Unit 3 Exam Review Questions MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

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Unit Eam Review Questions MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Some Useful Formulas: Compound interest formula: A=P + r nt n Continuously compounded interest formula: A=Pe rt Find all numbers that must be ecluded from the domain of the rational epression. - 8 ) + + 0 0 8 8, 5-8, -5 ) ) - + 8 + 5 -, -5 0, 5 ) ) - 6 + - 6 0-6, -, 6 ) ) + 7-6, - -7 6 ) Multiply or divide as indicated. Simplify completely. 5) - 8 + 6 8-0 - 0 80-8 + 6 ( - ) ( - ) 80 6 5) 6) - 6 7-7 + 8 + 6-7 - 7 7 7 6) 7) + 0 - + -0-0 7) - - + - + ( + ) + (- - )

8) + 8 + 6 + 9 + + 6 - - 8 8) - 7-7 ( + 9) - 7 + + 6 9) 8 + 0 + 5 9) 5 5 6 5 Add or subtract as indicated. 0) + - 6-0) - ( + )( - ) - + ( + )( - ) - + 6 ( + )( - ) - - ( + )( - ) ) + 5 + - + 5 - + - 8 ) 6 + + 6-0 6 + 6 + 5 - ( + )( - 6)( - ) 6 + 5 - ( - )( + 6)( + ) ) + - + 7 - ) 8 - ( - )( + )( - ) 9 - ( - )( + )( - ) - 9 ( - )( + )( - ) 9 - ( - )( - ) ) 5 - + + 5 + 5 - + 5 + ) + 5 + + - + 5 + + ) 7-6 - - 6 ) 7 7 - - 7 7 5) + 9-6 5) - 8 ( - 6) - 8 (6 - ) 8 - (6 - ) 8 - ( - 6)

Solve the equation. 6) + = - + + - + 6) - 5 {-} {} 7) m + m - m - + m - 8 m = + 8m + 6 m + m - 8 { -0 } { -0 } { 0 } { - } 7) 8) 9) y + - 7 y - = 0 y - 6 {8} { } {5} {-8} + 6 + + = - + 9 + 8 {0} {-6} {} 8) 9) Find the vertical asymptotes, if any, of the graph of the rational function. 0) h() = ( - ) = 0 and = - = = 0 and = no vertical asymptote ) f() = + = = -, = = - no vertical asymptote ) g() = - = =, = - =, = -, = 0 no vertical asymptote 0) ) ) ) - - + 7 = - = -, = -9 =, = 9, = - =, = 9 ) ) g() = - = 0 and = - = 0 and = = no vertical asymptote )

Find the horizontal asymptote, if any, of the graph of the rational function. 5) g() = 5 - - 6 6 - + 7 5) y = 5 6 y = y = 0 no horizontal asymptote 6) f() = + 5 6) y = - 5 y = 0 y = no horizontal asymptote 7) g() = + 7) y = y = y = 0 no horizontal asymptote -5 8) f() = 5 + + 8) y = - y = - y = 0 no horizontal asymptote Use the horizontal line test to determine whether the function is one-to-one. 9) 9) Yes No

0) 0) No Yes ) ) No Yes ) ) No Yes Find the inverse of the one-to-one function. ) f() = ( + 8) ) f - () = + 8 f - () = - 5 f - () = - 8 f - () = - 8 5

) f() = 7 - ) f - () = 7y + 7 f - () = - 7-7 f - () = 7 + 7 f - () = 7-5) f() = ( + 5) 5) f - () = + 5 f - () = - 5 f - () = - 5 f - () = - 5 6) f() = 5 + 8 6) f - () = 8 + 5 f - () = 8 5 - f - () = 8 5 + f - () = 8-5 Write the equation of the graph in its final position. 7) The graph of y = e is translated 6 units to the right and then units upward. 7) y = e + 6 + y = e - + 6 y = e + + 6 y = e - 6 + The graph of an eponential function is given. Select the function for the graph from the functions listed. 8) 8) f() = f() = - f() = - f() = + 6

