Chapter 10 Liquids, Solids and Phase Changes

Similar documents
What determines the phase of a substance? Temperature Pressure Interparticle Forces of Attraction

States of Matter; Liquids and Solids. Condensation - change of a gas to either the solid or liquid state

Liquids and Solids. H fus (Heat of fusion) H vap (Heat of vaporization) H sub (Heat of sublimation)

Chapter 12. Insert picture from First page of chapter. Intermolecular Forces and the Physical Properties of Liquids and Solids

Chapter 10. Liquids and Solids

Chapter 10. Liquids and Solids

Liquids, Solids, and Phase Changes

Chapter 11. Intermolecular Forces and Liquids & Solids

Chem 112 Dr. Kevin Moore

Intermolecular Forces and Liquids and Solids

Intermolecular Forces and Liquids and Solids

Intermolecular Forces and Liquids and Solids. Chapter 11. Copyright The McGraw Hill Companies, Inc. Permission required for

CHAPTER 11: INTERMOLECULAR FORCES AND LIQUIDS AND SOLIDS. Chemistry 1411 Joanna Sabey

compared to gases. They are incompressible. Their density doesn t change with temperature. These similarities are due

2. As gas P increases and/or T is lowered, intermolecular forces become significant, and deviations from ideal gas laws occur (van der Waal equation).

Intermolecular Forces and States of Matter AP Chemistry Lecture Outline

Ch. 9 Liquids and Solids

CHAPTER ELEVEN KINETIC MOLECULAR THEORY OF LIQUIDS AND SOLIDS KINETIC MOLECULAR THEORY OF LIQUIDS AND SOLIDS

= = 10.1 mol. Molar Enthalpies of Vaporization (at Boiling Point) Molar Enthalpy of Vaporization (kj/mol)

Chapter 10: Liquids and Solids

2. As gas P increases and/or T is lowered, intermolecular forces become significant, and deviations from ideal gas laws occur (van der Waal equation).

Intermolecular Forces and Liquids and Solids

- intermolecular forces forces that exist between molecules

Chapters 11 and 12: Intermolecular Forces of Liquids and Solids

Chapter 12 INTERMOLECULAR FORCES. Covalent Radius and van der Waals Radius. Intraand. Intermolecular Forces. ½ the distance of non-bonded

AP* Chapter 10. Liquids and Solids. Friday, November 22, 13

They are similar to each other. Intermolecular forces

ก ก ก Intermolecular Forces: Liquids, Solids, and Phase Changes

CRYSTAL STRUCTURE, PHASE CHANGES, AND PHASE DIAGRAMS

They are similar to each other

9/2/10 TYPES OF INTERMOLECULAR INTERACTIONS

Ch. 11: Liquids and Intermolecular Forces

Chemistry 101 Chapter 14 Liquids & Solids

States of matter. Chapter 11. Kinetic Molecular Theory of Liquids and Solids. Kinetic Molecular Theory of Solids Intermolecular Forces

Liquids, Solids and Phase Changes

CHEMISTRY The Molecular Nature of Matter and Change

CHAPTER 11: Intermolecular Forces, Liquids, and Solids. Are there any IDEAL GASES? The van der Waals equation corrects for deviations from ideality

Chapter 14. Liquids and Solids

Lecture Notes 1: Physical Equilibria Vapor Pressure

CHEMISTRY - TRO 4E CH.11 - LIQUIDS, SOLIDS & INTERMOLECULAR FORCES

Intermolecular Forces and Phase Equilibria

Chapter #16 Liquids and Solids

Chapter 10 Review Packet

Chapter 14. Liquids and Solids

Chapter 12 Intermolecular Forces of Attraction

Chemistry B11 Chapter 6 Gases, Liquids, and Solids

Intermolecular Forces, Liquids, Solids. IM Forces and Physical Properties

Chapter 10 Liquids and Solids

Liquids and Solids. Copyright The McGraw-Hill Companies, Inc. Permission required for reproduction or display.

