate E dl: Sum or Integrate over charges: q 1 r 1 q 2 r 2 r 3 q 3

Electromagnetism Physics 15b

Target Boards, JEE Main & Advanced (IIT), NEET Physics Gauss Law. H. O. D. Physics, Concept Bokaro Centre P. K. Bharti

Module 10: Sections 5.1 through 5.4 Module 11: Sections 5.5 through Table of Contents

Physics 11 Chapter 20: Electric Fields and Forces

2/20/2009. Lecture notes Electrostatics

Current, Resistance and

Fields and Waves I Spring 2005 Homework 4. Due 8 March 2005

AP Physics Electric Potential Energy

Chapter 13 Gravitation

Electric Forces: Coulomb s Law

Module 5: Gauss s Law 1

Chapter 4 Gauss s Law

1. THINK Ampere is the SI unit for current. An ampere is one coulomb per second.

Phys-272 Lecture 18. Mutual Inductance Self-Inductance R-L Circuits

ev dm e evd 2 m e 1 2 ev2 B) e 2 0 dm e D) m e

Physics 107 TUTORIAL ASSIGNMENT #8

F (-4.32x x10 k) Newtons a = (-4.742x x10 )m/s 9.11x10 kg

Your Comments. Conductors and Insulators with Gauss's law please...so basically everything!

20-9 ELECTRIC FIELD LINES 20-9 ELECTRIC POTENTIAL. Answers to the Conceptual Questions. Chapter 20 Electricity 241

Physics 235 Chapter 5. Chapter 5 Gravitation

AP Physics C: Electricity and Magnetism 2003 Scoring Guidelines

FI 2201 Electromagnetism

Ch 30 - Sources of Magnetic Field! The Biot-Savart Law! = k m. r 2. Example 1! Example 2!

Transcription:

Physics 1, Fall 1 7 Septembe 1 Today in Physics 1: getting V fom E When it s best to get V fom E, athe than vice vesa V within continuous chage distibutions Potential enegy of continuous chage distibutions Capacitance Potential enegy in capacitos Paallel-plate and cylindical capacitos 84-faad supecapacito module (ICD) 7 Septembe 1 Physics 1, Fall 1 1 When it s easie to get V fom E Even if a distibution does not stetch to infinity, thee ae cases in which one cannot use the naïve Coulomb s law fom of the potential, V kdq -. Tivial example: a chaged conducting sphee. Chage unifom on suface, so V = kq/ thee. But E = inside, so the suface and Q inteio ae an equipotential: b V Ed b a so V = kq/ eveywhee inside. b a Yet kdq -. 7 Septembe 1 Physics 1, Fall 1 Example 1: V within a unifom chaged sphee So emembe to include potential fom oute chage, when computing Vwithina distibution of chage. Usually this is easiest to do by using the foolpoof expession fo potential: V Ed Example: the unifom sphee of chage, fo which we calculated E using Gauss s law (18 Sept 1): 4kˆ 3, E 3ˆ 4k 3, 7 Septembe 1 Physics 1, Fall 1 3 (c) Univesity of ocheste 1

Physics 1, Fall 1 7 Septembe 1 V within a unifom chaged sphee (continued) Because E changes fom at =, we have to split the integal into a sum of two: 3 4k d 4k VEd dd 3 3 3 4 k 1 4 k 3 3 4k 4k. 3 6 kdq kq 4k 4k Compae d ( V!). - 3 7 Septembe 1 Physics 1, Fall 1 4 Example : V within a non-unifom chaged sphee Conside a sphee with chage density given by 1,, Calculate the total chage g Q, Q and V,. Fist find E. Since is spheically symmetic we get to use Gauss s Law with a spheical Gaussian suface: EdA E 4 4kQencl E kqencl 7 Septembe 1 Physics 1, Fall 1 5 V within a non-unifom chaged sphee (cont d) Qencl dv 1 4 d 1 4 4 d d 3 5 4 3 5 While we e at it, get the total chage: 3 5 3 8 Q 4 3 15 5 7 Septembe 1 Physics 1, Fall 1 6 (c) Univesity of ocheste

Physics 1, Fall 1 7 Septembe 1 V within a non-unifom chaged sphee (cont d) So outside the sphee ( > ), E ˆ kq, while inside 3 3 it s E 15kQ 4k ˆ ˆ 3 3 3 5 5 Now we e eady to calculate V V. Again A i the integal i t l beaks b k into two: V Ed 3 d 15kQ kq d 3 3 5 7 Septembe 1 Physics 1, Fall 1 7 V within a non-unifom chaged sphee (cont d) 4 1 15kQ V kq 3 6 4 4 kq 15kQ 3 6 6 kq kq 4 4 5 3 1 7 8 Check: kq kq 4 4 4 V 5 3 1 7 8 kq 7 Septembe 1 Physics 1, Fall 1 8 Electostatic potential enegy of a continuous distibution of chage Similaly, one must be caeful about using U = qv to calculate electostatic potential enegy of continuous distibutions of chage. Hee s an example (poblem 3-64 in the book). A sphee with adius contains a total chage Q, unifomly distibuted though its volume. Calculate its electostatic potential enegy. Imagine building the sphee by binging d infinitesimal shells of the ight chage density in fom infinity one by one. 7 Septembe 1 Physics 1, Fall 1 9 (c) Univesity of ocheste 3