9) 9) f() = - f() = - - f() = - f() = 0) 0) f() = - - f() = - f() = f() = - Solve the problem.. ) An initial investment of $80 earns interest for 7 years in an account that earns % interest, compounded quarterly. Find the amount of money in the account at the end of the 7 year period. $8. $9.5 $75. $695.0 ) Suppose that you have $000 to invest. Which investment yields the greater return over 9 years: 7.5% compounded continuously or 7.6% compounded semiannually? Both investment plans yield the same return. $000 invested at 7.6% compounded semiannually over 9 years yields the greater return. $000 invested at 7.5% compounded continuously over 9 years yields the greater return. ) Find the accumulated value of an investment of $0,000 at % compounded semiannually for 8 years. $50,807.0 $9,00.00 $,876.96 $9,59.6 ) Suppose that you have $0,000 to invest. Which investment yields the greater return over 7 years: 6.6% compounded monthly or 6.7% compounded quarterly? Both investment plans yield the same return. $0,000 invested at 6.6% compounded monthly over 7 years yields the greater return. $0,000 invested at 6.7% compounded quarterly over 7 years yields the greater return. ) ) ) ) 7

Solve the equation. 5) log / = - 5) 8 6 6 8 6) log ( + ) - log ( - ) = log 6) {0} {-0} 7) log = log 5 + log ( - ) 7) {-0} {0} - 5 8) log 5 ( + 5) = log 5 ( + ) 8) 7 {} {0} Simplify the epression. 9) 8 log 8 (6) 9) 8 8 6 6 Use common logarithms or natural logarithms and a calculator to evaluate to four decimal places 50) log 6 50) 0.689 0.80.565.75 5) log 7 5).7860 0.558 0.666.50 5) log (.85) 5) 7.965.966 0.005.50 Solve the equation. 5) 9 - =() 5) - -6 6 Solve the eponential equation. Epress the solution set in terms of natural logarithms. 5) + = 5 + 5 5) {ln 5 - ln } {7 ln 5-5 ln } ln 5 ln 5 - ln ln - ln 5 5 5-5 8

55) 5 9 =.7 55) ln.7.7 ln 9 9 ln.7 ln.7 9 ln 5 ln 5 ln 5 5 ln 9 Solve the equation by epressing each side as a power of the same base and then equating eponents. 56) ( + 6) = 7 56) 9 {} {-} {9} 57) 6 = 6 57) {} 5 58) e + = e 58) {-} {5} {-5} {} Solve the equation. Round your answer to three decimal places. 59) (-) = 9 59).800 -.65.588 Solve the eponential equation. Use a calculator to obtain a decimal approimation, correct to two decimal places, for the solution. 60) e = 7 60) -.5-0.6 0.6.5 Rewrite the epression as a single logarithm. 6) 6 log m (y )- log m ( ) 6) logm y6 5 logm 6y logm y6 logm y6 6 6) ln + 9ln y 6) ln y 9 ln ( + 9y) ln 9y ln y 9 6) log b y + 6log b z 6) log b y z 6 0log b yz log b yz log b (yz) 0 6) (log 7 (r - ) - log7 r) 6) log7 r - r log7 r - r log7 r - r log7 r - r 9

Rewrite the epression as a sum or difference of logarithms or multiples of logarithms. 65) log 9 y 8 7 9 log () + 8 log (y) - log (7) 9 log () - 8 log (y) - log (7) (9 log ())(8 log (y)) - log (7) 9 log () + 8 log (y) + log (7) 65) Use properties of logarithms to epand the logarithmic epression as much as possible. Where possible, evaluate logarithmic epressions without using a calculator. 66) log y 8 66) log - 8 log y 8 log y - log log + 8 log y 8 log ( y ) 67) log 67) log - - log log - - log 8 68) log y 68) 8 log - log y - log 8 log - log y - log 8 log - log y - log 8 log - log y - log Use properties of logarithms to epand the logarithmic epression as much as possible. 69) log 6 0 69) log 6 0 + log 6 log 6 0 + log 6 log 6 0 log 6 0 + log 6 70) log 5 + 5 70) log 5 ( + 5) - log 5 log 5 ( + 5) + log 5 log 5 ( + 5) - log 5 log 5 - log 5 ( + 5) 7) log w 7 log w 7 + log w + log w log w 7 - log w log w 7 + log w - log w log w 7) 0