Chapter 11. Intermolecular Forces, Liquids, and Solids

General Chemistry 202 CHM202 General Information. General Chemistry 202 CHM202 Policies. General Chemistry 202 CHM202 Laboratory Guidelines

Chapter 11 Intermolecular Forces, Liquids, and Solids

Intermolecular Forces and Liquids and Solids Chapter 11

Name: Date: Grade. Work Session # 12: Intermolecular Forces

Intermolecular forces (IMFs) CONDENSED STATES OF MATTER

Thermochemistry Chapter 8

Lecture Presentation. Chapter 11. Liquids and Intermolecular Forces Pearson Education, Inc.

Chapter 12 Intermolecular Forces and Liquids

Chem 112 Exam 1 Version A Spring /16/ :00am/Odago, M. O.

States of Matter. The Solid State. Particles are tightly packed, very close together (strong cohesive forces) Low kinetic energy (energy of motion)

Ch 9 Liquids & Solids (IMF) Masterson & Hurley

Chemistry: The Central Science

DIFFERENT TYPES OF INTEMOLECULAR FORCES INTERMOLECULAR FORCES

Chap. 12 INTERMOLECULAR FORCES

CHAPTER 11 INTERMOLECULAR FORCES AND LIQUIDS AND SOLIDS

Chapter 16: Phenomena. Chapter 16 Liquids and Solids. intermolecular forces? Intermolecular Forces. Intermolecular Forces. Intermolecular Forces

CHEM Principles of Chemistry II Chapter 10 - Liquids and Solids

Chapter 11 Intermolecular Forces, Liquids, and Solids

Property of liquid and Phase Diagram for EN 2017

Intermolecular Forces. Chapter 16 Liquids and Solids. Intermolecular Forces. Intermolecular Forces. Intermolecular Forces. Intermolecular Forces

Properties of Liquids and Solids. Vaporization of Liquids. Vaporization of Liquids. Aims:

Properties of Liquids and Solids. Vaporization of Liquids

Chapter 11/12: Liquids, Solids and Phase Changes Homework: Read Chapter 11 and 12 Keep up with assignments

Intermolecular Forces: Liquids, and Solids. Chapter 11

Intermolecular Forces

Properties of Liquids and Solids

Chapter 11. Freedom of Motion. Comparisons of the States of Matter. Liquids, Solids, and Intermolecular Forces

Chapter 10. Liquids and Solids. Copyright 2017 Cengage Learning. All Rights Reserved.

Chapter 11 Liquids and Intermolecular Forces

Intermolecular forces Liquids and Solids

Critical Temperature - the temperature above which the liquid state of a substance no longer exists regardless of the pressure.

Liquids & Solids. For the condensed states the ave KE is less than the attraction between molecules so they are held together.

Liquids and Solids Chapter 10

Honors Chemistry Dr. Kevin D. Moore

Chapter 11. Liquids, Solids, and Intermolecular Forces. Water, No Gravity. Lecture Presentation

London Dispersion Forces (LDFs) Intermolecular Forces Attractions BETWEEN molecules. London Dispersion Forces (LDFs) London Dispersion Forces (LDFs)

a) 1.3 x 10 3 atm b) 2.44 atm c) 8.35 atm d) 4.21 x 10-3 atm e) 86.5 atm

Sample Exercise 11.1 Identifying Substances That Can Form Hydrogen Bonds

GENERAL CHEMISTRY II CHM202 Unit 1 Practice Test Solutions

Nestor S. Valera Ateneo de Manila. Chapter 12 - Intermolecular Forces

UNIT 14 IMFs, LIQUIDS, SOLIDS PACKET. Name: Date: Period: #: BONDING & INTERMOLECULAR FORCES

Chem 1075 Chapter 13 Liquids and Solids Lecture Outline

INTERMOLECULAR FORCES AND COLLIGATIVE PROPERTIES HOMEWORK ANSWERS

Chem 1102 Semester 2, 2010 PHYSICAL STATES AND PHASE DIAGRAMS

Let's look at how different properties affect vapor pressure. P =0 P =vapor pressure P =vapor pressure. first all liquid