Physics 1, Fall 1 7 Septembe 1 Electostatic potential enegy of a continuous distibution of chage (continued) Since the chage is unifomly distibuted, the density is Q 3Q v 3 4 and if the infinitesimal chage bought fom infinity is spead d thick at this density, onto a sphee of adius composed of the shells which aived peviously, its value can be witten as dq 4 d dq d 7 Septembe 1 Physics 1, Fall 1 1 Electostatic potential enegy of a continuous distibution of chage (continued) Binging the shell in fom infinity involves wok, and this wok is the potential enegy of the shell-peviouslyexisting sphee combination: du dw V dq Since thee s no chage outside by Gauss s adius befoe the new shell Law aives, the potential at is calculated fom q d kq VEd kq d k dq 4 d 4k 3 7 Septembe 1 Physics 1, Fall 1 11 Electostatic potential enegy of a continuous distibution of chage (continued) Combine the last two esults and integate: 4 du V dq k 4 d 3 5 4 4 4 U k d k 3 3 5 3 4 3 3 kq k 3 5 5 Compae to the gavitational potential enegy of a unifom mass 3 GM M (PHY 11): U. 5 7 Septembe 1 Physics 1, Fall 1 1 dq d (c) Univesity of ocheste 4

Physics 1, Fall 1 7 Septembe 1 Capacitance Conside two conductos, chaged up to Q and Q. They ae equipotentials, and the voltage between them is V Ed, and nea each suface the electic field magnitude is E 4 k (18 Sept 1). Suppose we double the value of. What happens to the othe quantities? E Q -Q 7 Septembe 1 Physics 1, Fall 1 13 Capacitance (continued) Doubling doubles the total chage. It also doubles the magnitude of the electic field, but not the patten of field lines (just daw moe of them). And since it doubles the field, it doubles the voltage between the conductos. Appaently, dq is popotional to dv, so Q and V ae popotional. We call the popotionality facto the capacitance, C: Q = CV. E Q -Q 7 Septembe 1 Physics 1, Fall 1 14 What good is C? Enegy stoage in capacitos Capacitos ae impotant as electic cicuit elements. Cicuits can stoe enegy in, and eclaim enegy fom, capacitos. Conside, fo instance, caying a chage Q fom one conducto to the othe, one infinitesimal chage dq at a time: q dw Vdq dq C Q 1 1 Q 1 U W qdq C V. C C Usually we speak loosely about potential V and potential diffeence V in cicuits, and often wite Q CV o U CV. 7 Septembe 1 Physics 1, Fall 1 15 (c) Univesity of ocheste 5

Physics 1, Fall 1 7 Septembe 1 Calculation of the capacitance of aangements of conductos Othe mateials besides conductos have capacitance, but aangements of conductos lend themselves to staightfowad calculation of C. Usually this goes as follows: Pesume electic chage to be pesent; say, Q if thee is only one conducto, o ±Q if thee ae two. Eithe: Calculate the electic field fom the chages, and integate it to find the potential diffeence V between the conductos, o Solve fo the potential diffeence diectly, using V kdq -. Then C = Q/V. 7 Septembe 1 Physics 1, Fall 1 16 Paallel-plate capacito Conside two paallel conducting plates, sepaated by a distance d that is vey small compaed to thei extent in othe dimensions. Suppose each plate has aea A. It doesn t matte what the shape of the flat plates ae, as long as they ae paallel and vey close togethe. With chages Q on the plates, the chage densities ae unifom and have values Q A. w w w A d A d d A 7 Septembe 1 Physics 1, Fall 1 17 Paallel-plate capacito (continued) At points well inside the gap, the plates can be egaded as infinite, to good appoximation. As we found on 11 Septembe 1, the electic field between two oppositely-chaged infinite paallel plates is unifom, with magnitude E 4 k. Q A. d E 4 k Q A. 7 Septembe 1 Physics 1, Fall 1 18 (c) Univesity of ocheste 6

Physics 1, Fall 1 7 Septembe 1 Paallel-plate capacito (continued) So 4 kd Q V Ed 4kd Q A C A A C 4 kd d Q A. d E 4 k Q A. 7 Septembe 1 Physics 1, Fall 1 19 Cylindical capacito Conside two, coaxial, conducting cylindes with adii 1 and > 1. Thei length is L and they cay opposite chages Q (chage pe unit length QL). At points well inside the gap, the cylindes can be egaded as infinite, to good appoximation. 1 L 7 Septembe 1 Physics 1, Fall 1 Cylindical capacito (continued) We have shown by use of Gauss s law (18 Septembe 1) that kˆ, 1 E,, 1 fo infinite, oppositely-chaged coaxial cylindes. 1 L 7 Septembe 1 Physics 1, Fall 1 1 (c) Univesity of ocheste 7

Physics 1, Fall 1 7 Septembe 1 Cylindical capacito (continued) d Q Thus Q V Ed k k ln ; L 1 C 1 L L C. kln 1 ln 1 1 L 7 Septembe 1 Physics 1, Fall 1 Units of capacitance In MKS: the unit of capacitance, named in hono of Michael 1 coul Faaday, is the faad : 1F = 1 volt 1-1 - Note that 8.851 coul Nt m 1-1 -1 885 8.85 1 F m 8.85 885 pf m One faad is a Huge capacitance. Those found aound the lab and in cicuits ae usually in the pf- F ange (1-1 -1-6 F). A 1F paallel-plate capacito with d = 5 m (.1 in) has A =.8 km : 1.7 km on a side, if squae..8 cm 7 Septembe 1 Physics 1, Fall 1 3 (c) Univesity of ocheste 8