Determine whether the given ordered pair is a solution of the system. 7) (-, -) - y = -6 + y = - solution not a solution 7) (, ) - y = - y = 7 not a solution solution 7) (-5, ) = - - y = -8 - y not a solution solution 7) 7) 7) Solve the following systems of linear equations. 75) - y = - + y = 5 75) No Solution (, 5) (9, 8) (8, 9) 76) - + y = - y = 0 {(-6, -8)} {(-8, 6)} {(-8, -6)} {(-7, -6)} 76) 77) y = 5-5y + 5 = -95 {(, -)} {(-, -)} {(-, -)} 77) 78) 8 + 8y = 8 5 -y = 8 Infinitely Many Solutions {(, )} No Solution {(, )} 78) 79) 6 + y = 9-7y = -7 {(0, 0)} {(0, )} {(, 0)} {(, )} 80) + y = 0 + y = {(-, 6)} {(-6, )} {(6, -)} {(-6, )} 8) - + 5y = - 7 - y = {(-, -)} {(, )} {(, -)} {(-, )} 79) 80) 8)

Solve the problem. 8) The sum of two numbers is. If one number is subtracted from the other, their difference is 5. Find the numbers. -8, -7 8, -7 0, 8, 7 8) One number is 9 less than a second number. Twice the second number is more than times the first. Find the two numbers. -5 and -6 - and - 5 and - and -5 8) There were 60 people at a play. The admission price was $ for adults and $ for children. The admission receipts were $950. How many adults and how many children attended? 0 adults, 0 children 7 adults, 9 children 55 adults, 75 children 0 adults, 0 children 85) A vendor sells hot dogs and bags of potato chips. A customer buys hot dogs and bags of potato chips for $0.75. Another customer buys hot dogs and 5 bags of potato chips for $9.75. Find the cost of each item. $.00 for a hot dog; $.50 for a bag of potato chips $.75 for a hot dog; $.50 for a bag of potato chips $.5 for a hot dog; $.75 for a bag of potato chips $.75 for a hot dog; $.5 for a bag of potato chips 86) A rectangular lot whose perimeter is 500 feet is fenced along three sides. An epensive fencing along the lot's length costs $ per foot, and an inepensive fencing along the two side widths costs only $6 per foot. The total cost of the fencing along the three sides comes to $50. What are the lot's dimensions? Length 8 ft; Width 0 ft Length 00 ft; Width 00 ft Length 50 ft; Width 00 ft Length 5 ft; Width 96 ft 8) 8) 8) 85) 86)

Answer Key Testname: CA UNIT PRACTICE EXAM FALL0V59NOREGEN ) D ) A ) C ) B 5) B 6) C 7) A 8) B 9) A 0) D ) D ) B ) D ) D 5) A 6) D 7) B 8) D 9) D 0) B ) D ) B ) D ) C 5) A 6) C 7) A 8) C 9) B 0) B ) B ) A ) D ) B 5) B 6) D 7) D 8) B 9) B 0) B ) C ) C ) A ) C 5) D 6) B 7) C 8) D 9) D 50) C 5) D 5) B 5) D 5) B 55) A 56) C 57) D 58) C 59) D 60) D 6) D 6) D 6) A 6) B 65) A 66) A 67) C 68) A 69) D 70) C 7) C 7) B 7) A 7) B 75) D 76) C 77) C 78) A 79) B 80) C 8) C 8) B 8) D 8) D 85) D 86) C