Chapter 11. Kinetic Molecular Theory. Attractive Forces

Chapter 9. Liquids and Solids

Problem Set 10 Solutions

Honors Chemistry. Chapter 10: Forces of Attraction, Phase Change, Date / / Period and Solids Answer Key. Intermolecular and Intramolecular Forces

General Chemistry I. Dr. PHAN TẠI HUÂN Faculty of Food Science and Technology Nong Lam University. Module 3: The Three States of Matter

Transcription:

Chapter 10 Liquids, Solids and Phase Changes

The three phases of matter: solids, liquids and gases

Phase change properties of pure water at 1 atm pressure

What is a boiling point? What does it measure? H 2 O: a unique substance

Hydrogen bonds: hydrogen attached to an oxygen in particular, is capable of causing association. The association is electrostatic in nature and leads to compounds that have significantly more association than one would otherwise expect. Compounds that form hydrogen bonds have a form of chemical stickyness not found in other materials. Significance: Self association is fundamental to understanding all biological processes and more often than not, hydrogen bonding is responsible for this self association. A few examples: 1. reproduction of the genetic code 2. antigen-antibody response 3. transport across cell membranes 4. What hold paper together?

When many sugars are linked together you have polysaccharides, which are natural polymers: Because the single sugars can be either α or β, two different linkages arise. When glucose polymerizes, an α linkage makes starch and a β linkage makes cellulose. 11.3

oxygen: red; hydrogen: white Hydrogen bonding in H 2 O

Other types of weak bonds leading to some self association: 1. Dipole-dipole interactions: forces associated with nonsymmetrical molecules especial those that have atoms bonded with large electronegativity differences. 2. London dispersion forces: the weakest of all the forces we encounter. These forces are responsible for our ability to condense substances such as methane, N 2, He. These forces are often encountered in symmetrical molecules and in molecule in which the electrons are shared equally. What is the experimental evidence for these forces?

Electronegativities

a dipole is a vector, that is it has both magnitude and direction

Dipole moment is define as charge separation*distance of separation; dipole moments are vectors is so far as they have magnitude and direction.

Fusion enthalpy: the amount of heat necessary to convert a fixed amount of solid at its melting temperature to the liquid at the same temperature. Units: J/mol; J/g Vaporization enthalpy: the amount of heat necessary to convert a fixed amount of liquid at its boiling temperature to the gas at the same temperature. Units: J/mol; J/g

Normal boiling temperature: the temperature at which the vapor pressure of the liquid equals 1 atm How does vapor pressure vary with temperature? How do we measure vaporization enthalpy?

To vacuum liquid Liquid at a constant temperature One way of measuring vapor pressures 1. Cool the liquid to a very low temperature One method of 2. Open measuring the valve vapor to vacuum to pressure remove any air 3. Close the valve to the vacuum 4. Replace the liquid with a bath at a constant temperature and record the change in the different levels of mercury

Plot ln(p) against 1/T where T is in Kelvin What s ln(p)? Whats log(p)?

Logarithms: expressing a number in the form of an exponent number log logarithm base 10 10 1 10 1 100 2 10 2 1000 3 10 3 number ln logarithm base 2.718 2.718 1 2.718 1 = 2.718 7.39 2 2.718 2 = 7.39 20.09 3 2.718 3 = 20.09 ln(x) = 2.303log(x)

the log of the number 200 log(200) = 2.3 10 2.3 = 200; log uses the base 10 ln(200) = 5.2983; 2.718 5.2983 Where does the number 2.718 come from? 2.718 is the area under the curve of 1/x where x goes from 0 to infinity 1/x x

How do we measure vaporization enthalpy? It has been found that by measuring the vapor pressure of a liquid as a function of temperature, an exponential increase in vapor pressure is observed. Furthermore, it has bee also found that by plotting the logarithm of vapor pressure as a function of 1/T where T is in K, a linear plot is obtained. The slope of the line has been found to equal to -ΔH vap /R where R is the gas constant, 1.987 cal/mol or 8.314 J/mol

We can express this line using the general equation for a straight line: y = mx +b in this case y = lnp, and x = 1/T; the slope of the line is found to be -ΔH vap /R

Clausius Clapeyron Equation ln(p) = 2.303log(P) ΔH vap = vaporization enthalpy R=gas constant 1.987 cal/(k mol); 8.314 J/(mol K); 0.0821Latm/(K mol)

Let calculate the vaporization enthalpy of water at T = 298 K: lnp 1 = -ΔH vap / [1/T 1 ]/R + b lnp 2 = -ΔH vap [1/T 2 ] /R + b lets subtract the first eq from the second lnp 2 -lnp 1 = -ΔH vap [1/T 2-1/T 1 ] /R 3.459-2.862 = -ΔH vap [1/303-1/293] /R.597*8.314J/(mol K)=.00011 ΔH vap ΔH vap = 45120 J/mol at 298 K; the text reports 40670 at 373 K

We have now learned how to experimentally calculate ΔH vap ; ΔH sub is calculated in the same way using the same equation. We calculate ΔS vap for a phase change at constant temperature? ΔS vap = ΔH vap /T b where ΔH vap is the value measured at the boiling point T b ; likewise ΔH fus = ΔH fus /T fus where T fus is the melting point

The text reports 40670 at 373 K; since the boiling of water takes place at a constant temperature, ΔG = 0; the entropy change ΔS vap = ΔH vap /T b = 40670/373 = 109 J/(mol K) ΔS fus = ΔH fus /T fus = 6010/273 = 22.0 J/(mol K)

Phase Diagram of Water Vapor

Nitrogen bp = -186 C Dry Ice (CO 2 ) bp = -77 C? -77 C is the temperature at which the vapor pressure of CO 2 = 1 atm Why doesn t Dry Ice melt?

Phase Diagram of CO2

Viscosity and surface tension Viscosity relates to how freely molecules can flow over each other; is related to the nature of the intermolecular forces present in liquid. Surface tension is the term used to describe the unequal forces acting on those molecules on a surface that are not surrounded by other molecules; causes formation of spheres N =kg * m/s 2; force= mass*accelation

Packing in solids How is structure in the crystalline state determined? NaCl cubic structure

A brief tutorial on some properties of waves, light waves

λ = wavelength of light θ d θ 90 a (90 - θ) sin θ = a/d d= a /sin θ or a =dsin θ

a =dsin θ a =BC; CB BC +CB = 2d sin θ = nλ for constructive interference d = nλ/2sin θ

How do different substances pack in the solid?

52% of the volume occupied only polonium crystallizes in this motif 68 % of the volume used; examples Fe, Na + 14 other metals crystallize in this motif

Hexagonal closest packed 74% of the volume is occupied; Zn, Mg and 19 other metals pack in this motif Cubic closest packed 74% of the volume is occupied; Ag, Cu and 16 other metals pack in this motif

Unit cell: smallest repeat unit that can generate the entire 3-d structure; 14 different unit cell geometries possible 3 different kinds of cubic cell geometry 1. primitive cubic 2. face centered cubic 3. body centered cubic

How many atoms in each of these simplest repeat units? primitive cubic body centered cubic

Face centered cubic How many atoms in this unit cell?

Copper crystallizes in a face centered cubic unit cell with an edge length of 3.62x10-8 cm. How many atoms in a unit cell of Cu? What is the radius of a copper atom and what is the density of Cu? 4 h 2 = edge 2 + edge 2 h 2 = 2*(3.62x10-8 ) 2 h =[26.2x10-16 ] 1/2 h = 5.12x10-8 cm How many radui is h? 4, radius = 1.28x10-8 cm Volume of unit cell? V= r 3 V = (3.62x10-8 ) 3 = 47.8x 10-24 cm 3 How many atoms? 4 atoms If 4 atoms have this volume, then 6x10 23 atoms would have a volume of 6x10 23 x 47.8x 10-24 /4 cm 3 = 7.17 cm 3 63.5g/7.17cm 3 = 8.85 g/cm 3 ; 8.94g/cm 3 (25 C)

Liquid Crystals